3.2.29 \(\int \frac {e+f x}{(1+\sqrt {3}-x) \sqrt {-1+x^3}} \, dx\) [129]

3.2.29.1 Optimal result
3.2.29.2 Mathematica [C] (warning: unable to verify)
3.2.29.3 Rubi [A] (verified)
3.2.29.4 Maple [A] (verified)
3.2.29.5 Fricas [C] (verification not implemented)
3.2.29.6 Sympy [F]
3.2.29.7 Maxima [F]
3.2.29.8 Giac [F(-2)]
3.2.29.9 Mupad [F(-1)]

3.2.29.1 Optimal result

Integrand size = 27, antiderivative size = 190 \[ \int \frac {e+f x}{\left (1+\sqrt {3}-x\right ) \sqrt {-1+x^3}} \, dx=-\frac {\left (e+f+\sqrt {3} f\right ) \text {arctanh}\left (\frac {\sqrt {3+2 \sqrt {3}} (1-x)}{\sqrt {-1+x^3}}\right )}{\sqrt {3 \left (3+2 \sqrt {3}\right )}}-\frac {\sqrt {2-\sqrt {3}} \left (e+\left (1-\sqrt {3}\right ) f\right ) (1-x) \sqrt {\frac {1+x+x^2}{\left (1-\sqrt {3}-x\right )^2}} \operatorname {EllipticF}\left (\arcsin \left (\frac {1+\sqrt {3}-x}{1-\sqrt {3}-x}\right ),-7+4 \sqrt {3}\right )}{3^{3/4} \sqrt {-\frac {1-x}{\left (1-\sqrt {3}-x\right )^2}} \sqrt {-1+x^3}} \]

output
-1/3*(1-x)*EllipticF((1-x+3^(1/2))/(1-x-3^(1/2)),2*I-I*3^(1/2))*(e+f*(1-3^ 
(1/2)))*(1/2*6^(1/2)-1/2*2^(1/2))*((x^2+x+1)/(1-x-3^(1/2))^2)^(1/2)*3^(1/4 
)/(x^3-1)^(1/2)/((-1+x)/(1-x-3^(1/2))^2)^(1/2)-arctanh((1-x)*(3+2*3^(1/2)) 
^(1/2)/(x^3-1)^(1/2))*(e+f+f*3^(1/2))/(9+6*3^(1/2))^(1/2)
 
3.2.29.2 Mathematica [C] (warning: unable to verify)

Result contains complex when optimal does not.

Time = 20.51 (sec) , antiderivative size = 289, normalized size of antiderivative = 1.52 \[ \int \frac {e+f x}{\left (1+\sqrt {3}-x\right ) \sqrt {-1+x^3}} \, dx=\frac {2 \sqrt {\frac {2}{3}} \sqrt {-\frac {i (-1+x)}{3 i+\sqrt {3}}} \left (-3 i f \sqrt {-i+\sqrt {3}-2 i x} \left (-i \left ((2+i)+\sqrt {3}\right )+\left ((2-i)+\sqrt {3}\right ) x\right ) \operatorname {EllipticF}\left (\arcsin \left (\frac {\sqrt {i+\sqrt {3}+2 i x}}{\sqrt {2} \sqrt [4]{3}}\right ),\frac {2 \sqrt {3}}{3 i+\sqrt {3}}\right )+2 \left (\sqrt {3} e+\left (3+\sqrt {3}\right ) f\right ) \sqrt {i+\sqrt {3}+2 i x} \sqrt {1+x+x^2} \operatorname {EllipticPi}\left (\frac {2 \sqrt {3}}{3 i+(1+2 i) \sqrt {3}},\arcsin \left (\frac {\sqrt {i+\sqrt {3}+2 i x}}{\sqrt {2} \sqrt [4]{3}}\right ),\frac {2 \sqrt {3}}{3 i+\sqrt {3}}\right )\right )}{\left (3 i+(1+2 i) \sqrt {3}\right ) \sqrt {i+\sqrt {3}+2 i x} \sqrt {-1+x^3}} \]

input
Integrate[(e + f*x)/((1 + Sqrt[3] - x)*Sqrt[-1 + x^3]),x]
 
