3.2.50 \(\int \frac {1-\sqrt {3}-x}{(c+d x) \sqrt {-1+x^3}} \, dx\) [150]

3.2.50.1 Optimal result
3.2.50.2 Mathematica [C] (warning: unable to verify)
3.2.50.3 Rubi [A] (warning: unable to verify)
3.2.50.4 Maple [A] (verified)
3.2.50.5 Fricas [F(-1)]
3.2.50.6 Sympy [F]
3.2.50.7 Maxima [F]
3.2.50.8 Giac [F]
3.2.50.9 Mupad [F(-1)]

3.2.50.1 Optimal result

Integrand size = 29, antiderivative size = 342 \[ \int \frac {1-\sqrt {3}-x}{(c+d x) \sqrt {-1+x^3}} \, dx=-\frac {\left (c+d-\sqrt {3} d\right ) (1-x) \sqrt {\frac {1+x+x^2}{\left (1-\sqrt {3}-x\right )^2}} \arctan \left (\frac {\sqrt {c^2-c d+d^2} \sqrt {-\frac {1-x}{\left (1-\sqrt {3}-x\right )^2}}}{\sqrt {d} \sqrt {c+d} \sqrt {\frac {1+x+x^2}{\left (1-\sqrt {3}-x\right )^2}}}\right )}{\sqrt {d} \sqrt {c+d} \sqrt {c^2-c d+d^2} \sqrt {-\frac {1-x}{\left (1-\sqrt {3}-x\right )^2}} \sqrt {-1+x^3}}+\frac {4 \sqrt [4]{3} \sqrt {2-\sqrt {3}} (1-x) \sqrt {\frac {1+x+x^2}{\left (1-\sqrt {3}-x\right )^2}} \operatorname {EllipticPi}\left (\frac {\left (c+d-\sqrt {3} d\right )^2}{\left (c+d+\sqrt {3} d\right )^2},\arcsin \left (\frac {1+\sqrt {3}-x}{1-\sqrt {3}-x}\right ),-7+4 \sqrt {3}\right )}{\left (c+d+\sqrt {3} d\right ) \sqrt {-\frac {1-x}{\left (1-\sqrt {3}-x\right )^2}} \sqrt {-1+x^3}} \]

output
-(1-x)*arctan((c^2-c*d+d^2)^(1/2)*((-1+x)/(1-x-3^(1/2))^2)^(1/2)/d^(1/2)/( 
c+d)^(1/2)/((x^2+x+1)/(1-x-3^(1/2))^2)^(1/2))*(c+d-d*3^(1/2))*((x^2+x+1)/( 
1-x-3^(1/2))^2)^(1/2)/d^(1/2)/(c+d)^(1/2)/(c^2-c*d+d^2)^(1/2)/(x^3-1)^(1/2 
)/((-1+x)/(1-x-3^(1/2))^2)^(1/2)-4*3^(1/4)*(1-x)*EllipticPi((-1+x-3^(1/2)) 
/(1-x-3^(1/2)),(c+d-d*3^(1/2))^2/(c+d+d*3^(1/2))^2,2*I-I*3^(1/2))*(1/2*6^( 
1/2)-1/2*2^(1/2))*((x^2+x+1)/(1-x-3^(1/2))^2)^(1/2)/(c+d+d*3^(1/2))/(x^3-1 
)^(1/2)/((-1+x)/(1-x-3^(1/2))^2)^(1/2)
 
3.2.50.2 Mathematica [C] (warning: unable to verify)

Result contains complex when optimal does not.

Time = 10.54 (sec) , antiderivative size = 233, normalized size of antiderivative = 0.68 \[ \int \frac {1-\sqrt {3}-x}{(c+d x) \sqrt {-1+x^3}} \, dx=\frac {2 \sqrt {\frac {1-x}{1+\sqrt [3]{-1}}} \left (-\frac {3 \left (\sqrt [3]{-1}+x\right ) \sqrt {\frac {\sqrt [3]{-1}+(-1)^{2/3} x}{1+\sqrt [3]{-1}}} \operatorname {EllipticF}\left (\arcsin \left (\sqrt {\frac {1-(-1)^{2/3} x}{1+\sqrt [3]{-1}}}\right ),\sqrt [3]{-1}\right )}{\sqrt {\frac {1-(-1)^{2/3} x}{1+\sqrt [3]{-1}}}}+\frac {\sqrt [3]{-1} \left (1+\sqrt [3]{-1}\right ) \left (\sqrt {3} c+\left (-3+\sqrt {3}\right ) d\right ) \sqrt {1+x+x^2} \operatorname {EllipticPi}\left (\frac {i \sqrt {3} d}{-c+\sqrt [3]{-1} d},\arcsin \left (\sqrt {\frac {1-(-1)^{2/3} x}{1+\sqrt [3]{-1}}}\right ),\sqrt [3]{-1}\right )}{c-\sqrt [3]{-1} d}\right )}{3 d \sqrt {-1+x^3}} \]

