Optimal. Leaf size=150 \[ x \tanh ^{-1}(c+d \tanh (a+b x))+\frac {1}{2} x \log \left (1+\frac {(1-c-d) e^{2 a+2 b x}}{1-c+d}\right )-\frac {1}{2} x \log \left (1+\frac {(1+c+d) e^{2 a+2 b x}}{1+c-d}\right )+\frac {\text {PolyLog}\left (2,-\frac {(1-c-d) e^{2 a+2 b x}}{1-c+d}\right )}{4 b}-\frac {\text {PolyLog}\left (2,-\frac {(1+c+d) e^{2 a+2 b x}}{1+c-d}\right )}{4 b} \]
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Rubi [A]
time = 0.16, antiderivative size = 150, normalized size of antiderivative = 1.00, number of steps
used = 7, number of rules used = 4, integrand size = 11, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.364, Rules used = {6370, 2221,
2317, 2438} \begin {gather*} \frac {\text {Li}_2\left (-\frac {(-c-d+1) e^{2 a+2 b x}}{-c+d+1}\right )}{4 b}-\frac {\text {Li}_2\left (-\frac {(c+d+1) e^{2 a+2 b x}}{c-d+1}\right )}{4 b}+\frac {1}{2} x \log \left (\frac {(-c-d+1) e^{2 a+2 b x}}{-c+d+1}+1\right )-\frac {1}{2} x \log \left (\frac {(c+d+1) e^{2 a+2 b x}}{c-d+1}+1\right )+x \tanh ^{-1}(d \tanh (a+b x)+c) \end {gather*}
Antiderivative was successfully verified.
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Rule 2221
Rule 2317
Rule 2438
Rule 6370
Rubi steps
\begin {align*} \int \tanh ^{-1}(c+d \tanh (a+b x)) \, dx &=x \tanh ^{-1}(c+d \tanh (a+b x))+(b (1-c-d)) \int \frac {e^{2 a+2 b x} x}{1-c+d+(1-c-d) e^{2 a+2 b x}} \, dx-(b (1+c+d)) \int \frac {e^{2 a+2 b x} x}{1+c-d+(1+c+d) e^{2 a+2 b x}} \, dx\\ &=x \tanh ^{-1}(c+d \tanh (a+b x))+\frac {1}{2} x \log \left (1+\frac {(1-c-d) e^{2 a+2 b x}}{1-c+d}\right )-\frac {1}{2} x \log \left (1+\frac {(1+c+d) e^{2 a+2 b x}}{1+c-d}\right )-\frac {1}{2} \int \log \left (1+\frac {(1-c-d) e^{2 a+2 b x}}{1-c+d}\right ) \, dx+\frac {1}{2} \int \log \left (1+\frac {(1+c+d) e^{2 a+2 b x}}{1+c-d}\right ) \, dx\\ &=x \tanh ^{-1}(c+d \tanh (a+b x))+\frac {1}{2} x \log \left (1+\frac {(1-c-d) e^{2 a+2 b x}}{1-c+d}\right )-\frac {1}{2} x \log \left (1+\frac {(1+c+d) e^{2 a+2 b x}}{1+c-d}\right )-\frac {\text {Subst}\left (\int \frac {\log \left (1+\frac {(1-c-d) x}{1-c+d}\right )}{x} \, dx,x,e^{2 a+2 b x}\right )}{4 b}+\frac {\text {Subst}\left (\int \frac {\log \left (1+\frac {(1+c+d) x}{1+c-d}\right )}{x} \, dx,x,e^{2 a+2 b x}\right )}{4 b}\\ &=x \tanh ^{-1}(c+d \tanh (a+b x))+\frac {1}{2} x \log \left (1+\frac {(1-c-d) e^{2 a+2 b x}}{1-c+d}\right )-\frac {1}{2} x \log \left (1+\frac {(1+c+d) e^{2 a+2 b x}}{1+c-d}\right )+\frac {\text {Li}_2\left (-\frac {(1-c-d) e^{2 a+2 b x}}{1-c+d}\right )}{4 b}-\frac {\text {Li}_2\left (-\frac {(1+c+d) e^{2 a+2 b x}}{1+c-d}\right )}{4 b}\\ \end {align*}
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Mathematica [B] Leaf count is larger than twice the leaf count of optimal. \(366\) vs. \(2(150)=300\).
