\(\int (e x)^m \text {erfc}(d (a+b \log (c x^n))) \, dx\) [149]

Optimal result

Integrand size = 19, antiderivative size = 126 \[ \int (e x)^m \text {erfc}\left (d \left (a+b \log \left (c x^n\right )\right )\right ) \, dx=-\frac {e^{\frac {(1+m) \left (1+m-4 a b d^2 n\right )}{4 b^2 d^2 n^2}} x (e x)^m \left (c x^n\right )^{-\frac {1+m}{n}} \text {erf}\left (\frac {1+m-2 a b d^2 n-2 b^2 d^2 n \log \left (c x^n\right )}{2 b d n}\right )}{1+m}+\frac {(e x)^{1+m} \text {erfc}\left (d \left (a+b \log \left (c x^n\right )\right )\right )}{e (1+m)} \]

[Out]

-exp(1/4*(1+m)*(-4*a*b*d^2*n+m+1)/b^2/d^2/n^2)*x*(e*x)^m*erf(1/2*(1+m-2*a*b*d^2*n-2*b^2*d^2*n*ln(c*x^n))/b/d/n
)/(1+m)/((c*x^n)^((1+m)/n))+(e*x)^(1+m)*erfc(d*(a+b*ln(c*x^n)))/e/(1+m)

Rubi [A] (verified)

Time = 0.16 (sec) , antiderivative size = 126, normalized size of antiderivative = 1.00, number of steps used = 5, number of rules used = 5, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.263, Rules used = {6537, 2314, 2308, 2266, 2236} \[ \int (e x)^m \text {erfc}\left (d \left (a+b \log \left (c x^n\right )\right )\right ) \, dx=\frac {(e x)^{m+1} \text {erfc}\left (d \left (a+b \log \left (c x^n\right )\right )\right )}{e (m+1)}-\frac {x (e x)^m \left (c x^n\right )^{-\frac {m+1}{n}} \exp \left (\frac {(m+1) \left (-4 a b d^2 n+m+1\right )}{4 b^2 d^2 n^2}\right ) \text {erf}\left (\frac {-2 a b d^2 n-2 b^2 d^2 n \log \left (c x^n\right )+m+1}{2 b d n}\right )}{m+1} \]

[In]

Int[(e*x)^m*Erfc[d*(a + b*Log[c*x^n])],x]

[Out]

-((E^(((1 + m)*(1 + m - 4*a*b*d^2*n))/(4*b^2*d^2*n^2))*x*(e*x)^m*Erf[(1 + m - 2*a*b*d^2*n - 2*b^2*d^2*n*Log[c*
x^n])/(2*b*d*n)])/((1 + m)*(c*x^n)^((1 + m)/n))) + ((e*x)^(1 + m)*Erfc[d*(a + b*Log[c*x^n])])/(e*(1 + m))

Rule 2236

Int[(F_)^((a_.) + (b_.)*((c_.) + (d_.)*(x_))^2), x_Symbol] :> Simp[F^a*Sqrt[Pi]*(Erf[(c + d*x)*Rt[(-b)*Log[F],
2]]/(2*d*Rt[(-b)*Log[F], 2])), x] /; FreeQ[{F, a, b, c, d}, x] && NegQ[b]

Rule 2266

Int[(F_)^((a_.) + (b_.)*(x_) + (c_.)*(x_)^2), x_Symbol] :> Dist[F^(a - b^2/(4*c)), Int[F^((b + 2*c*x)^2/(4*c))
, x], x] /; FreeQ[{F, a, b, c}, x]

Rule 2308

Int[(F_)^(((a_.) + Log[(c_.)*((d_.) + (e_.)*(x_))^(n_.)]^2*(b_.))*(f_.))*((g_.) + (h_.)*(x_))^(m_.), x_Symbol]
:> Dist[(g + h*x)^(m + 1)/(h*n*(c*(d + e*x)^n)^((m + 1)/n)), Subst[Int[E^(a*f*Log[F] + ((m + 1)*x)/n + b*f*Lo
g[F]*x^2), x], x, Log[c*(d + e*x)^n]], x] /; FreeQ[{F, a, b, c, d, e, f, g, h, m, n}, x] && EqQ[e*g - d*h, 0]

Rule 2314

Int[(F_)^(((a_.) + Log[(c_.)*((d_.) + (e_.)*(x_))^(n_.)]*(b_.))^2*(f_.))*((g_.) + (h_.)*(x_))^(m_.), x_Symbol]
:> Dist[(g + h*x)^m*((c*(d + e*x)^n)^(2*a*b*f*Log[F])/(d + e*x)^(m + 2*a*b*f*n*Log[F])), Int[(d + e*x)^(m + 2
*a*b*f*n*Log[F])*F^(a^2*f + b^2*f*Log[c*(d + e*x)^n]^2), x], x] /; FreeQ[{F, a, b, c, d, e, f, g, h, m, n}, x]
&& EqQ[e*g - d*h, 0]