input
Integrate[(1 - Sqrt[3] - x)/((c + d*x)*Sqrt[-1 + x^3]),x]
 
output
(2*Sqrt[(1 - x)/(1 + (-1)^(1/3))]*((-3*((-1)^(1/3) + x)*Sqrt[((-1)^(1/3) + 
 (-1)^(2/3)*x)/(1 + (-1)^(1/3))]*EllipticF[ArcSin[Sqrt[(1 - (-1)^(2/3)*x)/ 
(1 + (-1)^(1/3))]], (-1)^(1/3)])/Sqrt[(1 - (-1)^(2/3)*x)/(1 + (-1)^(1/3))] 
 + ((-1)^(1/3)*(1 + (-1)^(1/3))*(Sqrt[3]*c + (-3 + Sqrt[3])*d)*Sqrt[1 + x 
+ x^2]*EllipticPi[(I*Sqrt[3]*d)/(-c + (-1)^(1/3)*d), ArcSin[Sqrt[(1 - (-1) 
^(2/3)*x)/(1 + (-1)^(1/3))]], (-1)^(1/3)])/(c - (-1)^(1/3)*d)))/(3*d*Sqrt[ 
-1 + x^3])
 
3.2.50.3 Rubi [A] (warning: unable to verify)

Time = 0.97 (sec) , antiderivative size = 299, normalized size of antiderivative = 0.87, number of steps used = 7, number of rules used = 6, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.207, Rules used = {2568, 2538, 412, 435, 104, 218}

Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.

\(\displaystyle \int \frac {-x-\sqrt {3}+1}{\sqrt {x^3-1} (c+d x)} \, dx\)

\(\Big \downarrow \) 2568

\(\displaystyle -\frac {4 \sqrt [4]{3} \sqrt {2+\sqrt {3}} (1-x) \sqrt {\frac {x^2+x+1}{\left (-x-\sqrt {3}+1\right )^2}} \int \frac {1}{\left (c+\sqrt {3} d+d-\frac {\left (c-\sqrt {3} d+d\right ) \left (-x+\sqrt {3}+1\right )}{-x-\sqrt {3}+1}\right ) \sqrt {1-\frac {\left (-x+\sqrt {3}+1\right )^2}{\left (-x-\sqrt {3}+1\right )^2}} \sqrt {\frac {\left (-x+\sqrt {3}+1\right )^2}{\left (-x-\sqrt {3}+1\right )^2}+4 \sqrt {3}+7}}d\left (-\frac {-x+\sqrt {3}+1}{-x-\sqrt {3}+1}\right )}{\sqrt {-\frac {1-x}{\left (-x-\sqrt {3}+1\right )^2}} \sqrt {x^3-1}}\)