time = 4.84, size = 366, normalized size = 2.44 \begin {gather*} x \tanh ^{-1}(c+d \tanh (a+b x))+\frac {(a+b x) \log \left (1-\frac {\sqrt {-1+c+d} e^{a+b x}}{\sqrt {1-c+d}}\right )+(a+b x) \log \left (1+\frac {\sqrt {-1+c+d} e^{a+b x}}{\sqrt {1-c+d}}\right )-(a+b x) \log \left (1-\frac {\sqrt {1+c+d} e^{a+b x}}{\sqrt {-1-c+d}}\right )-(a+b x) \log \left (1+\frac {\sqrt {1+c+d} e^{a+b x}}{\sqrt {-1-c+d}}\right )+a \log \left (1+c-d+e^{2 (a+b x)}+c e^{2 (a+b x)}+d e^{2 (a+b x)}\right )-a \log \left (1+d+e^{2 (a+b x)}-d e^{2 (a+b x)}-c \left (1+e^{2 (a+b x)}\right )\right )+\text {PolyLog}\left (2,-\frac {\sqrt {-1+c+d} e^{a+b x}}{\sqrt {1-c+d}}\right )+\text {PolyLog}\left (2,\frac {\sqrt {-1+c+d} e^{a+b x}}{\sqrt {1-c+d}}\right )-\text {PolyLog}\left (2,-\frac {\sqrt {1+c+d} e^{a+b x}}{\sqrt {-1-c+d}}\right )-\text {PolyLog}\left (2,\frac {\sqrt {1+c+d} e^{a+b x}}{\sqrt {-1-c+d}}\right )}{2 b} \end {gather*}
Antiderivative was successfully verified.
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Maple [B] Leaf count of result is larger than twice the leaf count of optimal. \(360\) vs.
\(2(138)=276\).
time = 0.91, size = 361, normalized size = 2.41
method | result | size |
derivativedivides | \(\frac {-\frac {\arctanh \left (c +d \tanh \left (b x +a \right )\right ) d \ln \left (-d \tanh \left (b x +a \right )+d \right )}{2}+\frac {\arctanh \left (c +d \tanh \left (b x +a \right )\right ) d \ln \left (-d \tanh \left (b x +a \right )-d \right )}{2}+\frac {d^{2} \left (\frac {\dilog \left (\frac {-d \tanh \left (b x +a \right )-c +1}{1-c +d}\right )}{2 d}+\frac {\ln \left (-d \tanh \left (b x +a \right )-d \right ) \ln \left (\frac {-d \tanh \left (b x +a \right )-c +1}{1-c +d}\right )}{2 d}-\frac {\dilog \left (\frac {-d \tanh \left (b x +a \right )-c -1}{-1-c +d}\right )}{2 d}-\frac {\ln \left (-d \tanh \left (b x +a \right )-d \right ) \ln \left (\frac {-d \tanh \left (b x +a \right )-c -1}{-1-c +d}\right )}{2 d}+\frac {\dilog \left (\frac {-d \tanh \left (b x +a \right )-c -1}{-1-c -d}\right )}{2 d}+\frac {\ln \left (-d \tanh \left (b x +a \right )+d \right ) \ln \left (\frac {-d \tanh \left (b x +a \right )-c -1}{-1-c -d}\right )}{2 d}-\frac {\dilog \left (\frac {-d \tanh \left (b x +a \right )-c +1}{1-c -d}\right )}{2 d}-\frac {\ln \left (-d \tanh \left (b x +a \right )+d \right ) \ln \left (\frac {-d \tanh \left (b x +a \right )-c +1}{1-c -d}\right )}{2 d}\right )}{2}}{b d}\) | \(361\) |
default | \(\frac {-\frac {\arctanh \left (c +d \tanh \left (b x +a \right )\right ) d \ln \left (-d \tanh \left (b x +a \right )+d \right )}{2}+\frac {\arctanh \left (c +d \tanh \left (b x +a \right )\right ) d \ln \left (-d \tanh \left (b x +a \right )-d \right )}{2}+\frac {d^{2} \left (\frac {\dilog \left (\frac {-d \tanh \left (b x +a \right )-c +1}{1-c +d}\right )}{2 d}+\frac {\ln \left (-d \tanh \left (b x +a \right )-d \right ) \ln \left (\frac {-d \tanh \left (b x +a \right )-c +1}{1-c +d}\right )}{2 d}-\frac {\dilog \left (\frac {-d \tanh \left (b x +a \right )-c -1}{-1-c +d}\right )}{2 d}-\frac {\ln \left (-d \tanh \left (b x +a \right )-d \right ) \ln \left (\frac {-d \tanh \left (b x +a \right )-c -1}{-1-c +d}\right )}{2 d}+\frac {\dilog \left (\frac {-d \tanh \left (b x +a \right )-c -1}{-1-c -d}\right )}{2 d}+\frac {\ln \left (-d \tanh \left (b x +a \right )+d \right ) \ln \left (\frac {-d \tanh \left (b x +a \right )-c -1}{-1-c -d}\right )}{2 d}-\frac {\dilog \left (\frac {-d \tanh \left (b x +a \right )-c +1}{1-c -d}\right )}{2 d}-\frac {\ln \left (-d \tanh \left (b x +a \right )+d \right ) \ln \left (\frac {-d \tanh \left (b x +a \right )-c +1}{1-c -d}\right )}{2 d}\right )}{2}}{b d}\) | \(361\) |
risch | \(\text {Expression too large to display}\) | \(3079\) |
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A]
time = 0.48, size = 142, normalized size = 0.95 \begin {gather*} -\frac {1}{4} \, b d {\left (\frac {2 \, b x \log \left (\frac {{\left (c + d + 1\right )} e^{\left (2 \, b x + 2 \, a\right )}}{c - d + 1} + 1\right ) + {\rm Li}_2\left (-\frac {{\left (c + d + 1\right )} e^{\left (2 \, b x + 2 \, a\right )}}{c - d + 1}\right )}{b^{2} d} - \frac {2 \, b x \log \left (\frac {{\left (c + d - 1\right )} e^{\left (2 \, b x + 2 \, a\right )}}{c - d - 1} + 1\right ) + {\rm Li}_2\left (-\frac {{\left (c + d - 1\right )} e^{\left (2 \, b x + 2 \, a\right )}}{c - d - 1}\right )}{b^{2} d}\right )} + x \operatorname {artanh}\left (d \tanh \left (b x + a\right ) + c\right ) \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [B] Leaf count of result is larger than twice the leaf count of optimal. 552 vs.
