Integrand size = 13, antiderivative size = 87 \[ \int \frac {x^{3/2}}{(a+b x)^3} \, dx=-\frac {2 x^{3/2}}{b (a+b x)^2}+\frac {3 a \left (\sqrt {x} \left (-\frac {1}{2 b (a+b x)^2}+\frac {1}{4 a b (a+b x)}\right )+\frac {\arctan \left (\frac {b x}{a}\right )}{4 a b \sqrt {a b}}\right )}{b} \]
-2*x^(3/2)/b/(b*x+a)^2+3*a/b*((-1/2/b/(b*x+a)^2+1/4/a/b/(b*x+a))*x^(1/2)+1 /4/a/b/(a*b)^(1/2)*arctan(b*x/a))
Time = 0.17 (sec) , antiderivative size = 59, normalized size of antiderivative = 0.68 \[ \int \frac {x^{3/2}}{(a+b x)^3} \, dx=-\frac {\sqrt {x} (3 a+5 b x)}{4 b^2 (a+b x)^2}+\frac {3 \arctan \left (\frac {\sqrt {b} \sqrt {x}}{\sqrt {a}}\right )}{4 \sqrt {a} b^{5/2}} \]
-1/4*(Sqrt[x]*(3*a + 5*b*x))/(b^2*(a + b*x)^2) + (3*ArcTan[(Sqrt[b]*Sqrt[x ])/Sqrt[a]])/(4*Sqrt[a]*b^(5/2))
Time = 0.17 (sec) , antiderivative size = 73, normalized size of antiderivative = 0.84, number of steps used = 5, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.308, Rules used = {51, 51, 73, 218}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int \frac {x^{3/2}}{(a+b x)^3} \, dx\) |
\(\Big \downarrow \) 51 |
\(\displaystyle \frac {3 \int \frac {\sqrt {x}}{(a+b x)^2}dx}{4 b}-\frac {x^{3/2}}{2 b (a+b x)^2}\) |
\(\Big \downarrow \) 51 |
\(\displaystyle \frac {3 \left (\frac {\int \frac {1}{\sqrt {x} (a+b x)}dx}{2 b}-\frac {\sqrt {x}}{b (a+b x)}\right )}{4 b}-\frac {x^{3/2}}{2 b (a+b x)^2}\) |
\(\Big \downarrow \) 73 |
\(\displaystyle \frac {3 \left (\frac {\int \frac {1}{a+b x}d\sqrt {x}}{b}-\frac {\sqrt {x}}{b (a+b x)}\right )}{4 b}-\frac {x^{3/2}}{2 b (a+b x)^2}\) |
\(\Big \downarrow \) 218 |
\(\displaystyle \frac {3 \left (\frac {\arctan \left (\frac {\sqrt {b} \sqrt {x}}{\sqrt {a}}\right )}{\sqrt {a} b^{3/2}}-\frac {\sqrt {x}}{b (a+b x)}\right )}{4 b}-\frac {x^{3/2}}{2 b (a+b x)^2}\) |
-1/2*x^(3/2)/(b*(a + b*x)^2) + (3*(-(Sqrt[x]/(b*(a + b*x))) + ArcTan[(Sqrt [b]*Sqrt[x])/Sqrt[a]]/(Sqrt[a]*b^(3/2))))/(4*b)
3.2.19.3.1 Defintions of rubi rules used
Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> Simp[ (a + b*x)^(m + 1)*((c + d*x)^n/(b*(m + 1))), x] - Simp[d*(n/(b*(m + 1))) Int[(a + b*x)^(m + 1)*(c + d*x)^(n - 1), x], x] /; FreeQ[{a, b, c, d, n}, x ] && ILtQ[m, -1] && FractionQ[n] && GtQ[n, 0]
Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> With[ {p = Denominator[m]}, Simp[p/b Subst[Int[x^(p*(m + 1) - 1)*(c - a*(d/b) + d*(x^p/b))^n, x], x, (a + b*x)^(1/p)], x]] /; FreeQ[{a, b, c, d}, x] && Lt Q[-1, m, 0] && LeQ[-1, n, 0] && LeQ[Denominator[n], Denominator[m]] && IntL inearQ[a, b, c, d, m, n, x]
Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(Rt[a/b, 2]/a)*ArcTan[x/R t[a/b, 2]], x] /; FreeQ[{a, b}, x] && PosQ[a/b]
Time = 0.07 (sec) , antiderivative size = 50, normalized size of antiderivative = 0.57
method | result | size |