Rule 6537

Int[Erfc[((a_.) + Log[(c_.)*(x_)^(n_.)]*(b_.))*(d_.)]*((e_.)*(x_))^(m_.), x_Symbol] :> Simp[(e*x)^(m + 1)*(Erf
c[d*(a + b*Log[c*x^n])]/(e*(m + 1))), x] + Dist[2*b*d*(n/(Sqrt[Pi]*(m + 1))), Int[(e*x)^m/E^(d*(a + b*Log[c*x^
n]))^2, x], x] /; FreeQ[{a, b, c, d, e, m, n}, x] && NeQ[m, -1]

Rubi steps \begin{align*} \text {integral}& = \frac {(e x)^{1+m} \text {erfc}\left (d \left (a+b \log \left (c x^n\right )\right )\right )}{e (1+m)}+\frac {(2 b d n) \int e^{-d^2 \left (a+b \log \left (c x^n\right )\right )^2} (e x)^m \, dx}{(1+m) \sqrt {\pi }} \\ & = \frac {(e x)^{1+m} \text {erfc}\left (d \left (a+b \log \left (c x^n\right )\right )\right )}{e (1+m)}+\frac {\left (2 b d n x^{-m+2 a b d^2 n} (e x)^m \left (c x^n\right )^{-2 a b d^2}\right ) \int e^{-a^2 d^2-b^2 d^2 \log ^2\left (c x^n\right )} x^{m-2 a b d^2 n} \, dx}{(1+m) \sqrt {\pi }} \\ & = \frac {(e x)^{1+m} \text {erfc}\left (d \left (a+b \log \left (c x^n\right )\right )\right )}{e (1+m)}+\frac {\left (2 b d x (e x)^m \left (c x^n\right )^{-2 a b d^2-\frac {1+m-2 a b d^2 n}{n}}\right ) \text {Subst}\left (\int \exp \left (-a^2 d^2+\frac {\left (1+m-2 a b d^2 n\right ) x}{n}-b^2 d^2 x^2\right ) \, dx,x,\log \left (c x^n\right )\right )}{(1+m) \sqrt {\pi }} \\ & = \frac {(e x)^{1+m} \text {erfc}\left (d \left (a+b \log \left (c x^n\right )\right )\right )}{e (1+m)}+\frac {\left (2 b d \exp \left (\frac {(1+m) \left (1+m-4 a b d^2 n\right )}{4 b^2 d^2 n^2}\right ) x (e x)^m \left (c x^n\right )^{-2 a b d^2-\frac {1+m-2 a b d^2 n}{n}}\right ) \text {Subst}\left (\int \exp \left (-\frac {\left (\frac {1+m-2 a b d^2 n}{n}-2 b^2 d^2 x\right )^2}{4 b^2 d^2}\right ) \, dx,x,\log \left (c x^n\right )\right )}{(1+m) \sqrt {\pi }} \\ & = -\frac {\exp \left (\frac {(1+m) \left (1+m-4 a b d^2 n\right )}{4 b^2 d^2 n^2}\right ) x (e x)^m \left (c x^n\right )^{-\frac {1+m}{n}} \text {erf}\left (\frac {1+m-2 a b d^2 n-2 b^2 d^2 n \log \left (c x^n\right )}{2 b d n}\right )}{1+m}+\frac {(e x)^{1+m} \text {erfc}\left (d \left (a+b \log \left (c x^n\right )\right )\right )}{e (1+m)} \\ \end{align*}

Mathematica [A] (verified)

Time = 0.34 (sec) , antiderivative size = 126, normalized size of antiderivative = 1.00 \[ \int (e x)^m \text {erfc}\left (d \left (a+b \log \left (c x^n\right )\right )\right ) \, dx=\frac {(e x)^m \left (e^{\frac {(1+m) \left (1+m-4 a b d^2 n+4 b^2 d^2 n^2 \log (x)-4 b^2 d^2 n \log \left (c x^n\right )\right )}{4 b^2 d^2 n^2}} x^{-m} \text {erf}\left (a d-\frac {1+m-2 b^2 d^2 n \log \left (c x^n\right )}{2 b d n}\right )+x \text {erfc}\left (d \left (a+b \log \left (c x^n\right )\right )\right )\right )}{1+m} \]

[In]

Integrate[(e*x)^m*Erfc[d*(a + b*Log[c*x^n])],x]

[Out]

((e*x)^m*((E^(((1 + m)*(1 + m - 4*a*b*d^2*n + 4*b^2*d^2*n^2*Log[x] - 4*b^2*d^2*n*Log[c*x^n]))/(4*b^2*d^2*n^2))
*Erf[a*d - (1 + m - 2*b^2*d^2*n*Log[c*x^n])/(2*b*d*n)])/x^m + x*Erfc[d*(a + b*Log[c*x^n])]))/(1 + m)

