Optimal. Leaf size=142 \[ \frac {81 a (d x)^{4+m} \, _2F_1\left (1,\frac {4+m}{3};\frac {7+m}{3};a x^3\right )}{d^4 (1+m)^4 (4+m)}+\frac {27 (d x)^{1+m} \log \left (1-a x^3\right )}{d (1+m)^4}+\frac {9 (d x)^{1+m} \text {PolyLog}\left (2,a x^3\right )}{d (1+m)^3}-\frac {3 (d x)^{1+m} \text {PolyLog}\left (3,a x^3\right )}{d (1+m)^2}+\frac {(d x)^{1+m} \text {PolyLog}\left (4,a x^3\right )}{d (1+m)} \]
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Rubi [A]
time = 0.07, antiderivative size = 142, normalized size of antiderivative = 1.00, number of steps
used = 6, number of rules used = 4, integrand size = 13, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.308, Rules used = {6726, 2505, 16,
371} \begin {gather*} \frac {81 a (d x)^{m+4} \, _2F_1\left (1,\frac {m+4}{3};\frac {m+7}{3};a x^3\right )}{d^4 (m+1)^4 (m+4)}+\frac {9 \text {Li}_2\left (a x^3\right ) (d x)^{m+1}}{d (m+1)^3}-\frac {3 \text {Li}_3\left (a x^3\right ) (d x)^{m+1}}{d (m+1)^2}+\frac {\text {Li}_4\left (a x^3\right ) (d x)^{m+1}}{d (m+1)}+\frac {27 \log \left (1-a x^3\right ) (d x)^{m+1}}{d (m+1)^4} \end {gather*}
Antiderivative was successfully verified.
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Rule 16
Rule 371
Rule 2505
Rule 6726
Rubi steps
\begin {align*} \int (d x)^m \text {Li}_4\left (a x^3\right ) \, dx &=\frac {(d x)^{1+m} \text {Li}_4\left (a x^3\right )}{d (1+m)}-\frac {3 \int (d x)^m \text {Li}_3\left (a x^3\right ) \, dx}{1+m}\\ &=-\frac {3 (d x)^{1+m} \text {Li}_3\left (a x^3\right )}{d (1+m)^2}+\frac {(d x)^{1+m} \text {Li}_4\left (a x^3\right )}{d (1+m)}+\frac {9 \int (d x)^m \text {Li}_2\left (a x^3\right ) \, dx}{(1+m)^2}\\ &=\frac {9 (d x)^{1+m} \text {Li}_2\left (a x^3\right )}{d (1+m)^3}-\frac {3 (d x)^{1+m} \text {Li}_3\left (a x^3\right )}{d (1+m)^2}+\frac {(d x)^{1+m} \text {Li}_4\left (a x^3\right )}{d (1+m)}+\frac {27 \int (d x)^m \log \left (1-a x^3\right ) \, dx}{(1+m)^3}\\ &=\frac {27 (d x)^{1+m} \log \left (1-a x^3\right )}{d (1+m)^4}+\frac {9 (d x)^{1+m} \text {Li}_2\left (a x^3\right )}{d (1+m)^3}-\frac {3 (d x)^{1+m} \text {Li}_3\left (a x^3\right )}{d (1+m)^2}+\frac {(d x)^{1+m} \text {Li}_4\left (a x^3\right )}{d (1+m)}+\frac {(81 a) \int \frac {x^2 (d x)^{1+m}}{1-a x^3} \, dx}{d (1+m)^4}\\ &=\frac {27 (d x)^{1+m} \log \left (1-a x^3\right )}{d (1+m)^4}+\frac {9 (d x)^{1+m} \text {Li}_2\left (a x^3\right )}{d (1+m)^3}-\frac {3 (d x)^{1+m} \text {Li}_3\left (a x^3\right )}{d (1+m)^2}+\frac {(d x)^{1+m} \text {Li}_4\left (a x^3\right )}{d (1+m)}+\frac {(81 a) \int \frac {(d x)^{3+m}}{1-a x^3} \, dx}{d^3 (1+m)^4}\\ &=\frac {81 a (d x)^{4+m} \, _2F_1\left (1,\frac {4+m}{3};\frac {7+m}{3};a x^3\right )}{d^4 (1+m)^4 (4+m)}+\frac {27 (d x)^{1+m} \log \left (1-a x^3\right )}{d (1+m)^4}+\frac {9 (d x)^{1+m} \text {Li}_2\left (a x^3\right )}{d (1+m)^3}-\frac {3 (d x)^{1+m} \text {Li}_3\left (a x^3\right )}{d (1+m)^2}+\frac {(d x)^{1+m} \text {Li}_4\left (a x^3\right )}{d (1+m)}\\ \end {align*}
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Mathematica [C] Result contains higher order function than in optimal. Order 9 vs. order 5 in
optimal.
