Optimal. Leaf size=48 \[ \frac {16}{315} b^2 x^{9/2}-\frac {8}{35} b x^{7/2} \tanh ^{-1}(\tanh (a+b x))+\frac {2}{5} x^{5/2} \tanh ^{-1}(\tanh (a+b x))^2 \]
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Rubi [A]
time = 0.02, antiderivative size = 48, normalized size of antiderivative = 1.00, number of steps
used = 3, number of rules used = 2, integrand size = 15, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.133, Rules used = {2199, 30}
\begin {gather*} -\frac {8}{35} b x^{7/2} \tanh ^{-1}(\tanh (a+b x))+\frac {2}{5} x^{5/2} \tanh ^{-1}(\tanh (a+b x))^2+\frac {16}{315} b^2 x^{9/2} \end {gather*}
Antiderivative was successfully verified.
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Rule 30
Rule 2199
Rubi steps
\begin {align*} \int x^{3/2} \tanh ^{-1}(\tanh (a+b x))^2 \, dx &=\frac {2}{5} x^{5/2} \tanh ^{-1}(\tanh (a+b x))^2-\frac {1}{5} (4 b) \int x^{5/2} \tanh ^{-1}(\tanh (a+b x)) \, dx\\ &=-\frac {8}{35} b x^{7/2} \tanh ^{-1}(\tanh (a+b x))+\frac {2}{5} x^{5/2} \tanh ^{-1}(\tanh (a+b x))^2+\frac {1}{35} \left (8 b^2\right ) \int x^{7/2} \, dx\\ &=\frac {16}{315} b^2 x^{9/2}-\frac {8}{35} b x^{7/2} \tanh ^{-1}(\tanh (a+b x))+\frac {2}{5} x^{5/2} \tanh ^{-1}(\tanh (a+b x))^2\\ \end {align*}
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Mathematica [A]
time = 0.03, size = 40, normalized size = 0.83 \begin {gather*} \frac {2}{315} x^{5/2} \left (8 b^2 x^2-36 b x \tanh ^{-1}(\tanh (a+b x))+63 \tanh ^{-1}(\tanh (a+b x))^2\right ) \end {gather*}
Antiderivative was successfully verified.
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Maple [A]
time = 0.28, size = 38, normalized size = 0.79
method | result | size |
derivativedivides | \(\frac {2 x^{\frac {5}{2}} \arctanh \left (\tanh \left (b x +a \right )\right )^{2}}{5}-\frac {8 b \left (\frac {x^{\frac {7}{2}} \arctanh \left (\tanh \left (b x +a \right )\right )}{7}-\frac {2 b \,x^{\frac {9}{2}}}{63}\right )}{5}\) | \(38\) |
default | \(\frac {2 x^{\frac {5}{2}} \arctanh \left (\tanh \left (b x +a \right )\right )^{2}}{5}-\frac {8 b \left (\frac {x^{\frac {7}{2}} \arctanh \left (\tanh \left (b x +a \right )\right )}{7}-\frac {2 b \,x^{\frac {9}{2}}}{63}\right )}{5}\) | \(38\) |
risch | \(\text {Expression too large to display}\) | \(2093\) |
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A]
time = 0.28, size = 36, normalized size = 0.75 \begin {gather*} \frac {16}{315} \, b^{2} x^{\frac {9}{2}} - \frac {8}{35} \, b x^{\frac {7}{2}} \operatorname {artanh}\left (\tanh \left (b x + a\right )\right ) + \frac {2}{5} \, x^{\frac {5}{2}} \operatorname {artanh}\left (\tanh \left (b x + a\right )\right )^{2} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A]
time = 0.36, size = 29, normalized size = 0.60 \begin {gather*} \frac {2}{315} \, {\left (35 \, b^{2} x^{4} + 90 \, a b x^{3} + 63 \, a^{2} x^{2}\right )} \sqrt {x} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int x^{\frac {3}{2}} \operatorname {atanh}^{2}{\left (\tanh {\left (a + b x \right )} \right )}\, dx \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A]
time = 0.38, size = 24, normalized size = 0.50 \begin {gather*} \frac {2}{9} \, b^{2} x^{\frac {9}{2}} + \frac {4}{7} \, a b x^{\frac {7}{2}} + \frac {2}{5} \, a^{2} x^{\frac {5}{2}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [B]
time = 1.14, size = 122, normalized size = 2.54 \begin {gather*} \frac {x^{5/2}\,{\left (\ln \left (\frac {2}{{\mathrm {e}}^{2\,a}\,{\mathrm {e}}^{2\,b\,x}+1}\right )-\ln \left (\frac {2\,{\mathrm {e}}^{2\,a}\,{\mathrm {e}}^{2\,b\,x}}{{\mathrm {e}}^{2\,a}\,{\mathrm {e}}^{2\,b\,x}+1}\right )+2\,b\,x\right )}^2}{10}+\frac {2\,b^2\,x^{9/2}}{9}-\frac {2\,b\,x^{7/2}\,\left (\ln \left (\frac {2}{{\mathrm {e}}^{2\,a}\,{\mathrm {e}}^{2\,b\,x}+1}\right )-\ln \left (\frac {2\,{\mathrm {e}}^{2\,a}\,{\mathrm {e}}^{2\,b\,x}}{{\mathrm {e}}^{2\,a}\,{\mathrm {e}}^{2\,b\,x}+1}\right )+2\,b\,x\right )}{7} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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