Optimal. Leaf size=161 \[ \frac {128 d \sqrt {d x}}{125 a}+\frac {128 (d x)^{5/2}}{625 d}-\frac {64 d^{3/2} \text {ArcTan}\left (\frac {\sqrt [4]{a} \sqrt {d x}}{\sqrt {d}}\right )}{125 a^{5/4}}-\frac {64 d^{3/2} \tanh ^{-1}\left (\frac {\sqrt [4]{a} \sqrt {d x}}{\sqrt {d}}\right )}{125 a^{5/4}}-\frac {32 (d x)^{5/2} \log \left (1-a x^2\right )}{125 d}-\frac {8 (d x)^{5/2} \text {PolyLog}\left (2,a x^2\right )}{25 d}+\frac {2 (d x)^{5/2} \text {PolyLog}\left (3,a x^2\right )}{5 d} \]
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Rubi [A]
time = 0.08, antiderivative size = 161, normalized size of antiderivative = 1.00, number of steps
used = 10, number of rules used = 8, integrand size = 15, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.533, Rules used = {6726, 2505,
16, 327, 335, 218, 214, 211} \begin {gather*} -\frac {64 d^{3/2} \text {ArcTan}\left (\frac {\sqrt [4]{a} \sqrt {d x}}{\sqrt {d}}\right )}{125 a^{5/4}}-\frac {64 d^{3/2} \tanh ^{-1}\left (\frac {\sqrt [4]{a} \sqrt {d x}}{\sqrt {d}}\right )}{125 a^{5/4}}-\frac {8 (d x)^{5/2} \text {Li}_2\left (a x^2\right )}{25 d}+\frac {2 (d x)^{5/2} \text {Li}_3\left (a x^2\right )}{5 d}-\frac {32 (d x)^{5/2} \log \left (1-a x^2\right )}{125 d}+\frac {128 d \sqrt {d x}}{125 a}+\frac {128 (d x)^{5/2}}{625 d} \end {gather*}
Antiderivative was successfully verified.
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Rule 16
Rule 211
Rule 214
Rule 218
Rule 327
Rule 335
Rule 2505
Rule 6726
Rubi steps
\begin {align*} \int (d x)^{3/2} \text {Li}_3\left (a x^2\right ) \, dx &=\frac {2 (d x)^{5/2} \text {Li}_3\left (a x^2\right )}{5 d}-\frac {4}{5} \int (d x)^{3/2} \text {Li}_2\left (a x^2\right ) \, dx\\ &=-\frac {8 (d x)^{5/2} \text {Li}_2\left (a x^2\right )}{25 d}+\frac {2 (d x)^{5/2} \text {Li}_3\left (a x^2\right )}{5 d}-\frac {16}{25} \int (d x)^{3/2} \log \left (1-a x^2\right ) \, dx\\ &=-\frac {32 (d x)^{5/2} \log \left (1-a x^2\right )}{125 d}-\frac {8 (d x)^{5/2} \text {Li}_2\left (a x^2\right )}{25 d}+\frac {2 (d x)^{5/2} \text {Li}_3\left (a x^2\right )}{5 d}-\frac {(64 a) \int \frac {x (d x)^{5/2}}{1-a x^2} \, dx}{125 d}\\ &=-\frac {32 (d x)^{5/2} \log \left (1-a x^2\right )}{125 d}-\frac {8 (d x)^{5/2} \text {Li}_2\left (a x^2\right )}{25 d}+\frac {2 (d x)^{5/2} \text {Li}_3\left (a x^2\right )}{5 d}-\frac {(64 a) \int \frac {(d x)^{7/2}}{1-a x^2} \, dx}{125 d^2}\\ &=\frac {128 (d x)^{5/2}}{625 d}-\frac {32 (d x)^{5/2} \log \left (1-a