Integrand size = 10, antiderivative size = 10 \[ \int \frac {\operatorname {FresnelS}(b x)^2}{x^6} \, dx=-\frac {b^2}{60 x^3}+\frac {b^2 \cos \left (b^2 \pi x^2\right )}{60 x^3}+\frac {7 b^5 \pi ^2 \operatorname {FresnelC}\left (\sqrt {2} b x\right )}{60 \sqrt {2}}-\frac {b^3 \pi \cos \left (\frac {1}{2} b^2 \pi x^2\right ) \operatorname {FresnelS}(b x)}{20 x^2}-\frac {\operatorname {FresnelS}(b x)^2}{5 x^5}-\frac {b \operatorname {FresnelS}(b x) \sin \left (\frac {1}{2} b^2 \pi x^2\right )}{10 x^4}-\frac {7 b^4 \pi \sin \left (b^2 \pi x^2\right )}{120 x}-\frac {1}{20} b^5 \pi ^2 \text {Int}\left (\frac {\operatorname {FresnelS}(b x) \sin \left (\frac {1}{2} b^2 \pi x^2\right )}{x},x\right ) \]
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Not integrable
Time = 0.10 (sec) , antiderivative size = 10, normalized size of antiderivative = 1.00, number of steps used = 0, number of rules used = 0, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.000, Rules used = {} \[ \int \frac {\operatorname {FresnelS}(b x)^2}{x^6} \, dx=\int \frac {\operatorname {FresnelS}(b x)^2}{x^6} \, dx \]
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Rubi steps \begin{align*} \text {integral}& = -\frac {\operatorname {FresnelS}(b x)^2}{5 x^5}+\frac {1}{5} (2 b) \int \frac {\operatorname {FresnelS}(b x) \sin \left (\frac {1}{2} b^2 \pi x^2\right )}{x^5} \, dx \\ & = -\frac {b^2}{60 x^3}-\frac {\operatorname {FresnelS}(b x)^2}{5 x^5}-\frac {b \operatorname {FresnelS}(b x) \sin \left (\frac {1}{2} b^2 \pi x^2\right )}{10 x^4}-\frac {1}{20} b^2 \int \frac {\cos \left (b^2 \pi x^2\right )}{x^4} \, dx+\frac {1}{10} \left (b^3 \pi \right ) \int \frac {\cos \left (\frac {1}{2} b^2 \pi x^2\right ) \operatorname {FresnelS}(b x)}{x^3} \, dx \\ & = -\frac {b^2}{60 x^3}+\frac {b^2 \cos \left (b^2 \pi x^2\right )}{60 x^3}-\frac {b^3 \pi \cos \left (\frac {1}{2} b^2 \pi x^2\right ) \operatorname {FresnelS}(b x)}{20 x^2}-\frac {\operatorname {FresnelS}(b x)^2}{5 x^5}-\frac {b \operatorname {FresnelS}(b x) \sin \left (\frac {1}{2} b^2 \pi x^2\right )}{10 x^4}+\frac {1}{40} \left (b^4 \pi \right ) \int \frac {\sin \left (b^2 \pi x^2\right )}{x^2} \, dx+\frac {1}{30} \left (b^4 \pi \right ) \int \frac {\sin \left (b^2 \pi x^2\right )}{x^2} \, dx-\frac {1}{20} \left (b^5 \pi ^2\right ) \int \frac {\operatorname {FresnelS}(b x) \sin \left (\frac {1}{2} b^2 \pi x^2\right )}{x} \, dx \\ & = -\frac {b^2}{60 x^3}+\frac {b^2 \cos \left (b^2 \pi x^2\right )}{60 x^3}-\frac {b^3 \pi \cos \left (\frac {1}{2} b^2 \pi x^2\right ) \operatorname {FresnelS}(b x)}{20 x^2}-\frac {\operatorname {FresnelS}(b x)^2}{5 x^5}-\frac {b \operatorname {FresnelS}(b x) \sin \left (\frac {1}{2} b^2 \pi x^2\right )}{10 x^4}-\frac {7 b^4 \pi \sin \left (b^2 \pi x^2\right )}{120 x}-\frac {1}{20} \left (b^5 \pi ^2\right ) \int \frac {\operatorname {FresnelS}(b x) \sin \left (\frac {1}{2} b^2 \pi x^2\right )}{x} \, dx+\frac {1}{20} \left (b^6 \pi ^2\right ) \int \cos \left (b^2 \pi x^2\right ) \, dx+\frac {1}{15} \left (b^6 \pi ^2\right ) \int \cos \left (b^2 \pi x^2\right ) \, dx \\ & = -\frac {b^2}{60 x^3}+\frac {b^2 \cos \left (b^2 \pi x^2\right )}{60 x^3}+\frac {7 b^5 \pi ^2 \operatorname {FresnelC}\left (\sqrt {2} b x\right )}{60 \sqrt {2}}-\frac {b^3 \pi \cos \left (\frac {1}{2} b^2 \pi x^2\right ) \operatorname {FresnelS}(b x)}{20 x^2}-\frac {\operatorname {FresnelS}(b x)^2}{5 x^5}-\frac {b \operatorname {FresnelS}(b x) \sin \left (\frac {1}{2} b^2 \pi x^2\right )}{10 x^4}-\frac {7 b^4 \pi \sin \left (b^2 \pi x^2\right )}{120 x}-\frac {1}{20} \left (b^5 \pi ^2\right ) \int \frac {\operatorname {FresnelS}(b x) \sin \left (\frac {1}{2} b^2 \pi x^2\right )}{x} \, dx \\ \end{align*}
Not integrable
Time = 0.02 (sec) , antiderivative size = 12, normalized size of antiderivative = 1.20 \[ \int \frac {\operatorname {FresnelS}(b x)^2}{x^6} \, dx=\int \frac {\operatorname {FresnelS}(b x)^2}{x^6} \, dx \]
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Not integrable
Time = 0.08 (sec) , antiderivative size = 10, normalized size of antiderivative = 1.00
\[\int \frac {\operatorname {FresnelS}\left (b x \right )^{2}}{x^{6}}d x\]
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Not integrable
Time = 0.26 (sec) , antiderivative size = 12, normalized size of antiderivative = 1.20 \[ \int \frac {\operatorname {FresnelS}(b x)^2}{x^6} \, dx=\int { \frac {\operatorname {S}\left (b x\right )^{2}}{x^{6}} \,d x } \]
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Not integrable
Time = 1.40 (sec) , antiderivative size = 10, normalized size of antiderivative = 1.00 \[ \int \frac {\operatorname {FresnelS}(b x)^2}{x^6} \, dx=\int \frac {S^{2}\left (b x\right )}{x^{6}}\, dx \]
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Not integrable
Time = 0.21 (sec) , antiderivative size = 12, normalized size of antiderivative = 1.20 \[ \int \frac {\operatorname {FresnelS}(b x)^2}{x^6} \, dx=\int { \frac {\operatorname {S}\left (b x\right )^{2}}{x^{6}} \,d x } \]
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Not integrable
Time = 0.26 (sec) , antiderivative size = 12, normalized size of antiderivative = 1.20 \[ \int \frac {\operatorname {FresnelS}(b x)^2}{x^6} \, dx=\int { \frac {\operatorname {S}\left (b x\right )^{2}}{x^{6}} \,d x } \]
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Not integrable
Time = 4.80 (sec) , antiderivative size = 12, normalized size of antiderivative = 1.20 \[ \int \frac {\operatorname {FresnelS}(b x)^2}{x^6} \, dx=\int \frac {{\mathrm {FresnelS}\left (b\,x\right )}^2}{x^6} \,d x \]
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