\(\int x \text {Shi}(b x)^2 \, dx\) [12]

Optimal result

Integrand size = 8, antiderivative size = 74 \[ \int x \text {Shi}(b x)^2 \, dx=-\frac {\text {Chi}(2 b x)}{2 b^2}+\frac {\log (x)}{2 b^2}+\frac {\sinh ^2(b x)}{2 b^2}-\frac {x \cosh (b x) \text {Shi}(b x)}{b}+\frac {\sinh (b x) \text {Shi}(b x)}{b^2}+\frac {1}{2} x^2 \text {Shi}(b x)^2 \]

[Out]

-1/2*Chi(2*b*x)/b^2+1/2*ln(x)/b^2-x*cosh(b*x)*Shi(b*x)/b+1/2*x^2*Shi(b*x)^2+Shi(b*x)*sinh(b*x)/b^2+1/2*sinh(b*
x)^2/b^2

Rubi [A] (verified)

Time = 0.07 (sec) , antiderivative size = 74, normalized size of antiderivative = 1.00, number of steps used = 10, number of rules used = 8, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 1.000, Rules used = {6671, 6677, 12, 2644, 30, 6681, 3393, 3382} \[ \int x \text {Shi}(b x)^2 \, dx=-\frac {\text {Chi}(2 b x)}{2 b^2}+\frac {\text {Shi}(b x) \sinh (b x)}{b^2}+\frac {\log (x)}{2 b^2}+\frac {\sinh ^2(b x)}{2 b^2}+\frac {1}{2} x^2 \text {Shi}(b x)^2-\frac {x \text {Shi}(b x) \cosh (b x)}{b} \]

[In]

Int[x*SinhIntegral[b*x]^2,x]

[Out]

-1/2*CoshIntegral[2*b*x]/b^2 + Log[x]/(2*b^2) + Sinh[b*x]^2/(2*b^2) - (x*Cosh[b*x]*SinhIntegral[b*x])/b + (Sin
h[b*x]*SinhIntegral[b*x])/b^2 + (x^2*SinhIntegral[b*x]^2)/2

Rule 12

Int[(a_)*(u_), x_Symbol] :> Dist[a, Int[u, x], x] /; FreeQ[a, x] &&  !MatchQ[u, (b_)*(v_) /; FreeQ[b, x]]

Rule 30

Int[(x_)^(m_.), x_Symbol] :> Simp[x^(m + 1)/(m + 1), x] /; FreeQ[m, x] && NeQ[m, -1]

Rule 2644

Int[cos[(e_.) + (f_.)*(x_)]^(n_.)*((a_.)*sin[(e_.) + (f_.)*(x_)])^(m_.), x_Symbol] :> Dist[1/(a*f), Subst[Int[
x^m*(1 - x^2/a^2)^((n - 1)/2), x], x, a*Sin[e + f*x]], x] /; FreeQ[{a, e, f, m}, x] && IntegerQ[(n - 1)/2] &&
!(IntegerQ[(m - 1)/2] && LtQ[0, m, n])

Rule 3382

Int[sin[(e_.) + (Complex[0, fz_])*(f_.)*(x_)]/((c_.) + (d_.)*(x_)), x_Symbol] :> Simp[CoshIntegral[c*f*(fz/d)
+ f*fz*x]/d, x] /; FreeQ[{c, d, e, f, fz}, x] && EqQ[d*(e - Pi/2) - c*f*fz*I, 0]

Rule 3393

Int[((c_.) + (d_.)*(x_))^(m_)*sin[(e_.) + (f_.)*(x_)]^(n_), x_Symbol] :> Int[ExpandTrigReduce[(c + d*x)^m, Sin
[e + f*x]^n, x], x] /; FreeQ[{c, d, e, f, m}, x] && IGtQ[n, 1] && ( !RationalQ[m] || (GeQ[m, -1] && LtQ[m, 1])
)

