3.2.90 \(\int \frac {(a+b x) \log (1-c x) \text {PolyLog}(2,c x)}{x^4} \, dx\) [190]

Optimal. Leaf size=460 \[ \frac {7 a c^2}{36 x}-\frac {1}{2} b c^2 \log (x)-\frac {5}{12} a c^3 \log (x)-\frac {1}{6} c^2 (3 b+2 a c) \log (x)+\frac {1}{2} b c^2 \log (1-c x)+\frac {5}{12} a c^3 \log (1-c x)+\frac {1}{6} c^2 (3 b+2 a c) \log (1-c x)-\frac {7 a c \log (1-c x)}{36 x^2}-\frac {b c \log (1-c x)}{2 x}-\frac {2 a c^2 \log (1-c x)}{9 x}-\frac {c (3 b+2 a c) \log (1-c x)}{6 x}-\frac {1}{4} b c^2 \log ^2(1-c x)-\frac {1}{9} a c^3 \log ^2(1-c x)+\frac {a \log ^2(1-c x)}{9 x^3}+\frac {b \log ^2(1-c x)}{4 x^2}+\frac {1}{6} c^2 (3 b+2 a c) \log (c x) \log ^2(1-c x)-\frac {1}{2} b c^2 \text {PolyLog}(2,c x)-\frac {2}{9} a c^3 \text {PolyLog}(2,c x)+\frac {a c \text {PolyLog}(2,c x)}{6 x^2}+\frac {c (3 b+2 a c) \text {PolyLog}(2,c x)}{6 x}+\frac {1}{6} c^2 (3 b+2 a c) \log (1-c x) \text {PolyLog}(2,c x)-\frac {1}{6} \left (\frac {2 a}{x^3}+\frac {3 b}{x^2}\right ) \log (1-c x) \text {PolyLog}(2,c x)+\frac {1}{3} c^2 (3 b+2 a c) \log (1-c x) \text {PolyLog}(2,1-c x)-\frac {1}{6} c^2 (3 b+2 a c) \text {PolyLog}(3,c x)-\frac {1}{3} c^2 (3 b+2 a c) \text {PolyLog}(3,1-c x) \]

[Out]

1/6*a*c*polylog(2,c*x)/x^2+1/6*c*(2*a*c+3*b)*polylog(2,c*x)/x-7/36*a*c*ln(-c*x+1)/x^2-1/2*b*c*ln(-c*x+1)/x-2/9
*a*c^2*ln(-c*x+1)/x-1/6*c*(2*a*c+3*b)*ln(-c*x+1)/x+1/6*c^2*(2*a*c+3*b)*ln(c*x)*ln(-c*x+1)^2+1/6*c^2*(2*a*c+3*b
)*ln(-c*x+1)*polylog(2,c*x)+1/3*c^2*(2*a*c+3*b)*ln(-c*x+1)*polylog(2,-c*x+1)+7/36*a*c^2/x-1/2*b*c^2*polylog(2,
c*x)-2/9*a*c^3*polylog(2,c*x)-1/6*c^2*(2*a*c+3*b)*polylog(3,c*x)-1/3*c^2*(2*a*c+3*b)*polylog(3,-c*x+1)-1/2*b*c
^2*ln(x)-5/12*a*c^3*ln(x)-1/6*c^2*(2*a*c+3*b)*ln(x)+1/2*b*c^2*ln(-c*x+1)+5/12*a*c^3*ln(-c*x+1)+1/6*c^2*(2*a*c+
3*b)*ln(-c*x+1)-1/4*b*c^2*ln(-c*x+1)^2-1/9*a*c^3*ln(-c*x+1)^2+1/9*a*ln(-c*x+1)^2/x^3+1/4*b*ln(-c*x+1)^2/x^2-1/
6*(2*a/x^3+3*b/x^2)*ln(-c*x+1)*polylog(2,c*x)