derivativedivides | \(\frac {-\frac {5 x^{\frac {3}{2}}}{4 b}-\frac {3 a \sqrt {x}}{4 b^{2}}}{\left (b x +a \right )^{2}}+\frac {3 \arctan \left (\frac {b \sqrt {x}}{\sqrt {a b}}\right )}{4 b^{2} \sqrt {a b}}\) | \(50\) |
default | \(\frac {-\frac {5 x^{\frac {3}{2}}}{4 b}-\frac {3 a \sqrt {x}}{4 b^{2}}}{\left (b x +a \right )^{2}}+\frac {3 \arctan \left (\frac {b \sqrt {x}}{\sqrt {a b}}\right )}{4 b^{2} \sqrt {a b}}\) | \(50\) |
2*(-5/8*x^(3/2)/b-3/8*a/b^2*x^(1/2))/(b*x+a)^2+3/4/b^2/(a*b)^(1/2)*arctan( b*x^(1/2)/(a*b)^(1/2))
Time = 0.26 (sec) , antiderivative size = 185, normalized size of antiderivative = 2.13 \[ \int \frac {x^{3/2}}{(a+b x)^3} \, dx=\left [-\frac {3 \, {\left (b^{2} x^{2} + 2 \, a b x + a^{2}\right )} \sqrt {-a b} \log \left (\frac {b x - a - 2 \, \sqrt {-a b} \sqrt {x}}{b x + a}\right ) + 2 \, {\left (5 \, a b^{2} x + 3 \, a^{2} b\right )} \sqrt {x}}{8 \, {\left (a b^{5} x^{2} + 2 \, a^{2} b^{4} x + a^{3} b^{3}\right )}}, -\frac {3 \, {\left (b^{2} x^{2} + 2 \, a b x + a^{2}\right )} \sqrt {a b} \arctan \left (\frac {\sqrt {a b}}{b \sqrt {x}}\right ) + {\left (5 \, a b^{2} x + 3 \, a^{2} b\right )} \sqrt {x}}{4 \, {\left (a b^{5} x^{2} + 2 \, a^{2} b^{4} x + a^{3} b^{3}\right )}}\right ] \]
[-1/8*(3*(b^2*x^2 + 2*a*b*x + a^2)*sqrt(-a*b)*log((b*x - a - 2*sqrt(-a*b)* sqrt(x))/(b*x + a)) + 2*(5*a*b^2*x + 3*a^2*b)*sqrt(x))/(a*b^5*x^2 + 2*a^2* b^4*x + a^3*b^3), -1/4*(3*(b^2*x^2 + 2*a*b*x + a^2)*sqrt(a*b)*arctan(sqrt( a*b)/(b*sqrt(x))) + (5*a*b^2*x + 3*a^2*b)*sqrt(x))/(a*b^5*x^2 + 2*a^2*b^4* x + a^3*b^3)]
Leaf count of result is larger than twice the leaf count of optimal. 605 vs. \(2 (66) = 132\).
Time = 9.86 (sec) , antiderivative size = 605, normalized size of antiderivative = 6.95 \[ \int \frac {x^{3/2}}{(a+b x)^3} \, dx=\begin {cases} \frac {\tilde {\infty }}{\sqrt {x}} & \text {for}\: a = 0 \wedge b = 0 \\\frac {2 x^{\frac {5}{2}}}{5 a^{3}} & \text {for}\: b = 0 \\- \frac {2}{b^{3} \sqrt {x}} & \text {for}\: a = 0 \\\frac {3 a^{2} \log {\left (\sqrt {x} - \sqrt {- \frac {a}{b}} \right )}}{8 a^{2} b^{3} \sqrt {- \frac {a}{b}} + 16 a b^{4} x \sqrt {- \frac {a}{b}} + 8 b^{5} x^{2} \sqrt {- \frac {a}{b}}} - \frac {3 a^{2} \log {\left (\sqrt {x} + \sqrt {- \frac {a}{b}} \right )}}{8 a^{2} b^{3} \sqrt {- \frac {a}{b}} + 16 a b^{4} x \sqrt {- \frac {a}{b}} + 8 b^{5} x^{2} \sqrt {- \frac {a}{b}}} - \frac {6 a b \sqrt {x} \sqrt {- \frac {a}{b}}}{8 a^{2} b^{3} \sqrt {- \frac {a}{b}} + 16 a b^{4} x \sqrt {- \frac {a}{b}} + 8 b^{5} x^{2} \sqrt {- \frac {a}{b}}} + \frac {6 a b x \log {\left (\sqrt {x} - \sqrt {- \frac {a}{b}} \right )}}{8 a^{2} b^{3} \sqrt {- \frac {a}{b}} + 16 a b^{4} x \sqrt {- \frac {a}{b}} + 8 b^{5} x^{2} \sqrt {- \frac {a}{b}}} - \frac {6 a b x \log {\left (\sqrt {x} + \sqrt {- \frac {a}{b}} \right )}}{8 a^{2} b^{3} \sqrt {- \frac {a}{b}} + 16 a b^{4} x \sqrt {- \frac {a}{b}} + 8 b^{5} x^{2} \sqrt {- \frac {a}{b}}} - \frac {10 b^{2} x^{\frac {3}{2}} \sqrt {- \frac {a}{b}}}{8 a^{2} b^{3} \sqrt {- \frac {a}{b}} + 16 a b^{4} x \sqrt {- \frac {a}{b}} + 8 b^{5} x^{2} \sqrt {- \frac {a}{b}}} + \frac {3 b^{2} x^{2} \log {\left (\sqrt {x} - \sqrt {- \frac {a}{b}} \right )}}{8 a^{2} b^{3} \sqrt {- \frac {a}{b}} + 16 a b^{4} x \sqrt {- \frac {a}{b}} + 8 b^{5} x^{2} \sqrt {- \frac {a}{b}}} - \frac {3 b^{2} x^{2} \log {\left (\sqrt {x} + \sqrt {- \frac {a}{b}} \right )}}{8 a^{2} b^{3} \sqrt {- \frac {a}{b}} + 16 a b^{4} x \sqrt {- \frac {a}{b}} + 8 b^{5} x^{2} \sqrt {- \frac {a}{b}}} & \text {otherwise} \end {cases} \]
Piecewise((zoo/sqrt(x), Eq(a, 0) & Eq(b, 0)), (2*x**(5/2)/(5*a**3), Eq(b, 0)), (-2/(b**3*sqrt(x)), Eq(a, 0)), (3*a**2*log(sqrt(x) - sqrt(-a/b))/(8*a **2*b**3*sqrt(-a/b) + 16*a*b**4*x*sqrt(-a/b) + 8*b**5*x**2*sqrt(-a/b)) - 3 *a**2*log(sqrt(x) + sqrt(-a/b))/(8*a**2*b**3*sqrt(-a/b) + 16*a*b**4*x*sqrt (-a/b) + 8*b**5*x**2*sqrt(-a/b)) - 6*a*b*sqrt(x)*sqrt(-a/b)/(8*a**2*b**3*s qrt(-a/b) + 16*a*b**4*x*sqrt(-a/b) + 8*b**5*x**2*sqrt(-a/b)) + 6*a*b*x*log (sqrt(x) - sqrt(-a/b))/(8*a**2*b**3*sqrt(-a/b) + 16*a*b**4*x*sqrt(-a/b) + 8*b**5*x**2*sqrt(-a/b)) - 6*a*b*x*log(sqrt(x) + sqrt(-a/b))/(8*a**2*b**3*s qrt(-a/b) + 16*a*b**4*x*sqrt(-a/b) + 8*b**5*x**2*sqrt(-a/b)) - 10*b**2*x** (3/2)*sqrt(-a/b)/(8*a**2*b**3*sqrt(-a/b) + 16*a*b**4*x*sqrt(-a/b) + 8*b**5 *x**2*sqrt(-a/b)) + 3*b**2*x**2*log(sqrt(x) - sqrt(-a/b))/(8*a**2*b**3*sqr t(-a/b) + 16*a*b**4*x*sqrt(-a/b) + 8*b**5*x**2*sqrt(-a/b)) - 3*b**2*x**2*l og(sqrt(x) + sqrt(-a/b))/(8*a**2*b**3*sqrt(-a/b) + 16*a*b**4*x*sqrt(-a/b) + 8*b**5*x**2*sqrt(-a/b)), True))
Time = 0.30 (sec) , antiderivative size = 61, normalized size of antiderivative = 0.70 \[ \int \frac {x^{3/2}}{(a+b x)^3} \, dx=-\frac {5 \, b x^{\frac {3}{2}} + 3 \, a \sqrt {x}}{4 \, {\left (b^{4} x^{2} + 2 \, a b^{3} x + a^{2} b^{2}\right )}} + \frac {3 \, \arctan \left (\frac {b \sqrt {x}}{\sqrt {a b}}\right )}{4 \, \sqrt {a b} b^{2}} \]
-1/4*(5*b*x^(3/2) + 3*a*sqrt(x))/(b^4*x^2 + 2*a*b^3*x + a^2*b^2) + 3/4*arc tan(b*sqrt(x)/sqrt(a*b))/(sqrt(a*b)*b^2)
Time = 0.26 (sec) , antiderivative size = 47, normalized size of antiderivative = 0.54 \[ \int \frac {x^{3/2}}{(a+b x)^3} \, dx=\frac {3 \, \arctan \left (\frac {b \sqrt {x}}{\sqrt {a b}}\right )}{4 \, \sqrt {a b} b^{2}} - \frac {5 \, b x^{\frac {3}{2}} + 3 \, a \sqrt {x}}{4 \, {\left (b x + a\right )}^{2} b^{2}} \]
3/4*arctan(b*sqrt(x)/sqrt(a*b))/(sqrt(a*b)*b^2) - 1/4*(5*b*x^(3/2) + 3*a*s qrt(x))/((b*x + a)^2*b^2)
Time = 15.44 (sec) , antiderivative size = 58, normalized size of antiderivative = 0.67 \[ \int \frac {x^{3/2}}{(a+b x)^3} \, dx=\frac {3\,\mathrm {atan}\left (\frac {\sqrt {b}\,\sqrt {x}}{\sqrt {a}}\right )}{4\,\sqrt {a}\,b^{5/2}}-\frac {\frac {5\,x^{3/2}}{4\,b}+\frac {3\,a\,\sqrt {x}}{4\,b^2}}{a^2+2\,a\,b\,x+b^2\,x^2} \]