Integrand size = 13, antiderivative size = 82 \[ \int x^2 \coth ^{-1}(\tanh (a+b x))^n \, dx=\frac {x^2 \coth ^{-1}(\tanh (a+b x))^{1+n}}{b (1+n)}-\frac {2 x \coth ^{-1}(\tanh (a+b x))^{2+n}}{b^2 (1+n) (2+n)}+\frac {2 \coth ^{-1}(\tanh (a+b x))^{3+n}}{b^3 (1+n) (2+n) (3+n)} \]
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Time = 0.04 (sec) , antiderivative size = 82, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.231, Rules used = {2199, 2188, 30} \[ \int x^2 \coth ^{-1}(\tanh (a+b x))^n \, dx=\frac {2 \coth ^{-1}(\tanh (a+b x))^{n+3}}{b^3 (n+1) (n+2) (n+3)}-\frac {2 x \coth ^{-1}(\tanh (a+b x))^{n+2}}{b^2 (n+1) (n+2)}+\frac {x^2 \coth ^{-1}(\tanh (a+b x))^{n+1}}{b (n+1)} \]
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Rule 30
Rule 2188
Rule 2199
Rubi steps \begin{align*} \text {integral}& = \frac {x^2 \coth ^{-1}(\tanh (a+b x))^{1+n}}{b (1+n)}-\frac {2 \int x \coth ^{-1}(\tanh (a+b x))^{1+n} \, dx}{b (1+n)} \\ & = \frac {x^2 \coth ^{-1}(\tanh (a+b x))^{1+n}}{b (1+n)}-\frac {2 x \coth ^{-1}(\tanh (a+b x))^{2+n}}{b^2 (1+n) (2+n)}+\frac {2 \int \coth ^{-1}(\tanh (a+b x))^{2+n} \, dx}{b^2 (1+n) (2+n)} \\ & = \frac {x^2 \coth ^{-1}(\tanh (a+b x))^{1+n}}{b (1+n)}-\frac {2 x \coth ^{-1}(\tanh (a+b x))^{2+n}}{b^2 (1+n) (2+n)}+\frac {2 \text {Subst}\left (\int x^{2+n} \, dx,x,\coth ^{-1}(\tanh (a+b x))\right )}{b^3 (1+n) (2+n)} \\ & = \frac {x^2 \coth ^{-1}(\tanh (a+b x))^{1+n}}{b (1+n)}-\frac {2 x \coth ^{-1}(\tanh (a+b x))^{2+n}}{b^2 (1+n) (2+n)}+\frac {2 \coth ^{-1}(\tanh (a+b x))^{3+n}}{b^3 (1+n) (2+n) (3+n)} \\ \end{align*}
Time = 0.05 (sec) , antiderivative size = 71, normalized size of antiderivative = 0.87 \[ \int x^2 \coth ^{-1}(\tanh (a+b x))^n \, dx=\frac {\coth ^{-1}(\tanh (a+b x))^{1+n} \left (b^2 \left (6+5 n+n^2\right ) x^2-2 b (3+n) x \coth ^{-1}(\tanh (a+b x))+2 \coth ^{-1}(\tanh (a+b x))^2\right )}{b^3 (1+n) (2+n) (3+n)} \]
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Time = 9.52 (sec) , antiderivative size = 163, normalized size of antiderivative = 1.99
method | result | size |
parallelrisch | \(-\frac {-2 \operatorname {arccoth}\left (\tanh \left (b x +a \right )\right )^{n} \operatorname {arccoth}\left (\tanh \left (b x +a \right )\right )^{3}-6 \operatorname {arccoth}\left (\tanh \left (b x +a \right )\right )^{n} x^{2} \operatorname {arccoth}\left (\tanh \left (b x +a \right )\right ) b^{2}+6 \operatorname {arccoth}\left (\tanh \left (b x +a \right )\right )^{n} \operatorname {arccoth}\left (\tanh \left (b x +a \right )\right )^{2} x b -x^{2} \operatorname {arccoth}\left (\tanh \left (b x +a \right )\right ) \operatorname {arccoth}\left (\tanh \left (b x +a \right )\right )^{n} b^{2} n^{2}-5 x^{2} \operatorname {arccoth}\left (\tanh \left (b x +a \right )\right ) \operatorname {arccoth}\left (\tanh \left (b x +a \right )\right )^{n} b^{2} n +2 x \operatorname {arccoth}\left (\tanh \left (b x +a \right )\right )^{2} \operatorname {arccoth}\left (\tanh \left (b x +a \right )\right )^{n} b n}{b^{3} \left (n^{3}+6 n^{2}+11 n +6\right )}\) | \(163\) |
risch | \(\text {Expression too large to display}\) | \(25561\) |
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Result contains complex when optimal does not.
