Integrand size = 11, antiderivative size = 150 \[ \int \coth ^{-1}(c+d \tanh (a+b x)) \, dx=x \coth ^{-1}(c+d \tanh (a+b x))+\frac {1}{2} x \log \left (1+\frac {(1-c-d) e^{2 a+2 b x}}{1-c+d}\right )-\frac {1}{2} x \log \left (1+\frac {(1+c+d) e^{2 a+2 b x}}{1+c-d}\right )+\frac {\operatorname {PolyLog}\left (2,-\frac {(1-c-d) e^{2 a+2 b x}}{1-c+d}\right )}{4 b}-\frac {\operatorname {PolyLog}\left (2,-\frac {(1+c+d) e^{2 a+2 b x}}{1+c-d}\right )}{4 b} \]
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Time = 0.18 (sec) , antiderivative size = 150, normalized size of antiderivative = 1.00, number of steps used = 7, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.364, Rules used = {6371, 2221, 2317, 2438} \[ \int \coth ^{-1}(c+d \tanh (a+b x)) \, dx=\frac {\operatorname {PolyLog}\left (2,-\frac {(-c-d+1) e^{2 a+2 b x}}{-c+d+1}\right )}{4 b}-\frac {\operatorname {PolyLog}\left (2,-\frac {(c+d+1) e^{2 a+2 b x}}{c-d+1}\right )}{4 b}+\frac {1}{2} x \log \left (\frac {(-c-d+1) e^{2 a+2 b x}}{-c+d+1}+1\right )-\frac {1}{2} x \log \left (\frac {(c+d+1) e^{2 a+2 b x}}{c-d+1}+1\right )+x \coth ^{-1}(d \tanh (a+b x)+c) \]
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Rule 2221
Rule 2317
Rule 2438
Rule 6371
Rubi steps \begin{align*} \text {integral}& = x \coth ^{-1}(c+d \tanh (a+b x))+(b (1-c-d)) \int \frac {e^{2 a+2 b x} x}{1-c+d+(1-c-d) e^{2 a+2 b x}} \, dx-(b (1+c+d)) \int \frac {e^{2 a+2 b x} x}{1+c-d+(1+c+d) e^{2 a+2 b x}} \, dx \\ & = x \coth ^{-1}(c+d \tanh (a+b x))+\frac {1}{2} x \log \left (1+\frac {(1-c-d) e^{2 a+2 b x}}{1-c+d}\right )-\frac {1}{2} x \log \left (1+\frac {(1+c+d) e^{2 a+2 b x}}{1+c-d}\right )-\frac {1}{2} \int \log \left (1+\frac {(1-c-d) e^{2 a+2 b x}}{1-c+d}\right ) \, dx+\frac {1}{2} \int \log \left (1+\frac {(1+c+d) e^{2 a+2 b x}}{1+c-d}\right ) \, dx \\ & = x \coth ^{-1}(c+d \tanh (a+b x))+\frac {1}{2} x \log \left (1+\frac {(1-c-d) e^{2 a+2 b x}}{1-c+d}\right )-\frac {1}{2} x \log \left (1+\frac {(1+c+d) e^{2 a+2 b x}}{1+c-d}\right )-\frac {\text {Subst}\left (\int \frac {\log \left (1+\frac {(1-c-d) x}{1-c+d}\right )}{x} \, dx,x,e^{2 a+2 b x}\right )}{4 b}+\frac {\text {Subst}\left (\int \frac {\log \left (1+\frac {(1+c+d) x}{1+c-d}\right )}{x} \, dx,x,e^{2 a+2 b x}\right )}{4 b} \\ & = x \coth ^{-1}(c+d \tanh (a+b x))+\frac {1}{2} x \log \left (1+\frac {(1-c-d) e^{2 a+2 b x}}{1-c+d}\right )-\frac {1}{2} x \log \left (1+\frac {(1+c+d) e^{2 a+2 b x}}{1+c-d}\right )+\frac {\operatorname {PolyLog}\left (2,-\frac {(1-c-d) e^{2 a+2 b x}}{1-c+d}\right )}{4 b}-\frac {\operatorname {PolyLog}\left (2,-\frac {(1+c+d) e^{2 a+2 b x}}{1+c-d}\right )}{4 b} \\ \end{align*}
Time = 0.14 (sec) , antiderivative size = 131, normalized size of antiderivative = 0.87 \[ \int \coth ^{-1}(c+d \tanh (a+b x)) \, dx=x \coth ^{-1}(c+d \tanh (a+b x))+\frac {2 b x \left (\log \left (1+\frac {(-1+c+d) e^{2 (a+b x)}}{-1+c-d}\right )-\log \left (1+\frac {(1+c+d) e^{2 (a+b x)}}{1+c-d}\right )\right )+\operatorname {PolyLog}\left (2,-\frac {(-1+c+d) e^{2 (a+b x)}}{-1+c-d}\right )-\operatorname {PolyLog}\left (2,-\frac {(1+c+d) e^{2 (a+b x)}}{1+c-d}\right )}{4 b} \]
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Leaf count of result is larger than twice the leaf count of optimal. \(347\) vs. \(2(138)=276\).