output
(2*Sqrt[2/3]*Sqrt[((-I)*(-1 + x))/(3*I + Sqrt[3])]*((-3*I)*f*Sqrt[-I + Sqr 
t[3] - (2*I)*x]*((-I)*((2 + I) + Sqrt[3]) + ((2 - I) + Sqrt[3])*x)*Ellipti 
cF[ArcSin[Sqrt[I + Sqrt[3] + (2*I)*x]/(Sqrt[2]*3^(1/4))], (2*Sqrt[3])/(3*I 
 + Sqrt[3])] + 2*(Sqrt[3]*e + (3 + Sqrt[3])*f)*Sqrt[I + Sqrt[3] + (2*I)*x] 
*Sqrt[1 + x + x^2]*EllipticPi[(2*Sqrt[3])/(3*I + (1 + 2*I)*Sqrt[3]), ArcSi 
n[Sqrt[I + Sqrt[3] + (2*I)*x]/(Sqrt[2]*3^(1/4))], (2*Sqrt[3])/(3*I + Sqrt[ 
3])]))/((3*I + (1 + 2*I)*Sqrt[3])*Sqrt[I + Sqrt[3] + (2*I)*x]*Sqrt[-1 + x^ 
3])
 
3.2.29.3 Rubi [A] (verified)

Time = 0.47 (sec) , antiderivative size = 187, normalized size of antiderivative = 0.98, number of steps used = 6, number of rules used = 5, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.185, Rules used = {2566, 27, 760, 2565, 219}

Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.

\(\displaystyle \int \frac {e+f x}{\left (-x+\sqrt {3}+1\right ) \sqrt {x^3-1}} \, dx\)

\(\Big \downarrow \) 2566

\(\displaystyle -\frac {1}{2} \left (f-\frac {e+f}{\sqrt {3}}\right ) \int \frac {1}{\sqrt {x^3-1}}dx-\frac {1}{12} \left (\frac {e+f}{\sqrt {3}}+f\right ) \int \frac {6 \left (-x-\sqrt {3}+1\right )}{\left (-x+\sqrt {3}+1\right ) \sqrt {x^3-1}}dx\)

\(\Big \downarrow \) 27

\(\displaystyle -\frac {1}{2} \left (f-\frac {e+f}{\sqrt {3}}\right ) \int \frac {1}{\sqrt {x^3-1}}dx-\frac {1}{2} \left (\frac {e+f}{\sqrt {3}}+f\right ) \int \frac {-x-\sqrt {3}+1}{\left (-x+\sqrt {3}+1\right ) \sqrt {x^3-1}}dx\)

\(\Big \downarrow \) 760

\(\displaystyle \frac {\sqrt {2-\sqrt {3}} (1-x) \sqrt {\frac {x^2+x+1}{\left (-x-\sqrt {3}+1\right )^2}} \left (f-\frac {e+f}{\sqrt {3}}\right ) \operatorname {EllipticF}\left (\arcsin \left (\frac {-x+\sqrt {3}+1}{-x-\sqrt {3}+1}\right ),-7+4 \sqrt {3}\right )}{\sqrt [4]{3} \sqrt {-\frac {1-x}{\left (-x-\sqrt {3}+1\right )^2}} \sqrt {x^3-1}}-\frac {1}{2} \left (\frac {e+f}{\sqrt {3}}+f\right ) \int \frac {-x-\sqrt {3}+1}{\left (-x+\sqrt {3}+1\right ) \sqrt {x^3-1}}dx\)

\(\Big \downarrow \) 2565

\(\displaystyle \frac {\sqrt {2-\sqrt {3}} (1-x) \sqrt {\frac {x^2+x+1}{\left (-x-\sqrt {3}+1\right )^2}} \left (f-\frac {e+f}{\sqrt {3}}\right ) \operatorname {EllipticF}\left (\arcsin \left (\frac {-x+\sqrt {3}+1}{-x-\sqrt {3}+1}\right ),-7+4 \sqrt {3}\right )}{\sqrt [4]{3} \sqrt {-\frac {1-x}{\left (-x-\sqrt {3}+1\right )^2}} \sqrt {x^3-1}}-\left (\frac {e+f}{\sqrt {3}}+f\right ) \int \frac {1}{1-\frac {\left (3+2 \sqrt {3}\right ) (1-x)^2}{x^3-1}}d\frac {1-x}{\sqrt {x^3-1}}\)

