Integrand size = 10, antiderivative size = 10 \[ \int \frac {\operatorname {FresnelC}(b x)^2}{x^4} \, dx=-\frac {b^2}{6 x}-\frac {b^2 \cos \left (b^2 \pi x^2\right )}{6 x}-\frac {b \cos \left (\frac {1}{2} b^2 \pi x^2\right ) \operatorname {FresnelC}(b x)}{3 x^2}-\frac {\operatorname {FresnelC}(b x)^2}{3 x^3}-\frac {b^3 \pi \operatorname {FresnelS}\left (\sqrt {2} b x\right )}{3 \sqrt {2}}-\frac {1}{3} b^3 \pi \text {Int}\left (\frac {\operatorname {FresnelC}(b x) \sin \left (\frac {1}{2} b^2 \pi x^2\right )}{x},x\right ) \]
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Not integrable
Time = 0.07 (sec) , antiderivative size = 10, normalized size of antiderivative = 1.00, number of steps used = 0, number of rules used = 0, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.000, Rules used = {} \[ \int \frac {\operatorname {FresnelC}(b x)^2}{x^4} \, dx=\int \frac {\operatorname {FresnelC}(b x)^2}{x^4} \, dx \]
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Rubi steps \begin{align*} \text {integral}& = -\frac {\operatorname {FresnelC}(b x)^2}{3 x^3}+\frac {1}{3} (2 b) \int \frac {\cos \left (\frac {1}{2} b^2 \pi x^2\right ) \operatorname {FresnelC}(b x)}{x^3} \, dx \\ & = -\frac {b^2}{6 x}-\frac {b \cos \left (\frac {1}{2} b^2 \pi x^2\right ) \operatorname {FresnelC}(b x)}{3 x^2}-\frac {\operatorname {FresnelC}(b x)^2}{3 x^3}+\frac {1}{6} b^2 \int \frac {\cos \left (b^2 \pi x^2\right )}{x^2} \, dx-\frac {1}{3} \left (b^3 \pi \right ) \int \frac {\operatorname {FresnelC}(b x) \sin \left (\frac {1}{2} b^2 \pi x^2\right )}{x} \, dx \\ & = -\frac {b^2}{6 x}-\frac {b^2 \cos \left (b^2 \pi x^2\right )}{6 x}-\frac {b \cos \left (\frac {1}{2} b^2 \pi x^2\right ) \operatorname {FresnelC}(b x)}{3 x^2}-\frac {\operatorname {FresnelC}(b x)^2}{3 x^3}-\frac {1}{3} \left (b^3 \pi \right ) \int \frac {\operatorname {FresnelC}(b x) \sin \left (\frac {1}{2} b^2 \pi x^2\right )}{x} \, dx-\frac {1}{3} \left (b^4 \pi \right ) \int \sin \left (b^2 \pi x^2\right ) \, dx \\ & = -\frac {b^2}{6 x}-\frac {b^2 \cos \left (b^2 \pi x^2\right )}{6 x}-\frac {b \cos \left (\frac {1}{2} b^2 \pi x^2\right ) \operatorname {FresnelC}(b x)}{3 x^2}-\frac {\operatorname {FresnelC}(b x)^2}{3 x^3}-\frac {b^3 \pi \operatorname {FresnelS}\left (\sqrt {2} b x\right )}{3 \sqrt {2}}-\frac {1}{3} \left (b^3 \pi \right ) \int \frac {\operatorname {FresnelC}(b x) \sin \left (\frac {1}{2} b^2 \pi x^2\right )}{x} \, dx \\ \end{align*}
Not integrable
Time = 0.02 (sec) , antiderivative size = 12, normalized size of antiderivative = 1.20 \[ \int \frac {\operatorname {FresnelC}(b x)^2}{x^4} \, dx=\int \frac {\operatorname {FresnelC}(b x)^2}{x^4} \, dx \]
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Not integrable
Time = 0.06 (sec) , antiderivative size = 10, normalized size of antiderivative = 1.00
\[\int \frac {\operatorname {FresnelC}\left (b x \right )^{2}}{x^{4}}d x\]
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Not integrable
Time = 0.26 (sec) , antiderivative size = 12, normalized size of antiderivative = 1.20 \[ \int \frac {\operatorname {FresnelC}(b x)^2}{x^4} \, dx=\int { \frac {\operatorname {C}\left (b x\right )^{2}}{x^{4}} \,d x } \]
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Not integrable
Time = 1.11 (sec) , antiderivative size = 10, normalized size of antiderivative = 1.00 \[ \int \frac {\operatorname {FresnelC}(b x)^2}{x^4} \, dx=\int \frac {C^{2}\left (b x\right )}{x^{4}}\, dx \]
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Not integrable
Time = 0.22 (sec) , antiderivative size = 12, normalized size of antiderivative = 1.20 \[ \int \frac {\operatorname {FresnelC}(b x)^2}{x^4} \, dx=\int { \frac {\operatorname {C}\left (b x\right )^{2}}{x^{4}} \,d x } \]
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Not integrable
Time = 0.26 (sec) , antiderivative size = 12, normalized size of antiderivative = 1.20 \[ \int \frac {\operatorname {FresnelC}(b x)^2}{x^4} \, dx=\int { \frac {\operatorname {C}\left (b x\right )^{2}}{x^{4}} \,d x } \]
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Not integrable
Time = 4.96 (sec) , antiderivative size = 12, normalized size of antiderivative = 1.20 \[ \int \frac {\operatorname {FresnelC}(b x)^2}{x^4} \, dx=\int \frac {{\mathrm {FresnelC}\left (b\,x\right )}^2}{x^4} \,d x \]
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