Integrand size = 24, antiderivative size = 160 \[ \int \frac {\left (a+b \coth ^{-1}\left (c x^n\right )\right ) \left (d+e \log \left (f x^m\right )\right )}{x} \, dx=a d \log (x)+\frac {a e \log ^2\left (f x^m\right )}{2 m}+\frac {b d \operatorname {PolyLog}\left (2,-\frac {x^{-n}}{c}\right )}{2 n}+\frac {b e \log \left (f x^m\right ) \operatorname {PolyLog}\left (2,-\frac {x^{-n}}{c}\right )}{2 n}-\frac {b d \operatorname {PolyLog}\left (2,\frac {x^{-n}}{c}\right )}{2 n}-\frac {b e \log \left (f x^m\right ) \operatorname {PolyLog}\left (2,\frac {x^{-n}}{c}\right )}{2 n}+\frac {b e m \operatorname {PolyLog}\left (3,-\frac {x^{-n}}{c}\right )}{2 n^2}-\frac {b e m \operatorname {PolyLog}\left (3,\frac {x^{-n}}{c}\right )}{2 n^2} \]
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Time = 0.45 (sec) , antiderivative size = 160, normalized size of antiderivative = 1.00, number of steps used = 11, number of rules used = 8, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.333, Rules used = {2338, 6874, 6036, 6032, 6219, 6217, 2421, 6724} \[ \int \frac {\left (a+b \coth ^{-1}\left (c x^n\right )\right ) \left (d+e \log \left (f x^m\right )\right )}{x} \, dx=a d \log (x)+\frac {a e \log ^2\left (f x^m\right )}{2 m}+\frac {b d \operatorname {PolyLog}\left (2,-\frac {x^{-n}}{c}\right )}{2 n}-\frac {b d \operatorname {PolyLog}\left (2,\frac {x^{-n}}{c}\right )}{2 n}+\frac {b e \operatorname {PolyLog}\left (2,-\frac {x^{-n}}{c}\right ) \log \left (f x^m\right )}{2 n}-\frac {b e \operatorname {PolyLog}\left (2,\frac {x^{-n}}{c}\right ) \log \left (f x^m\right )}{2 n}+\frac {b e m \operatorname {PolyLog}\left (3,-\frac {x^{-n}}{c}\right )}{2 n^2}-\frac {b e m \operatorname {PolyLog}\left (3,\frac {x^{-n}}{c}\right )}{2 n^2} \]
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Rule 2338
Rule 2421
Rule 6032
Rule 6036
Rule 6217
Rule 6219
Rule 6724
Rule 6874
Rubi steps \begin{align*} \text {integral}& = \int \left (\frac {d \left (a+b \coth ^{-1}\left (c x^n\right )\right )}{x}+\frac {e \left (a+b \coth ^{-1}\left (c x^n\right )\right ) \log \left (f x^m\right )}{x}\right ) \, dx \\ & = d \int \frac {a+b \coth ^{-1}\left (c x^n\right )}{x} \, dx+e \int \frac {\left (a+b \coth ^{-1}\left (c x^n\right )\right ) \log \left (f x^m\right )}{x} \, dx \\ & = (a e) \int \frac {\log \left (f x^m\right )}{x} \, dx+(b e) \int \frac {\coth ^{-1}\left (c x^n\right ) \log \left (f x^m\right )}{x} \, dx+\frac {d \text {Subst}\left (\int \frac {a+b \coth ^{-1}(c x)}{x} \, dx,x,x^n\right )}{n} \\ & = a d \log (x)+\frac {a e \log ^2\left (f x^m\right )}{2 m}+\frac {b d \operatorname {PolyLog}\left (2,-\frac {x^{-n}}{c}\right )}{2 n}-\frac {b d \operatorname {PolyLog}\left (2,\frac {x^{-n}}{c}\right )}{2 n}-\frac {1}{2} (b e) \int \frac {\log \left (f x^m\right ) \log \left (1-\frac {x^{-n}}{c}\right )}{x} \, dx+\frac {1}{2} (b e) \int \frac {\log \left (f x^m\right ) \log \left (1+\frac {x^{-n}}{c}\right )}{x} \, dx \\ & = a d \log (x)+\frac {a e \log ^2\left (f x^m\right )}{2 m}+\frac {b d \operatorname {PolyLog}\left (2,-\frac {x^{-n}}{c}\right )}{2 n}+\frac {b e \log \left (f x^m\right ) \operatorname {PolyLog}\left (2,-\frac {x^{-n}}{c}\right )}{2 n}-\frac {b d \operatorname {PolyLog}\left (2,\frac {x^{-n}}{c}\right )}{2 n}-\frac {b e \log \left (f x^m\right ) \operatorname {PolyLog}\left (2,\frac {x^{-n}}{c}\right )}{2 n}-\frac {(b e m) \int \frac {\operatorname {PolyLog}\left (2,-\frac {x^{-n}}{c}\right )}{x} \, dx}{2 n}+\frac {(b e m) \int \frac {\operatorname {PolyLog}\left (2,\frac {x^{-n}}{c}\right )}{x} \, dx}{2 n} \\ & = a d \log (x)+\frac {a e \log ^2\left (f x^m\right )}{2 m}+\frac {b d \operatorname {PolyLog}\left (2,-\frac {x^{-n}}{c}\right )}{2 n}+\frac {b e \log \left (f x^m\right ) \operatorname {PolyLog}\left (2,-\frac {x^{-n}}{c}\right )}{2 n}-\frac {b d \operatorname {PolyLog}\left (2,\frac {x^{-n}}{c}\right )}{2 n}-\frac {b e \log \left (f x^m\right ) \operatorname {PolyLog}\left (2,\frac {x^{-n}}{c}\right )}{2 n}+\frac {b e m \operatorname {PolyLog}\left (3,-\frac {x^{-n}}{c}\right )}{2 n^2}-\frac {b e m \operatorname {PolyLog}\left (3,\frac {x^{-n}}{c}\right )}{2 n^2} \\ \end{align*}
Result contains higher order function than in optimal. Order 5 vs. order 4 in optimal.
