Integrand size = 20, antiderivative size = 109 \[ \int \frac {\operatorname {FresnelS}(b x) \sin \left (\frac {1}{2} b^2 \pi x^2\right )}{x^4} \, dx=-\frac {b}{12 x^2}+\frac {b \cos \left (b^2 \pi x^2\right )}{12 x^2}-\frac {b^2 \pi \cos \left (\frac {1}{2} b^2 \pi x^2\right ) \operatorname {FresnelS}(b x)}{3 x}-\frac {1}{6} b^3 \pi ^2 \operatorname {FresnelS}(b x)^2-\frac {\operatorname {FresnelS}(b x) \sin \left (\frac {1}{2} b^2 \pi x^2\right )}{3 x^3}+\frac {1}{6} b^3 \pi \text {Si}\left (b^2 \pi x^2\right ) \]
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Time = 0.08 (sec) , antiderivative size = 109, normalized size of antiderivative = 1.00, number of steps used = 8, number of rules used = 8, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.400, Rules used = {6591, 6599, 6575, 30, 3456, 3461, 3378, 3380} \[ \int \frac {\operatorname {FresnelS}(b x) \sin \left (\frac {1}{2} b^2 \pi x^2\right )}{x^4} \, dx=-\frac {1}{6} \pi ^2 b^3 \operatorname {FresnelS}(b x)^2-\frac {\pi b^2 \operatorname {FresnelS}(b x) \cos \left (\frac {1}{2} \pi b^2 x^2\right )}{3 x}-\frac {\operatorname {FresnelS}(b x) \sin \left (\frac {1}{2} \pi b^2 x^2\right )}{3 x^3}+\frac {b \cos \left (\pi b^2 x^2\right )}{12 x^2}+\frac {1}{6} \pi b^3 \text {Si}\left (b^2 \pi x^2\right )-\frac {b}{12 x^2} \]
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Rule 30
Rule 3378
Rule 3380
Rule 3456
Rule 3461
Rule 6575
Rule 6591
Rule 6599
Rubi steps \begin{align*} \text {integral}& = -\frac {b}{12 x^2}-\frac {\operatorname {FresnelS}(b x) \sin \left (\frac {1}{2} b^2 \pi x^2\right )}{3 x^3}-\frac {1}{6} b \int \frac {\cos \left (b^2 \pi x^2\right )}{x^3} \, dx+\frac {1}{3} \left (b^2 \pi \right ) \int \frac {\cos \left (\frac {1}{2} b^2 \pi x^2\right ) \operatorname {FresnelS}(b x)}{x^2} \, dx \\ & = -\frac {b}{12 x^2}-\frac {b^2 \pi \cos \left (\frac {1}{2} b^2 \pi x^2\right ) \operatorname {FresnelS}(b x)}{3 x}-\frac {\operatorname {FresnelS}(b x) \sin \left (\frac {1}{2} b^2 \pi x^2\right )}{3 x^3}-\frac {1}{12} b \text {Subst}\left (\int \frac {\cos \left (b^2 \pi x\right )}{x^2} \, dx,x,x^2\right )+\frac {1}{6} \left (b^3 \pi \right ) \int \frac {\sin \left (b^2 \pi x^2\right )}{x} \, dx-\frac {1}{3} \left (b^4 \pi ^2\right ) \int \operatorname {FresnelS}(b x) \sin \left (\frac {1}{2} b^2 \pi x^2\right ) \, dx \\ & = -\frac {b}{12 x^2}+\frac {b \cos \left (b^2 \pi x^2\right )}{12 x^2}-\frac {b^2 \pi \cos \left (\frac {1}{2} b^2 \pi x^2\right ) \operatorname {FresnelS}(b x)}{3 x}-\frac {\operatorname {FresnelS}(b x) \sin \left (\frac {1}{2} b^2 \pi x^2\right )}{3 x^3}+\frac {1}{12} b^3 \pi \text {Si}\left (b^2 \pi x^2\right )+\frac {1}{12} \left (b^3 \pi \right ) \text {Subst}\left (\int \frac {\sin \left (b^2 \pi x\right )}{x} \, dx,x,x^2\right )-\frac {1}{3} \left (b^3 \pi ^2\right ) \text {Subst}(\int x \, dx,x,\operatorname {FresnelS}(b x)) \\ & = -\frac {b}{12 x^2}+\frac {b \cos \left (b^2 \pi x^2\right )}{12 x^2}-\frac {b^2 \pi \cos \left (\frac {1}{2} b^2 \pi x^2\right ) \operatorname {FresnelS}(b x)}{3 x}-\frac {1}{6} b^3 \pi ^2 \operatorname {FresnelS}(b x)^2-\frac {\operatorname {FresnelS}(b x) \sin \left (\frac {1}{2} b^2 \pi x^2\right )}{3 x^3}+\frac {1}{6} b^3 \pi \text {Si}\left (b^2 \pi x^2\right ) \\ \end{align*}
