Integrand size = 8, antiderivative size = 127 \[ \int \frac {\operatorname {FresnelC}(b x)}{x^{10}} \, dx=-\frac {b \cos \left (\frac {1}{2} b^2 \pi x^2\right )}{72 x^8}+\frac {b^5 \pi ^2 \cos \left (\frac {1}{2} b^2 \pi x^2\right )}{1728 x^4}+\frac {b^9 \pi ^4 \operatorname {CosIntegral}\left (\frac {1}{2} b^2 \pi x^2\right )}{6912}-\frac {\operatorname {FresnelC}(b x)}{9 x^9}+\frac {b^3 \pi \sin \left (\frac {1}{2} b^2 \pi x^2\right )}{432 x^6}-\frac {b^7 \pi ^3 \sin \left (\frac {1}{2} b^2 \pi x^2\right )}{3456 x^2} \]
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Time = 0.10 (sec) , antiderivative size = 127, normalized size of antiderivative = 1.00, number of steps used = 7, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.500, Rules used = {6562, 3461, 3378, 3383} \[ \int \frac {\operatorname {FresnelC}(b x)}{x^{10}} \, dx=-\frac {b \cos \left (\frac {1}{2} \pi b^2 x^2\right )}{72 x^8}+\frac {\pi ^4 b^9 \operatorname {CosIntegral}\left (\frac {1}{2} b^2 \pi x^2\right )}{6912}-\frac {\pi ^3 b^7 \sin \left (\frac {1}{2} \pi b^2 x^2\right )}{3456 x^2}+\frac {\pi ^2 b^5 \cos \left (\frac {1}{2} \pi b^2 x^2\right )}{1728 x^4}+\frac {\pi b^3 \sin \left (\frac {1}{2} \pi b^2 x^2\right )}{432 x^6}-\frac {\operatorname {FresnelC}(b x)}{9 x^9} \]
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Rule 3378
Rule 3383
Rule 3461
Rule 6562
Rubi steps \begin{align*} \text {integral}& = -\frac {\operatorname {FresnelC}(b x)}{9 x^9}+\frac {1}{9} b \int \frac {\cos \left (\frac {1}{2} b^2 \pi x^2\right )}{x^9} \, dx \\ & = -\frac {\operatorname {FresnelC}(b x)}{9 x^9}+\frac {1}{18} b \text {Subst}\left (\int \frac {\cos \left (\frac {1}{2} b^2 \pi x\right )}{x^5} \, dx,x,x^2\right ) \\ & = -\frac {b \cos \left (\frac {1}{2} b^2 \pi x^2\right )}{72 x^8}-\frac {\operatorname {FresnelC}(b x)}{9 x^9}-\frac {1}{144} \left (b^3 \pi \right ) \text {Subst}\left (\int \frac {\sin \left (\frac {1}{2} b^2 \pi x\right )}{x^4} \, dx,x,x^2\right ) \\ & = -\frac {b \cos \left (\frac {1}{2} b^2 \pi x^2\right )}{72 x^8}-\frac {\operatorname {FresnelC}(b x)}{9 x^9}+\frac {b^3 \pi \sin \left (\frac {1}{2} b^2 \pi x^2\right )}{432 x^6}-\frac {1}{864} \left (b^5 \pi ^2\right ) \text {Subst}\left (\int \frac {\cos \left (\frac {1}{2} b^2 \pi x\right )}{x^3} \, dx,x,x^2\right ) \\ & = -\frac {b \cos \left (\frac {1}{2} b^2 \pi x^2\right )}{72 x^8}+\frac {b^5 \pi ^2 \cos \left (\frac {1}{2} b^2 \pi x^2\right )}{1728 x^4}-\frac {\operatorname {FresnelC}(b x)}{9 x^9}+\frac {b^3 \pi \sin \left (\frac {1}{2} b^2 \pi x^2\right )}{432 x^6}+\frac {\left (b^7 \pi ^3\right ) \text {Subst}\left (\int \frac {\sin \left (\frac {1}{2} b^2 \pi x\right )}{x^2} \, dx,x,x^2\right )}{3456} \\ & = -\frac {b \cos \left (\frac {1}{2} b^2 \pi x^2\right )}{72 x^8}+\frac {b^5 \pi ^2 \cos \left (\frac {1}{2} b^2 \pi x^2\right )}{1728 x^4}-\frac {\operatorname {FresnelC}(b x)}{9 x^9}+\frac {b^3 \pi \sin \left (\frac {1}{2} b^2 \pi x^2\right )}{432 x^6}-\frac {b^7 \pi ^3 \sin \left (\frac {1}{2} b^2 \pi x^2\right )}{3456 x^2}+\frac {\left (b^9 \pi ^4\right ) \text {Subst}\left (\int \frac {\cos \left (\frac {1}{2} b^2 \pi x\right )}{x} \, dx,x,x^2\right )}{6912} \\ & = -\frac {b \cos \left (\frac {1}{2} b^2 \pi x^2\right )}{72 x^8}+\frac {b^5 \pi ^2 \cos \left (\frac {1}{2} b^2 \pi x^2\right )}{1728 x^4}+\frac {b^9 \pi ^4 \operatorname {CosIntegral}\left (\frac {1}{2} b^2 \pi x^2\right )}{6912}-\frac {\operatorname {FresnelC}(b x)}{9 x^9}+\frac {b^3 \pi \sin \left (\frac {1}{2} b^2 \pi x^2\right )}{432 x^6}-\frac {b^7 \pi ^3 \sin \left (\frac {1}{2} b^2 \pi x^2\right )}{3456 x^2} \\ \end{align*}
Time = 0.06 (sec) , antiderivative size = 96, normalized size of antiderivative = 0.76 \[ \int \frac {\operatorname {FresnelC}(b x)}{x^{10}} \, dx=\frac {\frac {4 b \left (-24+b^4 \pi ^2 x^4\right ) \cos \left (\frac {1}{2} b^2 \pi x^2\right )}{x^8}+b^9 \pi ^4 \operatorname {CosIntegral}\left (\frac {1}{2} b^2 \pi x^2\right )-\frac {768 \operatorname {FresnelC}(b x)}{x^9}-\frac {2 b^3 \pi \left (-8+b^4 \pi ^2 x^4\right ) \sin \left (\frac {1}{2} b^2 \pi x^2\right )}{x^6}}{6912} \]
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Result contains higher order function than in optimal. Order 5 vs. order 4.
Time = 0.52 (sec) , antiderivative size = 90, normalized size of antiderivative = 0.71
method | result | size |
meijerg | \(\frac {\pi ^{\frac {9}{2}} b^{9} \left (-\frac {\pi ^{\frac {3}{2}} x^{4} b^{4} \operatorname {hypergeom}\left (\left [1, 1, \frac {13}{4}\right ], \left [2, \frac {7}{2}, 4, \frac {17}{4}\right ], -\frac {x^{4} \pi ^{2} b^{4}}{16}\right )}{585}+\frac {-\frac {332}{243}+\frac {16 \gamma }{27}-\frac {16 \ln \left (2\right )}{27}+\frac {32 \ln \left (x \right )}{27}+\frac {16 \ln \left (\pi \right )}{27}+\frac {32 \ln \left (b \right )}{27}}{\sqrt {\pi }}-\frac {512}{\pi ^{\frac {9}{2}} x^{8} b^{8}}+\frac {128}{5 \pi ^{\frac {5}{2}} x^{4} b^{4}}\right )}{4096}\) | \(90\) |
parts | \(-\frac {\operatorname {FresnelC}\left (b x \right )}{9 x^{9}}+\frac {b \left (-\frac {\cos \left (\frac {b^{2} \pi \,x^{2}}{2}\right )}{8 x^{8}}-\frac {b^{2} \pi \left (-\frac {\sin \left (\frac {b^{2} \pi \,x^{2}}{2}\right )}{6 x^{6}}+\frac {b^{2} \pi \left (-\frac {\cos \left (\frac {b^{2} \pi \,x^{2}}{2}\right )}{4 x^{4}}-\frac {b^{2} \pi \left (-\frac {\sin \left (\frac {b^{2} \pi \,x^{2}}{2}\right )}{2 x^{2}}+\frac {b^{2} \pi \,\operatorname {Ci}\left (\frac {b^{2} \pi \,x^{2}}{2}\right )}{4}\right )}{4}\right )}{6}\right )}{8}\right )}{9}\) | \(112\) |
derivativedivides | \(b^{9} \left (-\frac {\operatorname {FresnelC}\left (b x \right )}{9 b^{9} x^{9}}-\frac {\cos \left (\frac {b^{2} \pi \,x^{2}}{2}\right )}{72 b^{8} x^{8}}-\frac {\pi \left (-\frac {\sin \left (\frac {b^{2} \pi \,x^{2}}{2}\right )}{6 b^{6} x^{6}}+\frac {\pi \left (-\frac {\cos \left (\frac {b^{2} \pi \,x^{2}}{2}\right )}{4 b^{4} x^{4}}-\frac {\pi \left (-\frac {\sin \left (\frac {b^{2} \pi \,x^{2}}{2}\right )}{2 b^{2} x^{2}}+\frac {\pi \,\operatorname {Ci}\left (\frac {b^{2} \pi \,x^{2}}{2}\right )}{4}\right )}{4}\right )}{6}\right )}{72}\right )\) | \(115\) |
