\(\int x^m \text {Shi}(b x) \, dx\) [1]

   Optimal result
   Rubi [A] (verified)
   Mathematica [A] (verified)
   Maple [C] (verified)
   Fricas [F]
   Sympy [A] (verification not implemented)
   Maxima [F]
   Giac [F]
   Mupad [F(-1)]

Optimal result

Integrand size = 8, antiderivative size = 76 \[ \int x^m \text {Shi}(b x) \, dx=-\frac {x^m (-b x)^{-m} \Gamma (1+m,-b x)}{2 b (1+m)}-\frac {x^m (b x)^{-m} \Gamma (1+m,b x)}{2 b (1+m)}+\frac {x^{1+m} \text {Shi}(b x)}{1+m} \]

[Out]

-1/2*x^m*GAMMA(1+m,-b*x)/b/(1+m)/((-b*x)^m)-1/2*x^m*GAMMA(1+m,b*x)/b/(1+m)/((b*x)^m)+x^(1+m)*Shi(b*x)/(1+m)

Rubi [A] (verified)

Time = 0.05 (sec) , antiderivative size = 76, normalized size of antiderivative = 1.00, number of steps used = 5, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.500, Rules used = {6667, 12, 3389, 2212} \[ \int x^m \text {Shi}(b x) \, dx=\frac {x^{m+1} \text {Shi}(b x)}{m+1}-\frac {x^m (-b x)^{-m} \Gamma (m+1,-b x)}{2 b (m+1)}-\frac {x^m (b x)^{-m} \Gamma (m+1,b x)}{2 b (m+1)} \]

[In]

Int[x^m*SinhIntegral[b*x],x]

[Out]

-1/2*(x^m*Gamma[1 + m, -(b*x)])/(b*(1 + m)*(-(b*x))^m) - (x^m*Gamma[1 + m, b*x])/(2*b*(1 + m)*(b*x)^m) + (x^(1
 + m)*SinhIntegral[b*x])/(1 + m)

Rule 12

Int[(a_)*(u_), x_Symbol] :> Dist[a, Int[u, x], x] /; FreeQ[a, x] &&  !MatchQ[u, (b_)*(v_) /; FreeQ[b, x]]

Rule 2212

Int[(F_)^((g_.)*((e_.) + (f_.)*(x_)))*((c_.) + (d_.)*(x_))^(m_), x_Symbol] :> Simp[(-F^(g*(e - c*(f/d))))*((c
+ d*x)^FracPart[m]/(d*((-f)*g*(Log[F]/d))^(IntPart[m] + 1)*((-f)*g*Log[F]*((c + d*x)/d))^FracPart[m]))*Gamma[m
 + 1, ((-f)*g*(Log[F]/d))*(c + d*x)], x] /; FreeQ[{F, c, d, e, f, g, m}, x] &&  !IntegerQ[m]

Rule 3389

Int[((c_.) + (d_.)*(x_))^(m_.)*sin[(e_.) + (f_.)*(x_)], x_Symbol] :> Dist[I/2, Int[(c + d*x)^m/E^(I*(e + f*x))
, x], x] - Dist[I/2, Int[(c + d*x)^m*E^(I*(e + f*x)), x], x] /; FreeQ[{c, d, e, f, m}, x]

Rule 6667

Int[((c_.) + (d_.)*(x_))^(m_.)*SinhIntegral[(a_.) + (b_.)*(x_)], x_Symbol] :> Simp[(c + d*x)^(m + 1)*(SinhInte
gral[a + b*x]/(d*(m + 1))), x] - Dist[b/(d*(m + 1)), Int[(c + d*x)^(m + 1)*(Sinh[a + b*x]/(a + b*x)), x], x] /
; FreeQ[{a, b, c, d, m}, x] && NeQ[m, -1]

