Integrand size = 13, antiderivative size = 75 \[ \int \frac {x^3}{\coth ^{-1}(\tanh (a+b x))^2} \, dx=\frac {3 x^2}{2 b^2}+\frac {3 x \left (b x-\coth ^{-1}(\tanh (a+b x))\right )}{b^3}-\frac {x^3}{b \coth ^{-1}(\tanh (a+b x))}+\frac {3 \left (b x-\coth ^{-1}(\tanh (a+b x))\right )^2 \log \left (\coth ^{-1}(\tanh (a+b x))\right )}{b^4} \]
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Time = 0.04 (sec) , antiderivative size = 75, normalized size of antiderivative = 1.00, number of steps used = 5, number of rules used = 5, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.385, Rules used = {2199, 2190, 2189, 2188, 29} \[ \int \frac {x^3}{\coth ^{-1}(\tanh (a+b x))^2} \, dx=\frac {3 \left (b x-\coth ^{-1}(\tanh (a+b x))\right )^2 \log \left (\coth ^{-1}(\tanh (a+b x))\right )}{b^4}+\frac {3 x \left (b x-\coth ^{-1}(\tanh (a+b x))\right )}{b^3}-\frac {x^3}{b \coth ^{-1}(\tanh (a+b x))}+\frac {3 x^2}{2 b^2} \]
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Rule 29
Rule 2188
Rule 2189
Rule 2190
Rule 2199
Rubi steps \begin{align*} \text {integral}& = -\frac {x^3}{b \coth ^{-1}(\tanh (a+b x))}+\frac {3 \int \frac {x^2}{\coth ^{-1}(\tanh (a+b x))} \, dx}{b} \\ & = \frac {3 x^2}{2 b^2}-\frac {x^3}{b \coth ^{-1}(\tanh (a+b x))}-\frac {\left (3 \left (-b x+\coth ^{-1}(\tanh (a+b x))\right )\right ) \int \frac {x}{\coth ^{-1}(\tanh (a+b x))} \, dx}{b^2} \\ & = \frac {3 x^2}{2 b^2}+\frac {3 x \left (b x-\coth ^{-1}(\tanh (a+b x))\right )}{b^3}-\frac {x^3}{b \coth ^{-1}(\tanh (a+b x))}+\frac {\left (3 \left (-b x+\coth ^{-1}(\tanh (a+b x))\right )^2\right ) \int \frac {1}{\coth ^{-1}(\tanh (a+b x))} \, dx}{b^3} \\ & = \frac {3 x^2}{2 b^2}+\frac {3 x \left (b x-\coth ^{-1}(\tanh (a+b x))\right )}{b^3}-\frac {x^3}{b \coth ^{-1}(\tanh (a+b x))}+\frac {\left (3 \left (-b x+\coth ^{-1}(\tanh (a+b x))\right )^2\right ) \text {Subst}\left (\int \frac {1}{x} \, dx,x,\coth ^{-1}(\tanh (a+b x))\right )}{b^4} \\ & = \frac {3 x^2}{2 b^2}+\frac {3 x \left (b x-\coth ^{-1}(\tanh (a+b x))\right )}{b^3}-\frac {x^3}{b \coth ^{-1}(\tanh (a+b x))}+\frac {3 \left (b x-\coth ^{-1}(\tanh (a+b x))\right )^2 \log \left (\coth ^{-1}(\tanh (a+b x))\right )}{b^4} \\ \end{align*}
Time = 0.04 (sec) , antiderivative size = 83, normalized size of antiderivative = 1.11 \[ \int \frac {x^3}{\coth ^{-1}(\tanh (a+b x))^2} \, dx=\frac {x^2}{2 b^2}-\frac {2 x \left (-b x+\coth ^{-1}(\tanh (a+b x))\right )}{b^3}+\frac {\left (-b x+\coth ^{-1}(\tanh (a+b x))\right )^3}{b^4 \coth ^{-1}(\tanh (a+b x))}+\frac {3 \left (-b x+\coth ^{-1}(\tanh (a+b x))\right )^2 \log \left (\coth ^{-1}(\tanh (a+b x))\right )}{b^4} \]
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Result contains higher order function than in optimal. Order 9 vs. order 3.
