\(\int \frac {\text {erfc}(b x)}{x^6} \, dx\) [117]

Optimal result

Integrand size = 8, antiderivative size = 81 \[ \int \frac {\text {erfc}(b x)}{x^6} \, dx=\frac {b e^{-b^2 x^2}}{10 \sqrt {\pi } x^4}-\frac {b^3 e^{-b^2 x^2}}{10 \sqrt {\pi } x^2}-\frac {\text {erfc}(b x)}{5 x^5}-\frac {b^5 \operatorname {ExpIntegralEi}\left (-b^2 x^2\right )}{10 \sqrt {\pi }} \]

[Out]

-1/5*erfc(b*x)/x^5+1/10*b/exp(b^2*x^2)/x^4/Pi^(1/2)-1/10*b^3/exp(b^2*x^2)/x^2/Pi^(1/2)-1/10*b^5*Ei(-b^2*x^2)/P
i^(1/2)

Rubi [A] (verified)

Time = 0.05 (sec) , antiderivative size = 81, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.375, Rules used = {6497, 2245, 2241} \[ \int \frac {\text {erfc}(b x)}{x^6} \, dx=\frac {b e^{-b^2 x^2}}{10 \sqrt {\pi } x^4}-\frac {b^5 \operatorname {ExpIntegralEi}\left (-b^2 x^2\right )}{10 \sqrt {\pi }}-\frac {b^3 e^{-b^2 x^2}}{10 \sqrt {\pi } x^2}-\frac {\text {erfc}(b x)}{5 x^5} \]

[In]

Int[Erfc[b*x]/x^6,x]

[Out]

b/(10*E^(b^2*x^2)*Sqrt[Pi]*x^4) - b^3/(10*E^(b^2*x^2)*Sqrt[Pi]*x^2) - Erfc[b*x]/(5*x^5) - (b^5*ExpIntegralEi[-
(b^2*x^2)])/(10*Sqrt[Pi])

Rule 2241

Int[(F_)^((a_.) + (b_.)*((c_.) + (d_.)*(x_))^(n_))/((e_.) + (f_.)*(x_)), x_Symbol] :> Simp[F^a*(ExpIntegralEi[
b*(c + d*x)^n*Log[F]]/(f*n)), x] /; FreeQ[{F, a, b, c, d, e, f, n}, x] && EqQ[d*e - c*f, 0]

Rule 2245

Int[(F_)^((a_.) + (b_.)*((c_.) + (d_.)*(x_))^(n_))*((c_.) + (d_.)*(x_))^(m_.), x_Symbol] :> Simp[(c + d*x)^(m
+ 1)*(F^(a + b*(c + d*x)^n)/(d*(m + 1))), x] - Dist[b*n*(Log[F]/(m + 1)), Int[(c + d*x)^(m + n)*F^(a + b*(c +
d*x)^n), x], x] /; FreeQ[{F, a, b, c, d}, x] && IntegerQ[2*((m + 1)/n)] && LtQ[-4, (m + 1)/n, 5] && IntegerQ[n
] && ((GtQ[n, 0] && LtQ[m, -1]) || (GtQ[-n, 0] && LeQ[-n, m + 1]))

Rule 6497

Int[Erfc[(a_.) + (b_.)*(x_)]*((c_.) + (d_.)*(x_))^(m_.), x_Symbol] :> Simp[(c + d*x)^(m + 1)*(Erfc[a + b*x]/(d
*(m + 1))), x] + Dist[2*(b/(Sqrt[Pi]*d*(m + 1))), Int[(c + d*x)^(m + 1)/E^(a + b*x)^2, x], x] /; FreeQ[{a, b,
c, d, m}, x] && NeQ[m, -1]

