Integrand size = 27, antiderivative size = 105 \[ \int e^{2 \coth ^{-1}(a x)} \sqrt {c-\frac {c}{a x}} x^2 \, dx=\frac {11 \sqrt {c-\frac {c}{a x}} x}{8 a^2}+\frac {11 \sqrt {c-\frac {c}{a x}} x^2}{12 a}+\frac {1}{3} \sqrt {c-\frac {c}{a x}} x^3+\frac {11 \sqrt {c} \text {arctanh}\left (\frac {\sqrt {c-\frac {c}{a x}}}{\sqrt {c}}\right )}{8 a^3} \]
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Time = 0.26 (sec) , antiderivative size = 105, normalized size of antiderivative = 1.00, number of steps used = 10, number of rules used = 9, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.333, Rules used = {6302, 6268, 25, 528, 457, 79, 44, 65, 214} \[ \int e^{2 \coth ^{-1}(a x)} \sqrt {c-\frac {c}{a x}} x^2 \, dx=\frac {11 \sqrt {c} \text {arctanh}\left (\frac {\sqrt {c-\frac {c}{a x}}}{\sqrt {c}}\right )}{8 a^3}+\frac {11 x \sqrt {c-\frac {c}{a x}}}{8 a^2}+\frac {1}{3} x^3 \sqrt {c-\frac {c}{a x}}+\frac {11 x^2 \sqrt {c-\frac {c}{a x}}}{12 a} \]
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Rule 25
Rule 44
Rule 65
Rule 79
Rule 214
Rule 457
Rule 528
Rule 6268
Rule 6302
Rubi steps \begin{align*} \text {integral}& = -\int e^{2 \text {arctanh}(a x)} \sqrt {c-\frac {c}{a x}} x^2 \, dx \\ & = -\int \frac {\sqrt {c-\frac {c}{a x}} x^2 (1+a x)}{1-a x} \, dx \\ & = \frac {c \int \frac {x (1+a x)}{\sqrt {c-\frac {c}{a x}}} \, dx}{a} \\ & = \frac {c \int \frac {\left (a+\frac {1}{x}\right ) x^2}{\sqrt {c-\frac {c}{a x}}} \, dx}{a} \\ & = -\frac {c \text {Subst}\left (\int \frac {a+x}{x^4 \sqrt {c-\frac {c x}{a}}} \, dx,x,\frac {1}{x}\right )}{a} \\ & = \frac {1}{3} \sqrt {c-\frac {c}{a x}} x^3-\frac {(11 c) \text {Subst}\left (\int \frac {1}{x^3 \sqrt {c-\frac {c x}{a}}} \, dx,x,\frac {1}{x}\right )}{6 a} \\ & = \frac {11 \sqrt {c-\frac {c}{a x}} x^2}{12 a}+\frac {1}{3} \sqrt {c-\frac {c}{a x}} x^3-\frac {(11 c) \text {Subst}\left (\int \frac {1}{x^2 \sqrt {c-\frac {c x}{a}}} \, dx,x,\frac {1}{x}\right )}{8 a^2} \\ & = \frac {11 \sqrt {c-\frac {c}{a x}} x}{8 a^2}+\frac {11 \sqrt {c-\frac {c}{a x}} x^2}{12 a}+\frac {1}{3} \sqrt {c-\frac {c}{a x}} x^3-\frac {(11 c) \text {Subst}\left (\int \frac {1}{x \sqrt {c-\frac {c x}{a}}} \, dx,x,\frac {1}{x}\right )}{16 a^3} \\ & = \frac {11 \sqrt {c-\frac {c}{a x}} x}{8 a^2}+\frac {11 \sqrt {c-\frac {c}{a x}} x^2}{12 a}+\frac {1}{3} \sqrt {c-\frac {c}{a x}} x^3+\frac {11 \text {Subst}\left (\int \frac {1}{a-\frac {a x^2}{c}} \, dx,x,\sqrt {c-\frac {c}{a x}}\right )}{8 a^2} \\ & = \frac {11 \sqrt {c-\frac {c}{a x}} x}{8 a^2}+\frac {11 \sqrt {c-\frac {c}{a x}} x^2}{12 a}+\frac {1}{3} \sqrt {c-\frac {c}{a x}} x^3+\frac {11 \sqrt {c} \text {arctanh}\left (\frac {\sqrt {c-\frac {c}{a x}}}{\sqrt {c}}\right )}{8 a^3} \\ \end{align*}
Result contains higher order function than in optimal. Order 5 vs. order 3 in optimal.
