Integrand size = 18, antiderivative size = 326 \[ \int (e+f x) \left (a+b \coth ^{-1}(c+d x)\right )^3 \, dx=\frac {3 b f \left (a+b \coth ^{-1}(c+d x)\right )^2}{2 d^2}+\frac {3 b f (c+d x) \left (a+b \coth ^{-1}(c+d x)\right )^2}{2 d^2}+\frac {(d e-c f) \left (a+b \coth ^{-1}(c+d x)\right )^3}{d^2}-\frac {\left (d^2 e^2-2 c d e f+\left (1+c^2\right ) f^2\right ) \left (a+b \coth ^{-1}(c+d x)\right )^3}{2 d^2 f}+\frac {(e+f x)^2 \left (a+b \coth ^{-1}(c+d x)\right )^3}{2 f}-\frac {3 b^2 f \left (a+b \coth ^{-1}(c+d x)\right ) \log \left (\frac {2}{1-c-d x}\right )}{d^2}-\frac {3 b (d e-c f) \left (a+b \coth ^{-1}(c+d x)\right )^2 \log \left (\frac {2}{1-c-d x}\right )}{d^2}-\frac {3 b^3 f \operatorname {PolyLog}\left (2,-\frac {1+c+d x}{1-c-d x}\right )}{2 d^2}-\frac {3 b^2 (d e-c f) \left (a+b \coth ^{-1}(c+d x)\right ) \operatorname {PolyLog}\left (2,1-\frac {2}{1-c-d x}\right )}{d^2}+\frac {3 b^3 (d e-c f) \operatorname {PolyLog}\left (3,1-\frac {2}{1-c-d x}\right )}{2 d^2} \]
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Time = 0.55 (sec) , antiderivative size = 325, normalized size of antiderivative = 1.00, number of steps used = 15, number of rules used = 11, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.611, Rules used = {6247, 6066, 6022, 6132, 6056, 2449, 2352, 6196, 6096, 6206, 6745} \[ \int (e+f x) \left (a+b \coth ^{-1}(c+d x)\right )^3 \, dx=-\frac {3 b^2 (d e-c f) \operatorname {PolyLog}\left (2,1-\frac {2}{-c-d x+1}\right ) \left (a+b \coth ^{-1}(c+d x)\right )}{d^2}-\frac {3 b^2 f \log \left (\frac {2}{-c-d x+1}\right ) \left (a+b \coth ^{-1}(c+d x)\right )}{d^2}+\frac {\left (-\frac {\left (c^2+1\right ) f}{d}+2 c e-\frac {d e^2}{f}\right ) \left (a+b \coth ^{-1}(c+d x)\right )^3}{2 d}+\frac {(d e-c f) \left (a+b \coth ^{-1}(c+d x)\right )^3}{d^2}-\frac {3 b (d e-c f) \log \left (\frac {2}{-c-d x+1}\right ) \left (a+b \coth ^{-1}(c+d x)\right )^2}{d^2}+\frac {3 b f \left (a+b \coth ^{-1}(c+d x)\right )^2}{2 d^2}+\frac {3 b f (c+d x) \left (a+b \coth ^{-1}(c+d x)\right )^2}{2 d^2}+\frac {(e+f x)^2 \left (a+b \coth ^{-1}(c+d x)\right )^3}{2 f}+\frac {3 b^3 (d e-c f) \operatorname {PolyLog}\left (3,1-\frac {2}{-c-d x+1}\right )}{2 d^2}-\frac {3 b^3 f \operatorname {PolyLog}\left (2,-\frac {c+d x+1}{-c-d x+1}\right )}{2 d^2} \]
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Rule 2352
Rule 2449
Rule 6022
Rule 6056
Rule 6066
Rule 6096
Rule 6132
Rule 6196
Rule 6206
Rule 6247
Rule 6745