Time = 2.75 (sec) , antiderivative size = 348, normalized size of antiderivative = 2.32
method | result | size |
derivativedivides | \(\frac {-\frac {\operatorname {arccoth}\left (c +d \tanh \left (b x +a \right )\right ) d \ln \left (-d \tanh \left (b x +a \right )+d \right )}{2}+\frac {\operatorname {arccoth}\left (c +d \tanh \left (b x +a \right )\right ) d \ln \left (-d \tanh \left (b x +a \right )-d \right )}{2}-\frac {d^{2} \left (\frac {-\frac {\operatorname {dilog}\left (\frac {-d \tanh \left (b x +a \right )-c -1}{-1-c -d}\right )}{2}-\frac {\ln \left (-d \tanh \left (b x +a \right )+d \right ) \ln \left (\frac {-d \tanh \left (b x +a \right )-c -1}{-1-c -d}\right )}{2}+\frac {\operatorname {dilog}\left (\frac {-d \tanh \left (b x +a \right )-c +1}{1-c -d}\right )}{2}+\frac {\ln \left (-d \tanh \left (b x +a \right )+d \right ) \ln \left (\frac {-d \tanh \left (b x +a \right )-c +1}{1-c -d}\right )}{2}}{d}-\frac {-\frac {\operatorname {dilog}\left (\frac {-d \tanh \left (b x +a \right )-c -1}{-1-c +d}\right )}{2}-\frac {\ln \left (-d \tanh \left (b x +a \right )-d \right ) \ln \left (\frac {-d \tanh \left (b x +a \right )-c -1}{-1-c +d}\right )}{2}+\frac {\operatorname {dilog}\left (\frac {-d \tanh \left (b x +a \right )-c +1}{1-c +d}\right )}{2}+\frac {\ln \left (-d \tanh \left (b x +a \right )-d \right ) \ln \left (\frac {-d \tanh \left (b x +a \right )-c +1}{1-c +d}\right )}{2}}{d}\right )}{2}}{b d}\) | \(348\) |
default | \(\frac {-\frac {\operatorname {arccoth}\left (c +d \tanh \left (b x +a \right )\right ) d \ln \left (-d \tanh \left (b x +a \right )+d \right )}{2}+\frac {\operatorname {arccoth}\left (c +d \tanh \left (b x +a \right )\right ) d \ln \left (-d \tanh \left (b x +a \right )-d \right )}{2}-\frac {d^{2} \left (\frac {-\frac {\operatorname {dilog}\left (\frac {-d \tanh \left (b x +a \right )-c -1}{-1-c -d}\right )}{2}-\frac {\ln \left (-d \tanh \left (b x +a \right )+d \right ) \ln \left (\frac {-d \tanh \left (b x +a \right )-c -1}{-1-c -d}\right )}{2}+\frac {\operatorname {dilog}\left (\frac {-d \tanh \left (b x +a \right )-c +1}{1-c -d}\right )}{2}+\frac {\ln \left (-d \tanh \left (b x +a \right )+d \right ) \ln \left (\frac {-d \tanh \left (b x +a \right )-c +1}{1-c -d}\right )}{2}}{d}-\frac {-\frac {\operatorname {dilog}\left (\frac {-d \tanh \left (b x +a \right )-c -1}{-1-c +d}\right )}{2}-\frac {\ln \left (-d \tanh \left (b x +a \right )-d \right ) \ln \left (\frac {-d \tanh \left (b x +a \right )-c -1}{-1-c +d}\right )}{2}+\frac {\operatorname {dilog}\left (\frac {-d \tanh \left (b x +a \right )-c +1}{1-c +d}\right )}{2}+\frac {\ln \left (-d \tanh \left (b x +a \right )-d \right ) \ln \left (\frac {-d \tanh \left (b x +a \right )-c +1}{1-c +d}\right )}{2}}{d}\right )}{2}}{b d}\) | \(348\) |
risch | \(\text {Expression too large to display}\) | \(3011\) |
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Leaf count of result is larger than twice the leaf count of optimal. 551 vs. \(2 (128) = 256\).