\(2 (128) = 256\).
time = 0.40, size = 552, normalized size = 3.68 \begin {gather*} \frac {b x \log \left (-\frac {{\left (c + 1\right )} \cosh \left (b x + a\right ) + d \sinh \left (b x + a\right )}{{\left (c - 1\right )} \cosh \left (b x + a\right ) + d \sinh \left (b x + a\right )}\right ) + a \log \left (2 \, {\left (c + d + 1\right )} \cosh \left (b x + a\right ) + 2 \, {\left (c + d + 1\right )} \sinh \left (b x + a\right ) + 2 \, {\left (c - d + 1\right )} \sqrt {-\frac {c + d + 1}{c - d + 1}}\right ) + a \log \left (2 \, {\left (c + d + 1\right )} \cosh \left (b x + a\right ) + 2 \, {\left (c + d + 1\right )} \sinh \left (b x + a\right ) - 2 \, {\left (c - d + 1\right )} \sqrt {-\frac {c + d + 1}{c - d + 1}}\right ) - a \log \left (2 \, {\left (c + d - 1\right )} \cosh \left (b x + a\right ) + 2 \, {\left (c + d - 1\right )} \sinh \left (b x + a\right ) + 2 \, {\left (c - d - 1\right )} \sqrt {-\frac {c + d - 1}{c - d - 1}}\right ) - a \log \left (2 \, {\left (c + d - 1\right )} \cosh \left (b x + a\right ) + 2 \, {\left (c + d - 1\right )} \sinh \left (b x + a\right ) - 2 \, {\left (c - d - 1\right )} \sqrt {-\frac {c + d - 1}{c - d - 1}}\right ) - {\left (b x + a\right )} \log \left (\sqrt {-\frac {c + d + 1}{c - d + 1}} {\left (\cosh \left (b x + a\right ) + \sinh \left (b x + a\right )\right )} + 1\right ) - {\left (b x + a\right )} \log \left (-\sqrt {-\frac {c + d + 1}{c - d + 1}} {\left (\cosh \left (b x + a\right ) + \sinh \left (b x + a\right )\right )} + 1\right ) + {\left (b x + a\right )} \log \left (\sqrt {-\frac {c + d - 1}{c - d - 1}} {\left (\cosh \left (b x + a\right ) + \sinh \left (b x + a\right )\right )} + 1\right ) + {\left (b x + a\right )} \log \left (-\sqrt {-\frac {c + d - 1}{c - d - 1}} {\left (\cosh \left (b x + a\right ) + \sinh \left (b x + a\right )\right )} + 1\right ) - {\rm Li}_2\left (\sqrt {-\frac {c + d + 1}{c - d + 1}} {\left (\cosh \left (b x + a\right ) + \sinh \left (b x + a\right )\right )}\right ) - {\rm Li}_2\left (-\sqrt {-\frac {c + d + 1}{c - d + 1}} {\left (\cosh \left (b x + a\right ) + \sinh \left (b x + a\right )\right )}\right ) + {\rm Li}_2\left (\sqrt {-\frac {c + d - 1}{c - d - 1}} {\left (\cosh \left (b x + a\right ) + \sinh \left (b x + a\right )\right )}\right ) + {\rm Li}_2\left (-\sqrt {-\frac {c + d - 1}{c - d - 1}} {\left (\cosh \left (b x + a\right ) + \sinh \left (b x + a\right )\right )}\right )}{2 \, b} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \operatorname {atanh}{\left (c + d \tanh {\left (a + b x \right )} \right )}\, dx \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [F]
time = 0.00, size = -1, normalized size = -0.01 \begin {gather*} \int \mathrm {atanh}\left (c+d\,\mathrm {tanh}\left (a+b\,x\right )\right ) \,d x \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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