Integrand size = 12, antiderivative size = 12 \[ \int \frac {\cosh (b x) \text {Shi}(b x)}{x} \, dx=\text {Int}\left (\frac {\cosh (b x) \text {Shi}(b x)}{x},x\right ) \]
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Not integrable
Time = 0.02 (sec) , antiderivative size = 12, normalized size of antiderivative = 1.00, number of steps used = 0, number of rules used = 0, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.000, Rules used = {} \[ \int \frac {\cosh (b x) \text {Shi}(b x)}{x} \, dx=\int \frac {\cosh (b x) \text {Shi}(b x)}{x} \, dx \]
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Rubi steps \begin{align*} \text {integral}& = \int \frac {\cosh (b x) \text {Shi}(b x)}{x} \, dx \\ \end{align*}
Not integrable
Time = 0.18 (sec) , antiderivative size = 14, normalized size of antiderivative = 1.17 \[ \int \frac {\cosh (b x) \text {Shi}(b x)}{x} \, dx=\int \frac {\cosh (b x) \text {Shi}(b x)}{x} \, dx \]
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Not integrable
Time = 0.23 (sec) , antiderivative size = 12, normalized size of antiderivative = 1.00
\[\int \frac {\cosh \left (b x \right ) \operatorname {Shi}\left (b x \right )}{x}d x\]
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Not integrable
Time = 0.24 (sec) , antiderivative size = 14, normalized size of antiderivative = 1.17 \[ \int \frac {\cosh (b x) \text {Shi}(b x)}{x} \, dx=\int { \frac {{\rm Shi}\left (b x\right ) \cosh \left (b x\right )}{x} \,d x } \]
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Not integrable
Time = 2.42 (sec) , antiderivative size = 12, normalized size of antiderivative = 1.00 \[ \int \frac {\cosh (b x) \text {Shi}(b x)}{x} \, dx=\int \frac {\cosh {\left (b x \right )} \operatorname {Shi}{\left (b x \right )}}{x}\, dx \]
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Not integrable
Time = 0.25 (sec) , antiderivative size = 14, normalized size of antiderivative = 1.17 \[ \int \frac {\cosh (b x) \text {Shi}(b x)}{x} \, dx=\int { \frac {{\rm Shi}\left (b x\right ) \cosh \left (b x\right )}{x} \,d x } \]
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Not integrable
Time = 0.28 (sec) , antiderivative size = 14, normalized size of antiderivative = 1.17 \[ \int \frac {\cosh (b x) \text {Shi}(b x)}{x} \, dx=\int { \frac {{\rm Shi}\left (b x\right ) \cosh \left (b x\right )}{x} \,d x } \]
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Not integrable
Time = 4.99 (sec) , antiderivative size = 14, normalized size of antiderivative = 1.17 \[ \int \frac {\cosh (b x) \text {Shi}(b x)}{x} \, dx=\int \frac {\mathrm {sinhint}\left (b\,x\right )\,\mathrm {cosh}\left (b\,x\right )}{x} \,d x \]
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