Integrand size = 24, antiderivative size = 172 \[ \int \frac {e^{-\coth ^{-1}(a x)}}{\left (c-\frac {c}{a^2 x^2}\right )^{3/2}} \, dx=\frac {\sqrt {1-\frac {1}{a^2 x^2}} x}{c \sqrt {c-\frac {c}{a^2 x^2}}}-\frac {\sqrt {1-\frac {1}{a^2 x^2}}}{2 a c \sqrt {c-\frac {c}{a^2 x^2}} (1+a x)}+\frac {\sqrt {1-\frac {1}{a^2 x^2}} \log (1-a x)}{4 a c \sqrt {c-\frac {c}{a^2 x^2}}}-\frac {5 \sqrt {1-\frac {1}{a^2 x^2}} \log (1+a x)}{4 a c \sqrt {c-\frac {c}{a^2 x^2}}} \]
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Time = 0.11 (sec) , antiderivative size = 172, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.125, Rules used = {6332, 6328, 90} \[ \int \frac {e^{-\coth ^{-1}(a x)}}{\left (c-\frac {c}{a^2 x^2}\right )^{3/2}} \, dx=\frac {x \sqrt {1-\frac {1}{a^2 x^2}}}{c \sqrt {c-\frac {c}{a^2 x^2}}}-\frac {\sqrt {1-\frac {1}{a^2 x^2}}}{2 a c (a x+1) \sqrt {c-\frac {c}{a^2 x^2}}}+\frac {\sqrt {1-\frac {1}{a^2 x^2}} \log (1-a x)}{4 a c \sqrt {c-\frac {c}{a^2 x^2}}}-\frac {5 \sqrt {1-\frac {1}{a^2 x^2}} \log (a x+1)}{4 a c \sqrt {c-\frac {c}{a^2 x^2}}} \]
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Rule 90
Rule 6328
Rule 6332
Rubi steps \begin{align*} \text {integral}& = \frac {\sqrt {1-\frac {1}{a^2 x^2}} \int \frac {e^{-\coth ^{-1}(a x)}}{\left (1-\frac {1}{a^2 x^2}\right )^{3/2}} \, dx}{c \sqrt {c-\frac {c}{a^2 x^2}}} \\ & = \frac {\left (a^3 \sqrt {1-\frac {1}{a^2 x^2}}\right ) \int \frac {x^3}{(-1+a x) (1+a x)^2} \, dx}{c \sqrt {c-\frac {c}{a^2 x^2}}} \\ & = \frac {\left (a^3 \sqrt {1-\frac {1}{a^2 x^2}}\right ) \int \left (\frac {1}{a^3}+\frac {1}{4 a^3 (-1+a x)}+\frac {1}{2 a^3 (1+a x)^2}-\frac {5}{4 a^3 (1+a x)}\right ) \, dx}{c \sqrt {c-\frac {c}{a^2 x^2}}} \\ & = \frac {\sqrt {1-\frac {1}{a^2 x^2}} x}{c \sqrt {c-\frac {c}{a^2 x^2}}}-\frac {\sqrt {1-\frac {1}{a^2 x^2}}}{2 a c \sqrt {c-\frac {c}{a^2 x^2}} (1+a x)}+\frac {\sqrt {1-\frac {1}{a^2 x^2}} \log (1-a x)}{4 a c \sqrt {c-\frac {c}{a^2 x^2}}}-\frac {5 \sqrt {1-\frac {1}{a^2 x^2}} \log (1+a x)}{4 a c \sqrt {c-\frac {c}{a^2 x^2}}} \\ \end{align*}
Time = 0.08 (sec) , antiderivative size = 70, normalized size of antiderivative = 0.41 \[ \int \frac {e^{-\coth ^{-1}(a x)}}{\left (c-\frac {c}{a^2 x^2}\right )^{3/2}} \, dx=\frac {\left (1-\frac {1}{a^2 x^2}\right )^{3/2} \left (4 x-\frac {2}{a+a^2 x}+\frac {\log (1-a x)}{a}-\frac {5 \log (1+a x)}{a}\right )}{4 \left (c-\frac {c}{a^2 x^2}\right )^{3/2}} \]
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Time = 0.05 (sec) , antiderivative size = 103, normalized size of antiderivative = 0.60
method | result | size |
default | \(-\frac {\sqrt {\frac {a x -1}{a x +1}}\, \left (a x +1\right ) \left (-4 a^{2} x^{2}+5 a \ln \left (a x +1\right ) x -a \ln \left (a x -1\right ) x -4 a x +5 \ln \left (a x +1\right )-\ln \left (a x -1\right )+2\right ) \left (a x -1\right )}{4 a^{4} x^{3} {\left (\frac {c \left (a^{2} x^{2}-1\right )}{a^{2} x^{2}}\right )}^{\frac {3}{2}}}\) | \(103\) |
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Time = 0.27 (sec) , antiderivative size = 66, normalized size of antiderivative = 0.38 \[ \int \frac {e^{-\coth ^{-1}(a x)}}{\left (c-\frac {c}{a^2 x^2}\right )^{3/2}} \, dx=\frac {{\left (4 \, a^{2} x^{2} + 4 \, a x - 5 \, {\left (a x + 1\right )} \log \left (a x + 1\right ) + {\left (a x + 1\right )} \log \left (a x - 1\right ) - 2\right )} \sqrt {a^{2} c}}{4 \, {\left (a^{3} c^{2} x + a^{2} c^{2}\right )}} \]
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Timed out. \[ \int \frac {e^{-\coth ^{-1}(a x)}}{\left (c-\frac {c}{a^2 x^2}\right )^{3/2}} \, dx=\text {Timed out} \]
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\[ \int \frac {e^{-\coth ^{-1}(a x)}}{\left (c-\frac {c}{a^2 x^2}\right )^{3/2}} \, dx=\int { \frac {\sqrt {\frac {a x - 1}{a x + 1}}}{{\left (c - \frac {c}{a^{2} x^{2}}\right )}^{\frac {3}{2}}} \,d x } \]
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Exception generated. \[ \int \frac {e^{-\coth ^{-1}(a x)}}{\left (c-\frac {c}{a^2 x^2}\right )^{3/2}} \, dx=\text {Exception raised: TypeError} \]
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Timed out. \[ \int \frac {e^{-\coth ^{-1}(a x)}}{\left (c-\frac {c}{a^2 x^2}\right )^{3/2}} \, dx=\int \frac {\sqrt {\frac {a\,x-1}{a\,x+1}}}{{\left (c-\frac {c}{a^2\,x^2}\right )}^{3/2}} \,d x \]
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