Time = 0.26 (sec) , antiderivative size = 276, normalized size of antiderivative = 3.37 \[ \int x^2 \coth ^{-1}(\tanh (a+b x))^n \, dx=-\frac {{\left (8 \, a^{2} b n x - 4 \, {\left (b^{3} n^{2} + 3 \, b^{3} n + 2 \, b^{3}\right )} x^{3} + i \, \pi ^{3} - 2 \, \pi ^{2} {\left (b n x - 3 \, a\right )} - 8 \, a^{3} - 4 \, {\left (a b^{2} n^{2} + a b^{2} n\right )} x^{2} + 2 i \, \pi {\left (4 \, a b n x - {\left (b^{2} n^{2} + b^{2} n\right )} x^{2} - 6 \, a^{2}\right )}\right )} \cosh \left (n \log \left (\frac {1}{2} i \, \pi + b x + a\right )\right ) + {\left (8 \, a^{2} b n x - 4 \, {\left (b^{3} n^{2} + 3 \, b^{3} n + 2 \, b^{3}\right )} x^{3} + i \, \pi ^{3} - 2 \, \pi ^{2} {\left (b n x - 3 \, a\right )} - 8 \, a^{3} - 4 \, {\left (a b^{2} n^{2} + a b^{2} n\right )} x^{2} + 2 i \, \pi {\left (4 \, a b n x - {\left (b^{2} n^{2} + b^{2} n\right )} x^{2} - 6 \, a^{2}\right )}\right )} \sinh \left (n \log \left (\frac {1}{2} i \, \pi + b x + a\right )\right )}{4 \, {\left (b^{3} n^{3} + 6 \, b^{3} n^{2} + 11 \, b^{3} n + 6 \, b^{3}\right )}} \]
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\[ \int x^2 \coth ^{-1}(\tanh (a+b x))^n \, dx=\begin {cases} \frac {x^{3} \operatorname {acoth}^{n}{\left (\tanh {\left (a \right )} \right )}}{3} & \text {for}\: b = 0 \\- \frac {x^{2}}{2 b \operatorname {acoth}^{2}{\left (\tanh {\left (a + b x \right )} \right )}} - \frac {x}{b^{2} \operatorname {acoth}{\left (\tanh {\left (a + b x \right )} \right )}} + \frac {\log {\left (\operatorname {acoth}{\left (\tanh {\left (a + b x \right )} \right )} \right )}}{b^{3}} & \text {for}\: n = -3 \\\int \frac {x^{2}}{\operatorname {acoth}^{2}{\left (\tanh {\left (a + b x \right )} \right )}}\, dx & \text {for}\: n = -2 \\\int \frac {x^{2}}{\operatorname {acoth}{\left (\tanh {\left (a + b x \right )} \right )}}\, dx & \text {for}\: n = -1 \\\frac {b^{2} n^{2} x^{2} \operatorname {acoth}{\left (\tanh {\left (a + b x \right )} \right )} \operatorname {acoth}^{n}{\left (\tanh {\left (a + b x \right )} \right )}}{b^{3} n^{3} + 6 b^{3} n^{2} + 11 b^{3} n + 6 b^{3}} + \frac {5 b^{2} n x^{2} \operatorname {acoth}{\left (\tanh {\left (a + b x \right )} \right )} \operatorname {acoth}^{n}{\left (\tanh {\left (a + b x \right )} \right )}}{b^{3} n^{3} + 6 b^{3} n^{2} + 11 b^{3} n + 6 b^{3}} + \frac {6 b^{2} x^{2} \operatorname {acoth}{\left (\tanh {\left (a + b x \right )} \right )} \operatorname {acoth}^{n}{\left (\tanh {\left (a + b x \right )} \right )}}{b^{3} n^{3} + 6 b^{3} n^{2} + 11 b^{3} n + 6 b^{3}} - \frac {2 b n x \operatorname {acoth}^{2}{\left (\tanh {\left (a + b x \right )} \right )} \operatorname {acoth}^{n}{\left (\tanh {\left (a + b x \right )} \right )}}{b^{3} n^{3} + 6 b^{3} n^{2} + 11 b^{3} n + 6 b^{3}} - \frac {6 b x \operatorname {acoth}^{2}{\left (\tanh {\left (a + b x \right )} \right )} \operatorname {acoth}^{n}{\left (\tanh {\left (a + b x \right )} \right )}}{b^{3} n^{3} + 6 b^{3} n^{2} + 11 b^{3} n + 6 b^{3}} + \frac {2 \operatorname {acoth}^{3}{\left (\tanh {\left (a + b x \right )} \right )} \operatorname {acoth}^{n}{\left (\tanh {\left (a + b x \right )} \right )}}{b^{3} n^{3} + 6 b^{3} n^{2} + 11 b^{3} n + 6 b^{3}} & \text {otherwise} \end {cases} \]
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Result contains complex when optimal does not.