\(\Big \downarrow \) 2538

\(\displaystyle -\frac {4 \sqrt [4]{3} \sqrt {2+\sqrt {3}} (1-x) \sqrt {\frac {x^2+x+1}{\left (-x-\sqrt {3}+1\right )^2}} \left (\left (c+\sqrt {3} d+d\right ) \int \frac {1}{\sqrt {1-\frac {\left (-x+\sqrt {3}+1\right )^2}{\left (-x-\sqrt {3}+1\right )^2}} \sqrt {\frac {\left (-x+\sqrt {3}+1\right )^2}{\left (-x-\sqrt {3}+1\right )^2}+4 \sqrt {3}+7} \left (\left (c+\sqrt {3} d+d\right )^2-\frac {\left (c-\sqrt {3} d+d\right )^2 \left (-x+\sqrt {3}+1\right )^2}{\left (-x-\sqrt {3}+1\right )^2}\right )}d\left (-\frac {-x+\sqrt {3}+1}{-x-\sqrt {3}+1}\right )-\left (c-\sqrt {3} d+d\right ) \int -\frac {-x+\sqrt {3}+1}{\sqrt {1-\frac {\left (-x+\sqrt {3}+1\right )^2}{\left (-x-\sqrt {3}+1\right )^2}} \sqrt {\frac {\left (-x+\sqrt {3}+1\right )^2}{\left (-x-\sqrt {3}+1\right )^2}+4 \sqrt {3}+7} \left (\left (c+\sqrt {3} d+d\right )^2-\frac {\left (c-\sqrt {3} d+d\right )^2 \left (-x+\sqrt {3}+1\right )^2}{\left (-x-\sqrt {3}+1\right )^2}\right ) \left (-x-\sqrt {3}+1\right )}d\left (-\frac {-x+\sqrt {3}+1}{-x-\sqrt {3}+1}\right )\right )}{\sqrt {-\frac {1-x}{\left (-x-\sqrt {3}+1\right )^2}} \sqrt {x^3-1}}\)

\(\Big \downarrow \) 412

\(\displaystyle -\frac {4 \sqrt [4]{3} \sqrt {2+\sqrt {3}} (1-x) \sqrt {\frac {x^2+x+1}{\left (-x-\sqrt {3}+1\right )^2}} \left (-\left (c-\sqrt {3} d+d\right ) \int -\frac {-x+\sqrt {3}+1}{\sqrt {1-\frac {\left (-x+\sqrt {3}+1\right )^2}{\left (-x-\sqrt {3}+1\right )^2}} \sqrt {\frac {\left (-x+\sqrt {3}+1\right )^2}{\left (-x-\sqrt {3}+1\right )^2}+4 \sqrt {3}+7} \left (\left (c+\sqrt {3} d+d\right )^2-\frac {\left (c-\sqrt {3} d+d\right )^2 \left (-x+\sqrt {3}+1\right )^2}{\left (-x-\sqrt {3}+1\right )^2}\right ) \left (-x-\sqrt {3}+1\right )}d\left (-\frac {-x+\sqrt {3}+1}{-x-\sqrt {3}+1}\right )-\frac {\operatorname {EllipticPi}\left (\frac {\left (c-\sqrt {3} d+d\right )^2}{\left (c+\sqrt {3} d+d\right )^2},\arcsin \left (\frac {-x+\sqrt {3}+1}{-x-\sqrt {3}+1}\right ),-7+4 \sqrt {3}\right )}{\sqrt {7+4 \sqrt {3}} \left (c+\sqrt {3} d+d\right )}\right )}{\sqrt {-\frac {1-x}{\left (-x-\sqrt {3}+1\right )^2}} \sqrt {x^3-1}}\)

\(\Big \downarrow \) 435

\(\displaystyle -\frac {4 \sqrt [4]{3} \sqrt {2+\sqrt {3}} (1-x) \sqrt {\frac {x^2+x+1}{\left (-x-\sqrt {3}+1\right )^2}} \left (-\frac {1}{2} \left (c-\sqrt {3} d+d\right ) \int \frac {1}{\sqrt {\frac {-x+\sqrt {3}+1}{-x-\sqrt {3}+1}+1} \left (\frac {\left (-x+\sqrt {3}+1\right ) \left (c-\sqrt {3} d+d\right )^2}{-x-\sqrt {3}+1}+\left (c+\sqrt {3} d+d\right )^2\right ) \sqrt {\frac {\left (-x+\sqrt {3}+1\right )^2}{\left (-x-\sqrt {3}+1\right )^2}+4 \sqrt {3}+7}}d\frac {\left (-x+\sqrt {3}+1\right )^2}{\left (-x-\sqrt {3}+1\right )^2}-\frac {\operatorname {EllipticPi}\left (\frac {\left (c-\sqrt {3} d+d\right )^2}{\left (c+\sqrt {3} d+d\right )^2},\arcsin \left (\frac {-x+\sqrt {3}+1}{-x-\sqrt {3}+1}\right ),-7+4 \sqrt {3}\right )}{\sqrt {7+4 \sqrt {3}} \left (c+\sqrt {3} d+d\right )}\right )}{\sqrt {-\frac {1-x}{\left (-x-\sqrt {3}+1\right )^2}} \sqrt {x^3-1}}\)