\(\Big \downarrow \) 219

\(\displaystyle \frac {\sqrt {2-\sqrt {3}} (1-x) \sqrt {\frac {x^2+x+1}{\left (-x-\sqrt {3}+1\right )^2}} \left (f-\frac {e+f}{\sqrt {3}}\right ) \operatorname {EllipticF}\left (\arcsin \left (\frac {-x+\sqrt {3}+1}{-x-\sqrt {3}+1}\right ),-7+4 \sqrt {3}\right )}{\sqrt [4]{3} \sqrt {-\frac {1-x}{\left (-x-\sqrt {3}+1\right )^2}} \sqrt {x^3-1}}-\frac {\text {arctanh}\left (\frac {\sqrt {3+2 \sqrt {3}} (1-x)}{\sqrt {x^3-1}}\right ) \left (\frac {e+f}{\sqrt {3}}+f\right )}{\sqrt {3+2 \sqrt {3}}}\)

input
Int[(e + f*x)/((1 + Sqrt[3] - x)*Sqrt[-1 + x^3]),x]
 
output
-(((f + (e + f)/Sqrt[3])*ArcTanh[(Sqrt[3 + 2*Sqrt[3]]*(1 - x))/Sqrt[-1 + x 
^3]])/Sqrt[3 + 2*Sqrt[3]]) + (Sqrt[2 - Sqrt[3]]*(f - (e + f)/Sqrt[3])*(1 - 
 x)*Sqrt[(1 + x + x^2)/(1 - Sqrt[3] - x)^2]*EllipticF[ArcSin[(1 + Sqrt[3] 
- x)/(1 - Sqrt[3] - x)], -7 + 4*Sqrt[3]])/(3^(1/4)*Sqrt[-((1 - x)/(1 - Sqr 
t[3] - x)^2)]*Sqrt[-1 + x^3])
 

3.2.29.3.1 Defintions of rubi rules used

rule 27
Int[(a_)*(Fx_), x_Symbol] :> Simp[a   Int[Fx, x], x] /; FreeQ[a, x] &&  !Ma 
tchQ[Fx, (b_)*(Gx_) /; FreeQ[b, x]]
 

rule 219
Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(1/(Rt[a, 2]*Rt[-b, 2]))* 
ArcTanh[Rt[-b, 2]*(x/Rt[a, 2])], x] /; FreeQ[{a, b}, x] && NegQ[a/b] && (Gt 
Q[a, 0] || LtQ[b, 0])
 

rule 760
Int[1/Sqrt[(a_) + (b_.)*(x_)^3], x_Symbol] :> With[{r = Numer[Rt[b/a, 3]], 
s = Denom[Rt[b/a, 3]]}, Simp[2*Sqrt[2 - Sqrt[3]]*(s + r*x)*(Sqrt[(s^2 - r*s 
*x + r^2*x^2)/((1 - Sqrt[3])*s + r*x)^2]/(3^(1/4)*r*Sqrt[a + b*x^3]*Sqrt[(- 
s)*((s + r*x)/((1 - Sqrt[3])*s + r*x)^2)]))*EllipticF[ArcSin[((1 + Sqrt[3]) 
*s + r*x)/((1 - Sqrt[3])*s + r*x)], -7 + 4*Sqrt[3]], x]] /; FreeQ[{a, b}, x 
] && NegQ[a]
 

rule 2565
Int[((e_) + (f_.)*(x_))/(((c_) + (d_.)*(x_))*Sqrt[(a_) + (b_.)*(x_)^3]), x_ 
Symbol] :> With[{k = Simplify[(d*e + 2*c*f)/(c*f)]}, Simp[(1 + k)*(e/d)   S 
ubst[Int[1/(1 + (3 + 2*k)*a*x^2), x], x, (1 + (1 + k)*d*(x/c))/Sqrt[a + b*x 
^3]], x]] /; FreeQ[{a, b, c, d, e, f}, x] && NeQ[d*e - c*f, 0] && EqQ[b^2*c 
^6 - 20*a*b*c^3*d^3 - 8*a^2*d^6, 0] && EqQ[6*a*d^4*e - c*f*(b*c^3 - 22*a*d^ 
3), 0]
 