Rubi steps \begin{align*} \text {integral}& = -\frac {\text {erfc}(b x)}{5 x^5}-\frac {(2 b) \int \frac {e^{-b^2 x^2}}{x^5} \, dx}{5 \sqrt {\pi }} \\ & = \frac {b e^{-b^2 x^2}}{10 \sqrt {\pi } x^4}-\frac {\text {erfc}(b x)}{5 x^5}+\frac {b^3 \int \frac {e^{-b^2 x^2}}{x^3} \, dx}{5 \sqrt {\pi }} \\ & = \frac {b e^{-b^2 x^2}}{10 \sqrt {\pi } x^4}-\frac {b^3 e^{-b^2 x^2}}{10 \sqrt {\pi } x^2}-\frac {\text {erfc}(b x)}{5 x^5}-\frac {b^5 \int \frac {e^{-b^2 x^2}}{x} \, dx}{5 \sqrt {\pi }} \\ & = \frac {b e^{-b^2 x^2}}{10 \sqrt {\pi } x^4}-\frac {b^3 e^{-b^2 x^2}}{10 \sqrt {\pi } x^2}-\frac {\text {erfc}(b x)}{5 x^5}-\frac {b^5 \operatorname {ExpIntegralEi}\left (-b^2 x^2\right )}{10 \sqrt {\pi }} \\ \end{align*}

Mathematica [A] (verified)

Time = 0.02 (sec) , antiderivative size = 73, normalized size of antiderivative = 0.90 \[ \int \frac {\text {erfc}(b x)}{x^6} \, dx=e^{-b^2 x^2} \left (\frac {b}{10 \sqrt {\pi } x^4}-\frac {b^3}{10 \sqrt {\pi } x^2}\right )-\frac {\text {erfc}(b x)}{5 x^5}-\frac {b^5 \operatorname {ExpIntegralEi}\left (-b^2 x^2\right )}{10 \sqrt {\pi }} \]

[In]

Integrate[Erfc[b*x]/x^6,x]

[Out]

(b/(10*Sqrt[Pi]*x^4) - b^3/(10*Sqrt[Pi]*x^2))/E^(b^2*x^2) - Erfc[b*x]/(5*x^5) - (b^5*ExpIntegralEi[-(b^2*x^2)]
)/(10*Sqrt[Pi])

Maple [A] (verified)

Time = 0.66 (sec) , antiderivative size = 66, normalized size of antiderivative = 0.81

method	result	size
parts	\(-\frac {\operatorname {erfc}\left (b x \right )}{5 x^{5}}-\frac {2 b \left (-\frac {{\mathrm e}^{-b^{2} x^{2}}}{4 x^{4}}-\frac {b^{2} \left (-\frac {{\mathrm e}^{-b^{2} x^{2}}}{2 x^{2}}+\frac {b^{2} \operatorname {Ei}_{1}\left (b^{2} x^{2}\right )}{2}\right )}{2}\right )}{5 \sqrt {\pi }}\)	\(66\)
derivativedivides	\(b^{5} \left (-\frac {\operatorname {erfc}\left (b x \right )}{5 b^{5} x^{5}}-\frac {2 \left (-\frac {{\mathrm e}^{-b^{2} x^{2}}}{4 b^{4} x^{4}}+\frac {{\mathrm e}^{-b^{2} x^{2}}}{4 x^{2} b^{2}}-\frac {\operatorname {Ei}_{1}\left (b^{2} x^{2}\right )}{4}\right )}{5 \sqrt {\pi }}\right )\)	\(71\)
default	\(b^{5} \left (-\frac {\operatorname {erfc}\left (b x \right )}{5 b^{5} x^{5}}-\frac {2 \left (-\frac {{\mathrm e}^{-b^{2} x^{2}}}{4 b^{4} x^{4}}+\frac {{\mathrm e}^{-b^{2} x^{2}}}{4 x^{2} b^{2}}-\frac {\operatorname {Ei}_{1}\left (b^{2} x^{2}\right )}{4}\right )}{5 \sqrt {\pi }}\right )\)	\(71\)

[In]

int(erfc(b*x)/x^6,x,method=_RETURNVERBOSE)

[Out]

-1/5*erfc(b*x)/x^5-2/5/Pi^(1/2)*b*(-1/4/x^4*exp(-b^2*x^2)-1/2*b^2*(-1/2/x^2*exp(-b^2*x^2)+1/2*b^2*Ei(1,b^2*x^2
)))

