\(\int e^{\coth ^{-1}(a x)} (c-a c x)^{7/2} \, dx\) [227]

Optimal result

Integrand size = 18, antiderivative size = 197 \[ \int e^{\coth ^{-1}(a x)} (c-a c x)^{7/2} \, dx=-\frac {8 \left (1+\frac {1}{a x}\right )^{3/2} (c-a c x)^{7/2}}{21 a \left (1-\frac {1}{a x}\right )^{7/2}}-\frac {568 \left (1+\frac {1}{a x}\right )^{3/2} (c-a c x)^{7/2}}{315 a^3 \left (1-\frac {1}{a x}\right )^{7/2} x^2}+\frac {48 \left (1+\frac {1}{a x}\right )^{3/2} (c-a c x)^{7/2}}{35 a^2 \left (1-\frac {1}{a x}\right )^{7/2} x}+\frac {2 \left (a-\frac {1}{x}\right )^3 \left (1+\frac {1}{a x}\right )^{3/2} x (c-a c x)^{7/2}}{9 a^3 \left (1-\frac {1}{a x}\right )^{7/2}} \]

[Out]

-8/21*(1+1/a/x)^(3/2)*(-a*c*x+c)^(7/2)/a/(1-1/a/x)^(7/2)-568/315*(1+1/a/x)^(3/2)*(-a*c*x+c)^(7/2)/a^3/(1-1/a/x
)^(7/2)/x^2+48/35*(1+1/a/x)^(3/2)*(-a*c*x+c)^(7/2)/a^2/(1-1/a/x)^(7/2)/x+2/9*(a-1/x)^3*(1+1/a/x)^(3/2)*x*(-a*c
*x+c)^(7/2)/a^3/(1-1/a/x)^(7/2)

Rubi [A] (verified)

Time = 0.14 (sec) , antiderivative size = 197, normalized size of antiderivative = 1.00, number of steps used = 6, number of rules used = 6, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.333, Rules used = {6311, 6316, 96, 91, 79, 37} \[ \int e^{\coth ^{-1}(a x)} (c-a c x)^{7/2} \, dx=-\frac {568 \left (\frac {1}{a x}+1\right )^{3/2} (c-a c x)^{7/2}}{315 a^3 x^2 \left (1-\frac {1}{a x}\right )^{7/2}}+\frac {2 x \left (a-\frac {1}{x}\right )^3 \left (\frac {1}{a x}+1\right )^{3/2} (c-a c x)^{7/2}}{9 a^3 \left (1-\frac {1}{a x}\right )^{7/2}}+\frac {48 \left (\frac {1}{a x}+1\right )^{3/2} (c-a c x)^{7/2}}{35 a^2 x \left (1-\frac {1}{a x}\right )^{7/2}}-\frac {8 \left (\frac {1}{a x}+1\right )^{3/2} (c-a c x)^{7/2}}{21 a \left (1-\frac {1}{a x}\right )^{7/2}} \]

[In]

Int[E^ArcCoth[a*x]*(c - a*c*x)^(7/2),x]

[Out]

(-8*(1 + 1/(a*x))^(3/2)*(c - a*c*x)^(7/2))/(21*a*(1 - 1/(a*x))^(7/2)) - (568*(1 + 1/(a*x))^(3/2)*(c - a*c*x)^(
7/2))/(315*a^3*(1 - 1/(a*x))^(7/2)*x^2) + (48*(1 + 1/(a*x))^(3/2)*(c - a*c*x)^(7/2))/(35*a^2*(1 - 1/(a*x))^(7/
2)*x) + (2*(a - x^(-1))^3*(1 + 1/(a*x))^(3/2)*x*(c - a*c*x)^(7/2))/(9*a^3*(1 - 1/(a*x))^(7/2))