Time = 0.22 (sec) , antiderivative size = 131, normalized size of antiderivative = 0.82 \[ \int \frac {\left (a+b \coth ^{-1}\left (c x^n\right )\right ) \left (d+e \log \left (f x^m\right )\right )}{x} \, dx=-\frac {b c e m x^n \, _4F_3\left (\frac {1}{2},\frac {1}{2},\frac {1}{2},1;\frac {3}{2},\frac {3}{2},\frac {3}{2};c^2 x^{2 n}\right )}{n^2}+\frac {b c x^n \, _3F_2\left (\frac {1}{2},\frac {1}{2},1;\frac {3}{2},\frac {3}{2};c^2 x^{2 n}\right ) \left (d+e \log \left (f x^m\right )\right )}{n}-\frac {1}{2} \left (a+b \coth ^{-1}\left (c x^n\right )-b \text {arctanh}\left (c x^n\right )\right ) \log (x) \left (e m \log (x)-2 \left (d+e \log \left (f x^m\right )\right )\right ) \]
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Result contains higher order function than in optimal. Order 9 vs. order 4.
Time = 146.70 (sec) , antiderivative size = 414, normalized size of antiderivative = 2.59
method | result | size |
risch | \(\frac {\left (-\frac {i e \pi \,\operatorname {csgn}\left (i f \right ) \operatorname {csgn}\left (i x^{m}\right ) \operatorname {csgn}\left (i f \,x^{m}\right )}{4}+\frac {i e \pi \,\operatorname {csgn}\left (i f \right ) \operatorname {csgn}\left (i f \,x^{m}\right )^{2}}{4}+\frac {i e \pi \,\operatorname {csgn}\left (i x^{m}\right ) \operatorname {csgn}\left (i f \,x^{m}\right )^{2}}{4}-\frac {i e \pi \operatorname {csgn}\left (i f \,x^{m}\right )^{3}}{4}+\frac {e \ln \left (f \right )}{2}+\frac {d}{2}\right ) \left (-b \operatorname {dilog}\left (c \,x^{n}+1\right )+2 a \ln \left (x^{n}\right )-\ln \left (c \,x^{n}\right ) \ln \left (c \,x^{n}-1\right ) b -\operatorname {dilog}\left (c \,x^{n}\right ) b \right )}{n}-\frac {e b m \ln \left (x \right ) \operatorname {polylog}\left (2, -c \,x^{n}\right )}{2 n}+\frac {b e m \operatorname {polylog}\left (3, -c \,x^{n}\right )}{2 n^{2}}+\frac {e b \operatorname {dilog}\left (c \,x^{n}+1\right ) m \ln \left (x \right )}{2 n}-\frac {e b \operatorname {dilog}\left (c \,x^{n}+1\right ) \ln \left (x^{m}\right )}{2 n}+\frac {e a \ln \left (x^{m}\right )^{2}}{2 m}+\frac {e b \ln \left (c \,x^{n}-1\right ) m \ln \left (x \right )^{2}}{4}-\frac {e b \ln \left (x \right ) \ln \left (x^{m}\right ) \ln \left (c \,x^{n}-1\right )}{2}-\frac {e b m \ln \left (x \right )^{2} \ln \left (1-c \,x^{n}\right )}{4}+\frac {e b m \ln \left (x \right ) \operatorname {polylog}\left (2, c \,x^{n}\right )}{2 n}-\frac {b e m \operatorname {polylog}\left (3, c \,x^{n}\right )}{2 n^{2}}+\frac {e b \ln \left (1-c \,x^{n}\right ) \ln \left (x \right ) \ln \left (x^{m}\right )}{2}+\frac {e b \ln \left (1-c \,x^{n}\right ) \ln \left (c \,x^{n}\right ) m \ln \left (x \right )}{2 n}-\frac {e b \ln \left (1-c \,x^{n}\right ) \ln \left (c \,x^{n}\right ) \ln \left (x^{m}\right )}{2 n}+\frac {e b \operatorname {dilog}\left (c \,x^{n}\right ) m \ln \left (x \right )}{2 n}-\frac {e b \operatorname {dilog}\left (c \,x^{n}\right ) \ln \left (x^{m}\right )}{2 n}\) | \(414\) |
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Leaf count of result is larger than twice the leaf count of optimal. 326 vs. \(2 (142) = 284\).