Time = 0.37 (sec) , antiderivative size = 166, normalized size of antiderivative = 2.02 \[ \int x^2 \coth ^{-1}(\tanh (a+b x))^n \, dx=\frac {{\left (4 \, {\left (n^{2} + 3 \, n + 2\right )} b^{3} x^{3} + i \, \pi ^{3} - 6 \, \pi ^{2} a - 12 i \, \pi a^{2} + 8 \, a^{3} - 2 \, {\left (i \, \pi {\left (n^{2} + n\right )} b^{2} - 2 \, {\left (n^{2} + n\right )} a b^{2}\right )} x^{2} + 2 \, {\left (\pi ^{2} b n + 4 i \, \pi a b n - 4 \, a^{2} b n\right )} x\right )} {\left (\cosh \left (-n \log \left (-i \, \pi + 2 \, b x + 2 \, a\right )\right ) - \sinh \left (-n \log \left (-i \, \pi + 2 \, b x + 2 \, a\right )\right )\right )}}{{\left (2^{n + 2} n^{3} + 3 \cdot 2^{n + 3} n^{2} + 11 \cdot 2^{n + 2} n + 3 \cdot 2^{n + 3}\right )} b^{3}} \]
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\[ \int x^2 \coth ^{-1}(\tanh (a+b x))^n \, dx=\int { x^{2} \operatorname {arcoth}\left (\tanh \left (b x + a\right )\right )^{n} \,d x } \]
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Time = 3.98 (sec) , antiderivative size = 304, normalized size of antiderivative = 3.71 \[ \int x^2 \coth ^{-1}(\tanh (a+b x))^n \, dx=-{\left (\frac {\ln \left (\frac {2\,{\mathrm {e}}^{2\,a}\,{\mathrm {e}}^{2\,b\,x}}{{\mathrm {e}}^{2\,a}\,{\mathrm {e}}^{2\,b\,x}-1}\right )}{2}-\frac {\ln \left (-\frac {2}{{\mathrm {e}}^{2\,a}\,{\mathrm {e}}^{2\,b\,x}-1}\right )}{2}\right )}^n\,\left (\frac {{\left (\ln \left (-\frac {2}{{\mathrm {e}}^{2\,a}\,{\mathrm {e}}^{2\,b\,x}-1}\right )-\ln \left (\frac {2\,{\mathrm {e}}^{2\,a}\,{\mathrm {e}}^{2\,b\,x}}{{\mathrm {e}}^{2\,a}\,{\mathrm {e}}^{2\,b\,x}-1}\right )+2\,b\,x\right )}^3}{4\,b^3\,\left (n^3+6\,n^2+11\,n+6\right )}-\frac {x^3\,\left (n^2+3\,n+2\right )}{n^3+6\,n^2+11\,n+6}+\frac {n\,x\,{\left (\ln \left (-\frac {2}{{\mathrm {e}}^{2\,a}\,{\mathrm {e}}^{2\,b\,x}-1}\right )-\ln \left (\frac {2\,{\mathrm {e}}^{2\,a}\,{\mathrm {e}}^{2\,b\,x}}{{\mathrm {e}}^{2\,a}\,{\mathrm {e}}^{2\,b\,x}-1}\right )+2\,b\,x\right )}^2}{2\,b^2\,\left (n^3+6\,n^2+11\,n+6\right )}+\frac {n\,x^2\,\left (n+1\right )\,\left (\ln \left (-\frac {2}{{\mathrm {e}}^{2\,a}\,{\mathrm {e}}^{2\,b\,x}-1}\right )-\ln \left (\frac {2\,{\mathrm {e}}^{2\,a}\,{\mathrm {e}}^{2\,b\,x}}{{\mathrm {e}}^{2\,a}\,{\mathrm {e}}^{2\,b\,x}-1}\right )+2\,b\,x\right )}{2\,b\,\left (n^3+6\,n^2+11\,n+6\right )}\right ) \]
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