time = 0.07, size = 166, normalized size = 1.17 \begin {gather*} \frac {3 x (d x)^m \Gamma \left (\frac {4+m}{3}\right ) \left (9 a (1+m) x^3 \Gamma \left (\frac {1+m}{3}\right ) \, _2\tilde {F}_1\left (1,\frac {4+m}{3};\frac {7+m}{3};a x^3\right )+27 \log \left (1-a x^3\right )+9 (1+m) \text {PolyLog}\left (2,a x^3\right )-3 \text {PolyLog}\left (3,a x^3\right )-6 m \text {PolyLog}\left (3,a x^3\right )-3 m^2 \text {PolyLog}\left (3,a x^3\right )+\text {PolyLog}\left (4,a x^3\right )+3 m \text {PolyLog}\left (4,a x^3\right )+3 m^2 \text {PolyLog}\left (4,a x^3\right )+m^3 \text {PolyLog}\left (4,a x^3\right )\right )}{(1+m)^5 \Gamma \left (\frac {1+m}{3}\right )} \end {gather*}
Antiderivative was successfully verified.
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Maple [C] Result contains higher order function than in optimal. Order 9 vs. order
5.
time = 0.49, size = 259, normalized size = 1.82
method | result | size |
meijerg | \(-\frac {\left (d x \right )^{m} x^{-m} \left (-a \right )^{-\frac {1}{3}-\frac {m}{3}} \left (\frac {3 x^{1+m} \left (-a \right )^{\frac {4}{3}+\frac {m}{3}} \left (-324-81 m \right )}{\left (4+m \right ) \left (1+m \right )^{5} a}-\frac {3 x^{1+m} \left (-a \right )^{\frac {4}{3}+\frac {m}{3}} \left (-108-27 m \right ) \ln \left (-a \,x^{3}+1\right )}{\left (4+m \right ) \left (1+m \right )^{4} a}+\frac {3 x^{1+m} \left (-a \right )^{\frac {4}{3}+\frac {m}{3}} \left (36+9 m \right ) \polylog \left (2, a \,x^{3}\right )}{\left (4+m \right ) \left (1+m \right )^{3} a}+\frac {3 x^{1+m} \left (-a \right )^{\frac {4}{3}+\frac {m}{3}} \left (-12-3 m \right ) \polylog \left (3, a \,x^{3}\right )}{\left (4+m \right ) \left (1+m \right )^{2} a}+\frac {3 x^{1+m} \left (-a \right )^{\frac {4}{3}+\frac {m}{3}} \polylog \left (4, a \,x^{3}\right )}{\left (1+m \right ) a}+\frac {3 x^{1+m} \left (-a \right )^{\frac {4}{3}+\frac {m}{3}} \left (108+27 m \right ) \Phi \left (a \,x^{3}, 1, \frac {m}{3}+\frac {1}{3}\right )}{\left (4+m \right ) \left (1+m \right )^{4} a}\right )}{3}\) | \(259\) |
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Failed to integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \left (d x\right )^{m} \operatorname {Li}_{4}\left (a x^{3}\right )\, dx \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [F]
time = 0.00, size = -1, normalized size = -0.01 \begin {gather*} \int \mathrm {polylog}\left (4,a\,x^3\right )\,{\left (d\,x\right )}^m \,d x \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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