\(\Big \downarrow \) 104

\(\displaystyle -\frac {4 \sqrt [4]{3} \sqrt {2+\sqrt {3}} (1-x) \sqrt {\frac {x^2+x+1}{\left (-x-\sqrt {3}+1\right )^2}} \left (-\left (c-\sqrt {3} d+d\right ) \int \frac {1}{-4 \sqrt {3} d (c+d)-\frac {4 \left (2+\sqrt {3}\right ) \left (c^2-d c+d^2\right ) \sqrt {\frac {-x+\sqrt {3}+1}{-x-\sqrt {3}+1}+1}}{\sqrt {\frac {\left (-x+\sqrt {3}+1\right )^2}{\left (-x-\sqrt {3}+1\right )^2}+4 \sqrt {3}+7}}}d\frac {\sqrt {\frac {-x+\sqrt {3}+1}{-x-\sqrt {3}+1}+1}}{\sqrt {\frac {\left (-x+\sqrt {3}+1\right )^2}{\left (-x-\sqrt {3}+1\right )^2}+4 \sqrt {3}+7}}-\frac {\operatorname {EllipticPi}\left (\frac {\left (c-\sqrt {3} d+d\right )^2}{\left (c+\sqrt {3} d+d\right )^2},\arcsin \left (\frac {-x+\sqrt {3}+1}{-x-\sqrt {3}+1}\right ),-7+4 \sqrt {3}\right )}{\sqrt {7+4 \sqrt {3}} \left (c+\sqrt {3} d+d\right )}\right )}{\sqrt {-\frac {1-x}{\left (-x-\sqrt {3}+1\right )^2}} \sqrt {x^3-1}}\)

\(\Big \downarrow \) 218

\(\displaystyle -\frac {4 \sqrt [4]{3} \sqrt {2+\sqrt {3}} (1-x) \sqrt {\frac {x^2+x+1}{\left (-x-\sqrt {3}+1\right )^2}} \left (-\frac {\operatorname {EllipticPi}\left (\frac {\left (c-\sqrt {3} d+d\right )^2}{\left (c+\sqrt {3} d+d\right )^2},\arcsin \left (\frac {-x+\sqrt {3}+1}{-x-\sqrt {3}+1}\right ),-7+4 \sqrt {3}\right )}{\sqrt {7+4 \sqrt {3}} \left (c+\sqrt {3} d+d\right )}-\frac {\left (c-\sqrt {3} d+d\right ) \arctan \left (\frac {\sqrt {2+\sqrt {3}} \left (-x+\sqrt {3}+1\right ) \sqrt {c^2-c d+d^2}}{\sqrt [4]{3} \sqrt {d} \left (-x-\sqrt {3}+1\right ) \sqrt {c+d}}\right )}{4 \sqrt [4]{3} \sqrt {2+\sqrt {3}} \sqrt {d} \sqrt {c+d} \sqrt {c^2-c d+d^2}}\right )}{\sqrt {-\frac {1-x}{\left (-x-\sqrt {3}+1\right )^2}} \sqrt {x^3-1}}\)

input
Int[(1 - Sqrt[3] - x)/((c + d*x)*Sqrt[-1 + x^3]),x]
 
output
(-4*3^(1/4)*Sqrt[2 + Sqrt[3]]*(1 - x)*Sqrt[(1 + x + x^2)/(1 - Sqrt[3] - x) 
^2]*(-1/4*((c + d - Sqrt[3]*d)*ArcTan[(Sqrt[2 + Sqrt[3]]*Sqrt[c^2 - c*d + 
d^2]*(1 + Sqrt[3] - x))/(3^(1/4)*Sqrt[d]*Sqrt[c + d]*(1 - Sqrt[3] - x))])/ 
(3^(1/4)*Sqrt[2 + Sqrt[3]]*Sqrt[d]*Sqrt[c + d]*Sqrt[c^2 - c*d + d^2]) - El 
lipticPi[(c + d - Sqrt[3]*d)^2/(c + d + Sqrt[3]*d)^2, ArcSin[(1 + Sqrt[3] 
- x)/(1 - Sqrt[3] - x)], -7 + 4*Sqrt[3]]/(Sqrt[7 + 4*Sqrt[3]]*(c + d + Sqr 
t[3]*d))))/(Sqrt[-((1 - x)/(1 - Sqrt[3] - x)^2)]*Sqrt[-1 + x^3])
 