Time = 0.28 (sec) , antiderivative size = 326, normalized size of antiderivative = 2.04 \[ \int \frac {\left (a+b \coth ^{-1}\left (c x^n\right )\right ) \left (d+e \log \left (f x^m\right )\right )}{x} \, dx=\frac {2 \, a e m n^{2} \log \left (x\right )^{2} - 2 \, b e m {\rm polylog}\left (3, c \cosh \left (n \log \left (x\right )\right ) + c \sinh \left (n \log \left (x\right )\right )\right ) + 2 \, b e m {\rm polylog}\left (3, -c \cosh \left (n \log \left (x\right )\right ) - c \sinh \left (n \log \left (x\right )\right )\right ) + 2 \, {\left (b e m n \log \left (x\right ) + b e n \log \left (f\right ) + b d n\right )} {\rm Li}_2\left (c \cosh \left (n \log \left (x\right )\right ) + c \sinh \left (n \log \left (x\right )\right )\right ) - 2 \, {\left (b e m n \log \left (x\right ) + b e n \log \left (f\right ) + b d n\right )} {\rm Li}_2\left (-c \cosh \left (n \log \left (x\right )\right ) - c \sinh \left (n \log \left (x\right )\right )\right ) - {\left (b e m n^{2} \log \left (x\right )^{2} + 2 \, {\left (b e n^{2} \log \left (f\right ) + b d n^{2}\right )} \log \left (x\right )\right )} \log \left (c \cosh \left (n \log \left (x\right )\right ) + c \sinh \left (n \log \left (x\right )\right ) + 1\right ) + {\left (b e m n^{2} \log \left (x\right )^{2} + 2 \, {\left (b e n^{2} \log \left (f\right ) + b d n^{2}\right )} \log \left (x\right )\right )} \log \left (-c \cosh \left (n \log \left (x\right )\right ) - c \sinh \left (n \log \left (x\right )\right ) + 1\right ) + 4 \, {\left (a e n^{2} \log \left (f\right ) + a d n^{2}\right )} \log \left (x\right ) + {\left (b e m n^{2} \log \left (x\right )^{2} + 2 \, {\left (b e n^{2} \log \left (f\right ) + b d n^{2}\right )} \log \left (x\right )\right )} \log \left (\frac {c \cosh \left (n \log \left (x\right )\right ) + c \sinh \left (n \log \left (x\right )\right ) + 1}{c \cosh \left (n \log \left (x\right )\right ) + c \sinh \left (n \log \left (x\right )\right ) - 1}\right )}{4 \, n^{2}} \]
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\[ \int \frac {\left (a+b \coth ^{-1}\left (c x^n\right )\right ) \left (d+e \log \left (f x^m\right )\right )}{x} \, dx=\int \frac {\left (a + b \operatorname {acoth}{\left (c x^{n} \right )}\right ) \left (d + e \log {\left (f x^{m} \right )}\right )}{x}\, dx \]
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\[ \int \frac {\left (a+b \coth ^{-1}\left (c x^n\right )\right ) \left (d+e \log \left (f x^m\right )\right )}{x} \, dx=\int { \frac {{\left (b \operatorname {arcoth}\left (c x^{n}\right ) + a\right )} {\left (e \log \left (f x^{m}\right ) + d\right )}}{x} \,d x } \]
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\[ \int \frac {\left (a+b \coth ^{-1}\left (c x^n\right )\right ) \left (d+e \log \left (f x^m\right )\right )}{x} \, dx=\int { \frac {{\left (b \operatorname {arcoth}\left (c x^{n}\right ) + a\right )} {\left (e \log \left (f x^{m}\right ) + d\right )}}{x} \,d x } \]
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Timed out. \[ \int \frac {\left (a+b \coth ^{-1}\left (c x^n\right )\right ) \left (d+e \log \left (f x^m\right )\right )}{x} \, dx=\int \frac {\left (a+b\,\mathrm {acoth}\left (c\,x^n\right )\right )\,\left (d+e\,\ln \left (f\,x^m\right )\right )}{x} \,d x \]
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