________________________________________________________________________________________

Rubi [A]
time = 0.44, antiderivative size = 460, normalized size of antiderivative = 1.00, number of steps used = 41, number of rules used = 19, integrand size = 21, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.905, Rules used = {6874, 6726, 2442, 46, 45, 6741, 2445, 2457, 36, 29, 31, 2438, 2437, 2338, 6724, 6731, 2443, 2481, 2421} \begin {gather*} -\frac {1}{6} c^2 (2 a c+3 b) \text {Li}_3(c x)-\frac {1}{3} c^2 (2 a c+3 b) \text {Li}_3(1-c x)+\frac {1}{6} c^2 (2 a c+3 b) \text {Li}_2(c x) \log (1-c x)+\frac {1}{3} c^2 (2 a c+3 b) \text {Li}_2(1-c x) \log (1-c x)+\frac {1}{6} c^2 (2 a c+3 b) \log (c x) \log ^2(1-c x)-\frac {1}{6} c^2 \log (x) (2 a c+3 b)+\frac {1}{6} c^2 (2 a c+3 b) \log (1-c x)-\frac {1}{6} \left (\frac {2 a}{x^3}+\frac {3 b}{x^2}\right ) \text {Li}_2(c x) \log (1-c x)+\frac {c (2 a c+3 b) \text {Li}_2(c x)}{6 x}-\frac {c (2 a c+3 b) \log (1-c x)}{6 x}-\frac {2}{9} a c^3 \text {Li}_2(c x)-\frac {1}{9} a c^3 \log ^2(1-c x)-\frac {5}{12} a c^3 \log (x)+\frac {5}{12} a c^3 \log (1-c x)+\frac {7 a c^2}{36 x}-\frac {2 a c^2 \log (1-c x)}{9 x}+\frac {a c \text {Li}_2(c x)}{6 x^2}+\frac {a \log ^2(1-c x)}{9 x^3}-\frac {7 a c \log (1-c x)}{36 x^2}-\frac {1}{2} b c^2 \text {Li}_2(c x)-\frac {1}{4} b c^2 \log ^2(1-c x)-\frac {1}{2} b c^2 \log (x)+\frac {1}{2} b c^2 \log (1-c x)+\frac {b \log ^2(1-c x)}{4 x^2}-\frac {b c \log (1-c x)}{2 x} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[((a + b*x)*Log[1 - c*x]*PolyLog[2, c*x])/x^4,x]

[Out]

(7*a*c^2)/(36*x) - (b*c^2*Log[x])/2 - (5*a*c^3*Log[x])/12 - (c^2*(3*b + 2*a*c)*Log[x])/6 + (b*c^2*Log[1 - c*x]
)/2 + (5*a*c^3*Log[1 - c*x])/12 + (c^2*(3*b + 2*a*c)*Log[1 - c*x])/6 - (7*a*c*Log[1 - c*x])/(36*x^2) - (b*c*Lo
g[1 - c*x])/(2*x) - (2*a*c^2*Log[1 - c*x])/(9*x) - (c*(3*b + 2*a*c)*Log[1 - c*x])/(6*x) - (b*c^2*Log[1 - c*x]^
2)/4 - (a*c^3*Log[1 - c*x]^2)/9 + (a*Log[1 - c*x]^2)/(9*x^3) + (b*Log[1 - c*x]^2)/(4*x^2) + (c^2*(3*b + 2*a*c)
*Log[c*x]*Log[1 - c*x]^2)/6 - (b*c^2*PolyLog[2, c*x])/2 - (2*a*c^3*PolyLog[2, c*x])/9 + (a*c*PolyLog[2, c*x])/
(6*x^2) + (c*(3*b + 2*a*c)*PolyLog[2, c*x])/(6*x) + (c^2*(3*b + 2*a*c)*Log[1 - c*x]*PolyLog[2, c*x])/6 - (((2*
a)/x^3 + (3*b)/x^2)*Log[1 - c*x]*PolyLog[2, c*x])/6 + (c^2*(3*b + 2*a*c)*Log[1 - c*x]*PolyLog[2, 1 - c*x])/3 -
(c^2*(3*b + 2*a*c)*PolyLog[3, c*x])/6 - (c^2*(3*b + 2*a*c)*PolyLog[3, 1 - c*x])/3

Rule 29

Int[(x_)^(-1), x_Symbol] :> Simp[Log[x], x]

Rule 31

Int[((a_) + (b_.)*(x_))^(-1), x_Symbol] :> Simp[Log[RemoveContent[a + b*x, x]]/b, x] /; FreeQ[{a, b}, x]

Rule 36

Int[1/(((a_.) + (b_.)*(x_))*((c_.) + (d_.)*(x_))), x_Symbol] :> Dist[b/(b*c - a*d), Int[1/(a + b*x), x], x] -
Dist[d/(b*c - a*d), Int[1/(c + d*x), x], x] /; FreeQ[{a, b, c, d}, x] && NeQ[b*c - a*d, 0]

Rule 45

Int[((a_.) + (b_.)*(x_))^(m_.)*((c_.) + (d_.)*(x_))^(n_.), x_Symbol] :> Int[ExpandIntegrand[(a + b*x)^m*(c + d
*x)^n, x], x] /; FreeQ[{a, b, c, d, n}, x] && NeQ[b*c - a*d, 0] && IGtQ[m, 0] && ( !IntegerQ[n] || (EqQ[c, 0]
&& LeQ[7*m + 4*n + 4, 0]) || LtQ[9*m + 5*(n + 1), 0] || GtQ[m + n + 2, 0])

Rule 46

Int[((a_) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_.), x_Symbol] :> Int[ExpandIntegrand[(a + b*x)^m*(c + d*x
)^n, x], x] /; FreeQ[{a, b, c, d}, x] && NeQ[b*c - a*d, 0] && ILtQ[m, 0] && IntegerQ[n] &&  !(IGtQ[n, 0] && Lt
Q[m + n + 2, 0])