3.2.50.3.1 Defintions of rubi rules used

rule 104
Int[(((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_))/((e_.) + (f_.)*(x 
_)), x_] :> With[{q = Denominator[m]}, Simp[q   Subst[Int[x^(q*(m + 1) - 1) 
/(b*e - a*f - (d*e - c*f)*x^q), x], x, (a + b*x)^(1/q)/(c + d*x)^(1/q)], x] 
] /; FreeQ[{a, b, c, d, e, f}, x] && EqQ[m + n + 1, 0] && RationalQ[n] && L 
tQ[-1, m, 0] && SimplerQ[a + b*x, c + d*x]
 

rule 218
Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(Rt[a/b, 2]/a)*ArcTan[x/R 
t[a/b, 2]], x] /; FreeQ[{a, b}, x] && PosQ[a/b]
 

rule 412
Int[1/(((a_) + (b_.)*(x_)^2)*Sqrt[(c_) + (d_.)*(x_)^2]*Sqrt[(e_) + (f_.)*(x 
_)^2]), x_Symbol] :> Simp[(1/(a*Sqrt[c]*Sqrt[e]*Rt[-d/c, 2]))*EllipticPi[b* 
(c/(a*d)), ArcSin[Rt[-d/c, 2]*x], c*(f/(d*e))], x] /; FreeQ[{a, b, c, d, e, 
 f}, x] &&  !GtQ[d/c, 0] && GtQ[c, 0] && GtQ[e, 0] &&  !( !GtQ[f/e, 0] && S 
implerSqrtQ[-f/e, -d/c])
 

rule 435
Int[(x_)^(m_.)*((a_.) + (b_.)*(x_)^2)^(p_.)*((c_.) + (d_.)*(x_)^2)^(q_.)*(( 
e_.) + (f_.)*(x_)^2)^(r_.), x_Symbol] :> Simp[1/2   Subst[Int[x^((m - 1)/2) 
*(a + b*x)^p*(c + d*x)^q*(e + f*x)^r, x], x, x^2], x] /; FreeQ[{a, b, c, d, 
 e, f, p, q, r}, x] && IntegerQ[(m - 1)/2]
 

rule 2538
Int[1/(((a_) + (b_.)*(x_))*Sqrt[(c_) + (d_.)*(x_)^2]*Sqrt[(e_) + (f_.)*(x_) 
^2]), x_Symbol] :> Simp[a   Int[1/((a^2 - b^2*x^2)*Sqrt[c + d*x^2]*Sqrt[e + 
 f*x^2]), x], x] - Simp[b   Int[x/((a^2 - b^2*x^2)*Sqrt[c + d*x^2]*Sqrt[e + 
 f*x^2]), x], x] /; FreeQ[{a, b, c, d, e, f}, x]
 

rule 2568
Int[((e_) + (f_.)*(x_))/(((c_) + (d_.)*(x_))*Sqrt[(a_) + (b_.)*(x_)^3]), x_ 
Symbol] :> With[{q = Simplify[(-1 + Sqrt[3])*(f/e)]}, Simp[4*3^(1/4)*Sqrt[2 
 + Sqrt[3]]*f*(1 - q*x)*(Sqrt[(1 + q*x + q^2*x^2)/(1 - Sqrt[3] - q*x)^2]/(q 
*Sqrt[a + b*x^3]*Sqrt[-(1 - q*x)/(1 - Sqrt[3] - q*x)^2]))   Subst[Int[1/((( 
1 + Sqrt[3])*d + c*q + ((1 - Sqrt[3])*d + c*q)*x)*Sqrt[1 - x^2]*Sqrt[7 + 4* 
Sqrt[3] + x^2]), x], x, (1 + Sqrt[3] - q*x)/(-1 + Sqrt[3] + q*x)], x]] /; F 
reeQ[{a, b, c, d, e, f}, x] && NeQ[d*e - c*f, 0] && EqQ[b*e^3 - 2*(5 - 3*Sq 
rt[3])*a*f^3, 0] && NeQ[b*c^3 - 2*(5 + 3*Sqrt[3])*a*d^3, 0]
 
