Optimal. Leaf size=66 \[ -\frac {4 a}{75 x^3}-\frac {4 a^2}{25 x}+\frac {4}{25} a^{5/2} \tanh ^{-1}\left (\sqrt {a} x\right )+\frac {2 \log \left (1-a x^2\right )}{25 x^5}-\frac {\text {PolyLog}\left (2,a x^2\right )}{5 x^5} \]
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Rubi [A]
time = 0.03, antiderivative size = 66, normalized size of antiderivative = 1.00, number of steps
used = 5, number of rules used = 4, integrand size = 11, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.364, Rules used = {6726, 2505,
331, 212} \begin {gather*} \frac {4}{25} a^{5/2} \tanh ^{-1}\left (\sqrt {a} x\right )-\frac {4 a^2}{25 x}-\frac {\text {Li}_2\left (a x^2\right )}{5 x^5}-\frac {4 a}{75 x^3}+\frac {2 \log \left (1-a x^2\right )}{25 x^5} \end {gather*}
Antiderivative was successfully verified.
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Rule 212
Rule 331
Rule 2505
Rule 6726
Rubi steps
\begin {align*} \int \frac {\text {Li}_2\left (a x^2\right )}{x^6} \, dx &=-\frac {\text {Li}_2\left (a x^2\right )}{5 x^5}-\frac {2}{5} \int \frac {\log \left (1-a x^2\right )}{x^6} \, dx\\ &=\frac {2 \log \left (1-a x^2\right )}{25 x^5}-\frac {\text {Li}_2\left (a x^2\right )}{5 x^5}+\frac {1}{25} (4 a) \int \frac {1}{x^4 \left (1-a x^2\right )} \, dx\\ &=-\frac {4 a}{75 x^3}+\frac {2 \log \left (1-a x^2\right )}{25 x^5}-\frac {\text {Li}_2\left (a x^2\right )}{5 x^5}+\frac {1}{25} \left (4 a^2\right ) \int \frac {1}{x^2 \left (1-a x^2\right )} \, dx\\ &=-\frac {4 a}{75 x^3}-\frac {4 a^2}{25 x}+\frac {2 \log \left (1-a x^2\right )}{25 x^5}-\frac {\text {Li}_2\left (a x^2\right )}{5 x^5}+\frac {1}{25} \left (4 a^3\right ) \int \frac {1}{1-a x^2} \, dx\\ &=-\frac {4 a}{75 x^3}-\frac {4 a^2}{25 x}+\frac {4}{25} a^{5/2} \tanh ^{-1}\left (\sqrt {a} x\right )+\frac {2 \log \left (1-a x^2\right )}{25 x^5}-\frac {\text {Li}_2\left (a x^2\right )}{5 x^5}\\ \end {align*}
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Mathematica [C] Result contains higher order function than in optimal. Order 5 vs. order 4 in
optimal.
time = 0.01, size = 47, normalized size = 0.71 \begin {gather*} -\frac {4 a x^2 \, _2F_1\left (-\frac {3}{2},1;-\frac {1}{2};a x^2\right )-6 \log \left (1-a x^2\right )+15 \text {PolyLog}\left (2,a x^2\right )}{75 x^5} \end {gather*}
Antiderivative was successfully verified.