Time = 0.38 (sec) , antiderivative size = 29109, normalized size of antiderivative = 388.12
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Result contains complex when optimal does not.
Time = 0.25 (sec) , antiderivative size = 151, normalized size of antiderivative = 2.01 \[ \int \frac {x^3}{\coth ^{-1}(\tanh (a+b x))^2} \, dx=\frac {4 \, b^{3} x^{3} - 12 \, a b^{2} x^{2} - 16 \, a^{2} b x - i \, \pi ^{3} + 2 \, \pi ^{2} {\left (2 \, b x - 3 \, a\right )} + 8 \, a^{3} - 2 i \, \pi {\left (3 \, b^{2} x^{2} + 8 \, a b x - 6 \, a^{2}\right )} + 3 \, {\left (8 \, a^{2} b x - i \, \pi ^{3} - 2 \, \pi ^{2} {\left (b x + 3 \, a\right )} + 8 \, a^{3} + 4 i \, \pi {\left (2 \, a b x + 3 \, a^{2}\right )}\right )} \log \left (i \, \pi + 2 \, b x + 2 \, a\right )}{4 \, {\left (2 \, b^{5} x + i \, \pi b^{4} + 2 \, a b^{4}\right )}} \]
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\[ \int \frac {x^3}{\coth ^{-1}(\tanh (a+b x))^2} \, dx=\int \frac {x^{3}}{\operatorname {acoth}^{2}{\left (\tanh {\left (a + b x \right )} \right )}}\, dx \]
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Result contains complex when optimal does not.
Time = 0.52 (sec) , antiderivative size = 123, normalized size of antiderivative = 1.64 \[ \int \frac {x^3}{\coth ^{-1}(\tanh (a+b x))^2} \, dx=\frac {4 \, b^{3} x^{3} + i \, \pi ^{3} - 6 \, \pi ^{2} a - 12 i \, \pi a^{2} + 8 \, a^{3} - 6 \, {\left (-i \, \pi b^{2} + 2 \, a b^{2}\right )} x^{2} + 4 \, {\left (\pi ^{2} b + 4 i \, \pi a b - 4 \, a^{2} b\right )} x}{4 \, {\left (2 \, b^{5} x - i \, \pi b^{4} + 2 \, a b^{4}\right )}} - \frac {3 \, {\left (\pi ^{2} + 4 i \, \pi a - 4 \, a^{2}\right )} \log \left (-i \, \pi + 2 \, b x + 2 \, a\right )}{4 \, b^{4}} \]
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Result contains complex when optimal does not.