Fricas [A] (verification not implemented)

none

Time = 0.25 (sec) , antiderivative size = 62, normalized size of antiderivative = 0.77 \[ \int \frac {\text {erfc}(b x)}{x^6} \, dx=-\frac {2 \, \pi - 2 \, \pi \operatorname {erf}\left (b x\right ) + \sqrt {\pi } {\left (b^{5} x^{5} {\rm Ei}\left (-b^{2} x^{2}\right ) + {\left (b^{3} x^{3} - b x\right )} e^{\left (-b^{2} x^{2}\right )}\right )}}{10 \, \pi x^{5}} \]

[In]

integrate(erfc(b*x)/x^6,x, algorithm="fricas")

[Out]

-1/10*(2*pi - 2*pi*erf(b*x) + sqrt(pi)*(b^5*x^5*Ei(-b^2*x^2) + (b^3*x^3 - b*x)*e^(-b^2*x^2)))/(pi*x^5)

Sympy [A] (verification not implemented)

Time = 1.84 (sec) , antiderivative size = 70, normalized size of antiderivative = 0.86 \[ \int \frac {\text {erfc}(b x)}{x^6} \, dx=\frac {b^{5} \operatorname {E}_{1}\left (b^{2} x^{2}\right )}{10 \sqrt {\pi }} - \frac {b^{3} e^{- b^{2} x^{2}}}{10 \sqrt {\pi } x^{2}} + \frac {b e^{- b^{2} x^{2}}}{10 \sqrt {\pi } x^{4}} - \frac {\operatorname {erfc}{\left (b x \right )}}{5 x^{5}} \]

[In]

integrate(erfc(b*x)/x**6,x)

[Out]

b**5*expint(1, b**2*x**2)/(10*sqrt(pi)) - b**3*exp(-b**2*x**2)/(10*sqrt(pi)*x**2) + b*exp(-b**2*x**2)/(10*sqrt
(pi)*x**4) - erfc(b*x)/(5*x**5)

Maxima [A] (verification not implemented)

none

Time = 0.26 (sec) , antiderivative size = 27, normalized size of antiderivative = 0.33 \[ \int \frac {\text {erfc}(b x)}{x^6} \, dx=\frac {b^{5} \Gamma \left (-2, b^{2} x^{2}\right )}{5 \, \sqrt {\pi }} - \frac {\operatorname {erfc}\left (b x\right )}{5 \, x^{5}} \]

[In]

integrate(erfc(b*x)/x^6,x, algorithm="maxima")

[Out]

1/5*b^5*gamma(-2, b^2*x^2)/sqrt(pi) - 1/5*erfc(b*x)/x^5

Giac [F]

\[ \int \frac {\text {erfc}(b x)}{x^6} \, dx=\int { \frac {\operatorname {erfc}\left (b x\right )}{x^{6}} \,d x } \]

[In]

integrate(erfc(b*x)/x^6,x, algorithm="giac")

[Out]

integrate(erfc(b*x)/x^6, x)

Mupad [B] (verification not implemented)

Time = 4.73 (sec) , antiderivative size = 66, normalized size of antiderivative = 0.81 \[ \int \frac {\text {erfc}(b x)}{x^6} \, dx=-\frac {\frac {\mathrm {erfc}\left (b\,x\right )}{5}+\frac {b^3\,x^3\,{\mathrm {e}}^{-b^2\,x^2}}{10\,\sqrt {\pi }}-\frac {b\,x\,{\mathrm {e}}^{-b^2\,x^2}}{10\,\sqrt {\pi }}}{x^5}-\frac {b^5\,\mathrm {ei}\left (-b^2\,x^2\right )}{10\,\sqrt {\pi }} \]

[In]

int(erfc(b*x)/x^6,x)

[Out]

- (erfc(b*x)/5 + (b^3*x^3*exp(-b^2*x^2))/(10*pi^(1/2)) - (b*x*exp(-b^2*x^2))/(10*pi^(1/2)))/x^5 - (b^5*ei(-b^2
*x^2))/(10*pi^(1/2))