Rule 2338

Int[((a_.) + Log[(c_.)*(x_)^(n_.)]*(b_.))/(x_), x_Symbol] :> Simp[(a + b*Log[c*x^n])^2/(2*b*n), x] /; FreeQ[{a
, b, c, n}, x]

Rule 2421

Int[(Log[(d_.)*((e_) + (f_.)*(x_)^(m_.))]*((a_.) + Log[(c_.)*(x_)^(n_.)]*(b_.))^(p_.))/(x_), x_Symbol] :> Simp
[(-PolyLog[2, (-d)*f*x^m])*((a + b*Log[c*x^n])^p/m), x] + Dist[b*n*(p/m), Int[PolyLog[2, (-d)*f*x^m]*((a + b*L
og[c*x^n])^(p - 1)/x), x], x] /; FreeQ[{a, b, c, d, e, f, m, n}, x] && IGtQ[p, 0] && EqQ[d*e, 1]

Rule 2437

Int[((a_.) + Log[(c_.)*((d_) + (e_.)*(x_))^(n_.)]*(b_.))^(p_.)*((f_) + (g_.)*(x_))^(q_.), x_Symbol] :> Dist[1/
e, Subst[Int[(f*(x/d))^q*(a + b*Log[c*x^n])^p, x], x, d + e*x], x] /; FreeQ[{a, b, c, d, e, f, g, n, p, q}, x]
&& EqQ[e*f - d*g, 0]

Rule 2438

Int[Log[(c_.)*((d_) + (e_.)*(x_)^(n_.))]/(x_), x_Symbol] :> Simp[-PolyLog[2, (-c)*e*x^n]/n, x] /; FreeQ[{c, d,
e, n}, x] && EqQ[c*d, 1]

Rule 2442

Int[((a_.) + Log[(c_.)*((d_) + (e_.)*(x_))^(n_.)]*(b_.))*((f_.) + (g_.)*(x_))^(q_.), x_Symbol] :> Simp[(f + g*
x)^(q + 1)*((a + b*Log[c*(d + e*x)^n])/(g*(q + 1))), x] - Dist[b*e*(n/(g*(q + 1))), Int[(f + g*x)^(q + 1)/(d +
e*x), x], x] /; FreeQ[{a, b, c, d, e, f, g, n, q}, x] && NeQ[e*f - d*g, 0] && NeQ[q, -1]

Rule 2443

Int[((a_.) + Log[(c_.)*((d_) + (e_.)*(x_))^(n_.)]*(b_.))^(p_)/((f_.) + (g_.)*(x_)), x_Symbol] :> Simp[Log[e*((
f + g*x)/(e*f - d*g))]*((a + b*Log[c*(d + e*x)^n])^p/g), x] - Dist[b*e*n*(p/g), Int[Log[(e*(f + g*x))/(e*f - d
*g)]*((a + b*Log[c*(d + e*x)^n])^(p - 1)/(d + e*x)), x], x] /; FreeQ[{a, b, c, d, e, f, g, n, p}, x] && NeQ[e*
f - d*g, 0] && IGtQ[p, 1]

Rule 2445

Int[((a_.) + Log[(c_.)*((d_) + (e_.)*(x_))^(n_.)]*(b_.))^(p_)*((f_.) + (g_.)*(x_))^(q_.), x_Symbol] :> Simp[(f
+ g*x)^(q + 1)*((a + b*Log[c*(d + e*x)^n])^p/(g*(q + 1))), x] - Dist[b*e*n*(p/(g*(q + 1))), Int[(f + g*x)^(q
+ 1)*((a + b*Log[c*(d + e*x)^n])^(p - 1)/(d + e*x)), x], x] /; FreeQ[{a, b, c, d, e, f, g, n, q}, x] && NeQ[e*
f - d*g, 0] && GtQ[p, 0] && NeQ[q, -1] && IntegersQ[2*p, 2*q] && ( !IGtQ[q, 0] || (EqQ[p, 2] && NeQ[q, 1]))

Rule 2457

Int[(Log[(c_.)*((d_) + (e_.)*(x_))]*(x_)^(m_.))/((f_) + (g_.)*(x_)), x_Symbol] :> Int[ExpandIntegrand[Log[c*(d
+ e*x)], x^m/(f + g*x), x], x] /; FreeQ[{c, d, e, f, g}, x] && EqQ[e*f - d*g, 0] && EqQ[c*d, 1] && IntegerQ[m
]

Rule 2481

Int[((a_.) + Log[(c_.)*((d_) + (e_.)*(x_))^(n_.)]*(b_.))^(p_.)*((f_.) + Log[(h_.)*((i_.) + (j_.)*(x_))^(m_.)]*
(g_.))*((k_.) + (l_.)*(x_))^(r_.), x_Symbol] :> Dist[1/e, Subst[Int[(k*(x/d))^r*(a + b*Log[c*x^n])^p*(f + g*Lo
g[h*((e*i - d*j)/e + j*(x/e))^m]), x], x, d + e*x], x] /; FreeQ[{a, b, c, d, e, f, g, h, i, j, k, l, n, p, r},
x] && EqQ[e*k - d*l, 0]