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Maple [A]
time = 0.08, size = 53, normalized size = 0.80
method | result | size |
default | \(-\frac {\polylog \left (2, a \,x^{2}\right )}{5 x^{5}}+\frac {2 \ln \left (-a \,x^{2}+1\right )}{25 x^{5}}+\frac {4 a \left (a^{\frac {3}{2}} \arctanh \left (x \sqrt {a}\right )-\frac {1}{3 x^{3}}-\frac {a}{x}\right )}{25}\) | \(53\) |
meijerg | \(\frac {a^{3} \left (-\frac {8}{75 x^{3} \left (-a \right )^{\frac {3}{2}}}-\frac {8 a}{25 x \left (-a \right )^{\frac {3}{2}}}-\frac {4 x \,a^{2} \left (\ln \left (1-\sqrt {a \,x^{2}}\right )-\ln \left (1+\sqrt {a \,x^{2}}\right )\right )}{25 \left (-a \right )^{\frac {3}{2}} \sqrt {a \,x^{2}}}+\frac {4 \ln \left (-a \,x^{2}+1\right )}{25 x^{5} \left (-a \right )^{\frac {3}{2}} a}-\frac {2 \polylog \left (2, a \,x^{2}\right )}{5 x^{5} \left (-a \right )^{\frac {3}{2}} a}\right )}{2 \sqrt {-a}}\) | \(118\) |
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A]
time = 0.46, size = 65, normalized size = 0.98 \begin {gather*} -\frac {2}{25} \, a^{\frac {5}{2}} \log \left (\frac {a x - \sqrt {a}}{a x + \sqrt {a}}\right ) - \frac {12 \, a^{2} x^{4} + 4 \, a x^{2} + 15 \, {\rm Li}_2\left (a x^{2}\right ) - 6 \, \log \left (-a x^{2} + 1\right )}{75 \, x^{5}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A]
time = 0.52, size = 132, normalized size = 2.00 \begin {gather*} \left [\frac {6 \, a^{\frac {5}{2}} x^{5} \log \left (\frac {a x^{2} + 2 \, \sqrt {a} x + 1}{a x^{2} - 1}\right ) - 12 \, a^{2} x^{4} - 4 \, a x^{2} - 15 \, {\rm Li}_2\left (a x^{2}\right ) + 6 \, \log \left (-a x^{2} + 1\right )}{75 \, x^{5}}, -\frac {12 \, \sqrt {-a} a^{2} x^{5} \arctan \left (\sqrt {-a} x\right ) + 12 \, a^{2} x^{4} + 4 \, a x^{2} + 15 \, {\rm Li}_2\left (a x^{2}\right ) - 6 \, \log \left (-a x^{2} + 1\right )}{75 \, x^{5}}\right ] \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [B] Leaf count of result is larger than twice the leaf count of optimal. 299 vs.
\(2 (60) = 120\).
time = 140.03, size = 299, normalized size = 4.53 \begin {gather*} \begin {cases} - \frac {\pi ^{2}}{30 x^{5}} & \text {for}\: a = \frac {1}{x^{2}} \\0 & \text {for}\: a = 0 \\- \frac {12 a^{3} x^{7} \sqrt {\frac {1}{a}} \log {\left (x - \sqrt {\frac {1}{a}} \right )}}{75 x^{7} - \frac {75 x^{5}}{a}} - \frac {6 a^{3} x^{7} \sqrt {\frac {1}{a}} \operatorname {Li}_{1}\left (a x^{2}\right )}{75 x^{7} - \frac {75 x^{5}}{a}} - \frac {12 a^{2} x^{6}}{75 x^{7} - \frac {75 x^{5}}{a}} + \frac {12 a^{2} x^{5} \sqrt {\frac {1}{a}} \log {\left (x - \sqrt {\frac {1}{a}} \right )}}{75 x^{7} - \frac {75 x^{5}}{a}} + \frac {6 a^{2} x^{5} \sqrt {\frac {1}{a}} \operatorname {Li}_{1}\left (a x^{2}\right )}{75 x^{7} - \frac {75 x^{5}}{a}} + \frac {8 a x^{4}}{75 x^{7} - \frac {75 x^{5}}{a}} - \frac {6 x^{2} \operatorname {Li}_{1}\left (a x^{2}\right )}{75 x^{7} - \frac {75 x^{5}}{a}} - \frac {15 x^{2} \operatorname {Li}_{2}\left (a x^{2}\right )}{75 x^{7} - \frac {75 x^{5}}{a}} + \frac {4 x^{2}}{75 x^{7} - \frac {75 x^{5}}{a}} + \frac {6 \operatorname {Li}_{1}\left (a x^{2}\right )}{75 a x^{7} - 75 x^{5}} + \frac {15 \operatorname {Li}_{2}\left (a x^{2}\right )}{75 a x^{7} - 75 x^{5}} & \text {otherwise} \end {cases} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [B]
time = 0.34, size = 58, normalized size = 0.88 \begin {gather*} \frac {2\,\ln \left (1-a\,x^2\right )}{25\,x^5}-\frac {4\,a^2\,x^2+\frac {4\,a}{3}}{25\,x^3}-\frac {\mathrm {polylog}\left (2,a\,x^2\right )}{5\,x^5}-\frac {a^{5/2}\,\mathrm {atan}\left (\sqrt {a}\,x\,1{}\mathrm {i}\right )\,4{}\mathrm {i}}{25} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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