Integrand size = 12, antiderivative size = 118 \[ \int \frac {e^{\text {sech}^{-1}\left (a x^2\right )}}{x^3} \, dx=\frac {1}{4 a x^4}-\frac {e^{\text {sech}^{-1}\left (a x^2\right )}}{2 x^2}+\frac {\sqrt {\frac {1}{1+a x^2}} \sqrt {1+a x^2} \sqrt {1-a^2 x^4}}{4 a x^4}+\frac {1}{4} a \sqrt {\frac {1}{1+a x^2}} \sqrt {1+a x^2} \text {arctanh}\left (\sqrt {1-a^2 x^4}\right ) \]
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Time = 0.04 (sec) , antiderivative size = 118, normalized size of antiderivative = 1.00, number of steps used = 7, number of rules used = 7, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.583, Rules used = {6470, 30, 265, 272, 44, 65, 214} \[ \int \frac {e^{\text {sech}^{-1}\left (a x^2\right )}}{x^3} \, dx=\frac {1}{4} a \sqrt {\frac {1}{a x^2+1}} \sqrt {a x^2+1} \text {arctanh}\left (\sqrt {1-a^2 x^4}\right )+\frac {\sqrt {\frac {1}{a x^2+1}} \sqrt {a x^2+1} \sqrt {1-a^2 x^4}}{4 a x^4}+\frac {1}{4 a x^4}-\frac {e^{\text {sech}^{-1}\left (a x^2\right )}}{2 x^2} \]
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Rule 30
Rule 44
Rule 65
Rule 214
Rule 265
Rule 272
Rule 6470
Rubi steps \begin{align*} \text {integral}& = -\frac {e^{\text {sech}^{-1}\left (a x^2\right )}}{2 x^2}-\frac {\int \frac {1}{x^5} \, dx}{a}-\frac {\left (\sqrt {\frac {1}{1+a x^2}} \sqrt {1+a x^2}\right ) \int \frac {1}{x^5 \sqrt {1-a x^2} \sqrt {1+a x^2}} \, dx}{a} \\ & = \frac {1}{4 a x^4}-\frac {e^{\text {sech}^{-1}\left (a x^2\right )}}{2 x^2}-\frac {\left (\sqrt {\frac {1}{1+a x^2}} \sqrt {1+a x^2}\right ) \int \frac {1}{x^5 \sqrt {1-a^2 x^4}} \, dx}{a} \\ & = \frac {1}{4 a x^4}-\frac {e^{\text {sech}^{-1}\left (a x^2\right )}}{2 x^2}-\frac {\left (\sqrt {\frac {1}{1+a x^2}} \sqrt {1+a x^2}\right ) \text {Subst}\left (\int \frac {1}{x^2 \sqrt {1-a^2 x}} \, dx,x,x^4\right )}{4 a} \\ & = \frac {1}{4 a x^4}-\frac {e^{\text {sech}^{-1}\left (a x^2\right )}}{2 x^2}+\frac {\sqrt {\frac {1}{1+a x^2}} \sqrt {1+a x^2} \sqrt {1-a^2 x^4}}{4 a x^4}-\frac {1}{8} \left (a \sqrt {\frac {1}{1+a x^2}} \sqrt {1+a x^2}\right ) \text {Subst}\left (\int \frac {1}{x \sqrt {1-a^2 x}} \, dx,x,x^4\right ) \\ & = \frac {1}{4 a x^4}-\frac {e^{\text {sech}^{-1}\left (a x^2\right )}}{2 x^2}+\frac {\sqrt {\frac {1}{1+a x^2}} \sqrt {1+a x^2} \sqrt {1-a^2 x^4}}{4 a x^4}+\frac {\left (\sqrt {\frac {1}{1+a x^2}} \sqrt {1+a x^2}\right ) \text {Subst}\left (\int \frac {1}{\frac {1}{a^2}-\frac {x^2}{a^2}} \, dx,x,\sqrt {1-a^2 x^4}\right )}{4 a} \\ & = \frac {1}{4 a x^4}-\frac {e^{\text {sech}^{-1}\left (a x^2\right )}}{2 x^2}+\frac {\sqrt {\frac {1}{1+a x^2}} \sqrt {1+a x^2} \sqrt {1-a^2 x^4}}{4 a x^4}+\frac {1}{4} a \sqrt {\frac {1}{1+a x^2}} \sqrt {1+a x^2} \text {arctanh}\left (\sqrt {1-a^2 x^4}\right ) \\ \end{align*}
Time = 0.40 (sec) , antiderivative size = 105, normalized size of antiderivative = 0.89 \[ \int \frac {e^{\text {sech}^{-1}\left (a x^2\right )}}{x^3} \, dx=-\frac {\frac {1}{x^4}+\frac {\sqrt {\frac {1-a x^2}{1+a x^2}} \left (1+a x^2\right )}{x^4}-\frac {a^2 \sqrt {\frac {1-a x^2}{1+a x^2}} \left (1+a x^2\right ) \arctan \left (\sqrt {-1+a^2 x^4}\right )}{\sqrt {-1+a^2 x^4}}}{4 a} \]
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Result contains higher order function than in optimal. Order 9 vs. order 3.