Rule 37

Int[((a_.) + (b_.)*(x_))^(m_.)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> Simp[(a + b*x)^(m + 1)*((c + d*x)^(n +
1)/((b*c - a*d)*(m + 1))), x] /; FreeQ[{a, b, c, d, m, n}, x] && NeQ[b*c - a*d, 0] && EqQ[m + n + 2, 0] && NeQ
[m, -1]

Rule 79

Int[((a_.) + (b_.)*(x_))*((c_.) + (d_.)*(x_))^(n_.)*((e_.) + (f_.)*(x_))^(p_.), x_Symbol] :> Simp[(-(b*e - a*f
))*(c + d*x)^(n + 1)*((e + f*x)^(p + 1)/(f*(p + 1)*(c*f - d*e))), x] - Dist[(a*d*f*(n + p + 2) - b*(d*e*(n + 1
) + c*f*(p + 1)))/(f*(p + 1)*(c*f - d*e)), Int[(c + d*x)^n*(e + f*x)^(p + 1), x], x] /; FreeQ[{a, b, c, d, e,
f, n}, x] && LtQ[p, -1] && ( !LtQ[n, -1] || IntegerQ[p] ||  !(IntegerQ[n] ||  !(EqQ[e, 0] ||  !(EqQ[c, 0] || L
tQ[p, n]))))

Rule 91

Int[((a_.) + (b_.)*(x_))^2*((c_.) + (d_.)*(x_))^(n_.)*((e_.) + (f_.)*(x_))^(p_.), x_Symbol] :> Simp[(b*c - a*d
)^2*(c + d*x)^(n + 1)*((e + f*x)^(p + 1)/(d^2*(d*e - c*f)*(n + 1))), x] - Dist[1/(d^2*(d*e - c*f)*(n + 1)), In
t[(c + d*x)^(n + 1)*(e + f*x)^p*Simp[a^2*d^2*f*(n + p + 2) + b^2*c*(d*e*(n + 1) + c*f*(p + 1)) - 2*a*b*d*(d*e*
(n + 1) + c*f*(p + 1)) - b^2*d*(d*e - c*f)*(n + 1)*x, x], x], x] /; FreeQ[{a, b, c, d, e, f, n, p}, x] && (LtQ
[n, -1] || (EqQ[n + p + 3, 0] && NeQ[n, -1] && (SumSimplerQ[n, 1] ||  !SumSimplerQ[p, 1])))

Rule 96

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_.)*((e_.) + (f_.)*(x_))^(p_.), x_Symbol] :> Simp[(a + b*
x)^(m + 1)*(c + d*x)^n*((e + f*x)^(p + 1)/((m + 1)*(b*e - a*f))), x] - Dist[n*((d*e - c*f)/((m + 1)*(b*e - a*f
))), Int[(a + b*x)^(m + 1)*(c + d*x)^(n - 1)*(e + f*x)^p, x], x] /; FreeQ[{a, b, c, d, e, f, m, p}, x] && EqQ[
m + n + p + 2, 0] && GtQ[n, 0] && (SumSimplerQ[m, 1] ||  !SumSimplerQ[p, 1]) && NeQ[m, -1]

Rule 6311

Int[E^(ArcCoth[(a_.)*(x_)]*(n_.))*(u_.)*((c_) + (d_.)*(x_))^(p_), x_Symbol] :> Dist[(c + d*x)^p/(x^p*(1 + c/(d
*x))^p), Int[u*x^p*(1 + c/(d*x))^p*E^(n*ArcCoth[a*x]), x], x] /; FreeQ[{a, c, d, n, p}, x] && EqQ[a^2*c^2 - d^
2, 0] &&  !IntegerQ[n/2] &&  !IntegerQ[p]