Time = 0.29 (sec) , antiderivative size = 97, normalized size of antiderivative = 1.29 \[ \int \frac {x^3}{\coth ^{-1}(\tanh (a+b x))^2} \, dx=-\frac {i \, \pi ^{3} + 6 \, \pi ^{2} a - 12 i \, \pi a^{2} - 8 \, a^{3}}{4 \, {\left (2 \, b^{5} x + i \, \pi b^{4} + 2 \, a b^{4}\right )}} + \frac {x^{2}}{2 \, b^{2}} + \frac {{\left (-i \, \pi - 2 \, a\right )} x}{b^{3}} - \frac {3 \, {\left (\pi ^{2} - 4 i \, \pi a - 4 \, a^{2}\right )} \log \left (i \, \pi + 2 \, b x + 2 \, a\right )}{4 \, b^{4}} \]
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Time = 0.18 (sec) , antiderivative size = 490, normalized size of antiderivative = 6.53 \[ \int \frac {x^3}{\coth ^{-1}(\tanh (a+b x))^2} \, dx=\frac {x^2}{2\,b^2}+\frac {\ln \left (\ln \left (\frac {2\,{\mathrm {e}}^{2\,a}\,{\mathrm {e}}^{2\,b\,x}}{{\mathrm {e}}^{2\,a}\,{\mathrm {e}}^{2\,b\,x}-1}\right )-\ln \left (-\frac {2}{{\mathrm {e}}^{2\,a}\,{\mathrm {e}}^{2\,b\,x}-1}\right )\right )\,\left (3\,{\left (2\,a-\ln \left (\frac {2\,{\mathrm {e}}^{2\,a}\,{\mathrm {e}}^{2\,b\,x}}{{\mathrm {e}}^{2\,a}\,{\mathrm {e}}^{2\,b\,x}-1}\right )+\ln \left (-\frac {2}{{\mathrm {e}}^{2\,a}\,{\mathrm {e}}^{2\,b\,x}-1}\right )+2\,b\,x\right )}^2-12\,a\,\left (2\,a-\ln \left (\frac {2\,{\mathrm {e}}^{2\,a}\,{\mathrm {e}}^{2\,b\,x}}{{\mathrm {e}}^{2\,a}\,{\mathrm {e}}^{2\,b\,x}-1}\right )+\ln \left (-\frac {2}{{\mathrm {e}}^{2\,a}\,{\mathrm {e}}^{2\,b\,x}-1}\right )+2\,b\,x\right )+12\,a^2\right )}{4\,b^4}-\frac {{\left (2\,a-\ln \left (\frac {2\,{\mathrm {e}}^{2\,a}\,{\mathrm {e}}^{2\,b\,x}}{{\mathrm {e}}^{2\,a}\,{\mathrm {e}}^{2\,b\,x}-1}\right )+\ln \left (-\frac {2}{{\mathrm {e}}^{2\,a}\,{\mathrm {e}}^{2\,b\,x}-1}\right )+2\,b\,x\right )}^3-8\,a^3-6\,a\,{\left (2\,a-\ln \left (\frac {2\,{\mathrm {e}}^{2\,a}\,{\mathrm {e}}^{2\,b\,x}}{{\mathrm {e}}^{2\,a}\,{\mathrm {e}}^{2\,b\,x}-1}\right )+\ln \left (-\frac {2}{{\mathrm {e}}^{2\,a}\,{\mathrm {e}}^{2\,b\,x}-1}\right )+2\,b\,x\right )}^2+12\,a^2\,\left (2\,a-\ln \left (\frac {2\,{\mathrm {e}}^{2\,a}\,{\mathrm {e}}^{2\,b\,x}}{{\mathrm {e}}^{2\,a}\,{\mathrm {e}}^{2\,b\,x}-1}\right )+\ln \left (-\frac {2}{{\mathrm {e}}^{2\,a}\,{\mathrm {e}}^{2\,b\,x}-1}\right )+2\,b\,x\right )}{4\,b\,\left (2\,a\,b^3+2\,b^4\,x-b^3\,\left (2\,a-\ln \left (\frac {2\,{\mathrm {e}}^{2\,a}\,{\mathrm {e}}^{2\,b\,x}}{{\mathrm {e}}^{2\,a}\,{\mathrm {e}}^{2\,b\,x}-1}\right )+\ln \left (-\frac {2}{{\mathrm {e}}^{2\,a}\,{\mathrm {e}}^{2\,b\,x}-1}\right )+2\,b\,x\right )\right )}+\frac {x\,\left (\ln \left (-\frac {2}{{\mathrm {e}}^{2\,a}\,{\mathrm {e}}^{2\,b\,x}-1}\right )-\ln \left (\frac {2\,{\mathrm {e}}^{2\,a}\,{\mathrm {e}}^{2\,b\,x}}{{\mathrm {e}}^{2\,a}\,{\mathrm {e}}^{2\,b\,x}-1}\right )+2\,b\,x\right )}{b^3} \]
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