Time = 0.01 (sec) , antiderivative size = 109, normalized size of antiderivative = 1.00 \[ \int \frac {\operatorname {FresnelS}(b x) \sin \left (\frac {1}{2} b^2 \pi x^2\right )}{x^4} \, dx=-\frac {b}{12 x^2}+\frac {b \cos \left (b^2 \pi x^2\right )}{12 x^2}-\frac {b^2 \pi \cos \left (\frac {1}{2} b^2 \pi x^2\right ) \operatorname {FresnelS}(b x)}{3 x}-\frac {1}{6} b^3 \pi ^2 \operatorname {FresnelS}(b x)^2-\frac {\operatorname {FresnelS}(b x) \sin \left (\frac {1}{2} b^2 \pi x^2\right )}{3 x^3}+\frac {1}{6} b^3 \pi \text {Si}\left (b^2 \pi x^2\right ) \]
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\[\int \frac {\operatorname {FresnelS}\left (b x \right ) \sin \left (\frac {b^{2} \pi \,x^{2}}{2}\right )}{x^{4}}d x\]
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none
Time = 0.28 (sec) , antiderivative size = 98, normalized size of antiderivative = 0.90 \[ \int \frac {\operatorname {FresnelS}(b x) \sin \left (\frac {1}{2} b^2 \pi x^2\right )}{x^4} \, dx=-\frac {\pi ^{2} b^{3} x^{3} \operatorname {S}\left (b x\right )^{2} - \pi b^{3} x^{3} \operatorname {Si}\left (\pi b^{2} x^{2}\right ) + 2 \, \pi b^{2} x^{2} \cos \left (\frac {1}{2} \, \pi b^{2} x^{2}\right ) \operatorname {S}\left (b x\right ) - b x \cos \left (\frac {1}{2} \, \pi b^{2} x^{2}\right )^{2} + b x + 2 \, \operatorname {S}\left (b x\right ) \sin \left (\frac {1}{2} \, \pi b^{2} x^{2}\right )}{6 \, x^{3}} \]
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\[ \int \frac {\operatorname {FresnelS}(b x) \sin \left (\frac {1}{2} b^2 \pi x^2\right )}{x^4} \, dx=\int \frac {\sin {\left (\frac {\pi b^{2} x^{2}}{2} \right )} S\left (b x\right )}{x^{4}}\, dx \]
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\[ \int \frac {\operatorname {FresnelS}(b x) \sin \left (\frac {1}{2} b^2 \pi x^2\right )}{x^4} \, dx=\int { \frac {\operatorname {S}\left (b x\right ) \sin \left (\frac {1}{2} \, \pi b^{2} x^{2}\right )}{x^{4}} \,d x } \]
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\[ \int \frac {\operatorname {FresnelS}(b x) \sin \left (\frac {1}{2} b^2 \pi x^2\right )}{x^4} \, dx=\int { \frac {\operatorname {S}\left (b x\right ) \sin \left (\frac {1}{2} \, \pi b^{2} x^{2}\right )}{x^{4}} \,d x } \]
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Timed out. \[ \int \frac {\operatorname {FresnelS}(b x) \sin \left (\frac {1}{2} b^2 \pi x^2\right )}{x^4} \, dx=\int \frac {\mathrm {FresnelS}\left (b\,x\right )\,\sin \left (\frac {\Pi \,b^2\,x^2}{2}\right )}{x^4} \,d x \]
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