Rule 6316

Int[E^(ArcCoth[(a_.)*(x_)]*(n_.))*((c_) + (d_.)/(x_))^(p_.)*(x_)^(m_), x_Symbol] :> Dist[(-c^p)*x^m*(1/x)^m, S
ubst[Int[(1 + d*(x/c))^p*((1 + x/a)^(n/2)/(x^(m + 2)*(1 - x/a)^(n/2))), x], x, 1/x], x] /; FreeQ[{a, c, d, m,
n, p}, x] && EqQ[c^2 - a^2*d^2, 0] &&  !IntegerQ[n/2] && (IntegerQ[p] || GtQ[c, 0]) &&  !IntegerQ[m]

Rubi steps \begin{align*} \text {integral}& = \frac {(c-a c x)^{7/2} \int e^{\coth ^{-1}(a x)} \left (1-\frac {1}{a x}\right )^{7/2} x^{7/2} \, dx}{\left (1-\frac {1}{a x}\right )^{7/2} x^{7/2}} \\ & = -\frac {\left (\left (\frac {1}{x}\right )^{7/2} (c-a c x)^{7/2}\right ) \text {Subst}\left (\int \frac {\left (1-\frac {x}{a}\right )^3 \sqrt {1+\frac {x}{a}}}{x^{11/2}} \, dx,x,\frac {1}{x}\right )}{\left (1-\frac {1}{a x}\right )^{7/2}} \\ & = \frac {2 \left (a-\frac {1}{x}\right )^3 \left (1+\frac {1}{a x}\right )^{3/2} x (c-a c x)^{7/2}}{9 a^3 \left (1-\frac {1}{a x}\right )^{7/2}}+\frac {\left (4 \left (\frac {1}{x}\right )^{7/2} (c-a c x)^{7/2}\right ) \text {Subst}\left (\int \frac {\left (1-\frac {x}{a}\right )^2 \sqrt {1+\frac {x}{a}}}{x^{9/2}} \, dx,x,\frac {1}{x}\right )}{3 a \left (1-\frac {1}{a x}\right )^{7/2}} \\ & = -\frac {8 \left (1+\frac {1}{a x}\right )^{3/2} (c-a c x)^{7/2}}{21 a \left (1-\frac {1}{a x}\right )^{7/2}}+\frac {2 \left (a-\frac {1}{x}\right )^3 \left (1+\frac {1}{a x}\right )^{3/2} x (c-a c x)^{7/2}}{9 a^3 \left (1-\frac {1}{a x}\right )^{7/2}}+\frac {\left (8 \left (\frac {1}{x}\right )^{7/2} (c-a c x)^{7/2}\right ) \text {Subst}\left (\int \frac {\left (-\frac {9}{a}+\frac {7 x}{2 a^2}\right ) \sqrt {1+\frac {x}{a}}}{x^{7/2}} \, dx,x,\frac {1}{x}\right )}{21 a \left (1-\frac {1}{a x}\right )^{7/2}} \\ & = -\frac {8 \left (1+\frac {1}{a x}\right )^{3/2} (c-a c x)^{7/2}}{21 a \left (1-\frac {1}{a x}\right )^{7/2}}+\frac {48 \left (1+\frac {1}{a x}\right )^{3/2} (c-a c x)^{7/2}}{35 a^2 \left (1-\frac {1}{a x}\right )^{7/2} x}+\frac {2 \left (a-\frac {1}{x}\right )^3 \left (1+\frac {1}{a x}\right )^{3/2} x (c-a c x)^{7/2}}{9 a^3 \left (1-\frac {1}{a x}\right )^{7/2}}+\frac {\left (284 \left (\frac {1}{x}\right )^{7/2} (c-a c x)^{7/2}\right ) \text {Subst}\left (\int \frac {\sqrt {1+\frac {x}{a}}}{x^{5/2}} \, dx,x,\frac {1}{x}\right )}{105 a^3 \left (1-\frac {1}{a x}\right )^{7/2}} \\ & = -\frac {8 \left (1+\frac {1}{a x}\right )^{3/2} (c-a c x)^{7/2}}{21 a \left (1-\frac {1}{a x}\right )^{7/2}}-\frac {568 \left (1+\frac {1}{a x}\right )^{3/2} (c-a c x)^{7/2}}{315 a^3 \left (1-\frac {1}{a x}\right )^{7/2} x^2}+\frac {48 \left (1+\frac {1}{a x}\right )^{3/2} (c-a c x)^{7/2}}{35 a^2 \left (1-\frac {1}{a x}\right )^{7/2} x}+\frac {2 \left (a-\frac {1}{x}\right )^3 \left (1+\frac {1}{a x}\right )^{3/2} x (c-a c x)^{7/2}}{9 a^3 \left (1-\frac {1}{a x}\right )^{7/2}} \\ \end{align*}

