Integrand size = 8, antiderivative size = 52 \[ \int \frac {\text {Chi}(b x)}{x} \, dx=-\frac {1}{2} b x \, _3F_3(1,1,1;2,2,2;-b x)+\frac {1}{2} b x \, _3F_3(1,1,1;2,2,2;b x)+\gamma \log (x)+\frac {1}{2} \log ^2(b x) \]
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Time = 0.02 (sec) , antiderivative size = 52, normalized size of antiderivative = 1.00, number of steps used = 1, number of rules used = 1, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.125, Rules used = {6666} \[ \int \frac {\text {Chi}(b x)}{x} \, dx=-\frac {1}{2} b x \, _3F_3(1,1,1;2,2,2;-b x)+\frac {1}{2} b x \, _3F_3(1,1,1;2,2,2;b x)+\frac {1}{2} \log ^2(b x)+\gamma \log (x) \]
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Rule 6666
Rubi steps \begin{align*} \text {integral}& = -\frac {1}{2} b x \, _3F_3(1,1,1;2,2,2;-b x)+\frac {1}{2} b x \, _3F_3(1,1,1;2,2,2;b x)+\gamma \log (x)+\frac {1}{2} \log ^2(b x) \\ \end{align*}
Time = 0.00 (sec) , antiderivative size = 52, normalized size of antiderivative = 1.00 \[ \int \frac {\text {Chi}(b x)}{x} \, dx=-\frac {1}{2} b x \, _3F_3(1,1,1;2,2,2;-b x)+\frac {1}{2} b x \, _3F_3(1,1,1;2,2,2;b x)+\gamma \log (x)+\frac {1}{2} \log ^2(b x) \]
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\[\int \frac {\operatorname {Chi}\left (b x \right )}{x}d x\]
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\[ \int \frac {\text {Chi}(b x)}{x} \, dx=\int { \frac {{\rm Chi}\left (b x\right )}{x} \,d x } \]
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Time = 0.92 (sec) , antiderivative size = 42, normalized size of antiderivative = 0.81 \[ \int \frac {\text {Chi}(b x)}{x} \, dx=\frac {b^{2} x^{2} {{}_{3}F_{4}\left (\begin {matrix} 1, 1, 1 \\ \frac {3}{2}, 2, 2, 2 \end {matrix}\middle | {\frac {b^{2} x^{2}}{4}} \right )}}{8} + \frac {\log {\left (b^{2} x^{2} \right )}^{2}}{8} + \frac {\gamma \log {\left (b^{2} x^{2} \right )}}{2} \]
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\[ \int \frac {\text {Chi}(b x)}{x} \, dx=\int { \frac {{\rm Chi}\left (b x\right )}{x} \,d x } \]
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\[ \int \frac {\text {Chi}(b x)}{x} \, dx=\int { \frac {{\rm Chi}\left (b x\right )}{x} \,d x } \]
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Timed out. \[ \int \frac {\text {Chi}(b x)}{x} \, dx=\int \frac {\mathrm {coshint}\left (b\,x\right )}{x} \,d x \]
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