Rubi steps \begin{align*} \text {integral}& = \frac {\text {Subst}\left (\int \left (\frac {d e-c f}{d}+\frac {f x}{d}\right ) \left (a+b \coth ^{-1}(x)\right )^3 \, dx,x,c+d x\right )}{d} \\ & = \frac {(e+f x)^2 \left (a+b \coth ^{-1}(c+d x)\right )^3}{2 f}-\frac {(3 b) \text {Subst}\left (\int \left (-\frac {f^2 \left (a+b \coth ^{-1}(x)\right )^2}{d^2}+\frac {\left (d^2 e^2-2 c d e f+\left (1+c^2\right ) f^2+2 f (d e-c f) x\right ) \left (a+b \coth ^{-1}(x)\right )^2}{d^2 \left (1-x^2\right )}\right ) \, dx,x,c+d x\right )}{2 f} \\ & = \frac {(e+f x)^2 \left (a+b \coth ^{-1}(c+d x)\right )^3}{2 f}-\frac {(3 b) \text {Subst}\left (\int \frac {\left (d^2 e^2-2 c d e f+\left (1+c^2\right ) f^2+2 f (d e-c f) x\right ) \left (a+b \coth ^{-1}(x)\right )^2}{1-x^2} \, dx,x,c+d x\right )}{2 d^2 f}+\frac {(3 b f) \text {Subst}\left (\int \left (a+b \coth ^{-1}(x)\right )^2 \, dx,x,c+d x\right )}{2 d^2} \\ & = \frac {3 b f (c+d x) \left (a+b \coth ^{-1}(c+d x)\right )^2}{2 d^2}+\frac {(e+f x)^2 \left (a+b \coth ^{-1}(c+d x)\right )^3}{2 f}-\frac {(3 b) \text {Subst}\left (\int \left (\frac {d^2 e^2 \left (1+\frac {f \left (-2 c d e+f+c^2 f\right )}{d^2 e^2}\right ) \left (a+b \coth ^{-1}(x)\right )^2}{1-x^2}-\frac {2 f (-d e+c f) x \left (a+b \coth ^{-1}(x)\right )^2}{1-x^2}\right ) \, dx,x,c+d x\right )}{2 d^2 f}-\frac {\left (3 b^2 f\right ) \text {Subst}\left (\int \frac {x \left (a+b \coth ^{-1}(x)\right )}{1-x^2} \, dx,x,c+d x\right )}{d^2} \\ & = \frac {3 b f \left (a+b \coth ^{-1}(c+d x)\right )^2}{2 d^2}+\frac {3 b f (c+d x) \left (a+b \coth ^{-1}(c+d x)\right )^2}{2 d^2}+\frac {(e+f x)^2 \left (a+b \coth ^{-1}(c+d x)\right )^3}{2 f}-\frac {\left (3 b^2 f\right ) \text {Subst}\left (\int \frac {a+b \coth ^{-1}(x)}{1-x} \, dx,x,c+d x\right )}{d^2}-\frac {(3 b (d e-c f)) \text {Subst}\left (\int \frac {x \left (a+b \coth ^{-1}(x)\right )^2}{1-x^2} \, dx,x,c+d x\right )}{d^2}-\frac {\left (3 b \left (d^2 e^2-2 c d e f+\left (1+c^2\right ) f^2\right )\right ) \text {Subst}\left (\int \frac {\left (a+b \coth ^{-1}(x)\right )^2}{1-x^2} \, dx,x,c+d x\right )}{2 d^2 f} \\ & = \frac {3 b f \left (a+b \coth ^{-1}(c+d x)\right )^2}{2 d^2}+\frac {3 b f (c+d x) \left (a+b \coth ^{-1}(c+d x)\right )^2}{2 d^2}+\frac {(d e-c f) \left (a+b \coth ^{-1}(c+d x)\right )^3}{d^2}-\frac {\left (d^2 e^2-2 c d e f+\left (1+c^2\right ) f^2\right ) \left (a+b \coth ^{-1}(c+d x)\right )^3}{2 d^2 f}+\frac {(e+f x)^2 \left (a+b \coth ^{-1}(c+d x)\right )^3}{2 f}-\frac {3 b^2 f \left (a+b \coth ^{-1}(c+d x)\right ) \log \left (\frac {2}{1-c-d x}\right )}{d^2}+\frac {\left (3 b^3 f\right ) \text {Subst}\left (\int \frac {\log \left (\frac {2}{1-x}\right )}{1-x^2} \, dx,x,c+d x\right )}{d^2}-\frac {(3 b (d e-c f)) \text {Subst}\left (\int \frac {\left (a+b \coth ^{-1}(x)\right )^2}{1-x} \, dx,x,c+d x\right )}{d^2} \\ & = \frac {3 b f \left (a+b \coth ^{-1}(c+d x)\right )^2}{2 d^2}+\frac {3 b f (c+d x) \left (a+b \coth ^{-1}(c+d x)\right )^2}{2 d^2}+\frac {(d e-c f) \left (a+b \coth ^{-1}(c+d x)\right )^3}{d^2}-\frac {\left (d^2 e^2-2 c d e f+\left (1+c^2\right ) f^2\right ) \left (a+b \coth ^{-1}(c+d x)\right )^3}{2 d^2 f}+\frac {(e+f x)^2 \left (a+b \coth ^{-1}(c+d x)\right )^3}{2 f}-\frac {3 b^2 f \left (a+b \coth ^{-1}(c+d x)\right ) \log \left (\frac {2}{1-c-d x}\right )}{d^2}-\frac {3 b (d e-c f) \left (a+b \coth ^{-1}(c+d x)\right )^2 \log \left (\frac {2}{1-c-d x}\right )}{d^2}-\frac {\left (3 b^3 f\right ) \text {Subst}\left (\int \frac {\log (2 x)}{1-2 x} \, dx,x,\frac {1}{1-c-d x}\right )}{d^2}+\frac {\left (6 b^2 (d e-c f)\right ) \text {Subst}\left (\int \frac {\left (a+b \coth ^{-1}(x)\right ) \log \left (\frac {2}{1-x}\right )}{1-x^2} \, dx,x,c+d x\right )}{d^2} \\ & = \frac {3 b f \left (a+b \coth ^{-1}(c+d x)\right )^2}{2 d^2}+\frac {3 b f (c+d x) \left (a+b \coth ^{-1}(c+d x)\right )^2}{2 d^2}+\frac {(d e-c f) \left (a+b \coth ^{-1}(c+d x)\right )^3}{d^2}-\frac {\left (d^2 e^2-2 c d e f+\left (1+c^2\right ) f^2\right ) \left (a+b \coth ^{-1}(c+d x)\right )^3}{2 d^2 f}+\frac {(e+f x)^2 \left (a+b \coth ^{-1}(c+d x)\right )^3}{2 f}-\frac {3 b^2 f \left (a+b \coth ^{-1}(c+d x)\right ) \log \left (\frac {2}{1-c-d x}\right )}{d^2}-\frac {3 b (d e-c f) \left (a+b \coth ^{-1}(c+d x)\right )^2 \log \left (\frac {2}{1-c-d x}\right )}{d^2}-\frac {3 b^3 f \operatorname {PolyLog}\left (2,1-\frac {2}{1-c-d x}\right )}{2 d^2}-\frac {3 b^2 (d e-c f) \left (a+b \coth ^{-1}(c+d x)\right ) \operatorname {PolyLog}\left (2,1-\frac {2}{1-c-d x}\right )}{d^2}+\frac {\left (3 b^3 (d e-c f)\right ) \text {Subst}\left (\int \frac {\operatorname {PolyLog}\left (2,1-\frac {2}{1-x}\right )}{1-x^2} \, dx,x,c+d x\right )}{d^2} \\ & = \frac {3 b f \left (a+b \coth ^{-1}(c+d x)\right )^2}{2 d^2}+\frac {3 b f (c+d x) \left (a+b \coth ^{-1}(c+d x)\right )^2}{2 d^2}+\frac {(d e-c f) \left (a+b \coth ^{-1}(c+d x)\right )^3}{d^2}-\frac {\left (d^2 e^2-2 c d e f+\left (1+c^2\right ) f^2\right ) \left (a+b \coth ^{-1}(c+d x)\right )^3}{2 d^2 f}+\frac {(e+f x)^2 \left (a+b \coth ^{-1}(c+d x)\right )^3}{2 f}-\frac {3 b^2 f \left (a+b \coth ^{-1}(c+d x)\right ) \log \left (\frac {2}{1-c-d x}\right )}{d^2}-\frac {3 b (d e-c f) \left (a+b \coth ^{-1}(c+d x)\right )^2 \log \left (\frac {2}{1-c-d x}\right )}{d^2}-\frac {3 b^3 f \operatorname {PolyLog}\left (2,1-\frac {2}{1-c-d x}\right )}{2 d^2}-\frac {3 b^2 (d e-c f) \left (a+b \coth ^{-1}(c+d x)\right ) \operatorname {PolyLog}\left (2,1-\frac {2}{1-c-d x}\right )}{d^2}+\frac {3 b^3 (d e-c f) \operatorname {PolyLog}\left (3,1-\frac {2}{1-c-d x}\right )}{2 d^2} \\ \end{align*}
Result contains complex when optimal does not.
