Optimal. Leaf size=73 \[ -\frac {4 x}{25 a^2}-\frac {4 x^3}{75 a}-\frac {4 x^5}{125}+\frac {4 \tanh ^{-1}\left (\sqrt {a} x\right )}{25 a^{5/2}}+\frac {2}{25} x^5 \log \left (1-a x^2\right )+\frac {1}{5} x^5 \text {PolyLog}\left (2,a x^2\right ) \]
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Rubi [A]
time = 0.03, antiderivative size = 73, normalized size of antiderivative = 1.00, number of steps
used = 5, number of rules used = 4, integrand size = 11, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.364, Rules used = {6726, 2505,
308, 212} \begin {gather*} \frac {4 \tanh ^{-1}\left (\sqrt {a} x\right )}{25 a^{5/2}}-\frac {4 x}{25 a^2}+\frac {1}{5} x^5 \text {Li}_2\left (a x^2\right )-\frac {4 x^3}{75 a}+\frac {2}{25} x^5 \log \left (1-a x^2\right )-\frac {4 x^5}{125} \end {gather*}
Antiderivative was successfully verified.
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Rule 212
Rule 308
Rule 2505
Rule 6726
Rubi steps
\begin {align*} \int x^4 \text {Li}_2\left (a x^2\right ) \, dx &=\frac {1}{5} x^5 \text {Li}_2\left (a x^2\right )+\frac {2}{5} \int x^4 \log \left (1-a x^2\right ) \, dx\\ &=\frac {2}{25} x^5 \log \left (1-a x^2\right )+\frac {1}{5} x^5 \text {Li}_2\left (a x^2\right )+\frac {1}{25} (4 a) \int \frac {x^6}{1-a x^2} \, dx\\ &=\frac {2}{25} x^5 \log \left (1-a x^2\right )+\frac {1}{5} x^5 \text {Li}_2\left (a x^2\right )+\frac {1}{25} (4 a) \int \left (-\frac {1}{a^3}-\frac {x^2}{a^2}-\frac {x^4}{a}+\frac {1}{a^3 \left (1-a x^2\right )}\right ) \, dx\\ &=-\frac {4 x}{25 a^2}-\frac {4 x^3}{75 a}-\frac {4 x^5}{125}+\frac {2}{25} x^5 \log \left (1-a x^2\right )+\frac {1}{5} x^5 \text {Li}_2\left (a x^2\right )+\frac {4 \int \frac {1}{1-a x^2} \, dx}{25 a^2}\\ &=-\frac {4 x}{25 a^2}-\frac {4 x^3}{75 a}-\frac {4 x^5}{125}+\frac {4 \tanh ^{-1}\left (\sqrt {a} x\right )}{25 a^{5/2}}+\frac {2}{25} x^5 \log \left (1-a x^2\right )+\frac {1}{5} x^5 \text {Li}_2\left (a x^2\right )\\ \end {align*}
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Mathematica [A]
time = 0.05, size = 65, normalized size = 0.89 \begin {gather*} \frac {1}{375} \left (-\frac {60 x}{a^2}-\frac {20 x^3}{a}-12 x^5+\frac {60 \tanh ^{-1}\left (\sqrt {a} x\right )}{a^{5/2}}+30 x^5 \log \left (1-a x^2\right )+75 x^5 \text {PolyLog}\left (2,a x^2\right )\right ) \end {gather*}
Antiderivative was successfully verified.
