\(\int \text {erf}(b x) \sin (c+i b^2 x^2) \, dx\) [96]

   Optimal result
   Rubi [A] (verified)
   Mathematica [A] (verified)
   Maple [F]
   Fricas [F]
   Sympy [F]
   Maxima [F]
   Giac [F]
   Mupad [F(-1)]

Optimal result

Integrand size = 18, antiderivative size = 66 \[ \int \text {erf}(b x) \sin \left (c+i b^2 x^2\right ) \, dx=-\frac {i e^{i c} \sqrt {\pi } \text {erf}(b x)^2}{8 b}+\frac {i b e^{-i c} x^2 \, _2F_2\left (1,1;\frac {3}{2},2;b^2 x^2\right )}{2 \sqrt {\pi }} \]

[Out]

1/2*I*b*x^2*hypergeom([1, 1],[3/2, 2],b^2*x^2)/exp(I*c)/Pi^(1/2)-1/8*I*exp(I*c)*erf(b*x)^2*Pi^(1/2)/b

Rubi [A] (verified)

Time = 0.05 (sec) , antiderivative size = 66, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.222, Rules used = {6539, 6511, 6508, 30} \[ \int \text {erf}(b x) \sin \left (c+i b^2 x^2\right ) \, dx=\frac {i b e^{-i c} x^2 \, _2F_2\left (1,1;\frac {3}{2},2;b^2 x^2\right )}{2 \sqrt {\pi }}-\frac {i \sqrt {\pi } e^{i c} \text {erf}(b x)^2}{8 b} \]

[In]

Int[Erf[b*x]*Sin[c + I*b^2*x^2],x]

[Out]

((-1/8*I)*E^(I*c)*Sqrt[Pi]*Erf[b*x]^2)/b + ((I/2)*b*x^2*HypergeometricPFQ[{1, 1}, {3/2, 2}, b^2*x^2])/(E^(I*c)
*Sqrt[Pi])

Rule 30

Int[(x_)^(m_.), x_Symbol] :> Simp[x^(m + 1)/(m + 1), x] /; FreeQ[m, x] && NeQ[m, -1]

Rule 6508

Int[E^((c_.) + (d_.)*(x_)^2)*Erf[(b_.)*(x_)]^(n_.), x_Symbol] :> Dist[E^c*(Sqrt[Pi]/(2*b)), Subst[Int[x^n, x],
 x, Erf[b*x]], x] /; FreeQ[{b, c, d, n}, x] && EqQ[d, -b^2]

Rule 6511

Int[E^((c_.) + (d_.)*(x_)^2)*Erf[(b_.)*(x_)], x_Symbol] :> Simp[b*E^c*(x^2/Sqrt[Pi])*HypergeometricPFQ[{1, 1},
 {3/2, 2}, b^2*x^2], x] /; FreeQ[{b, c, d}, x] && EqQ[d, b^2]

Rule 6539

Int[Erf[(b_.)*(x_)]*Sin[(c_.) + (d_.)*(x_)^2], x_Symbol] :> Dist[I/2, Int[E^((-I)*c - I*d*x^2)*Erf[b*x], x], x
] - Dist[I/2, Int[E^(I*c + I*d*x^2)*Erf[b*x], x], x] /; FreeQ[{b, c, d}, x] && EqQ[d^2, -b^4]

Rubi steps \begin{align*} \text {integral}& = -\left (\frac {1}{2} i \int e^{i c-b^2 x^2} \text {erf}(b x) \, dx\right )+\frac {1}{2} i \int e^{-i c+b^2 x^2} \text {erf}(b x) \, dx \\ & = \frac {i b e^{-i c} x^2 \, _2F_2\left (1,1;\frac {3}{2},2;b^2 x^2\right )}{2 \sqrt {\pi }}-\frac {\left (i e^{i c} \sqrt {\pi }\right ) \text {Subst}(\int x \, dx,x,\text {erf}(b x))}{4 b} \\ & = -\frac {i e^{i c} \sqrt {\pi } \text {erf}(b x)^2}{8 b}+\frac {i b e^{-i c} x^2 \, _2F_2\left (1,1;\frac {3}{2},2;b^2 x^2\right )}{2 \sqrt {\pi }} \\ \end{align*}