x^2\right )}{125 d}-\frac {8 (d x)^{5/2} \text {Li}_2\left (a x^2\right )}{25 d}+\frac {2 (d x)^{5/2} \text {Li}_3\left (a x^2\right )}{5 d}-\frac {64}{125} \int \frac {(d x)^{3/2}}{1-a x^2} \, dx\\ &=\frac {128 d \sqrt {d x}}{125 a}+\frac {128 (d x)^{5/2}}{625 d}-\frac {32 (d x)^{5/2} \log \left (1-a x^2\right )}{125 d}-\frac {8 (d x)^{5/2} \text {Li}_2\left (a x^2\right )}{25 d}+\frac {2 (d x)^{5/2} \text {Li}_3\left (a x^2\right )}{5 d}-\frac {\left (64 d^2\right ) \int \frac {1}{\sqrt {d x} \left (1-a x^2\right )} \, dx}{125 a}\\ &=\frac {128 d \sqrt {d x}}{125 a}+\frac {128 (d x)^{5/2}}{625 d}-\frac {32 (d x)^{5/2} \log \left (1-a x^2\right )}{125 d}-\frac {8 (d x)^{5/2} \text {Li}_2\left (a x^2\right )}{25 d}+\frac {2 (d x)^{5/2} \text {Li}_3\left (a x^2\right )}{5 d}-\frac {(128 d) \text {Subst}\left (\int \frac {1}{1-\frac {a x^4}{d^2}} \, dx,x,\sqrt {d x}\right )}{125 a}\\ &=\frac {128 d \sqrt {d x}}{125 a}+\frac {128 (d x)^{5/2}}{625 d}-\frac {32 (d x)^{5/2} \log \left (1-a x^2\right )}{125 d}-\frac {8 (d x)^{5/2} \text {Li}_2\left (a x^2\right )}{25 d}+\frac {2 (d x)^{5/2} \text {Li}_3\left (a x^2\right )}{5 d}-\frac {\left (64 d^2\right ) \text {Subst}\left (\int \frac {1}{d-\sqrt {a} x^2} \, dx,x,\sqrt {d x}\right )}{125 a}-\frac {\left (64 d^2\right ) \text {Subst}\left (\int \frac {1}{d+\sqrt {a} x^2} \, dx,x,\sqrt {d x}\right )}{125 a}\\ &=\frac {128 d \sqrt {d x}}{125 a}+\frac {128 (d x)^{5/2}}{625 d}-\frac {64 d^{3/2} \tan ^{-1}\left (\frac {\sqrt [4]{a} \sqrt {d x}}{\sqrt {d}}\right )}{125 a^{5/4}}-\frac {64 d^{3/2} \tanh ^{-1}\left (\frac {\sqrt [4]{a} \sqrt {d x}}{\sqrt {d}}\right )}{125 a^{5/4}}-\frac {32 (d x)^{5/2} \log \left (1-a x^2\right )}{125 d}-\frac {8 (d x)^{5/2} \text {Li}_2\left (a x^2\right )}{25 d}+\frac {2 (d x)^{5/2} \text {Li}_3\left (a x^2\right )}{5 d}\\ \end {align*}
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Mathematica [C] Result contains higher order function than in optimal. Order 5 vs. order 4 in
optimal.
time = 0.07, size = 89, normalized size = 0.55 \begin {gather*} -\frac {9 d \sqrt {d x} \Gamma \left (\frac {9}{4}\right ) \left (-320-64 a x^2+320 \, _2F_1\left (\frac {1}{4},1;\frac {5}{4};a x^2\right )+80 a x^2 \log \left (1-a x^2\right )+100 a x^2 \text {PolyLog}\left (2,a x^2\right )-125 a x^2 \text {PolyLog}\left (3,a x^2\right )\right )}{1250 a \Gamma \left (\frac {13}{4}\right )} \end {gather*}
Antiderivative was successfully verified.