rule 2566
Int[((e_.) + (f_.)*(x_))/(((c_) + (d_.)*(x_))*Sqrt[(a_) + (b_.)*(x_)^3]), x 
_Symbol] :> Simp[-(6*a*d^4*e - c*f*(b*c^3 - 22*a*d^3))/(c*d*(b*c^3 - 28*a*d 
^3))   Int[1/Sqrt[a + b*x^3], x], x] + Simp[(d*e - c*f)/(c*d*(b*c^3 - 28*a* 
d^3))   Int[(c*(b*c^3 - 22*a*d^3) + 6*a*d^4*x)/((c + d*x)*Sqrt[a + b*x^3]), 
 x], x] /; FreeQ[{a, b, c, d, e, f}, x] && NeQ[d*e - c*f, 0] && EqQ[b^2*c^6 
 - 20*a*b*c^3*d^3 - 8*a^2*d^6, 0] && NeQ[6*a*d^4*e - c*f*(b*c^3 - 22*a*d^3) 
, 0]
 
3.2.29.4 Maple [A] (verified)

Time = 1.42 (sec) , antiderivative size = 262, normalized size of antiderivative = 1.38

method result size
default \(-\frac {2 f \left (-\frac {3}{2}-\frac {i \sqrt {3}}{2}\right ) \sqrt {\frac {x -1}{-\frac {3}{2}-\frac {i \sqrt {3}}{2}}}\, \sqrt {\frac {x +\frac {1}{2}-\frac {i \sqrt {3}}{2}}{\frac {3}{2}-\frac {i \sqrt {3}}{2}}}\, \sqrt {\frac {x +\frac {1}{2}+\frac {i \sqrt {3}}{2}}{\frac {3}{2}+\frac {i \sqrt {3}}{2}}}\, F\left (\sqrt {\frac {x -1}{-\frac {3}{2}-\frac {i \sqrt {3}}{2}}}, \sqrt {\frac {\frac {3}{2}+\frac {i \sqrt {3}}{2}}{\frac {3}{2}-\frac {i \sqrt {3}}{2}}}\right )}{\sqrt {x^{3}-1}}-\frac {2 \left (-e -f -f \sqrt {3}\right ) \left (-\frac {3}{2}-\frac {i \sqrt {3}}{2}\right ) \sqrt {\frac {x -1}{-\frac {3}{2}-\frac {i \sqrt {3}}{2}}}\, \sqrt {\frac {x +\frac {1}{2}-\frac {i \sqrt {3}}{2}}{\frac {3}{2}-\frac {i \sqrt {3}}{2}}}\, \sqrt {\frac {x +\frac {1}{2}+\frac {i \sqrt {3}}{2}}{\frac {3}{2}+\frac {i \sqrt {3}}{2}}}\, \sqrt {3}\, \Pi \left (\sqrt {\frac {x -1}{-\frac {3}{2}-\frac {i \sqrt {3}}{2}}}, -\frac {\left (\frac {3}{2}+\frac {i \sqrt {3}}{2}\right ) \sqrt {3}}{3}, \sqrt {\frac {\frac {3}{2}+\frac {i \sqrt {3}}{2}}{\frac {3}{2}-\frac {i \sqrt {3}}{2}}}\right )}{3 \sqrt {x^{3}-1}}\) \(262\)
elliptic \(-\frac {2 f \left (-\frac {3}{2}-\frac {i \sqrt {3}}{2}\right ) \sqrt {\frac {x -1}{-\frac {3}{2}-\frac {i \sqrt {3}}{2}}}\, \sqrt {\frac {x +\frac {1}{2}-\frac {i \sqrt {3}}{2}}{\frac {3}{2}-\frac {i \sqrt {3}}{2}}}\, \sqrt {\frac {x +\frac {1}{2}+\frac {i \sqrt {3}}{2}}{\frac {3}{2}+\frac {i \sqrt {3}}{2}}}\, F\left (\sqrt {\frac {x -1}{-\frac {3}{2}-\frac {i \sqrt {3}}{2}}}, \sqrt {\frac {\frac {3}{2}+\frac {i \sqrt {3}}{2}}{\frac {3}{2}-\frac {i \sqrt {3}}{2}}}\right )}{\sqrt {x^{3}-1}}-\frac {2 \left (-e -f -f \sqrt {3}\right ) \left (-\frac {3}{2}-\frac {i \sqrt {3}}{2}\right ) \sqrt {\frac {x -1}{-\frac {3}{2}-\frac {i \sqrt {3}}{2}}}\, \sqrt {\frac {x +\frac {1}{2}-\frac {i \sqrt {3}}{2}}{\frac {3}{2}-\frac {i \sqrt {3}}{2}}}\, \sqrt {\frac {x +\frac {1}{2}+\frac {i \sqrt {3}}{2}}{\frac {3}{2}+\frac {i \sqrt {3}}{2}}}\, \sqrt {3}\, \Pi \left (\sqrt {\frac {x -1}{-\frac {3}{2}-\frac {i \sqrt {3}}{2}}}, -\frac {\left (\frac {3}{2}+\frac {i \sqrt {3}}{2}\right ) \sqrt {3}}{3}, \sqrt {\frac {\frac {3}{2}+\frac {i \sqrt {3}}{2}}{\frac {3}{2}-\frac {i \sqrt {3}}{2}}}\right )}{3 \sqrt {x^{3}-1}}\) \(262\)