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Maple [A]
time = 0.08, size = 63, normalized size = 0.86
method | result | size |
default | \(\frac {x^{5} \polylog \left (2, a \,x^{2}\right )}{5}+\frac {2 x^{5} \ln \left (-a \,x^{2}+1\right )}{25}+\frac {4 a \left (-\frac {\frac {1}{5} a^{2} x^{5}+\frac {1}{3} a \,x^{3}+x}{a^{3}}+\frac {\arctanh \left (x \sqrt {a}\right )}{a^{\frac {7}{2}}}\right )}{25}\) | \(63\) |
meijerg | \(-\frac {-\frac {2 x \left (-a \right )^{\frac {7}{2}} \left (84 a^{2} x^{4}+140 a \,x^{2}+420\right )}{2625 a^{3}}-\frac {4 x \left (-a \right )^{\frac {7}{2}} \left (\ln \left (1-\sqrt {a \,x^{2}}\right )-\ln \left (1+\sqrt {a \,x^{2}}\right )\right )}{25 a^{3} \sqrt {a \,x^{2}}}+\frac {4 x^{5} \left (-a \right )^{\frac {7}{2}} \ln \left (-a \,x^{2}+1\right )}{25 a}+\frac {2 x^{5} \left (-a \right )^{\frac {7}{2}} \polylog \left (2, a \,x^{2}\right )}{5 a}}{2 a^{2} \sqrt {-a}}\) | \(124\) |
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A]
time = 0.47, size = 80, normalized size = 1.10 \begin {gather*} \frac {75 \, a^{2} x^{5} {\rm Li}_2\left (a x^{2}\right ) + 30 \, a^{2} x^{5} \log \left (-a x^{2} + 1\right ) - 12 \, a^{2} x^{5} - 20 \, a x^{3} - 60 \, x}{375 \, a^{2}} - \frac {2 \, \log \left (\frac {a x - \sqrt {a}}{a x + \sqrt {a}}\right )}{25 \, a^{\frac {5}{2}}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A]
time = 0.59, size = 159, normalized size = 2.18 \begin {gather*} \left [\frac {75 \, a^{3} x^{5} {\rm Li}_2\left (a x^{2}\right ) + 30 \, a^{3} x^{5} \log \left (-a x^{2} + 1\right ) - 12 \, a^{3} x^{5} - 20 \, a^{2} x^{3} - 60 \, a x + 30 \, \sqrt {a} \log \left (\frac {a x^{2} + 2 \, \sqrt {a} x + 1}{a x^{2} - 1}\right )}{375 \, a^{3}}, \frac {75 \, a^{3} x^{5} {\rm Li}_2\left (a x^{2}\right ) + 30 \, a^{3} x^{5} \log \left (-a x^{2} + 1\right ) - 12 \, a^{3} x^{5} - 20 \, a^{2} x^{3} - 60 \, a x - 60 \, \sqrt {-a} \arctan \left (\sqrt {-a} x\right )}{375 \, a^{3}}\right ] \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [A]
time = 48.48, size = 94, normalized size = 1.29 \begin {gather*} \begin {cases} - \frac {2 x^{5} \operatorname {Li}_{1}\left (a x^{2}\right )}{25} + \frac {x^{5} \operatorname {Li}_{2}\left (a x^{2}\right )}{5} - \frac {4 x^{5}}{125} - \frac {4 x^{3}}{75 a} - \frac {4 x}{25 a^{2}} - \frac {4 \log {\left (x - \sqrt {\frac {1}{a}} \right )}}{25 a^{3} \sqrt {\frac {1}{a}}} - \frac {2 \operatorname {Li}_{1}\left (a x^{2}\right )}{25 a^{3} \sqrt {\frac {1}{a}}} & \text {for}\: a \neq 0 \\0 & \text {otherwise} \end {cases} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [B]
time = 0.41, size = 60, normalized size = 0.82 \begin {gather*} \frac {x^5\,\mathrm {polylog}\left (2,a\,x^2\right )}{5}-\frac {4\,x}{25\,a^2}+\frac {2\,x^5\,\ln \left (1-a\,x^2\right )}{25}-\frac {4\,x^5}{125}-\frac {4\,x^3}{75\,a}-\frac {\mathrm {atan}\left (\sqrt {a}\,x\,1{}\mathrm {i}\right )\,4{}\mathrm {i}}{25\,a^{5/2}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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