Optimal. Leaf size=16 \[ \frac {\tanh ^{-1}(\tanh (a+b x))^5}{5 b} \]
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Rubi [A]
time = 0.00, antiderivative size = 16, normalized size of antiderivative = 1.00, number of steps
used = 2, number of rules used = 2, integrand size = 9, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.222, Rules used = {2188, 30}
\begin {gather*} \frac {\tanh ^{-1}(\tanh (a+b x))^5}{5 b} \end {gather*}
Antiderivative was successfully verified.
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Rule 30
Rule 2188
Rubi steps
\begin {align*} \int \tanh ^{-1}(\tanh (a+b x))^4 \, dx &=\frac {\text {Subst}\left (\int x^4 \, dx,x,\tanh ^{-1}(\tanh (a+b x))\right )}{b}\\ &=\frac {\tanh ^{-1}(\tanh (a+b x))^5}{5 b}\\ \end {align*}
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Mathematica [A]
time = 0.01, size = 16, normalized size = 1.00 \begin {gather*} \frac {\tanh ^{-1}(\tanh (a+b x))^5}{5 b} \end {gather*}
Antiderivative was successfully verified.
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Maple [A]
time = 34.82, size = 15, normalized size = 0.94
method | result | size |
derivativedivides | \(\frac {\arctanh \left (\tanh \left (b x +a \right )\right )^{5}}{5 b}\) | \(15\) |
default | \(\frac {\arctanh \left (\tanh \left (b x +a \right )\right )^{5}}{5 b}\) | \(15\) |
risch | \(\text {Expression too large to display}\) | \(21473\) |
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [B] Leaf count of result is larger than twice the leaf count of optimal. 69 vs.
\(2 (14) = 28\).
time = 0.41, size = 69, normalized size = 4.31 \begin {gather*} -2 \, b x^{2} \operatorname {artanh}\left (\tanh \left (b x + a\right )\right )^{3} + x \operatorname {artanh}\left (\tanh \left (b x + a\right )\right )^{4} + \frac {1}{5} \, {\left (10 \, b x^{3} \operatorname {artanh}\left (\tanh \left (b x + a\right )\right )^{2} + {\left (b^{2} x^{5} - 5 \, b x^{4} \operatorname {artanh}\left (\tanh \left (b x + a\right )\right )\right )} b\right )} b \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [B] Leaf count of result is larger than twice the leaf count of optimal. 42 vs.
\(2 (14) = 28\).
time = 0.35, size = 42, normalized size = 2.62 \begin {gather*} \frac {1}{5} \, b^{4} x^{5} + a b^{3} x^{4} + 2 \, a^{2} b^{2} x^{3} + 2 \, a^{3} b x^{2} + a^{4} x \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [A]
time = 0.29, size = 20, normalized size = 1.25 \begin {gather*} \begin {cases} \frac {\operatorname {atanh}^{5}{\left (\tanh {\left (a + b x \right )} \right )}}{5 b} & \text {for}\: b \neq 0 \\x \operatorname {atanh}^{4}{\left (\tanh {\left (a \right )} \right )} & \text {otherwise} \end {cases} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [B] Leaf count of result is larger than twice the leaf count of optimal. 42 vs.
\(2 (14) = 28\).
time = 0.38, size = 42, normalized size = 2.62 \begin {gather*} \frac {1}{5} \, b^{4} x^{5} + a b^{3} x^{4} + 2 \, a^{2} b^{2} x^{3} + 2 \, a^{3} b x^{2} + a^{4} x \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [B]
time = 0.98, size = 67, normalized size = 4.19 \begin {gather*} \frac {b^4\,x^5}{5}-b^3\,x^4\,\mathrm {atanh}\left (\mathrm {tanh}\left (a+b\,x\right )\right )+2\,b^2\,x^3\,{\mathrm {atanh}\left (\mathrm {tanh}\left (a+b\,x\right )\right )}^2-2\,b\,x^2\,{\mathrm {atanh}\left (\mathrm {tanh}\left (a+b\,x\right )\right )}^3+x\,{\mathrm {atanh}\left (\mathrm {tanh}\left (a+b\,x\right )\right )}^4 \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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