Maple [F]

\[\int \left (e x \right )^{m} \operatorname {erfc}\left (d \left (a +b \ln \left (c \,x^{n}\right )\right )\right )d x\]

[In]

int((e*x)^m*erfc(d*(a+b*ln(c*x^n))),x)

[Out]

int((e*x)^m*erfc(d*(a+b*ln(c*x^n))),x)

Fricas [A] (verification not implemented)

none

Time = 0.26 (sec) , antiderivative size = 194, normalized size of antiderivative = 1.54 \[ \int (e x)^m \text {erfc}\left (d \left (a+b \log \left (c x^n\right )\right )\right ) \, dx=-\frac {x \operatorname {erf}\left (b d \log \left (c x^{n}\right ) + a d\right ) e^{\left (m \log \left (e\right ) + m \log \left (x\right )\right )} - \sqrt {b^{2} d^{2} n^{2}} \operatorname {erf}\left (\frac {{\left (2 \, b^{2} d^{2} n^{2} \log \left (x\right ) + 2 \, b^{2} d^{2} n \log \left (c\right ) + 2 \, a b d^{2} n - m - 1\right )} \sqrt {b^{2} d^{2} n^{2}}}{2 \, b^{2} d^{2} n^{2}}\right ) e^{\left (\frac {4 \, b^{2} d^{2} m n^{2} \log \left (e\right ) - 4 \, {\left (b^{2} d^{2} m + b^{2} d^{2}\right )} n \log \left (c\right ) + m^{2} - 4 \, {\left (a b d^{2} m + a b d^{2}\right )} n + 2 \, m + 1}{4 \, b^{2} d^{2} n^{2}}\right )} - x e^{\left (m \log \left (e\right ) + m \log \left (x\right )\right )}}{m + 1} \]

[In]

integrate((e*x)^m*erfc(d*(a+b*log(c*x^n))),x, algorithm="fricas")

[Out]

-(x*erf(b*d*log(c*x^n) + a*d)*e^(m*log(e) + m*log(x)) - sqrt(b^2*d^2*n^2)*erf(1/2*(2*b^2*d^2*n^2*log(x) + 2*b^
2*d^2*n*log(c) + 2*a*b*d^2*n - m - 1)*sqrt(b^2*d^2*n^2)/(b^2*d^2*n^2))*e^(1/4*(4*b^2*d^2*m*n^2*log(e) - 4*(b^2
*d^2*m + b^2*d^2)*n*log(c) + m^2 - 4*(a*b*d^2*m + a*b*d^2)*n + 2*m + 1)/(b^2*d^2*n^2)) - x*e^(m*log(e) + m*log
(x)))/(m + 1)

Sympy [F]

\[ \int (e x)^m \text {erfc}\left (d \left (a+b \log \left (c x^n\right )\right )\right ) \, dx=\int \left (e x\right )^{m} \operatorname {erfc}{\left (a d + b d \log {\left (c x^{n} \right )} \right )}\, dx \]

[In]

integrate((e*x)**m*erfc(d*(a+b*ln(c*x**n))),x)

[Out]

Integral((e*x)**m*erfc(a*d + b*d*log(c*x**n)), x)

Maxima [F]

\[ \int (e x)^m \text {erfc}\left (d \left (a+b \log \left (c x^n\right )\right )\right ) \, dx=\int { \left (e x\right )^{m} \operatorname {erfc}\left ({\left (b \log \left (c x^{n}\right ) + a\right )} d\right ) \,d x } \]

[In]

integrate((e*x)^m*erfc(d*(a+b*log(c*x^n))),x, algorithm="maxima")

[Out]

integrate((e*x)^m*erfc((b*log(c*x^n) + a)*d), x)

Giac [F]

\[ \int (e x)^m \text {erfc}\left (d \left (a+b \log \left (c x^n\right )\right )\right ) \, dx=\int { \left (e x\right )^{m} \operatorname {erfc}\left ({\left (b \log \left (c x^{n}\right ) + a\right )} d\right ) \,d x } \]

[In]

integrate((e*x)^m*erfc(d*(a+b*log(c*x^n))),x, algorithm="giac")

[Out]

integrate((e*x)^m*erfc((b*log(c*x^n) + a)*d), x)

Mupad [F(-1)]

Timed out. \[ \int (e x)^m \text {erfc}\left (d \left (a+b \log \left (c x^n\right )\right )\right ) \, dx=\int \mathrm {erfc}\left (d\,\left (a+b\,\ln \left (c\,x^n\right )\right )\right )\,{\left (e\,x\right )}^m \,d x \]

[In]

int(erfc(d*(a + b*log(c*x^n)))*(e*x)^m,x)

[Out]

int(erfc(d*(a + b*log(c*x^n)))*(e*x)^m, x)