Rule 6724

Int[PolyLog[n_, (c_.)*((a_.) + (b_.)*(x_))^(p_.)]/((d_.) + (e_.)*(x_)), x_Symbol] :> Simp[PolyLog[n + 1, c*(a
+ b*x)^p]/(e*p), x] /; FreeQ[{a, b, c, d, e, n, p}, x] && EqQ[b*d, a*e]

Rule 6726

Int[((d_.)*(x_))^(m_.)*PolyLog[n_, (a_.)*((b_.)*(x_)^(p_.))^(q_.)], x_Symbol] :> Simp[(d*x)^(m + 1)*(PolyLog[n
, a*(b*x^p)^q]/(d*(m + 1))), x] - Dist[p*(q/(m + 1)), Int[(d*x)^m*PolyLog[n - 1, a*(b*x^p)^q], x], x] /; FreeQ
[{a, b, d, m, p, q}, x] && NeQ[m, -1] && GtQ[n, 0]

Rule 6731

Int[PolyLog[2, (c_.)*((a_.) + (b_.)*(x_))]/((d_.) + (e_.)*(x_)), x_Symbol] :> Simp[Log[1 - a*c - b*c*x]*(PolyL
og[2, c*(a + b*x)]/e), x] + Dist[b/e, Int[Log[1 - a*c - b*c*x]^2/(a + b*x), x], x] /; FreeQ[{a, b, c, d, e}, x
] && EqQ[c*(b*d - a*e) + e, 0]

Rule 6741

Int[((g_.) + Log[(f_.)*((d_.) + (e_.)*(x_))^(n_.)]*(h_.))*(Px_)*(x_)^(m_.)*PolyLog[2, (c_.)*((a_.) + (b_.)*(x_
))], x_Symbol] :> With[{u = IntHide[x^m*Px, x]}, Simp[u*(g + h*Log[f*(d + e*x)^n])*PolyLog[2, c*(a + b*x)], x]
+ (Dist[b, Int[ExpandIntegrand[(g + h*Log[f*(d + e*x)^n])*Log[1 - a*c - b*c*x], u/(a + b*x), x], x], x] - Dis
t[e*h*n, Int[ExpandIntegrand[PolyLog[2, c*(a + b*x)], u/(d + e*x), x], x], x])] /; FreeQ[{a, b, c, d, e, f, g,
h, n}, x] && PolyQ[Px, x] && IntegerQ[m]

Rule 6874

Int[u_, x_Symbol] :> With[{v = ExpandIntegrand[u, x]}, Int[v, x] /; SumQ[v]]