Mathematica [A] (verified)

Time = 0.05 (sec) , antiderivative size = 69, normalized size of antiderivative = 1.05 \[ \int \text {erf}(b x) \sin \left (c+i b^2 x^2\right ) \, dx=\frac {(\cos (c)-i \sin (c)) \left (4 i b^2 x^2 \, _2F_2\left (1,1;\frac {3}{2},2;b^2 x^2\right )+\pi \text {erf}(b x)^2 (-i \cos (2 c)+\sin (2 c))\right )}{8 b \sqrt {\pi }} \]

[In]

Integrate[Erf[b*x]*Sin[c + I*b^2*x^2],x]

[Out]

((Cos[c] - I*Sin[c])*((4*I)*b^2*x^2*HypergeometricPFQ[{1, 1}, {3/2, 2}, b^2*x^2] + Pi*Erf[b*x]^2*((-I)*Cos[2*c
] + Sin[2*c])))/(8*b*Sqrt[Pi])

Maple [F]

\[\int \operatorname {erf}\left (b x \right ) \sin \left (i b^{2} x^{2}+c \right )d x\]

[In]

int(erf(b*x)*sin(c+I*b^2*x^2),x)

[Out]

int(erf(b*x)*sin(c+I*b^2*x^2),x)

Fricas [F]

\[ \int \text {erf}(b x) \sin \left (c+i b^2 x^2\right ) \, dx=\int { \operatorname {erf}\left (b x\right ) \sin \left (i \, b^{2} x^{2} + c\right ) \,d x } \]

[In]

integrate(erf(b*x)*sin(c+I*b^2*x^2),x, algorithm="fricas")

[Out]

integral(1/2*(-I*erf(b*x)*e^(-2*b^2*x^2 + 2*I*c) + I*erf(b*x))*e^(b^2*x^2 - I*c), x)

Sympy [F]

\[ \int \text {erf}(b x) \sin \left (c+i b^2 x^2\right ) \, dx=\int \sin {\left (i b^{2} x^{2} + c \right )} \operatorname {erf}{\left (b x \right )}\, dx \]

[In]

integrate(erf(b*x)*sin(c+I*b**2*x**2),x)

[Out]

Integral(sin(I*b**2*x**2 + c)*erf(b*x), x)

Maxima [F]

\[ \int \text {erf}(b x) \sin \left (c+i b^2 x^2\right ) \, dx=\int { \operatorname {erf}\left (b x\right ) \sin \left (i \, b^{2} x^{2} + c\right ) \,d x } \]

[In]

integrate(erf(b*x)*sin(c+I*b^2*x^2),x, algorithm="maxima")

[Out]

-1/8*I*sqrt(pi)*cos(c)*erf(b*x)^2/b + 1/8*sqrt(pi)*erf(b*x)^2*sin(c)/b + 1/2*I*cos(c)*integrate(erf(b*x)*e^(b^
2*x^2), x) + 1/2*integrate(erf(b*x)*e^(b^2*x^2), x)*sin(c)

Giac [F]

\[ \int \text {erf}(b x) \sin \left (c+i b^2 x^2\right ) \, dx=\int { \operatorname {erf}\left (b x\right ) \sin \left (i \, b^{2} x^{2} + c\right ) \,d x } \]

[In]

integrate(erf(b*x)*sin(c+I*b^2*x^2),x, algorithm="giac")

[Out]

integrate(erf(b*x)*sin(I*b^2*x^2 + c), x)

Mupad [F(-1)]

Timed out. \[ \int \text {erf}(b x) \sin \left (c+i b^2 x^2\right ) \, dx=\int \sin \left (b^2\,x^2\,1{}\mathrm {i}+c\right )\,\mathrm {erf}\left (b\,x\right ) \,d x \]

[In]

int(sin(c + b^2*x^2*1i)*erf(b*x),x)

[Out]

int(sin(c + b^2*x^2*1i)*erf(b*x), x)