Time = 0.04 (sec) , antiderivative size = 50, normalized size of antiderivative = 0.48 \[ \int e^{2 \coth ^{-1}(a x)} \sqrt {c-\frac {c}{a x}} x^2 \, dx=\frac {\sqrt {c-\frac {c}{a x}} \left (a^3 x^3+11 \operatorname {Hypergeometric2F1}\left (\frac {1}{2},3,\frac {3}{2},1-\frac {1}{a x}\right )\right )}{3 a^3} \]
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Time = 0.50 (sec) , antiderivative size = 119, normalized size of antiderivative = 1.13
method | result | size |
risch | \(\frac {\left (8 a^{2} x^{2}+22 a x +33\right ) x \sqrt {\frac {c \left (a x -1\right )}{a x}}}{24 a^{2}}+\frac {11 \ln \left (\frac {-\frac {1}{2} a c +a^{2} c x}{\sqrt {a^{2} c}}+\sqrt {a^{2} c \,x^{2}-a c x}\right ) \sqrt {\frac {c \left (a x -1\right )}{a x}}\, \sqrt {c \left (a x -1\right ) a x}}{16 a^{2} \sqrt {a^{2} c}\, \left (a x -1\right )}\) | \(119\) |
default | \(\frac {\sqrt {\frac {c \left (a x -1\right )}{a x}}\, x \left (16 \left (a \,x^{2}-x \right )^{\frac {3}{2}} a^{\frac {5}{2}}+60 \sqrt {a \,x^{2}-x}\, a^{\frac {5}{2}} x -30 \sqrt {a \,x^{2}-x}\, a^{\frac {3}{2}}+96 a^{\frac {3}{2}} \sqrt {\left (a x -1\right ) x}+48 a \ln \left (\frac {2 \sqrt {\left (a x -1\right ) x}\, \sqrt {a}+2 a x -1}{2 \sqrt {a}}\right )-15 \ln \left (\frac {2 \sqrt {a \,x^{2}-x}\, \sqrt {a}+2 a x -1}{2 \sqrt {a}}\right ) a \right )}{48 \sqrt {\left (a x -1\right ) x}\, a^{\frac {7}{2}}}\) | \(155\) |
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Time = 0.25 (sec) , antiderivative size = 163, normalized size of antiderivative = 1.55 \[ \int e^{2 \coth ^{-1}(a x)} \sqrt {c-\frac {c}{a x}} x^2 \, dx=\left [\frac {2 \, {\left (8 \, a^{3} x^{3} + 22 \, a^{2} x^{2} + 33 \, a x\right )} \sqrt {\frac {a c x - c}{a x}} + 33 \, \sqrt {c} \log \left (-2 \, a c x - 2 \, a \sqrt {c} x \sqrt {\frac {a c x - c}{a x}} + c\right )}{48 \, a^{3}}, \frac {{\left (8 \, a^{3} x^{3} + 22 \, a^{2} x^{2} + 33 \, a x\right )} \sqrt {\frac {a c x - c}{a x}} - 33 \, \sqrt {-c} \arctan \left (\frac {\sqrt {-c} \sqrt {\frac {a c x - c}{a x}}}{c}\right )}{24 \, a^{3}}\right ] \]
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\[ \int e^{2 \coth ^{-1}(a x)} \sqrt {c-\frac {c}{a x}} x^2 \, dx=\int \frac {x^{2} \sqrt {- c \left (-1 + \frac {1}{a x}\right )} \left (a x + 1\right )}{a x - 1}\, dx \]
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\[ \int e^{2 \coth ^{-1}(a x)} \sqrt {c-\frac {c}{a x}} x^2 \, dx=\int { \frac {{\left (a x + 1\right )} \sqrt {c - \frac {c}{a x}} x^{2}}{a x - 1} \,d x } \]
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Time = 0.30 (sec) , antiderivative size = 127, normalized size of antiderivative = 1.21 \[ \int e^{2 \coth ^{-1}(a x)} \sqrt {c-\frac {c}{a x}} x^2 \, dx=\frac {1}{24} \, \sqrt {a^{2} c x^{2} - a c x} {\left (2 \, x {\left (\frac {4 \, x {\left | a \right |}}{a^{2} \mathrm {sgn}\left (x\right )} + \frac {11 \, {\left | a \right |}}{a^{3} \mathrm {sgn}\left (x\right )}\right )} + \frac {33 \, {\left | a \right |}}{a^{4} \mathrm {sgn}\left (x\right )}\right )} + \frac {11 \, \sqrt {c} \log \left ({\left | a \right |} {\left | c \right |}\right ) \mathrm {sgn}\left (x\right )}{16 \, a^{3}} - \frac {11 \, \sqrt {c} \log \left ({\left | -2 \, {\left (\sqrt {a^{2} c} x - \sqrt {a^{2} c x^{2} - a c x}\right )} \sqrt {c} {\left | a \right |} + a c \right |}\right )}{16 \, a^{3} \mathrm {sgn}\left (x\right )} \]
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Timed out. \[ \int e^{2 \coth ^{-1}(a x)} \sqrt {c-\frac {c}{a x}} x^2 \, dx=\int \frac {x^2\,\sqrt {c-\frac {c}{a\,x}}\,\left (a\,x+1\right )}{a\,x-1} \,d x \]
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