Optimal. Leaf size=95 \[ 4 b^2 x \left (b x-\tanh ^{-1}(\tanh (a+b x))\right )^2-2 b \left (b x-\tanh ^{-1}(\tanh (a+b x))\right ) \tanh ^{-1}(\tanh (a+b x))^2+\frac {4}{3} b \tanh ^{-1}(\tanh (a+b x))^3-\frac {\tanh ^{-1}(\tanh (a+b x))^4}{x}-4 b \left (b x-\tanh ^{-1}(\tanh (a+b x))\right )^3 \log (x) \]
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Rubi [A]
time = 0.05, antiderivative size = 95, normalized size of antiderivative = 1.00, number of steps
used = 5, number of rules used = 4, integrand size = 13, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.308, Rules used = {2199, 2190,
2189, 29} \begin {gather*} 4 b^2 x \left (b x-\tanh ^{-1}(\tanh (a+b x))\right )^2-\frac {\tanh ^{-1}(\tanh (a+b x))^4}{x}+\frac {4}{3} b \tanh ^{-1}(\tanh (a+b x))^3-2 b \left (b x-\tanh ^{-1}(\tanh (a+b x))\right ) \tanh ^{-1}(\tanh (a+b x))^2-4 b \log (x) \left (b x-\tanh ^{-1}(\tanh (a+b x))\right )^3 \end {gather*}
Antiderivative was successfully verified.
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Rule 29
Rule 2189
Rule 2190
Rule 2199
Rubi steps
\begin {align*} \int \frac {\tanh ^{-1}(\tanh (a+b x))^4}{x^2} \, dx &=-\frac {\tanh ^{-1}(\tanh (a+b x))^4}{x}+(4 b) \int \frac {\tanh ^{-1}(\tanh (a+b x))^3}{x} \, dx\\ &=\frac {4}{3} b \tanh ^{-1}(\tanh (a+b x))^3-\frac {\tanh ^{-1}(\tanh (a+b x))^4}{x}-\left (4 b \left (b x-\tanh ^{-1}(\tanh (a+b x))\right )\right ) \int \frac {\tanh ^{-1}(\tanh (a+b x))^2}{x} \, dx\\ &=-2 b \left (b x-\tanh ^{-1}(\tanh (a+b x))\right ) \tanh ^{-1}(\tanh (a+b x))^2+\frac {4}{3} b \tanh ^{-1}(\tanh (a+b x))^3-\frac {\tanh ^{-1}(\tanh (a+b x))^4}{x}+\left (4 b \left (b x-\tanh ^{-1}(\tanh (a+b x))\right )^2\right ) \int \frac {\tanh ^{-1}(\tanh (a+b x))}{x} \, dx\\ &=4 b^2 x \left (b x-\tanh ^{-1}(\tanh (a+b x))\right )^2-2 b \left (b x-\tanh ^{-1}(\tanh (a+b x))\right ) \tanh ^{-1}(\tanh (a+b x))^2+\frac {4}{3} b \tanh ^{-1}(\tanh (a+b x))^3-\frac {\tanh ^{-1}(\tanh (a+b x))^4}{x}-\left (4 b \left (b x-\tanh ^{-1}(\tanh (a+b x))\right )^3\right ) \int \frac {1}{x} \, dx\\ &=4 b^2 x \left (b x-\tanh ^{-1}(\tanh (a+b x))\right )^2-2 b \left (b x-\tanh ^{-1}(\tanh (a+b x))\right ) \tanh ^{-1}(\tanh (a+b x))^2+\frac {4}{3} b \tanh ^{-1}(\tanh (a+b x))^3-\frac {\tanh ^{-1}(\tanh (a+b x))^4}{x}-4 b \left (b x-\tanh ^{-1}(\tanh (a+b x))\right )^3 \log (x)\\ \end {align*}
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Mathematica [A]
time = 0.06, size = 85, normalized size = 0.89 \begin {gather*} -\frac {\tanh ^{-1}(\tanh (a+b x))^4}{x}+\frac {2}{3} b^4 x^3 (5-6 \log (x))-12 b^2 x \tanh ^{-1}(\tanh (a+b x))^2 \log (x)+4 b \tanh ^{-1}(\tanh (a+b x))^3 (1+\log (x))+6 b^3 x^2 \tanh ^{-1}(\tanh (a+b x)) (-1+2 \log (x)) \end {gather*}
Antiderivative was successfully verified.