Rule 6671

Int[(x_)^(m_.)*SinhIntegral[(b_.)*(x_)]^2, x_Symbol] :> Simp[x^(m + 1)*(SinhIntegral[b*x]^2/(m + 1)), x] - Dis
t[2/(m + 1), Int[x^m*Sinh[b*x]*SinhIntegral[b*x], x], x] /; FreeQ[b, x] && IGtQ[m, 0]

Rule 6677

Int[((e_.) + (f_.)*(x_))^(m_.)*Sinh[(a_.) + (b_.)*(x_)]*SinhIntegral[(c_.) + (d_.)*(x_)], x_Symbol] :> Simp[(e
+ f*x)^m*Cosh[a + b*x]*(SinhIntegral[c + d*x]/b), x] + (-Dist[d/b, Int[(e + f*x)^m*Cosh[a + b*x]*(Sinh[c + d*
x]/(c + d*x)), x], x] - Dist[f*(m/b), Int[(e + f*x)^(m - 1)*Cosh[a + b*x]*SinhIntegral[c + d*x], x], x]) /; Fr
eeQ[{a, b, c, d, e, f}, x] && IGtQ[m, 0]

Rule 6681

Int[Cosh[(a_.) + (b_.)*(x_)]*SinhIntegral[(c_.) + (d_.)*(x_)], x_Symbol] :> Simp[Sinh[a + b*x]*(SinhIntegral[c
+ d*x]/b), x] - Dist[d/b, Int[Sinh[a + b*x]*(Sinh[c + d*x]/(c + d*x)), x], x] /; FreeQ[{a, b, c, d}, x]

Rubi steps \begin{align*} \text {integral}& = \frac {1}{2} x^2 \text {Shi}(b x)^2-\int x \sinh (b x) \text {Shi}(b x) \, dx \\ & = -\frac {x \cosh (b x) \text {Shi}(b x)}{b}+\frac {1}{2} x^2 \text {Shi}(b x)^2+\frac {\int \cosh (b x) \text {Shi}(b x) \, dx}{b}+\int \frac {\cosh (b x) \sinh (b x)}{b} \, dx \\ & = -\frac {x \cosh (b x) \text {Shi}(b x)}{b}+\frac {\sinh (b x) \text {Shi}(b x)}{b^2}+\frac {1}{2} x^2 \text {Shi}(b x)^2+\frac {\int \cosh (b x) \sinh (b x) \, dx}{b}-\frac {\int \frac {\sinh ^2(b x)}{b x} \, dx}{b} \\ & = -\frac {x \cosh (b x) \text {Shi}(b x)}{b}+\frac {\sinh (b x) \text {Shi}(b x)}{b^2}+\frac {1}{2} x^2 \text {Shi}(b x)^2-\frac {\int \frac {\sinh ^2(b x)}{x} \, dx}{b^2}-\frac {\text {Subst}(\int x \, dx,x,i \sinh (b x))}{b^2} \\ & = \frac {\sinh ^2(b x)}{2 b^2}-\frac {x \cosh (b x) \text {Shi}(b x)}{b}+\frac {\sinh (b x) \text {Shi}(b x)}{b^2}+\frac {1}{2} x^2 \text {Shi}(b x)^2+\frac {\int \left (\frac {1}{2 x}-\frac {\cosh (2 b x)}{2 x}\right ) \, dx}{b^2} \\ & = \frac {\log (x)}{2 b^2}+\frac {\sinh ^2(b x)}{2 b^2}-\frac {x \cosh (b x) \text {Shi}(b x)}{b}+\frac {\sinh (b x) \text {Shi}(b x)}{b^2}+\frac {1}{2} x^2 \text {Shi}(b x)^2-\frac {\int \frac {\cosh (2 b x)}{x} \, dx}{2 b^2} \\ & = -\frac {\text {Chi}(2 b x)}{2 b^2}+\frac {\log (x)}{2 b^2}+\frac {\sinh ^2(b x)}{2 b^2}-\frac {x \cosh (b x) \text {Shi}(b x)}{b}+\frac {\sinh (b x) \text {Shi}(b x)}{b^2}+\frac {1}{2} x^2 \text {Shi}(b x)^2 \\ \end{align*}