Rubi steps

\begin {align*} \int \frac {(a+b x) \log (1-c x) \text {Li}_2(c x)}{x^4} \, dx &=-\frac {1}{6} \left (\frac {2 a}{x^3}+\frac {3 b}{x^2}\right ) \log (1-c x) \text {Li}_2(c x)+c \int \left (-\frac {a \text {Li}_2(c x)}{3 x^3}+\frac {(-3 b-2 a c) \text {Li}_2(c x)}{6 x^2}-\frac {c (3 b+2 a c) \text {Li}_2(c x)}{6 x}+\frac {c^2 (3 b+2 a c) \text {Li}_2(c x)}{6 (-1+c x)}\right ) \, dx+\int \left (-\frac {a \log ^2(1-c x)}{3 x^4}-\frac {b \log ^2(1-c x)}{2 x^3}\right ) \, dx\\ &=-\frac {1}{6} \left (\frac {2 a}{x^3}+\frac {3 b}{x^2}\right ) \log (1-c x) \text {Li}_2(c x)-\frac {1}{3} a \int \frac {\log ^2(1-c x)}{x^4} \, dx-\frac {1}{2} b \int \frac {\log ^2(1-c x)}{x^3} \, dx-\frac {1}{3} (a c) \int \frac {\text {Li}_2(c x)}{x^3} \, dx-\frac {1}{6} (c (3 b+2 a c)) \int \frac {\text {Li}_2(c x)}{x^2} \, dx-\frac {1}{6} \left (c^2 (3 b+2 a c)\right ) \int \frac {\text {Li}_2(c x)}{x} \, dx+\frac {1}{6} \left (c^3 (3 b+2 a c)\right ) \int \frac {\text {Li}_2(c x)}{-1+c x} \, dx\\ &=\frac {a \log ^2(1-c x)}{9 x^3}+\frac {b \log ^2(1-c x)}{4 x^2}+\frac {a c \text {Li}_2(c x)}{6 x^2}+\frac {c (3 b+2 a c) \text {Li}_2(c x)}{6 x}+\frac {1}{6} c^2 (3 b+2 a c) \log (1-c x) \text {Li}_2(c x)-\frac {1}{6} \left (\frac {2 a}{x^3}+\frac {3 b}{x^2}\right ) \log (1-c x) \text {Li}_2(c x)-\frac {1}{6} c^2 (3 b+2 a c) \text {Li}_3(c x)+\frac {1}{6} (a c) \int \frac {\log (1-c x)}{x^3} \, dx+\frac {1}{9} (2 a c) \int \frac {\log (1-c x)}{x^3 (1-c x)} \, dx+\frac {1}{2} (b c) \int \frac {\log (1-c x)}{x^2 (1-c x)} \, dx+\frac {1}{6} (c (3 b+2 a c)) \int \frac {\log (1-c x)}{x^2} \, dx+\frac {1}{6} \left (c^2 (3 b+2 a c)\right ) \int \frac {\log ^2(1-c x)}{x} \, dx\\ &=-\frac {a c \log (1-c x)}{12 x^2}-\frac {c (3 b+2 a c) \log (1-c x)}{6 x}+\frac {a \log ^2(1-c x)}{9 x^3}+\frac {b \log ^2(1-c x)}{4 x^2}+\frac {1}{6} c^2 (3 b+2 a c) \log (c x) \log ^2(1-c x)+\frac {a c \text {Li}_2(c x)}{6 x^2}+\frac {c (3 b+2 a c) \text {Li}_2(c x)}{6 x}+\frac {1}{6} c^2 (3 b+2 a c) \log (1-c x) \text {Li}_2(c x)-\frac {1}{6} \left (\frac {2 a}{x^3}+\frac {3 b}{x^2}\right ) \log (1-c x) \text {Li}_2(c x)-\frac {1}{6} c^2 (3 b+2 a c) \text {Li}_3(c x)+\frac {1}{9} (2 a c) \int \left (\frac {\log (1-c x)}{x^3}+\frac {c \log (1-c x)}{x^2}+\frac {c^2 \log (1-c x)}{x}-\frac {c^3 \log (1-c x)}{-1+c x}\right ) \, dx+\frac {1}{2} (b c) \int \left (\frac {\log (1-c x)}{x^2}+\frac {c \log (1-c x)}{x}-\frac {c^2 \log (1-c x)}{-1+c x}\right ) \, dx-\frac {1}{12} \left (a c^2\right ) \int \frac {1}{x^2 (1-c x)} \, dx-\frac {1}{6} \left (c^2 (3 b+2 a c)\right ) \int \frac {1}{x (1-c x)} \, dx+\frac {1}{3} \left (c^3 (3 b+2 a c)\right ) \int \frac {\log (c x) \log (1-c x)}{1-c x} \, dx\\ &=-\frac {a c \log (1-c x)}{12 x^2}-\frac {c (3 b+2 a c) \log (1-c x)}{6 x}+\frac {a \log ^2(1-c x)}{9 x^3}+\frac {b \log ^2(1-c x)}{4 x^2}+\frac {1}{6} c^2 (3 b+2 a c) \log (c x) \log ^2(1-c x)+\frac {a c \text {Li}_2(c x)}{6 x^2}+\frac {c (3 b+2 a c) \text {Li}_2(c x)}{6 x}+\frac {1}{6} c^2 (3 b+2 a c) \log (1-c x) \text {Li}_2(c x)-\frac {1}{6} \left (\frac {2 a}{x^3}+\frac {3 b}{x^2}\right ) \log (1-c x) \text {Li}_2(c x)-\frac {1}{6} c^2 (3 b+2 a c) \text {Li}_3(c x)+\frac {1}{9} (2 a c) \int \frac {\log (1-c x)}{x^3} \, dx+\frac {1}{2} (b c) \int \frac {\log (1-c x)}{x^2} \, dx-\frac {1}{12} \left (a c^2\right ) \int \left (\frac {1}{x^2}+\frac {c}{x}-\frac {c^2}{-1+c x}\right ) \, dx+\frac {1}{9} \left (2 a c^2\right ) \int \frac {\log (1-c x)}{x^2} \, dx+\frac {1}{2} \left (b c^2\right ) \int \frac {\log (1-c x)}{x} \, dx+\frac {1}{9} \left (2 a c^3\right ) \int \frac {\log (1-c x)}{x} \, dx-\frac {1}{2} \left (b c^3\right ) \int \frac {\log (1-c x)}{-1+c x} \, dx-\frac {1}{9} \left (2 a c^4\right ) \int \frac {\log (1-c x)}{-1+c x} \, dx-\frac {1}{6} \left (c^2 (3 b+2 a c)\right ) \int \frac {1}{x} \, dx-\frac {1}{3} \left (c^2 (3 b+2 a c)\right ) \text {Subst}\left (\int \frac {\log (x) \log \left (c \left (\frac {1}{c}-\frac {x}{c}\right )\right )}{x} \, dx,x,1-c x\right )-\frac {1}{6} \left (c^3 (3 b+2 a c)\right ) \int \frac {1}{1-c x} \, dx\\ &=\frac {a c^2}{12 x}-\frac {1}{12} a c^3 \log (x)-\frac {1}{6} c^2 (3 b+2 a c) \log (x)+\frac {1}{12} a c^3 \log (1-c x)+\frac {1}{6} c^2 (3 b+2 a c) \log (1-c x)-\frac {7 a c \log (1-c x)}{36 x^2}-\frac {b c \log (1-c x)}{2 x}-\frac {2 a c^2 \log (1-c x)}{9 x}-\frac {c (3 b+2 a c) \log (1-c x)}{6 x}+\frac {a \log ^2(1-c x)}{9 x^3}+\frac {b \log ^2(1-c x)}{4 x^2}+\frac {1}{6} c^2 (3 b+2 a c) \log (c x) \log ^2(1-c x)-\frac {1}{2} b c^2 \text {Li}_2(c x)-\frac {2}{9} a c^3 \text {Li}_2(c x)+\frac {a c \text {Li}_2(c x)}{6 x^2}+\frac {c (3 b+2 a c) \text {Li}_2(c x)}{6 x}+\frac {1}{6} c^2 (3 b+2 a c) \log (1-c x) \text {Li}_2(c x)-\frac {1}{6} \left (\frac {2 a}{x^3}+\frac {3 b}{x^2}\right ) \log (1-c x) \text {Li}_2(c x)+\frac {1}{3} c^2 (3 b+2 a c) \log (1-c x) \text {Li}_2(1-c x)-\frac {1}{6} c^2 (3 b+2 a c) \text {Li}_3(c x)-\frac {1}{9} \left (a c^2\right ) \int \frac {1}{x^2 (1-c x)} \, dx-\frac {1}{2} \left (b c^2\right ) \int \frac {1}{x (1-c x)} \, dx-\frac {1}{2} \left (b c^2\right ) \text {Subst}\left (\int \frac {\log (x)}{x} \, dx,x,1-c x\right )-\frac {1}{9} \left (2 a c^3\right ) \int \frac {1}{x (1-c x)} \, dx-\frac {1}{9} \left (2 a c^3\right ) \text {Subst}\left (\int \frac {\log (x)}{x} \, dx,x,1-c x\right )-\frac {1}{3} \left (c^2 (3 b+2 a c)\right ) \text {Subst}\left (\int \frac {\text {Li}_2(x)}{x} \, dx,x,1-c x\right )\\ &=\frac {a c^2}{12 x}-\frac {1}{12} a c^3 \log (x)-\frac {1}{6} c^2 (3 b+2 a c) \log (x)+\frac {1}{12} a c^3 \log (1-c x)+\frac {1}{6} c^2 (3 b+2 a c) \log (1-c x)-\frac {7 a c \log (1-c x)}{36 x^2}-\frac {b c \log (1-c x)}{2 x}-\frac {2 a c^2 \log (1-c x)}{9 x}-\frac {c (3 b+2 a c) \log (1-c x)}{6 x}-\frac {1}{4} b c^2 \log ^2(1-c x)-\frac {1}{9} a c^3 \log ^2(1-c x)+\frac {a \log ^2(1-c x)}{9 x^3}+\frac {b \log ^2(1-c x)}{4 x^2}+\frac {1}{6} c^2 (3 b+2 a c) \log (c x) \log ^2(1-c x)-\frac {1}{2} b c^2 \text {Li}_2(c x)-\frac {2}{9} a c^3 \text {Li}_2(c x)+\frac {a c \text {Li}_2(c x)}{6 x^2}+\frac {c (3 b+2 a c) \text {Li}_2(c x)}{6 x}+\frac {1}{6} c^2 (3 b+2 a c) \log (1-c x) \text {Li}_2(c x)-\frac {1}{6} \left (\frac {2 a}{x^3}+\frac {3 b}{x^2}\right ) \log (1-c x) \text {Li}_2(c x)+\frac {1}{3} c^2 (3 b+2 a c) \log (1-c x) \text {Li}_2(1-c x)-\frac {1}{6} c^2 (3 b+2 a c) \text {Li}_3(c x)-\frac {1}{3} c^2 (3 b+2 a c) \text {Li}_3(1-c x)-\frac {1}{9} \left (a c^2\right ) \int \left (\frac {1}{x^2}+\frac {c}{x}-\frac {c^2}{-1+c x}\right ) \, dx-\frac {1}{2} \left (b c^2\right ) \int \frac {1}{x} \, dx-\frac {1}{9} \left (2 a c^3\right ) \int \frac {1}{x} \, dx-\frac {1}{2} \left (b c^3\right ) \int \frac {1}{1-c x} \, dx-\frac {1}{9} \left (2 a c^4\right ) \int \frac {1}{1-c x} \, dx\\ &=\frac {7 a c^2}{36 x}-\frac {1}{2} b c^2 \log (x)-\frac {5}{12} a c^3 \log (x)-\frac {1}{6} c^2 (3 b+2 a c) \log (x)+\frac {1}{2} b c^2 \log (1-c x)+\frac {5}{12} a c^3 \log (1-c x)+\frac {1}{6} c^2 (3 b+2 a c) \log (1-c x)-\frac {7 a c \log (1-c x)}{36 x^2}-\frac {b c \log (1-c x)}{2 x}-\frac {2 a c^2 \log (1-c x)}{9 x}-\frac {c (3 b+2 a c) \log (1-c x)}{6 x}-\frac {1}{4} b c^2 \log ^2(1-c x)-\frac {1}{9} a c^3 \log ^2(1-c x)+\frac {a \log ^2(1-c x)}{9 x^3}+\frac {b \log ^2(1-c x)}{4 x^2}+\frac {1}{6} c^2 (3 b+2 a c) \log (c x) \log ^2(1-c x)-\frac {1}{2} b c^2 \text {Li}_2(c x)-\frac {2}{9} a c^3 \text {Li}_2(c x)+\frac {a c \text {Li}_2(c x)}{6 x^2}+\frac {c (3 b+2 a c) \text {Li}_2(c x)}{6 x}+\frac {1}{6} c^2 (3 b+2 a c) \log (1-c x) \text {Li}_2(c x)-\frac {1}{6} \left (\frac {2 a}{x^3}+\frac {3 b}{x^2}\right ) \log (1-c x) \text {Li}_2(c x)+\frac {1}{3} c^2 (3 b+2 a c) \log (1-c x) \text {Li}_2(1-c x)-\frac {1}{6} c^2 (3 b+2 a c) \text {Li}_3(c x)-\frac {1}{3} c^2 (3 b+2 a c) \text {Li}_3(1-c x)\\ \end {align*}