Time = 3.69 (sec) , antiderivative size = 600, normalized size of antiderivative = 1.84 \[ \int (e+f x) \left (a+b \coth ^{-1}(c+d x)\right )^3 \, dx=\frac {2 a^2 (2 a d e+3 b f-2 a c f) (c+d x)+2 a^3 f (c+d x)^2-6 a^2 b (c+d x) (c f-d (2 e+f x)) \coth ^{-1}(c+d x)+3 a^2 b (2 d e+f-2 c f) \log (1-c-d x)+3 a^2 b (2 d e-(1+2 c) f) \log (1+c+d x)+12 a b^2 f \left ((c+d x) \coth ^{-1}(c+d x)+\frac {1}{2} \left (-1+(c+d x)^2\right ) \coth ^{-1}(c+d x)^2-\log \left (\frac {1}{(c+d x) \sqrt {1-\frac {1}{(c+d x)^2}}}\right )\right )+12 a b^2 d e \left (\coth ^{-1}(c+d x) \left ((-1+c+d x) \coth ^{-1}(c+d x)-2 \log \left (1-e^{-2 \coth ^{-1}(c+d x)}\right )\right )+\operatorname {PolyLog}\left (2,e^{-2 \coth ^{-1}(c+d x)}\right )\right )-12 a b^2 c f \left (\coth ^{-1}(c+d x) \left ((-1+c+d x) \coth ^{-1}(c+d x)-2 \log \left (1-e^{-2 \coth ^{-1}(c+d x)}\right )\right )+\operatorname {PolyLog}\left (2,e^{-2 \coth ^{-1}(c+d x)}\right )\right )+2 b^3 f \left (\coth ^{-1}(c+d x) \left (3 (-1+c+d x) \coth ^{-1}(c+d x)+\left (-1+c^2+2 c d x+d^2 x^2\right ) \coth ^{-1}(c+d x)^2-6 \log \left (1-e^{-2 \coth ^{-1}(c+d x)}\right )\right )+3 \operatorname {PolyLog}\left (2,e^{-2 \coth ^{-1}(c+d x)}\right )\right )+4 b^3 d e \left (-\frac {i \pi ^3}{8}+\coth ^{-1}(c+d x)^3+(c+d x) \coth ^{-1}(c+d x)^3-3 \coth ^{-1}(c+d x)^2 \log \left (1-e^{2 \coth ^{-1}(c+d x)}\right )-3 \coth ^{-1}(c+d x) \operatorname {PolyLog}\left (2,e^{2 \coth ^{-1}(c+d x)}\right )+\frac {3}{2} \operatorname {PolyLog}\left (3,e^{2 \coth ^{-1}(c+d x)}\right )\right )-4 b^3 c f \left (-\frac {i \pi ^3}{8}+\coth ^{-1}(c+d x)^3+(c+d x) \coth ^{-1}(c+d x)^3-3 \coth ^{-1}(c+d x)^2 \log \left (1-e^{2 \coth ^{-1}(c+d x)}\right )-3 \coth ^{-1}(c+d x) \operatorname {PolyLog}\left (2,e^{2 \coth ^{-1}(c+d x)}\right )+\frac {3}{2} \operatorname {PolyLog}\left (3,e^{2 \coth ^{-1}(c+d x)}\right )\right )}{4 d^2} \]
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Result contains higher order function than in optimal. Order 9 vs. order 4.
Time = 5.56 (sec) , antiderivative size = 7528, normalized size of antiderivative = 23.09
method | result | size |
parts | \(\text {Expression too large to display}\) | \(7528\) |
derivativedivides | \(\text {Expression too large to display}\) | \(7638\) |
default | \(\text {Expression too large to display}\) | \(7638\) |
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\[ \int (e+f x) \left (a+b \coth ^{-1}(c+d x)\right )^3 \, dx=\int { {\left (f x + e\right )} {\left (b \operatorname {arcoth}\left (d x + c\right ) + a\right )}^{3} \,d x } \]
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\[ \int (e+f x) \left (a+b \coth ^{-1}(c+d x)\right )^3 \, dx=\int \left (a + b \operatorname {acoth}{\left (c + d x \right )}\right )^{3} \left (e + f x\right )\, dx \]
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\[ \int (e+f x) \left (a+b \coth ^{-1}(c+d x)\right )^3 \, dx=\int { {\left (f x + e\right )} {\left (b \operatorname {arcoth}\left (d x + c\right ) + a\right )}^{3} \,d x } \]
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\[ \int (e+f x) \left (a+b \coth ^{-1}(c+d x)\right )^3 \, dx=\int { {\left (f x + e\right )} {\left (b \operatorname {arcoth}\left (d x + c\right ) + a\right )}^{3} \,d x } \]
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Timed out. \[ \int (e+f x) \left (a+b \coth ^{-1}(c+d x)\right )^3 \, dx=\int \left (e+f\,x\right )\,{\left (a+b\,\mathrm {acoth}\left (c+d\,x\right )\right )}^3 \,d x \]
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