Integrand size = 19, antiderivative size = 66 \[ \int \frac {e^{c+b^2 x^2} \text {erf}(b x)}{x^2} \, dx=-\frac {e^{c+b^2 x^2} \text {erf}(b x)}{x}+\frac {2 b^3 e^c x^2 \, _2F_2\left (1,1;\frac {3}{2},2;b^2 x^2\right )}{\sqrt {\pi }}+\frac {2 b e^c \log (x)}{\sqrt {\pi }} \]
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Time = 0.05 (sec) , antiderivative size = 66, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.211, Rules used = {6526, 6511, 12, 29} \[ \int \frac {e^{c+b^2 x^2} \text {erf}(b x)}{x^2} \, dx=\frac {2 b^3 e^c x^2 \, _2F_2\left (1,1;\frac {3}{2},2;b^2 x^2\right )}{\sqrt {\pi }}-\frac {e^{b^2 x^2+c} \text {erf}(b x)}{x}+\frac {2 b e^c \log (x)}{\sqrt {\pi }} \]
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Rule 12
Rule 29
Rule 6511
Rule 6526
Rubi steps \begin{align*} \text {integral}& = -\frac {e^{c+b^2 x^2} \text {erf}(b x)}{x}+\left (2 b^2\right ) \int e^{c+b^2 x^2} \text {erf}(b x) \, dx+\frac {(2 b) \int \frac {e^c}{x} \, dx}{\sqrt {\pi }} \\ & = -\frac {e^{c+b^2 x^2} \text {erf}(b x)}{x}+\frac {2 b^3 e^c x^2 \, _2F_2\left (1,1;\frac {3}{2},2;b^2 x^2\right )}{\sqrt {\pi }}+\frac {\left (2 b e^c\right ) \int \frac {1}{x} \, dx}{\sqrt {\pi }} \\ & = -\frac {e^{c+b^2 x^2} \text {erf}(b x)}{x}+\frac {2 b^3 e^c x^2 \, _2F_2\left (1,1;\frac {3}{2},2;b^2 x^2\right )}{\sqrt {\pi }}+\frac {2 b e^c \log (x)}{\sqrt {\pi }} \\ \end{align*}
Time = 0.15 (sec) , antiderivative size = 74, normalized size of antiderivative = 1.12 \[ \int \frac {e^{c+b^2 x^2} \text {erf}(b x)}{x^2} \, dx=\frac {e^c \left (\text {erf}(b x) \left (-e^{b^2 x^2} \sqrt {\pi }+b \pi x \text {erfi}(b x)\right )-2 b^3 x^3 \, _2F_2\left (1,1;\frac {3}{2},2;-b^2 x^2\right )+2 b x \log (x)\right )}{\sqrt {\pi } x} \]
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\[\int \frac {{\mathrm e}^{b^{2} x^{2}+c} \operatorname {erf}\left (b x \right )}{x^{2}}d x\]
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\[ \int \frac {e^{c+b^2 x^2} \text {erf}(b x)}{x^2} \, dx=\int { \frac {\operatorname {erf}\left (b x\right ) e^{\left (b^{2} x^{2} + c\right )}}{x^{2}} \,d x } \]
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Time = 9.92 (sec) , antiderivative size = 46, normalized size of antiderivative = 0.70 \[ \int \frac {e^{c+b^2 x^2} \text {erf}(b x)}{x^2} \, dx=\frac {2 b^{3} x^{2} e^{c} {{}_{2}F_{2}\left (\begin {matrix} 1, 1 \\ 2, \frac {5}{2} \end {matrix}\middle | {b^{2} x^{2}} \right )}}{3 \sqrt {\pi }} + \frac {b e^{c} \log {\left (b^{2} x^{2} \right )}}{\sqrt {\pi }} \]
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\[ \int \frac {e^{c+b^2 x^2} \text {erf}(b x)}{x^2} \, dx=\int { \frac {\operatorname {erf}\left (b x\right ) e^{\left (b^{2} x^{2} + c\right )}}{x^{2}} \,d x } \]
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\[ \int \frac {e^{c+b^2 x^2} \text {erf}(b x)}{x^2} \, dx=\int { \frac {\operatorname {erf}\left (b x\right ) e^{\left (b^{2} x^{2} + c\right )}}{x^{2}} \,d x } \]
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Timed out. \[ \int \frac {e^{c+b^2 x^2} \text {erf}(b x)}{x^2} \, dx=\int \frac {{\mathrm {e}}^{b^2\,x^2+c}\,\mathrm {erf}\left (b\,x\right )}{x^2} \,d x \]
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