Mathematica [A] (verified)

Time = 0.06 (sec) , antiderivative size = 78, normalized size of antiderivative = 0.40 \[ \int e^{\coth ^{-1}(a x)} (c-a c x)^{7/2} \, dx=-\frac {2 c^3 \sqrt {1+\frac {1}{a x}} \sqrt {c-a c x} \left (-319+2 a x+156 a^2 x^2-130 a^3 x^3+35 a^4 x^4\right )}{315 a \sqrt {1-\frac {1}{a x}}} \]

[In]

Integrate[E^ArcCoth[a*x]*(c - a*c*x)^(7/2),x]

[Out]

(-2*c^3*Sqrt[1 + 1/(a*x)]*Sqrt[c - a*c*x]*(-319 + 2*a*x + 156*a^2*x^2 - 130*a^3*x^3 + 35*a^4*x^4))/(315*a*Sqrt
[1 - 1/(a*x)])

Maple [A] (verified)

Time = 0.42 (sec) , antiderivative size = 61, normalized size of antiderivative = 0.31

method	result	size
default	\(-\frac {2 \sqrt {-c \left (a x -1\right )}\, c^{3} \left (a x +1\right ) \left (35 a^{3} x^{3}-165 a^{2} x^{2}+321 a x -319\right )}{315 \sqrt {\frac {a x -1}{a x +1}}\, a}\)	\(61\)
gosper	\(\frac {2 \left (a x +1\right ) \left (35 a^{3} x^{3}-165 a^{2} x^{2}+321 a x -319\right ) \left (-a c x +c \right )^{\frac {7}{2}}}{315 a \left (a x -1\right )^{3} \sqrt {\frac {a x -1}{a x +1}}}\)	\(64\)
risch	\(\frac {2 c^{4} \left (a x -1\right ) \left (35 a^{4} x^{4}-130 a^{3} x^{3}+156 a^{2} x^{2}+2 a x -319\right )}{315 \sqrt {\frac {a x -1}{a x +1}}\, \sqrt {-c \left (a x -1\right )}\, a}\)	\(69\)

[In]

int(1/((a*x-1)/(a*x+1))^(1/2)*(-a*c*x+c)^(7/2),x,method=_RETURNVERBOSE)

[Out]

-2/315/((a*x-1)/(a*x+1))^(1/2)*(-c*(a*x-1))^(1/2)*c^3*(a*x+1)*(35*a^3*x^3-165*a^2*x^2+321*a*x-319)/a

Fricas [A] (verification not implemented)

none

Time = 0.24 (sec) , antiderivative size = 94, normalized size of antiderivative = 0.48 \[ \int e^{\coth ^{-1}(a x)} (c-a c x)^{7/2} \, dx=-\frac {2 \, {\left (35 \, a^{5} c^{3} x^{5} - 95 \, a^{4} c^{3} x^{4} + 26 \, a^{3} c^{3} x^{3} + 158 \, a^{2} c^{3} x^{2} - 317 \, a c^{3} x - 319 \, c^{3}\right )} \sqrt {-a c x + c} \sqrt {\frac {a x - 1}{a x + 1}}}{315 \, {\left (a^{2} x - a\right )}} \]