input
int((f*x+e)/(1-x+3^(1/2))/(x^3-1)^(1/2),x,method=_RETURNVERBOSE)
 
output
-2*f*(-3/2-1/2*I*3^(1/2))*((x-1)/(-3/2-1/2*I*3^(1/2)))^(1/2)*((x+1/2-1/2*I 
*3^(1/2))/(3/2-1/2*I*3^(1/2)))^(1/2)*((x+1/2+1/2*I*3^(1/2))/(3/2+1/2*I*3^( 
1/2)))^(1/2)/(x^3-1)^(1/2)*EllipticF(((x-1)/(-3/2-1/2*I*3^(1/2)))^(1/2),(( 
3/2+1/2*I*3^(1/2))/(3/2-1/2*I*3^(1/2)))^(1/2))-2/3*(-e-f-f*3^(1/2))*(-3/2- 
1/2*I*3^(1/2))*((x-1)/(-3/2-1/2*I*3^(1/2)))^(1/2)*((x+1/2-1/2*I*3^(1/2))/( 
3/2-1/2*I*3^(1/2)))^(1/2)*((x+1/2+1/2*I*3^(1/2))/(3/2+1/2*I*3^(1/2)))^(1/2 
)/(x^3-1)^(1/2)*3^(1/2)*EllipticPi(((x-1)/(-3/2-1/2*I*3^(1/2)))^(1/2),-1/3 
*(3/2+1/2*I*3^(1/2))*3^(1/2),((3/2+1/2*I*3^(1/2))/(3/2-1/2*I*3^(1/2)))^(1/ 
2))
 
3.2.29.5 Fricas [C] (verification not implemented)

Result contains higher order function than in optimal. Order 9 vs. order 4.