default | \(b^{9} \left (-\frac {\operatorname {FresnelC}\left (b x \right )}{9 b^{9} x^{9}}-\frac {\cos \left (\frac {b^{2} \pi \,x^{2}}{2}\right )}{72 b^{8} x^{8}}-\frac {\pi \left (-\frac {\sin \left (\frac {b^{2} \pi \,x^{2}}{2}\right )}{6 b^{6} x^{6}}+\frac {\pi \left (-\frac {\cos \left (\frac {b^{2} \pi \,x^{2}}{2}\right )}{4 b^{4} x^{4}}-\frac {\pi \left (-\frac {\sin \left (\frac {b^{2} \pi \,x^{2}}{2}\right )}{2 b^{2} x^{2}}+\frac {\pi \,\operatorname {Ci}\left (\frac {b^{2} \pi \,x^{2}}{2}\right )}{4}\right )}{4}\right )}{6}\right )}{72}\right )\) | \(115\) |
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Time = 0.28 (sec) , antiderivative size = 91, normalized size of antiderivative = 0.72 \[ \int \frac {\operatorname {FresnelC}(b x)}{x^{10}} \, dx=\frac {\pi ^{4} b^{9} x^{9} \operatorname {Ci}\left (\frac {1}{2} \, \pi b^{2} x^{2}\right ) + 4 \, {\left (\pi ^{2} b^{5} x^{5} - 24 \, b x\right )} \cos \left (\frac {1}{2} \, \pi b^{2} x^{2}\right ) - 2 \, {\left (\pi ^{3} b^{7} x^{7} - 8 \, \pi b^{3} x^{3}\right )} \sin \left (\frac {1}{2} \, \pi b^{2} x^{2}\right ) - 768 \, \operatorname {C}\left (b x\right )}{6912 \, x^{9}} \]
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Time = 6.96 (sec) , antiderivative size = 76, normalized size of antiderivative = 0.60 \[ \int \frac {\operatorname {FresnelC}(b x)}{x^{10}} \, dx=- \frac {\pi ^{6} b^{13} x^{4} \Gamma \left (\frac {13}{4}\right ) {{}_{3}F_{4}\left (\begin {matrix} 1, 1, \frac {13}{4} \\ 2, \frac {7}{2}, 4, \frac {17}{4} \end {matrix}\middle | {- \frac {\pi ^{2} b^{4} x^{4}}{16}} \right )}}{737280 \Gamma \left (\frac {17}{4}\right )} + \frac {\pi ^{4} b^{9} \log {\left (b^{4} x^{4} \right )}}{13824} + \frac {\pi ^{2} b^{5}}{160 x^{4}} - \frac {b}{8 x^{8}} \]
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Result contains complex when optimal does not.
Time = 0.28 (sec) , antiderivative size = 46, normalized size of antiderivative = 0.36 \[ \int \frac {\operatorname {FresnelC}(b x)}{x^{10}} \, dx=-\frac {1}{576} \, {\left (\pi ^{4} \Gamma \left (-4, \frac {1}{2} i \, \pi b^{2} x^{2}\right ) + \pi ^{4} \Gamma \left (-4, -\frac {1}{2} i \, \pi b^{2} x^{2}\right )\right )} b^{9} - \frac {\operatorname {C}\left (b x\right )}{9 \, x^{9}} \]
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\[ \int \frac {\operatorname {FresnelC}(b x)}{x^{10}} \, dx=\int { \frac {\operatorname {C}\left (b x\right )}{x^{10}} \,d x } \]
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Timed out. \[ \int \frac {\operatorname {FresnelC}(b x)}{x^{10}} \, dx=\int \frac {\mathrm {FresnelC}\left (b\,x\right )}{x^{10}} \,d x \]
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