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Maple [B] Leaf count of result is larger than twice the leaf count of optimal. \(205\) vs.
\(2(93)=186\).
time = 0.70, size = 206, normalized size = 2.17
method | result | size |
default | \(-\frac {\arctanh \left (\tanh \left (b x +a \right )\right )^{4}}{x}+4 b \left (\ln \left (x \right ) \arctanh \left (\tanh \left (b x +a \right )\right )^{3}-3 b \left (\frac {b^{2} x^{3} \ln \left (x \right )}{3}-\frac {b^{2} x^{3}}{9}+a b \,x^{2} \ln \left (x \right )-\frac {a b \,x^{2}}{2}+b \left (\arctanh \left (\tanh \left (b x +a \right )\right )-b x -a \right ) x^{2} \ln \left (x \right )-\frac {b \left (\arctanh \left (\tanh \left (b x +a \right )\right )-b x -a \right ) x^{2}}{2}+\ln \left (x \right ) x \,a^{2}-x \,a^{2}+2 \ln \left (x \right ) x a \left (\arctanh \left (\tanh \left (b x +a \right )\right )-b x -a \right )-2 x a \left (\arctanh \left (\tanh \left (b x +a \right )\right )-b x -a \right )+\ln \left (x \right ) x \left (\arctanh \left (\tanh \left (b x +a \right )\right )-b x -a \right )^{2}-x \left (\arctanh \left (\tanh \left (b x +a \right )\right )-b x -a \right )^{2}\right )\right )\) | \(206\) |
risch | \(\text {Expression too large to display}\) | \(17762\) |
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A]
time = 0.70, size = 77, normalized size = 0.81 \begin {gather*} 4 \, b \operatorname {artanh}\left (\tanh \left (b x + a\right )\right )^{3} \log \left (x\right ) - \frac {\operatorname {artanh}\left (\tanh \left (b x + a\right )\right )^{4}}{x} + \frac {2}{3} \, {\left (2 \, b^{3} x^{3} + 9 \, a b^{2} x^{2} + 18 \, a^{2} b x + 6 \, a^{3} \log \left (x\right ) - 6 \, \operatorname {artanh}\left (\tanh \left (b x + a\right )\right )^{3} \log \left (x\right )\right )} b \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A]
time = 0.33, size = 47, normalized size = 0.49 \begin {gather*} \frac {b^{4} x^{4} + 6 \, a b^{3} x^{3} + 18 \, a^{2} b^{2} x^{2} + 12 \, a^{3} b x \log \left (x\right ) - 3 \, a^{4}}{3 \, x} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {\operatorname {atanh}^{4}{\left (\tanh {\left (a + b x \right )} \right )}}{x^{2}}\, dx \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A]
time = 0.38, size = 44, normalized size = 0.46 \begin {gather*} \frac {1}{3} \, b^{4} x^{3} + 2 \, a b^{3} x^{2} + 6 \, a^{2} b^{2} x + 4 \, a^{3} b \log \left ({\left | x \right |}\right ) - \frac {a^{4}}{x} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [B]