Time = 0.17 (sec) , antiderivative size = 723, normalized size of antiderivative = 3.81 \[ \int \frac {e+f x}{\left (1+\sqrt {3}-x\right ) \sqrt {-1+x^3}} \, dx=\left [\frac {1}{3} \, {\left (\sqrt {3} {\left (e + f\right )} - 3 \, f\right )} {\rm weierstrassPInverse}\left (0, 4, x\right ) + \frac {1}{12} \, \sqrt {-3 \, e^{2} + 6 \, e f + 2 \, \sqrt {3} {\left (e^{2} - e f + f^{2}\right )}} \log \left (-\frac {{\left (e^{2} + 2 \, e f - 2 \, f^{2}\right )} x^{8} + 16 \, {\left (e^{2} + 2 \, e f - 2 \, f^{2}\right )} x^{7} + 112 \, {\left (e^{2} + 2 \, e f - 2 \, f^{2}\right )} x^{6} + 16 \, {\left (e^{2} + 2 \, e f - 2 \, f^{2}\right )} x^{5} + 112 \, {\left (e^{2} + 2 \, e f - 2 \, f^{2}\right )} x^{4} - 224 \, {\left (e^{2} + 2 \, e f - 2 \, f^{2}\right )} x^{3} + 64 \, {\left (e^{2} + 2 \, e f - 2 \, f^{2}\right )} x^{2} + 4 \, {\left ({\left (2 \, e - f\right )} x^{6} + 18 \, {\left (e - f\right )} x^{5} + 6 \, {\left (7 \, e - 2 \, f\right )} x^{4} + 8 \, {\left (e - 5 \, f\right )} x^{3} + 36 \, f x^{2} - 24 \, {\left (e + f\right )} x + \sqrt {3} {\left ({\left (e - f\right )} x^{6} + 6 \, {\left (2 \, e - f\right )} x^{5} + 6 \, {\left (3 \, e - 4 \, f\right )} x^{4} + 8 \, {\left (2 \, e + f\right )} x^{3} - 12 \, {\left (e + f\right )} x^{2} + 24 \, f x - 8 \, e - 16 \, f\right )} + 8 \, e + 32 \, f\right )} \sqrt {x^{3} - 1} \sqrt {-3 \, e^{2} + 6 \, e f + 2 \, \sqrt {3} {\left (e^{2} - e f + f^{2}\right )}} + 112 \, e^{2} + 224 \, e f - 224 \, f^{2} - 128 \, {\left (e^{2} + 2 \, e f - 2 \, f^{2}\right )} x + 16 \, \sqrt {3} {\left ({\left (e^{2} + 2 \, e f - 2 \, f^{2}\right )} x^{7} + 2 \, {\left (e^{2} + 2 \, e f - 2 \, f^{2}\right )} x^{6} + 6 \, {\left (e^{2} + 2 \, e f - 2 \, f^{2}\right )} x^{5} - 5 \, {\left (e^{2} + 2 \, e f - 2 \, f^{2}\right )} x^{4} + 2 \, {\left (e^{2} + 2 \, e f - 2 \, f^{2}\right )} x^{3} - 6 \, {\left (e^{2} + 2 \, e f - 2 \, f^{2}\right )} x^{2} - 4 \, e^{2} - 8 \, e f + 8 \, f^{2} + 4 \, {\left (e^{2} + 2 \, e f - 2 \, f^{2}\right )} x\right )}}{x^{8} - 8 \, x^{7} + 16 \, x^{6} + 16 \, x^{5} - 56 \, x^{4} - 32 \, x^{3} + 64 \, x^{2} + 64 \, x + 16}\right ), \frac {1}{3} \, {\left (\sqrt {3} {\left (e + f\right )} - 3 \, f\right )} {\rm weierstrassPInverse}\left (0, 4, x\right ) + \frac {1}{6} \, \sqrt {3 \, e^{2} - 6 \, e f - 2 \, \sqrt {3} {\left (e^{2} - e f + f^{2}\right )}} \arctan \left (\frac {{\left (3 \, f x^{2} - 6 \, {\left (e - f\right )} x - \sqrt {3} {\left ({\left (e + f\right )} x^{2} + 2 \, {\left (2 \, e - f\right )} x - 2 \, e + 4 \, f\right )} + 6 \, e\right )} \sqrt {x^{3} - 1} \sqrt {3 \, e^{2} - 6 \, e f - 2 \, \sqrt {3} {\left (e^{2} - e f + f^{2}\right )}}}{6 \, {\left ({\left (e^{2} + 2 \, e f - 2 \, f^{2}\right )} x^{3} - e^{2} - 2 \, e f + 2 \, f^{2}\right )}}\right )\right ] \]

input
integrate((f*x+e)/(1-x+3^(1/2))/(x^3-1)^(1/2),x, algorithm="fricas")
 