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Mathematica [A]
time = 1.00, size = 389, normalized size = 0.85 \begin {gather*} \frac {1}{36} \left (-7 a c^3+\frac {7 a c^2}{x}-36 b c^2 \log (c x)-27 a c^3 \log (c x)+36 b c^2 \log (1-c x)+27 a c^3 \log (1-c x)-\frac {7 a c \log (1-c x)}{x^2}-\frac {36 b c \log (1-c x)}{x}-\frac {20 a c^2 \log (1-c x)}{x}+18 b c^2 \log (c x) \log (1-c x)+8 a c^3 \log (c x) \log (1-c x)-9 b c^2 \log ^2(1-c x)-4 a c^3 \log ^2(1-c x)+\frac {4 a \log ^2(1-c x)}{x^3}+\frac {9 b \log ^2(1-c x)}{x^2}+18 b c^2 \log (c x) \log ^2(1-c x)+12 a c^3 \log (c x) \log ^2(1-c x)+\frac {6 \left (c x (a+3 b x+2 a c x)+\left (-2 a-3 b x+3 b c^2 x^3+2 a c^3 x^3\right ) \log (1-c x)\right ) \text {PolyLog}(2,c x)}{x^3}+2 c^2 (9 b+4 a c+6 (3 b+2 a c) \log (1-c x)) \text {PolyLog}(2,1-c x)-18 b c^2 \text {PolyLog}(3,c x)-12 a c^3 \text {PolyLog}(3,c x)-36 b c^2 \text {PolyLog}(3,1-c x)-24 a c^3 \text {PolyLog}(3,1-c x)\right ) \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[((a + b*x)*Log[1 - c*x]*PolyLog[2, c*x])/x^4,x]