Rubi steps \begin{align*} \text {integral}& = \frac {x^{1+m} \text {Shi}(b x)}{1+m}-\frac {b \int \frac {x^m \sinh (b x)}{b} \, dx}{1+m} \\ & = \frac {x^{1+m} \text {Shi}(b x)}{1+m}-\frac {\int x^m \sinh (b x) \, dx}{1+m} \\ & = \frac {x^{1+m} \text {Shi}(b x)}{1+m}+\frac {\int e^{-b x} x^m \, dx}{2 (1+m)}-\frac {\int e^{b x} x^m \, dx}{2 (1+m)} \\ & = -\frac {x^m (-b x)^{-m} \Gamma (1+m,-b x)}{2 b (1+m)}-\frac {x^m (b x)^{-m} \Gamma (1+m,b x)}{2 b (1+m)}+\frac {x^{1+m} \text {Shi}(b x)}{1+m} \\ \end{align*}

Mathematica [A] (verified)

Time = 0.09 (sec) , antiderivative size = 56, normalized size of antiderivative = 0.74 \[ \int x^m \text {Shi}(b x) \, dx=-\frac {x^m \left ((-b x)^{-m} \Gamma (1+m,-b x)+(b x)^{-m} \Gamma (1+m,b x)-2 b x \text {Shi}(b x)\right )}{2 b (1+m)} \]

[In]

Integrate[x^m*SinhIntegral[b*x],x]

[Out]

-1/2*(x^m*(Gamma[1 + m, -(b*x)]/(-(b*x))^m + Gamma[1 + m, b*x]/(b*x)^m - 2*b*x*SinhIntegral[b*x]))/(b*(1 + m))

Maple [C] (verified)

Result contains higher order function than in optimal. Order 5 vs. order 4.

Time = 0.60 (sec) , antiderivative size = 37, normalized size of antiderivative = 0.49

method result size
meijerg \(\frac {b \,x^{2+m} \operatorname {hypergeom}\left (\left [\frac {1}{2}, 1+\frac {m}{2}\right ], \left [\frac {3}{2}, \frac {3}{2}, 2+\frac {m}{2}\right ], \frac {b^{2} x^{2}}{4}\right )}{2+m}\) \(37\)

[In]

int(x^m*Shi(b*x),x,method=_RETURNVERBOSE)

[Out]

b/(2+m)*x^(2+m)*hypergeom([1/2,1+1/2*m],[3/2,3/2,2+1/2*m],1/4*b^2*x^2)

Fricas [F]

\[ \int x^m \text {Shi}(b x) \, dx=\int { x^{m} {\rm Shi}\left (b x\right ) \,d x } \]

[In]

integrate(x^m*Shi(b*x),x, algorithm="fricas")

[Out]

integral(x^m*sinh_integral(b*x), x)

Sympy [A] (verification not implemented)

Time = 0.57 (sec) , antiderivative size = 42, normalized size of antiderivative = 0.55 \[ \int x^m \text {Shi}(b x) \, dx=\frac {b x^{m + 2} \Gamma \left (\frac {m}{2} + 1\right ) {{}_{2}F_{3}\left (\begin {matrix} \frac {1}{2}, \frac {m}{2} + 1 \\ \frac {3}{2}, \frac {3}{2}, \frac {m}{2} + 2 \end {matrix}\middle | {\frac {b^{2} x^{2}}{4}} \right )}}{2 \Gamma \left (\frac {m}{2} + 2\right )} \]

[In]

integrate(x**m*Shi(b*x),x)

[Out]

b*x**(m + 2)*gamma(m/2 + 1)*hyper((1/2, m/2 + 1), (3/2, 3/2, m/2 + 2), b**2*x**2/4)/(2*gamma(m/2 + 2))

Maxima [F]

\[ \int x^m \text {Shi}(b x) \, dx=\int { x^{m} {\rm Shi}\left (b x\right ) \,d x } \]

[In]

integrate(x^m*Shi(b*x),x, algorithm="maxima")

[Out]

integrate(x^m*Shi(b*x), x)

Giac [F]

\[ \int x^m \text {Shi}(b x) \, dx=\int { x^{m} {\rm Shi}\left (b x\right ) \,d x } \]

[In]

integrate(x^m*Shi(b*x),x, algorithm="giac")

[Out]

integrate(x^m*Shi(b*x), x)

Mupad [F(-1)]

Timed out. \[ \int x^m \text {Shi}(b x) \, dx=\int x^m\,\mathrm {sinhint}\left (b\,x\right ) \,d x \]

[In]

int(x^m*sinhint(b*x),x)

[Out]

int(x^m*sinhint(b*x), x)