Integrand size = 12, antiderivative size = 33 \[ \int \frac {e^{\coth ^{-1}(x)}}{1-x} \, dx=\frac {2 \left (1+\frac {1}{x}\right )}{\sqrt {1-\frac {1}{x^2}}}-\text {arctanh}\left (\sqrt {1-\frac {1}{x^2}}\right ) \]
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Time = 0.09 (sec) , antiderivative size = 33, normalized size of antiderivative = 1.00, number of steps used = 7, number of rules used = 7, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.583, Rules used = {6310, 6313, 866, 1819, 272, 65, 212} \[ \int \frac {e^{\coth ^{-1}(x)}}{1-x} \, dx=\frac {2 \left (\frac {1}{x}+1\right )}{\sqrt {1-\frac {1}{x^2}}}-\text {arctanh}\left (\sqrt {1-\frac {1}{x^2}}\right ) \]
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Rule 65
Rule 212
Rule 272
Rule 866
Rule 1819
Rule 6310
Rule 6313
Rubi steps \begin{align*} \text {integral}& = -\int \frac {e^{\coth ^{-1}(x)}}{\left (1-\frac {1}{x}\right ) x} \, dx \\ & = \text {Subst}\left (\int \frac {\sqrt {1-x^2}}{(1-x)^2 x} \, dx,x,\frac {1}{x}\right ) \\ & = \text {Subst}\left (\int \frac {(1+x)^2}{x \left (1-x^2\right )^{3/2}} \, dx,x,\frac {1}{x}\right ) \\ & = \frac {2 \left (1+\frac {1}{x}\right )}{\sqrt {1-\frac {1}{x^2}}}+\text {Subst}\left (\int \frac {1}{x \sqrt {1-x^2}} \, dx,x,\frac {1}{x}\right ) \\ & = \frac {2 \left (1+\frac {1}{x}\right )}{\sqrt {1-\frac {1}{x^2}}}+\frac {1}{2} \text {Subst}\left (\int \frac {1}{\sqrt {1-x} x} \, dx,x,\frac {1}{x^2}\right ) \\ & = \frac {2 \left (1+\frac {1}{x}\right )}{\sqrt {1-\frac {1}{x^2}}}-\text {Subst}\left (\int \frac {1}{1-x^2} \, dx,x,\sqrt {1-\frac {1}{x^2}}\right ) \\ & = \frac {2 \left (1+\frac {1}{x}\right )}{\sqrt {1-\frac {1}{x^2}}}-\text {arctanh}\left (\sqrt {1-\frac {1}{x^2}}\right ) \\ \end{align*}
Time = 0.04 (sec) , antiderivative size = 38, normalized size of antiderivative = 1.15 \[ \int \frac {e^{\coth ^{-1}(x)}}{1-x} \, dx=\frac {2 \sqrt {1-\frac {1}{x^2}} x}{-1+x}-\log \left (\left (1+\sqrt {1-\frac {1}{x^2}}\right ) x\right ) \]
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Time = 0.46 (sec) , antiderivative size = 52, normalized size of antiderivative = 1.58
method | result | size |
risch | \(\frac {2}{\sqrt {\frac {x -1}{1+x}}}-\frac {\ln \left (x +\sqrt {x^{2}-1}\right ) \sqrt {\left (x -1\right ) \left (1+x \right )}}{\sqrt {\frac {x -1}{1+x}}\, \left (1+x \right )}\) | \(52\) |
trager | \(\frac {2 \left (1+x \right ) \sqrt {-\frac {1-x}{1+x}}}{x -1}+\ln \left (-\sqrt {-\frac {1-x}{1+x}}\, x -\sqrt {-\frac {1-x}{1+x}}+x \right )\) | \(62\) |
default | \(\frac {\left (x^{2}-1\right )^{\frac {3}{2}}-x^{2} \sqrt {x^{2}-1}-\ln \left (x +\sqrt {x^{2}-1}\right ) x^{2}+2 x \sqrt {x^{2}-1}+2 \ln \left (x +\sqrt {x^{2}-1}\right ) x -\sqrt {x^{2}-1}-\ln \left (x +\sqrt {x^{2}-1}\right )}{\left (x -1\right ) \sqrt {\left (x -1\right ) \left (1+x \right )}\, \sqrt {\frac {x -1}{1+x}}}\) | \(106\) |
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Leaf count of result is larger than twice the leaf count of optimal. 61 vs. \(2 (29) = 58\).
Time = 0.25 (sec) , antiderivative size = 61, normalized size of antiderivative = 1.85 \[ \int \frac {e^{\coth ^{-1}(x)}}{1-x} \, dx=-\frac {{\left (x - 1\right )} \log \left (\sqrt {\frac {x - 1}{x + 1}} + 1\right ) - {\left (x - 1\right )} \log \left (\sqrt {\frac {x - 1}{x + 1}} - 1\right ) - 2 \, {\left (x + 1\right )} \sqrt {\frac {x - 1}{x + 1}}}{x - 1} \]
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\[ \int \frac {e^{\coth ^{-1}(x)}}{1-x} \, dx=- \int \frac {1}{x \sqrt {\frac {x}{x + 1} - \frac {1}{x + 1}} - \sqrt {\frac {x}{x + 1} - \frac {1}{x + 1}}}\, dx \]
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none
Time = 0.26 (sec) , antiderivative size = 44, normalized size of antiderivative = 1.33 \[ \int \frac {e^{\coth ^{-1}(x)}}{1-x} \, dx=\frac {2}{\sqrt {\frac {x - 1}{x + 1}}} - \log \left (\sqrt {\frac {x - 1}{x + 1}} + 1\right ) + \log \left (\sqrt {\frac {x - 1}{x + 1}} - 1\right ) \]
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none
Time = 0.27 (sec) , antiderivative size = 49, normalized size of antiderivative = 1.48 \[ \int \frac {e^{\coth ^{-1}(x)}}{1-x} \, dx=\frac {\log \left ({\left | -x + \sqrt {x^{2} - 1} \right |}\right )}{\mathrm {sgn}\left (x + 1\right )} - \frac {4}{{\left (x - \sqrt {x^{2} - 1} - 1\right )} \mathrm {sgn}\left (x + 1\right )} - 2 \, \mathrm {sgn}\left (x + 1\right ) \]
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Time = 4.25 (sec) , antiderivative size = 28, normalized size of antiderivative = 0.85 \[ \int \frac {e^{\coth ^{-1}(x)}}{1-x} \, dx=\frac {2}{\sqrt {\frac {x-1}{x+1}}}-2\,\mathrm {atanh}\left (\sqrt {\frac {x-1}{x+1}}\right ) \]
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