time = 0.14, size = 553, normalized size = 5.82 \begin {gather*} \ln \left (x\right )\,\left (4\,a^3\,b-\frac {b\,{\left (2\,a-\ln \left (\frac {2\,{\mathrm {e}}^{2\,a}\,{\mathrm {e}}^{2\,b\,x}}{{\mathrm {e}}^{2\,a}\,{\mathrm {e}}^{2\,b\,x}+1}\right )+\ln \left (\frac {2}{{\mathrm {e}}^{2\,a}\,{\mathrm {e}}^{2\,b\,x}+1}\right )+2\,b\,x\right )}^3}{2}+3\,a\,b\,{\left (2\,a-\ln \left (\frac {2\,{\mathrm {e}}^{2\,a}\,{\mathrm {e}}^{2\,b\,x}}{{\mathrm {e}}^{2\,a}\,{\mathrm {e}}^{2\,b\,x}+1}\right )+\ln \left (\frac {2}{{\mathrm {e}}^{2\,a}\,{\mathrm {e}}^{2\,b\,x}+1}\right )+2\,b\,x\right )}^2-6\,a^2\,b\,\left (2\,a-\ln \left (\frac {2\,{\mathrm {e}}^{2\,a}\,{\mathrm {e}}^{2\,b\,x}}{{\mathrm {e}}^{2\,a}\,{\mathrm {e}}^{2\,b\,x}+1}\right )+\ln \left (\frac {2}{{\mathrm {e}}^{2\,a}\,{\mathrm {e}}^{2\,b\,x}+1}\right )+2\,b\,x\right )\right )-\frac {{\left (2\,a-\ln \left (\frac {2\,{\mathrm {e}}^{2\,a}\,{\mathrm {e}}^{2\,b\,x}}{{\mathrm {e}}^{2\,a}\,{\mathrm {e}}^{2\,b\,x}+1}\right )+\ln \left (\frac {2}{{\mathrm {e}}^{2\,a}\,{\mathrm {e}}^{2\,b\,x}+1}\right )+2\,b\,x\right )}^4+24\,a^2\,{\left (2\,a-\ln \left (\frac {2\,{\mathrm {e}}^{2\,a}\,{\mathrm {e}}^{2\,b\,x}}{{\mathrm {e}}^{2\,a}\,{\mathrm {e}}^{2\,b\,x}+1}\right )+\ln \left (\frac {2}{{\mathrm {e}}^{2\,a}\,{\mathrm {e}}^{2\,b\,x}+1}\right )+2\,b\,x\right )}^2+16\,a^4-8\,a\,{\left (2\,a-\ln \left (\frac {2\,{\mathrm {e}}^{2\,a}\,{\mathrm {e}}^{2\,b\,x}}{{\mathrm {e}}^{2\,a}\,{\mathrm {e}}^{2\,b\,x}+1}\right )+\ln \left (\frac {2}{{\mathrm {e}}^{2\,a}\,{\mathrm {e}}^{2\,b\,x}+1}\right )+2\,b\,x\right )}^3-32\,a^3\,\left (2\,a-\ln \left (\frac {2\,{\mathrm {e}}^{2\,a}\,{\mathrm {e}}^{2\,b\,x}}{{\mathrm {e}}^{2\,a}\,{\mathrm {e}}^{2\,b\,x}+1}\right )+\ln \left (\frac {2}{{\mathrm {e}}^{2\,a}\,{\mathrm {e}}^{2\,b\,x}+1}\right )+2\,b\,x\right )}{16\,x}+\frac {b^4\,x^3}{3}+\frac {3\,b^2\,x\,{\left (\ln \left (\frac {2}{{\mathrm {e}}^{2\,a}\,{\mathrm {e}}^{2\,b\,x}+1}\right )-\ln \left (\frac {2\,{\mathrm {e}}^{2\,a}\,{\mathrm {e}}^{2\,b\,x}}{{\mathrm {e}}^{2\,a}\,{\mathrm {e}}^{2\,b\,x}+1}\right )+2\,b\,x\right )}^2}{2}-b^3\,x^2\,\left (\ln \left (\frac {2}{{\mathrm {e}}^{2\,a}\,{\mathrm {e}}^{2\,b\,x}+1}\right )-\ln \left (\frac {2\,{\mathrm {e}}^{2\,a}\,{\mathrm {e}}^{2\,b\,x}}{{\mathrm {e}}^{2\,a}\,{\mathrm {e}}^{2\,b\,x}+1}\right )+2\,b\,x\right ) \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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