[Out]

(-7*a*c^3 + (7*a*c^2)/x - 36*b*c^2*Log[c*x] - 27*a*c^3*Log[c*x] + 36*b*c^2*Log[1 - c*x] + 27*a*c^3*Log[1 - c*x
] - (7*a*c*Log[1 - c*x])/x^2 - (36*b*c*Log[1 - c*x])/x - (20*a*c^2*Log[1 - c*x])/x + 18*b*c^2*Log[c*x]*Log[1 -
c*x] + 8*a*c^3*Log[c*x]*Log[1 - c*x] - 9*b*c^2*Log[1 - c*x]^2 - 4*a*c^3*Log[1 - c*x]^2 + (4*a*Log[1 - c*x]^2)
/x^3 + (9*b*Log[1 - c*x]^2)/x^2 + 18*b*c^2*Log[c*x]*Log[1 - c*x]^2 + 12*a*c^3*Log[c*x]*Log[1 - c*x]^2 + (6*(c*
x*(a + 3*b*x + 2*a*c*x) + (-2*a - 3*b*x + 3*b*c^2*x^3 + 2*a*c^3*x^3)*Log[1 - c*x])*PolyLog[2, c*x])/x^3 + 2*c^
2*(9*b + 4*a*c + 6*(3*b + 2*a*c)*Log[1 - c*x])*PolyLog[2, 1 - c*x] - 18*b*c^2*PolyLog[3, c*x] - 12*a*c^3*PolyL
og[3, c*x] - 36*b*c^2*PolyLog[3, 1 - c*x] - 24*a*c^3*PolyLog[3, 1 - c*x])/36