3.2.50.4 Maple [A] (verified)

Time = 1.09 (sec) , antiderivative size = 277, normalized size of antiderivative = 0.81

method result size
default \(-\frac {2 \left (-\frac {3}{2}-\frac {i \sqrt {3}}{2}\right ) \sqrt {\frac {x -1}{-\frac {3}{2}-\frac {i \sqrt {3}}{2}}}\, \sqrt {\frac {x +\frac {1}{2}-\frac {i \sqrt {3}}{2}}{\frac {3}{2}-\frac {i \sqrt {3}}{2}}}\, \sqrt {\frac {x +\frac {1}{2}+\frac {i \sqrt {3}}{2}}{\frac {3}{2}+\frac {i \sqrt {3}}{2}}}\, F\left (\sqrt {\frac {x -1}{-\frac {3}{2}-\frac {i \sqrt {3}}{2}}}, \sqrt {\frac {\frac {3}{2}+\frac {i \sqrt {3}}{2}}{\frac {3}{2}-\frac {i \sqrt {3}}{2}}}\right )}{d \sqrt {x^{3}-1}}-\frac {2 \left (d \sqrt {3}-c -d \right ) \left (-\frac {3}{2}-\frac {i \sqrt {3}}{2}\right ) \sqrt {\frac {x -1}{-\frac {3}{2}-\frac {i \sqrt {3}}{2}}}\, \sqrt {\frac {x +\frac {1}{2}-\frac {i \sqrt {3}}{2}}{\frac {3}{2}-\frac {i \sqrt {3}}{2}}}\, \sqrt {\frac {x +\frac {1}{2}+\frac {i \sqrt {3}}{2}}{\frac {3}{2}+\frac {i \sqrt {3}}{2}}}\, \Pi \left (\sqrt {\frac {x -1}{-\frac {3}{2}-\frac {i \sqrt {3}}{2}}}, \frac {\frac {3}{2}+\frac {i \sqrt {3}}{2}}{1+\frac {c}{d}}, \sqrt {\frac {\frac {3}{2}+\frac {i \sqrt {3}}{2}}{\frac {3}{2}-\frac {i \sqrt {3}}{2}}}\right )}{d^{2} \sqrt {x^{3}-1}\, \left (1+\frac {c}{d}\right )}\) \(277\)
elliptic \(-\frac {2 \left (-\frac {3}{2}-\frac {i \sqrt {3}}{2}\right ) \sqrt {\frac {x -1}{-\frac {3}{2}-\frac {i \sqrt {3}}{2}}}\, \sqrt {\frac {x +\frac {1}{2}-\frac {i \sqrt {3}}{2}}{\frac {3}{2}-\frac {i \sqrt {3}}{2}}}\, \sqrt {\frac {x +\frac {1}{2}+\frac {i \sqrt {3}}{2}}{\frac {3}{2}+\frac {i \sqrt {3}}{2}}}\, F\left (\sqrt {\frac {x -1}{-\frac {3}{2}-\frac {i \sqrt {3}}{2}}}, \sqrt {\frac {\frac {3}{2}+\frac {i \sqrt {3}}{2}}{\frac {3}{2}-\frac {i \sqrt {3}}{2}}}\right )}{d \sqrt {x^{3}-1}}-\frac {2 \left (d \sqrt {3}-c -d \right ) \left (-\frac {3}{2}-\frac {i \sqrt {3}}{2}\right ) \sqrt {\frac {x -1}{-\frac {3}{2}-\frac {i \sqrt {3}}{2}}}\, \sqrt {\frac {x +\frac {1}{2}-\frac {i \sqrt {3}}{2}}{\frac {3}{2}-\frac {i \sqrt {3}}{2}}}\, \sqrt {\frac {x +\frac {1}{2}+\frac {i \sqrt {3}}{2}}{\frac {3}{2}+\frac {i \sqrt {3}}{2}}}\, \Pi \left (\sqrt {\frac {x -1}{-\frac {3}{2}-\frac {i \sqrt {3}}{2}}}, \frac {\frac {3}{2}+\frac {i \sqrt {3}}{2}}{1+\frac {c}{d}}, \sqrt {\frac {\frac {3}{2}+\frac {i \sqrt {3}}{2}}{\frac {3}{2}-\frac {i \sqrt {3}}{2}}}\right )}{d^{2} \sqrt {x^{3}-1}\, \left (1+\frac {c}{d}\right )}\) \(277\)

input
int((1-x-3^(1/2))/(d*x+c)/(x^3-1)^(1/2),x,method=_RETURNVERBOSE)
 