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Maple [A]
time = 0.14, size = 155, normalized size = 0.96
method | result | size |
meijerg | \(-\frac {\left (d x \right )^{\frac {3}{2}} \left (\frac {4 \sqrt {x}\, \left (-a \right )^{\frac {9}{4}} \left (576 a \,x^{2}+2880\right )}{5625 a^{2}}+\frac {64 \sqrt {x}\, \left (-a \right )^{\frac {9}{4}} \left (\ln \left (1-\left (a \,x^{2}\right )^{\frac {1}{4}}\right )-\ln \left (1+\left (a \,x^{2}\right )^{\frac {1}{4}}\right )-2 \arctan \left (\left (a \,x^{2}\right )^{\frac {1}{4}}\right )\right )}{125 a^{2} \left (a \,x^{2}\right )^{\frac {1}{4}}}-\frac {64 x^{\frac {5}{2}} \left (-a \right )^{\frac {9}{4}} \ln \left (-a \,x^{2}+1\right )}{125 a}-\frac {16 x^{\frac {5}{2}} \left (-a \right )^{\frac {9}{4}} \polylog \left (2, a \,x^{2}\right )}{25 a}+\frac {4 x^{\frac {5}{2}} \left (-a \right )^{\frac {9}{4}} \polylog \left (3, a \,x^{2}\right )}{5 a}\right )}{2 x^{\frac {3}{2}} \left (-a \right )^{\frac {5}{4}}}\) | \(155\) |
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A]
time = 0.47, size = 175, normalized size = 1.09 \begin {gather*} -\frac {2 \, {\left (\frac {100 \, \left (d x\right )^{\frac {5}{2}} a {\rm Li}_2\left (a x^{2}\right ) + 80 \, \left (d x\right )^{\frac {5}{2}} a \log \left (-a d^{2} x^{2} + d^{2}\right ) - 125 \, \left (d x\right )^{\frac {5}{2}} a {\rm Li}_{3}(a x^{2}) - 32 \, \left (d x\right )^{\frac {5}{2}} {\left (5 \, a \log \left (d\right ) + 2 \, a\right )} - 320 \, \sqrt {d x} d^{2}}{a} + \frac {80 \, {\left (\frac {2 \, d^{3} \arctan \left (\frac {\sqrt {d x} \sqrt {a}}{\sqrt {\sqrt {a} d}}\right )}{\sqrt {\sqrt {a} d}} - \frac {d^{3} \log \left (\frac {\sqrt {d x} \sqrt {a} - \sqrt {\sqrt {a} d}}{\sqrt {d x} \sqrt {a} + \sqrt {\sqrt {a} d}}\right )}{\sqrt {\sqrt {a} d}}\right )}}{a}\right )}}{625 \, d} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A]
time = 0.41, size = 213, normalized size = 1.32 \begin {gather*} \frac {2 \, {\left (125 \, \sqrt {d x} a d x^{2} {\rm polylog}\left (3, a x^{2}\right ) + 320 \, a \left (\frac {d^{6}}{a^{5}}\right )^{\frac {1}{4}} \arctan \left (-\frac {\sqrt {d x} a^{4} d \left (\frac {d^{6}}{a^{5}}\right )^{\frac {3}{4}} - \sqrt {d^{3} x + a^{2} \sqrt {\frac {d^{6}}{a^{5}}}} a^{4} \left (\frac {d^{6}}{a^{5}}\right )^{\frac {3}{4}}}{d^{6}}\right ) - 80 \, a \left (\frac {d^{6}}{a^{5}}\right )^{\frac {1}{4}} \log \left (32 \, \sqrt {d x} d + 32 \, a \left (\frac {d^{6}}{a^{5}}\right )^{\frac {1}{4}}\right ) + 80 \, a \left (\frac {d^{6}}{a^{5}}\right )^{\frac {1}{4}} \log \left (32 \, \sqrt {d x} d - 32 \, a \left (\frac {d^{6}}{a^{5}}\right )^{\frac {1}{4}}\right ) - 4 \, {\left (25 \, a d x^{2} {\rm Li}_2\left (a x^{2}\right ) + 20 \, a d x^{2} \log \left (-a x^{2} + 1\right ) - 16 \, a d x^{2} - 80 \, d\right )} \sqrt {d x}\right )}}{625 \, a} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \left (d x\right )^{\frac {3}{2}} \operatorname {Li}_{3}\left (a x^{2}\right )\, dx \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [F]
time = 0.00, size = -1, normalized size = -0.01 \begin {gather*} \int \mathrm {polylog}\left (3,a\,x^2\right )\,{\left (d\,x\right )}^{3/2} \,d x \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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