Mathematica [A] (verified)

Time = 0.04 (sec) , antiderivative size = 58, normalized size of antiderivative = 0.78 \[ \int x \text {Shi}(b x)^2 \, dx=\frac {\cosh (2 b x)-2 \text {Chi}(2 b x)+2 \log (x)+(-4 b x \cosh (b x)+4 \sinh (b x)) \text {Shi}(b x)+2 b^2 x^2 \text {Shi}(b x)^2}{4 b^2} \]

[In]

Integrate[x*SinhIntegral[b*x]^2,x]

[Out]

(Cosh[2*b*x] - 2*CoshIntegral[2*b*x] + 2*Log[x] + (-4*b*x*Cosh[b*x] + 4*Sinh[b*x])*SinhIntegral[b*x] + 2*b^2*x
^2*SinhIntegral[b*x]^2)/(4*b^2)

Maple [A] (verified)

Time = 0.57 (sec) , antiderivative size = 62, normalized size of antiderivative = 0.84

method	result	size
derivativedivides	\(\frac {\frac {b^{2} x^{2} \operatorname {Shi}\left (b x \right )^{2}}{2}-2 \,\operatorname {Shi}\left (b x \right ) \left (\frac {b x \cosh \left (b x \right )}{2}-\frac {\sinh \left (b x \right )}{2}\right )+\frac {\cosh \left (b x \right )^{2}}{2}+\frac {\ln \left (b x \right )}{2}-\frac {\operatorname {Chi}\left (2 b x \right )}{2}}{b^{2}}\)	\(62\)
default	\(\frac {\frac {b^{2} x^{2} \operatorname {Shi}\left (b x \right )^{2}}{2}-2 \,\operatorname {Shi}\left (b x \right ) \left (\frac {b x \cosh \left (b x \right )}{2}-\frac {\sinh \left (b x \right )}{2}\right )+\frac {\cosh \left (b x \right )^{2}}{2}+\frac {\ln \left (b x \right )}{2}-\frac {\operatorname {Chi}\left (2 b x \right )}{2}}{b^{2}}\)	\(62\)

[In]

int(x*Shi(b*x)^2,x,method=_RETURNVERBOSE)

[Out]

1/b^2*(1/2*b^2*x^2*Shi(b*x)^2-2*Shi(b*x)*(1/2*b*x*cosh(b*x)-1/2*sinh(b*x))+1/2*cosh(b*x)^2+1/2*ln(b*x)-1/2*Chi
(2*b*x))

Fricas [F]

\[ \int x \text {Shi}(b x)^2 \, dx=\int { x {\rm Shi}\left (b x\right )^{2} \,d x } \]

[In]

integrate(x*Shi(b*x)^2,x, algorithm="fricas")

[Out]

integral(x*sinh_integral(b*x)^2, x)

Sympy [F]

\[ \int x \text {Shi}(b x)^2 \, dx=\int x \operatorname {Shi}^{2}{\left (b x \right )}\, dx \]

[In]

integrate(x*Shi(b*x)**2,x)

[Out]

Integral(x*Shi(b*x)**2, x)

Maxima [F]

\[ \int x \text {Shi}(b x)^2 \, dx=\int { x {\rm Shi}\left (b x\right )^{2} \,d x } \]

[In]

integrate(x*Shi(b*x)^2,x, algorithm="maxima")

[Out]

integrate(x*Shi(b*x)^2, x)

Giac [F]

\[ \int x \text {Shi}(b x)^2 \, dx=\int { x {\rm Shi}\left (b x\right )^{2} \,d x } \]

[In]

integrate(x*Shi(b*x)^2,x, algorithm="giac")

[Out]

integrate(x*Shi(b*x)^2, x)

Mupad [F(-1)]

Timed out. \[ \int x \text {Shi}(b x)^2 \, dx=\int x\,{\mathrm {sinhint}\left (b\,x\right )}^2 \,d x \]

[In]

int(x*sinhint(b*x)^2,x)

[Out]

int(x*sinhint(b*x)^2, x)