output
-2/d*(-3/2-1/2*I*3^(1/2))*((x-1)/(-3/2-1/2*I*3^(1/2)))^(1/2)*((x+1/2-1/2*I 
*3^(1/2))/(3/2-1/2*I*3^(1/2)))^(1/2)*((x+1/2+1/2*I*3^(1/2))/(3/2+1/2*I*3^( 
1/2)))^(1/2)/(x^3-1)^(1/2)*EllipticF(((x-1)/(-3/2-1/2*I*3^(1/2)))^(1/2),(( 
3/2+1/2*I*3^(1/2))/(3/2-1/2*I*3^(1/2)))^(1/2))-2*(d*3^(1/2)-c-d)/d^2*(-3/2 
-1/2*I*3^(1/2))*((x-1)/(-3/2-1/2*I*3^(1/2)))^(1/2)*((x+1/2-1/2*I*3^(1/2))/ 
(3/2-1/2*I*3^(1/2)))^(1/2)*((x+1/2+1/2*I*3^(1/2))/(3/2+1/2*I*3^(1/2)))^(1/ 
2)/(x^3-1)^(1/2)/(1+c/d)*EllipticPi(((x-1)/(-3/2-1/2*I*3^(1/2)))^(1/2),(3/ 
2+1/2*I*3^(1/2))/(1+c/d),((3/2+1/2*I*3^(1/2))/(3/2-1/2*I*3^(1/2)))^(1/2))
 
3.2.50.5 Fricas [F(-1)]

Timed out. \[ \int \frac {1-\sqrt {3}-x}{(c+d x) \sqrt {-1+x^3}} \, dx=\text {Timed out} \]

input
integrate((1-x-3^(1/2))/(d*x+c)/(x^3-1)^(1/2),x, algorithm="fricas")
 
output
Timed out
 
3.2.50.6 Sympy [F]

\[ \int \frac {1-\sqrt {3}-x}{(c+d x) \sqrt {-1+x^3}} \, dx=- \int \frac {\sqrt {3}}{c \sqrt {x^{3} - 1} + d x \sqrt {x^{3} - 1}}\, dx - \int \frac {x}{c \sqrt {x^{3} - 1} + d x \sqrt {x^{3} - 1}}\, dx - \int \left (- \frac {1}{c \sqrt {x^{3} - 1} + d x \sqrt {x^{3} - 1}}\right )\, dx \]

input
integrate((1-x-3**(1/2))/(d*x+c)/(x**3-1)**(1/2),x)
 
output
-Integral(sqrt(3)/(c*sqrt(x**3 - 1) + d*x*sqrt(x**3 - 1)), x) - Integral(x 
/(c*sqrt(x**3 - 1) + d*x*sqrt(x**3 - 1)), x) - Integral(-1/(c*sqrt(x**3 - 
1) + d*x*sqrt(x**3 - 1)), x)
 
3.2.50.7 Maxima [F]

\[ \int \frac {1-\sqrt {3}-x}{(c+d x) \sqrt {-1+x^3}} \, dx=\int { -\frac {x + \sqrt {3} - 1}{\sqrt {x^{3} - 1} {\left (d x + c\right )}} \,d x } \]

input
integrate((1-x-3^(1/2))/(d*x+c)/(x^3-1)^(1/2),x, algorithm="maxima")
 
output
-integrate((x + sqrt(3) - 1)/(sqrt(x^3 - 1)*(d*x + c)), x)
 
3.2.50.8 Giac [F]

\[ \int \frac {1-\sqrt {3}-x}{(c+d x) \sqrt {-1+x^3}} \, dx=\int { -\frac {x + \sqrt {3} - 1}{\sqrt {x^{3} - 1} {\left (d x + c\right )}} \,d x } \]

input
integrate((1-x-3^(1/2))/(d*x+c)/(x^3-1)^(1/2),x, algorithm="giac")
 
output
integrate(-(x + sqrt(3) - 1)/(sqrt(x^3 - 1)*(d*x + c)), x)
 
3.2.50.9 Mupad [F(-1)]

Timed out. \[ \int \frac {1-\sqrt {3}-x}{(c+d x) \sqrt {-1+x^3}} \, dx=\text {Hanged} \]

input
int(-(x + 3^(1/2) - 1)/((x^3 - 1)^(1/2)*(c + d*x)),x)
 
output
\text{Hanged}