Time = 0.10 (sec) , antiderivative size = 129, normalized size of antiderivative = 1.09
method | result | size |
default | \(\frac {\sqrt {-\frac {a \,x^{2}-1}{a \,x^{2}}}\, \sqrt {\frac {a \,x^{2}+1}{a \,x^{2}}}\, \left (\ln \left (\frac {2 \,\operatorname {csgn}\left (\frac {1}{a}\right ) a \sqrt {-\frac {x^{4} a^{2}-1}{a^{2}}}+2}{a^{2} x^{2}}\right ) x^{4} a -\sqrt {-\frac {x^{4} a^{2}-1}{a^{2}}}\, \operatorname {csgn}\left (\frac {1}{a}\right )\right ) \operatorname {csgn}\left (\frac {1}{a}\right )}{4 x^{2} \sqrt {-\frac {x^{4} a^{2}-1}{a^{2}}}}-\frac {1}{4 a \,x^{4}}\) | \(129\) |
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Time = 0.26 (sec) , antiderivative size = 146, normalized size of antiderivative = 1.24 \[ \int \frac {e^{\text {sech}^{-1}\left (a x^2\right )}}{x^3} \, dx=\frac {a^{2} x^{4} \log \left (a x^{2} \sqrt {\frac {a x^{2} + 1}{a x^{2}}} \sqrt {-\frac {a x^{2} - 1}{a x^{2}}} + 1\right ) - a^{2} x^{4} \log \left (a x^{2} \sqrt {\frac {a x^{2} + 1}{a x^{2}}} \sqrt {-\frac {a x^{2} - 1}{a x^{2}}} - 1\right ) - 2 \, a x^{2} \sqrt {\frac {a x^{2} + 1}{a x^{2}}} \sqrt {-\frac {a x^{2} - 1}{a x^{2}}} - 2}{8 \, a x^{4}} \]
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Time = 4.07 (sec) , antiderivative size = 82, normalized size of antiderivative = 0.69 \[ \int \frac {e^{\text {sech}^{-1}\left (a x^2\right )}}{x^3} \, dx=- \frac {a \left (2 \sqrt {-1 + \frac {1}{a x^{2}}} \left (\frac {\left (1 + \frac {1}{a x^{2}}\right )^{\frac {3}{2}}}{4} - \frac {\sqrt {1 + \frac {1}{a x^{2}}}}{4}\right ) - \log {\left (2 \sqrt {-1 + \frac {1}{a x^{2}}} + 2 \sqrt {1 + \frac {1}{a x^{2}}} \right )}\right )}{2} - \frac {1}{4 a x^{4}} \]
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\[ \int \frac {e^{\text {sech}^{-1}\left (a x^2\right )}}{x^3} \, dx=\int { \frac {\sqrt {\frac {1}{a x^{2}} + 1} \sqrt {\frac {1}{a x^{2}} - 1} + \frac {1}{a x^{2}}}{x^{3}} \,d x } \]
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Exception generated. \[ \int \frac {e^{\text {sech}^{-1}\left (a x^2\right )}}{x^3} \, dx=\text {Exception raised: TypeError} \]
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Time = 5.19 (sec) , antiderivative size = 71, normalized size of antiderivative = 0.60 \[ \int \frac {e^{\text {sech}^{-1}\left (a x^2\right )}}{x^3} \, dx=\frac {a\,\ln \left (\sqrt {\frac {1}{a\,x^2}-1}\,\sqrt {\frac {1}{a\,x^2}+1}+\frac {1}{a\,x^2}\right )}{4}-\frac {1}{4\,a\,x^4}-\frac {\sqrt {\frac {1}{a\,x^2}-1}\,\sqrt {\frac {1}{a\,x^2}+1}}{4\,x^2} \]
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