[In]

integrate(1/((a*x-1)/(a*x+1))^(1/2)*(-a*c*x+c)^(7/2),x, algorithm="fricas")

[Out]

-2/315*(35*a^5*c^3*x^5 - 95*a^4*c^3*x^4 + 26*a^3*c^3*x^3 + 158*a^2*c^3*x^2 - 317*a*c^3*x - 319*c^3)*sqrt(-a*c*
x + c)*sqrt((a*x - 1)/(a*x + 1))/(a^2*x - a)

Sympy [F(-1)]

Timed out. \[ \int e^{\coth ^{-1}(a x)} (c-a c x)^{7/2} \, dx=\text {Timed out} \]

[In]

integrate(1/((a*x-1)/(a*x+1))**(1/2)*(-a*c*x+c)**(7/2),x)

[Out]

Timed out

Maxima [A] (verification not implemented)

none

Time = 0.22 (sec) , antiderivative size = 83, normalized size of antiderivative = 0.42 \[ \int e^{\coth ^{-1}(a x)} (c-a c x)^{7/2} \, dx=-\frac {2 \, {\left (35 \, a^{4} \sqrt {-c} c^{3} x^{4} - 130 \, a^{3} \sqrt {-c} c^{3} x^{3} + 156 \, a^{2} \sqrt {-c} c^{3} x^{2} + 2 \, a \sqrt {-c} c^{3} x - 319 \, \sqrt {-c} c^{3}\right )} \sqrt {a x + 1}}{315 \, a} \]

[In]

integrate(1/((a*x-1)/(a*x+1))^(1/2)*(-a*c*x+c)^(7/2),x, algorithm="maxima")

[Out]

-2/315*(35*a^4*sqrt(-c)*c^3*x^4 - 130*a^3*sqrt(-c)*c^3*x^3 + 156*a^2*sqrt(-c)*c^3*x^2 + 2*a*sqrt(-c)*c^3*x - 3
19*sqrt(-c)*c^3)*sqrt(a*x + 1)/a

Giac [F(-2)]

Exception generated. \[ \int e^{\coth ^{-1}(a x)} (c-a c x)^{7/2} \, dx=\text {Exception raised: TypeError} \]

[In]

integrate(1/((a*x-1)/(a*x+1))^(1/2)*(-a*c*x+c)^(7/2),x, algorithm="giac")

[Out]

Exception raised: TypeError >> an error occurred running a Giac command:INPUT:sage2:=int(sage0,sageVARx):;OUTP
UT:sym2poly/r2sym(const gen & e,const index_m & i,const vecteur & l) Error: Bad Argument Value

Mupad [B] (verification not implemented)

Time = 4.45 (sec) , antiderivative size = 102, normalized size of antiderivative = 0.52 \[ \int e^{\coth ^{-1}(a x)} (c-a c x)^{7/2} \, dx=\frac {2\,c^3\,\sqrt {c-a\,c\,x}\,\sqrt {\frac {a\,x-1}{a\,x+1}}\,\left (-35\,a^4\,x^4+60\,a^3\,x^3+34\,a^2\,x^2-124\,a\,x+193\right )}{315\,a}+\frac {1024\,c^3\,\sqrt {c-a\,c\,x}\,\sqrt {\frac {a\,x-1}{a\,x+1}}}{315\,a\,\left (a\,x-1\right )} \]

[In]

int((c - a*c*x)^(7/2)/((a*x - 1)/(a*x + 1))^(1/2),x)

[Out]

(2*c^3*(c - a*c*x)^(1/2)*((a*x - 1)/(a*x + 1))^(1/2)*(34*a^2*x^2 - 124*a*x + 60*a^3*x^3 - 35*a^4*x^4 + 193))/(
315*a) + (1024*c^3*(c - a*c*x)^(1/2)*((a*x - 1)/(a*x + 1))^(1/2))/(315*a*(a*x - 1))