Time = 0.28 (sec) , antiderivative size = 551, normalized size of antiderivative = 3.67 \[ \int \coth ^{-1}(c+d \tanh (a+b x)) \, dx=\frac {b x \log \left (\frac {{\left (c + 1\right )} \cosh \left (b x + a\right ) + d \sinh \left (b x + a\right )}{{\left (c - 1\right )} \cosh \left (b x + a\right ) + d \sinh \left (b x + a\right )}\right ) + a \log \left (2 \, {\left (c + d + 1\right )} \cosh \left (b x + a\right ) + 2 \, {\left (c + d + 1\right )} \sinh \left (b x + a\right ) + 2 \, {\left (c - d + 1\right )} \sqrt {-\frac {c + d + 1}{c - d + 1}}\right ) + a \log \left (2 \, {\left (c + d + 1\right )} \cosh \left (b x + a\right ) + 2 \, {\left (c + d + 1\right )} \sinh \left (b x + a\right ) - 2 \, {\left (c - d + 1\right )} \sqrt {-\frac {c + d + 1}{c - d + 1}}\right ) - a \log \left (2 \, {\left (c + d - 1\right )} \cosh \left (b x + a\right ) + 2 \, {\left (c + d - 1\right )} \sinh \left (b x + a\right ) + 2 \, {\left (c - d - 1\right )} \sqrt {-\frac {c + d - 1}{c - d - 1}}\right ) - a \log \left (2 \, {\left (c + d - 1\right )} \cosh \left (b x + a\right ) + 2 \, {\left (c + d - 1\right )} \sinh \left (b x + a\right ) - 2 \, {\left (c - d - 1\right )} \sqrt {-\frac {c + d - 1}{c - d - 1}}\right ) - {\left (b x + a\right )} \log \left (\sqrt {-\frac {c + d + 1}{c - d + 1}} {\left (\cosh \left (b x + a\right ) + \sinh \left (b x + a\right )\right )} + 1\right ) - {\left (b x + a\right )} \log \left (-\sqrt {-\frac {c + d + 1}{c - d + 1}} {\left (\cosh \left (b x + a\right ) + \sinh \left (b x + a\right )\right )} + 1\right ) + {\left (b x + a\right )} \log \left (\sqrt {-\frac {c + d - 1}{c - d - 1}} {\left (\cosh \left (b x + a\right ) + \sinh \left (b x + a\right )\right )} + 1\right ) + {\left (b x + a\right )} \log \left (-\sqrt {-\frac {c + d - 1}{c - d - 1}} {\left (\cosh \left (b x + a\right ) + \sinh \left (b x + a\right )\right )} + 1\right ) - {\rm Li}_2\left (\sqrt {-\frac {c + d + 1}{c - d + 1}} {\left (\cosh \left (b x + a\right ) + \sinh \left (b x + a\right )\right )}\right ) - {\rm Li}_2\left (-\sqrt {-\frac {c + d + 1}{c - d + 1}} {\left (\cosh \left (b x + a\right ) + \sinh \left (b x + a\right )\right )}\right ) + {\rm Li}_2\left (\sqrt {-\frac {c + d - 1}{c - d - 1}} {\left (\cosh \left (b x + a\right ) + \sinh \left (b x + a\right )\right )}\right ) + {\rm Li}_2\left (-\sqrt {-\frac {c + d - 1}{c - d - 1}} {\left (\cosh \left (b x + a\right ) + \sinh \left (b x + a\right )\right )}\right )}{2 \, b} \]
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\[ \int \coth ^{-1}(c+d \tanh (a+b x)) \, dx=\int \operatorname {acoth}{\left (c + d \tanh {\left (a + b x \right )} \right )}\, dx \]
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Time = 0.47 (sec) , antiderivative size = 142, normalized size of antiderivative = 0.95 \[ \int \coth ^{-1}(c+d \tanh (a+b x)) \, dx=-\frac {1}{4} \, b d {\left (\frac {2 \, b x \log \left (\frac {{\left (c + d + 1\right )} e^{\left (2 \, b x + 2 \, a\right )}}{c - d + 1} + 1\right ) + {\rm Li}_2\left (-\frac {{\left (c + d + 1\right )} e^{\left (2 \, b x + 2 \, a\right )}}{c - d + 1}\right )}{b^{2} d} - \frac {2 \, b x \log \left (\frac {{\left (c + d - 1\right )} e^{\left (2 \, b x + 2 \, a\right )}}{c - d - 1} + 1\right ) + {\rm Li}_2\left (-\frac {{\left (c + d - 1\right )} e^{\left (2 \, b x + 2 \, a\right )}}{c - d - 1}\right )}{b^{2} d}\right )} + x \operatorname {arcoth}\left (d \tanh \left (b x + a\right ) + c\right ) \]
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\[ \int \coth ^{-1}(c+d \tanh (a+b x)) \, dx=\int { \operatorname {arcoth}\left (d \tanh \left (b x + a\right ) + c\right ) \,d x } \]
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Timed out. \[ \int \coth ^{-1}(c+d \tanh (a+b x)) \, dx=\int \mathrm {acoth}\left (c+d\,\mathrm {tanh}\left (a+b\,x\right )\right ) \,d x \]
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