Integrand size = 20, antiderivative size = 96 \[ \int \frac {e^{n \coth ^{-1}(a x)}}{\sqrt {c-a c x}} \, dx=\frac {2 \left (\frac {a-\frac {1}{x}}{a+\frac {1}{x}}\right )^{\frac {1+n}{2}} \left (1-\frac {1}{a x}\right )^{-n/2} \left (1+\frac {1}{a x}\right )^{\frac {2+n}{2}} x \operatorname {Hypergeometric2F1}\left (-\frac {1}{2},\frac {1+n}{2},\frac {1}{2},\frac {2}{\left (a+\frac {1}{x}\right ) x}\right )}{\sqrt {c-a c x}} \]
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Time = 0.14 (sec) , antiderivative size = 96, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.150, Rules used = {6311, 6316, 134} \[ \int \frac {e^{n \coth ^{-1}(a x)}}{\sqrt {c-a c x}} \, dx=\frac {2 x \left (\frac {a-\frac {1}{x}}{a+\frac {1}{x}}\right )^{\frac {n+1}{2}} \left (1-\frac {1}{a x}\right )^{-n/2} \left (\frac {1}{a x}+1\right )^{\frac {n+2}{2}} \operatorname {Hypergeometric2F1}\left (-\frac {1}{2},\frac {n+1}{2},\frac {1}{2},\frac {2}{\left (a+\frac {1}{x}\right ) x}\right )}{\sqrt {c-a c x}} \]
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Rule 134
Rule 6311
Rule 6316
Rubi steps \begin{align*} \text {integral}& = \frac {\left (\sqrt {1-\frac {1}{a x}} \sqrt {x}\right ) \int \frac {e^{n \coth ^{-1}(a x)}}{\sqrt {1-\frac {1}{a x}} \sqrt {x}} \, dx}{\sqrt {c-a c x}} \\ & = -\frac {\sqrt {1-\frac {1}{a x}} \text {Subst}\left (\int \frac {\left (1-\frac {x}{a}\right )^{-\frac {1}{2}-\frac {n}{2}} \left (1+\frac {x}{a}\right )^{n/2}}{x^{3/2}} \, dx,x,\frac {1}{x}\right )}{\sqrt {\frac {1}{x}} \sqrt {c-a c x}} \\ & = \frac {2 \left (\frac {a-\frac {1}{x}}{a+\frac {1}{x}}\right )^{\frac {1+n}{2}} \left (1-\frac {1}{a x}\right )^{-n/2} \left (1+\frac {1}{a x}\right )^{\frac {2+n}{2}} x \operatorname {Hypergeometric2F1}\left (-\frac {1}{2},\frac {1+n}{2},\frac {1}{2},\frac {2}{\left (a+\frac {1}{x}\right ) x}\right )}{\sqrt {c-a c x}} \\ \end{align*}
Time = 0.07 (sec) , antiderivative size = 96, normalized size of antiderivative = 1.00 \[ \int \frac {e^{n \coth ^{-1}(a x)}}{\sqrt {c-a c x}} \, dx=\frac {2 \left (1-\frac {1}{a x}\right )^{-n/2} \left (1+\frac {1}{a x}\right )^{n/2} \left (\frac {-1+a x}{1+a x}\right )^{\frac {1+n}{2}} (1+a x) \operatorname {Hypergeometric2F1}\left (-\frac {1}{2},\frac {1+n}{2},\frac {1}{2},\frac {2}{1+a x}\right )}{a \sqrt {c-a c x}} \]
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\[\int \frac {{\mathrm e}^{n \,\operatorname {arccoth}\left (a x \right )}}{\sqrt {-a c x +c}}d x\]
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\[ \int \frac {e^{n \coth ^{-1}(a x)}}{\sqrt {c-a c x}} \, dx=\int { \frac {\left (\frac {a x + 1}{a x - 1}\right )^{\frac {1}{2} \, n}}{\sqrt {-a c x + c}} \,d x } \]
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\[ \int \frac {e^{n \coth ^{-1}(a x)}}{\sqrt {c-a c x}} \, dx=\int \frac {e^{n \operatorname {acoth}{\left (a x \right )}}}{\sqrt {- c \left (a x - 1\right )}}\, dx \]
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\[ \int \frac {e^{n \coth ^{-1}(a x)}}{\sqrt {c-a c x}} \, dx=\int { \frac {\left (\frac {a x + 1}{a x - 1}\right )^{\frac {1}{2} \, n}}{\sqrt {-a c x + c}} \,d x } \]
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\[ \int \frac {e^{n \coth ^{-1}(a x)}}{\sqrt {c-a c x}} \, dx=\int { \frac {\left (\frac {a x + 1}{a x - 1}\right )^{\frac {1}{2} \, n}}{\sqrt {-a c x + c}} \,d x } \]
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Timed out. \[ \int \frac {e^{n \coth ^{-1}(a x)}}{\sqrt {c-a c x}} \, dx=\int \frac {{\mathrm {e}}^{n\,\mathrm {acoth}\left (a\,x\right )}}{\sqrt {c-a\,c\,x}} \,d x \]
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