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Maple [F]
time = 0.01, size = 0, normalized size = 0.00 \[\int \frac {\left (b x +a \right ) \ln \left (-c x +1\right ) \polylog \left (2, c x \right )}{x^{4}}\, dx\]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((b*x+a)*ln(-c*x+1)*polylog(2,c*x)/x^4,x)

[Out]

int((b*x+a)*ln(-c*x+1)*polylog(2,c*x)/x^4,x)

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Maxima [A]
time = 0.32, size = 287, normalized size = 0.62 \begin {gather*} \frac {1}{6} \, {\left (2 \, a c^{3} + 3 \, b c^{2}\right )} {\left (\log \left (c x\right ) \log \left (-c x + 1\right )^{2} + 2 \, {\rm Li}_2\left (-c x + 1\right ) \log \left (-c x + 1\right ) - 2 \, {\rm Li}_{3}(-c x + 1)\right )} + \frac {1}{18} \, {\left (4 \, a c^{3} + 9 \, b c^{2}\right )} {\left (\log \left (c x\right ) \log \left (-c x + 1\right ) + {\rm Li}_2\left (-c x + 1\right )\right )} - \frac {1}{4} \, {\left (3 \, a c^{3} + 4 \, b c^{2}\right )} \log \left (x\right ) - \frac {1}{6} \, {\left (2 \, a c^{3} + 3 \, b c^{2}\right )} {\rm Li}_{3}(c x) + \frac {7 \, a c^{2} x^{2} - {\left ({\left (4 \, a c^{3} + 9 \, b c^{2}\right )} x^{3} - 9 \, b x - 4 \, a\right )} \log \left (-c x + 1\right )^{2} + 6 \, {\left (a c x + {\left (2 \, a c^{2} + 3 \, b c\right )} x^{2} + {\left ({\left (2 \, a c^{3} + 3 \, b c^{2}\right )} x^{3} - 3 \, b x - 2 \, a\right )} \log \left (-c x + 1\right )\right )} {\rm Li}_2\left (c x\right ) + {\left (9 \, {\left (3 \, a c^{3} + 4 \, b c^{2}\right )} x^{3} - 7 \, a c x - 4 \, {\left (5 \, a c^{2} + 9 \, b c\right )} x^{2}\right )} \log \left (-c x + 1\right )}{36 \, x^{3}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x+a)*log(-c*x+1)*polylog(2,c*x)/x^4,x, algorithm="maxima")

[Out]

1/6*(2*a*c^3 + 3*b*c^2)*(log(c*x)*log(-c*x + 1)^2 + 2*dilog(-c*x + 1)*log(-c*x + 1) - 2*polylog(3, -c*x + 1))
+ 1/18*(4*a*c^3 + 9*b*c^2)*(log(c*x)*log(-c*x + 1) + dilog(-c*x + 1)) - 1/4*(3*a*c^3 + 4*b*c^2)*log(x) - 1/6*(
2*a*c^3 + 3*b*c^2)*polylog(3, c*x) + 1/36*(7*a*c^2*x^2 - ((4*a*c^3 + 9*b*c^2)*x^3 - 9*b*x - 4*a)*log(-c*x + 1)
^2 + 6*(a*c*x + (2*a*c^2 + 3*b*c)*x^2 + ((2*a*c^3 + 3*b*c^2)*x^3 - 3*b*x - 2*a)*log(-c*x + 1))*dilog(c*x) + (9
*(3*a*c^3 + 4*b*c^2)*x^3 - 7*a*c*x - 4*(5*a*c^2 + 9*b*c)*x^2)*log(-c*x + 1))/x^3

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Fricas [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x+a)*log(-c*x+1)*polylog(2,c*x)/x^4,x, algorithm="fricas")

[Out]

integral((b*x + a)*dilog(c*x)*log(-c*x + 1)/x^4, x)

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Sympy [F(-1)] Timed out
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Timed out} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x+a)*ln(-c*x+1)*polylog(2,c*x)/x**4,x)

[Out]

Timed out

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Giac [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x+a)*log(-c*x+1)*polylog(2,c*x)/x^4,x, algorithm="giac")

[Out]

integrate((b*x + a)*dilog(c*x)*log(-c*x + 1)/x^4, x)

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Mupad [F]
time = 0.00, size = -1, normalized size = -0.00 \begin {gather*} \int \frac {\ln \left (1-c\,x\right )\,\mathrm {polylog}\left (2,c\,x\right )\,\left (a+b\,x\right )}{x^4} \,d x \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((log(1 - c*x)*polylog(2, c*x)*(a + b*x))/x^4,x)

[Out]

int((log(1 - c*x)*polylog(2, c*x)*(a + b*x))/x^4, x)

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