output
[1/3*(sqrt(3)*(e + f) - 3*f)*weierstrassPInverse(0, 4, x) + 1/12*sqrt(-3*e 
^2 + 6*e*f + 2*sqrt(3)*(e^2 - e*f + f^2))*log(-((e^2 + 2*e*f - 2*f^2)*x^8 
+ 16*(e^2 + 2*e*f - 2*f^2)*x^7 + 112*(e^2 + 2*e*f - 2*f^2)*x^6 + 16*(e^2 + 
 2*e*f - 2*f^2)*x^5 + 112*(e^2 + 2*e*f - 2*f^2)*x^4 - 224*(e^2 + 2*e*f - 2 
*f^2)*x^3 + 64*(e^2 + 2*e*f - 2*f^2)*x^2 + 4*((2*e - f)*x^6 + 18*(e - f)*x 
^5 + 6*(7*e - 2*f)*x^4 + 8*(e - 5*f)*x^3 + 36*f*x^2 - 24*(e + f)*x + sqrt( 
3)*((e - f)*x^6 + 6*(2*e - f)*x^5 + 6*(3*e - 4*f)*x^4 + 8*(2*e + f)*x^3 - 
12*(e + f)*x^2 + 24*f*x - 8*e - 16*f) + 8*e + 32*f)*sqrt(x^3 - 1)*sqrt(-3* 
e^2 + 6*e*f + 2*sqrt(3)*(e^2 - e*f + f^2)) + 112*e^2 + 224*e*f - 224*f^2 - 
 128*(e^2 + 2*e*f - 2*f^2)*x + 16*sqrt(3)*((e^2 + 2*e*f - 2*f^2)*x^7 + 2*( 
e^2 + 2*e*f - 2*f^2)*x^6 + 6*(e^2 + 2*e*f - 2*f^2)*x^5 - 5*(e^2 + 2*e*f - 
2*f^2)*x^4 + 2*(e^2 + 2*e*f - 2*f^2)*x^3 - 6*(e^2 + 2*e*f - 2*f^2)*x^2 - 4 
*e^2 - 8*e*f + 8*f^2 + 4*(e^2 + 2*e*f - 2*f^2)*x))/(x^8 - 8*x^7 + 16*x^6 + 
 16*x^5 - 56*x^4 - 32*x^3 + 64*x^2 + 64*x + 16)), 1/3*(sqrt(3)*(e + f) - 3 
*f)*weierstrassPInverse(0, 4, x) + 1/6*sqrt(3*e^2 - 6*e*f - 2*sqrt(3)*(e^2 
 - e*f + f^2))*arctan(1/6*(3*f*x^2 - 6*(e - f)*x - sqrt(3)*((e + f)*x^2 + 
2*(2*e - f)*x - 2*e + 4*f) + 6*e)*sqrt(x^3 - 1)*sqrt(3*e^2 - 6*e*f - 2*sqr 
t(3)*(e^2 - e*f + f^2))/((e^2 + 2*e*f - 2*f^2)*x^3 - e^2 - 2*e*f + 2*f^2)) 
]
 
3.2.29.6 Sympy [F]

\[ \int \frac {e+f x}{\left (1+\sqrt {3}-x\right ) \sqrt {-1+x^3}} \, dx=- \int \frac {e}{x \sqrt {x^{3} - 1} - \sqrt {3} \sqrt {x^{3} - 1} - \sqrt {x^{3} - 1}}\, dx - \int \frac {f x}{x \sqrt {x^{3} - 1} - \sqrt {3} \sqrt {x^{3} - 1} - \sqrt {x^{3} - 1}}\, dx \]

input
integrate((f*x+e)/(1-x+3**(1/2))/(x**3-1)**(1/2),x)
 
output
-Integral(e/(x*sqrt(x**3 - 1) - sqrt(3)*sqrt(x**3 - 1) - sqrt(x**3 - 1)), 
x) - Integral(f*x/(x*sqrt(x**3 - 1) - sqrt(3)*sqrt(x**3 - 1) - sqrt(x**3 - 
 1)), x)
 
3.2.29.7 Maxima [F]

\[ \int \frac {e+f x}{\left (1+\sqrt {3}-x\right ) \sqrt {-1+x^3}} \, dx=\int { -\frac {f x + e}{\sqrt {x^{3} - 1} {\left (x - \sqrt {3} - 1\right )}} \,d x } \]

input
integrate((f*x+e)/(1-x+3^(1/2))/(x^3-1)^(1/2),x, algorithm="maxima")
 
output
-integrate((f*x + e)/(sqrt(x^3 - 1)*(x - sqrt(3) - 1)), x)
 
3.2.29.8 Giac [F(-2)]

Exception generated. \[ \int \frac {e+f x}{\left (1+\sqrt {3}-x\right ) \sqrt {-1+x^3}} \, dx=\text {Exception raised: TypeError} \]

input
integrate((f*x+e)/(1-x+3^(1/2))/(x^3-1)^(1/2),x, algorithm="giac")
 
output
Exception raised: TypeError >> an error occurred running a Giac command:IN 
PUT:sage2:=int(sage0,sageVARx):;OUTPUT:Unable to divide, perhaps due to ro 
unding error%%%{1,[2]%%%} / %%%{%%{[2,4]:[1,0,-3]%%},[2]%%%} Error: Bad Ar 
gument Va
 
3.2.29.9 Mupad [F(-1)]

Timed out. \[ \int \frac {e+f x}{\left (1+\sqrt {3}-x\right ) \sqrt {-1+x^3}} \, dx=\text {Hanged} \]

input
int((e + f*x)/((x^3 - 1)^(1/2)*(3^(1/2) - x + 1)),x)
 
output
\text{Hanged}