Integrand size = 18, antiderivative size = 44 \[ \int e^{-2 \coth ^{-1}(a x)} (c-a c x)^p \, dx=\frac {(c-a c x)^{2+p} \operatorname {Hypergeometric2F1}\left (1,2+p,3+p,\frac {1}{2} (1-a x)\right )}{2 a c^2 (2+p)} \]
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Time = 0.05 (sec) , antiderivative size = 44, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.222, Rules used = {6302, 6265, 21, 70} \[ \int e^{-2 \coth ^{-1}(a x)} (c-a c x)^p \, dx=\frac {(c-a c x)^{p+2} \operatorname {Hypergeometric2F1}\left (1,p+2,p+3,\frac {1}{2} (1-a x)\right )}{2 a c^2 (p+2)} \]
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Rule 21
Rule 70
Rule 6265
Rule 6302
Rubi steps \begin{align*} \text {integral}& = -\int e^{-2 \text {arctanh}(a x)} (c-a c x)^p \, dx \\ & = -\int \frac {(1-a x) (c-a c x)^p}{1+a x} \, dx \\ & = -\frac {\int \frac {(c-a c x)^{1+p}}{1+a x} \, dx}{c} \\ & = \frac {(c-a c x)^{2+p} \operatorname {Hypergeometric2F1}\left (1,2+p,3+p,\frac {1}{2} (1-a x)\right )}{2 a c^2 (2+p)} \\ \end{align*}
Time = 0.02 (sec) , antiderivative size = 44, normalized size of antiderivative = 1.00 \[ \int e^{-2 \coth ^{-1}(a x)} (c-a c x)^p \, dx=-\frac {(-1+a x) (c-a c x)^p \left (-1+\operatorname {Hypergeometric2F1}\left (1,1+p,2+p,\frac {1}{2} (1-a x)\right )\right )}{a (1+p)} \]
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\[\int \frac {\left (-a c x +c \right )^{p} \left (a x -1\right )}{a x +1}d x\]
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\[ \int e^{-2 \coth ^{-1}(a x)} (c-a c x)^p \, dx=\int { \frac {{\left (a x - 1\right )} {\left (-a c x + c\right )}^{p}}{a x + 1} \,d x } \]
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\[ \int e^{-2 \coth ^{-1}(a x)} (c-a c x)^p \, dx=\int \frac {\left (- c \left (a x - 1\right )\right )^{p} \left (a x - 1\right )}{a x + 1}\, dx \]
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\[ \int e^{-2 \coth ^{-1}(a x)} (c-a c x)^p \, dx=\int { \frac {{\left (a x - 1\right )} {\left (-a c x + c\right )}^{p}}{a x + 1} \,d x } \]
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\[ \int e^{-2 \coth ^{-1}(a x)} (c-a c x)^p \, dx=\int { \frac {{\left (a x - 1\right )} {\left (-a c x + c\right )}^{p}}{a x + 1} \,d x } \]
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Timed out. \[ \int e^{-2 \coth ^{-1}(a x)} (c-a c x)^p \, dx=\int \frac {{\left (c-a\,c\,x\right )}^p\,\left (a\,x-1\right )}{a\,x+1} \,d x \]
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