3.6.58 \(\int \frac {x}{a c+b c x^3+d \sqrt {a+b x^3}} \, dx\) [558]

3.6.58.1 Optimal result
3.6.58.2 Mathematica [A] (verified)
3.6.58.3 Rubi [A] (verified)
3.6.58.4 Maple [C] (warning: unable to verify)
3.6.58.5 Fricas [F(-1)]
3.6.58.6 Sympy [F]
3.6.58.7 Maxima [F]
3.6.58.8 Giac [F]
3.6.58.9 Mupad [F(-1)]

3.6.58.1 Optimal result

Integrand size = 27, antiderivative size = 304 \[ \int \frac {x}{a c+b c x^3+d \sqrt {a+b x^3}} \, dx=-\frac {d x^2 \sqrt {1+\frac {b x^3}{a}} \operatorname {AppellF1}\left (\frac {2}{3},\frac {1}{2},1,\frac {5}{3},-\frac {b x^3}{a},-\frac {b c^2 x^3}{a c^2-d^2}\right )}{2 \left (a c^2-d^2\right ) \sqrt {a+b x^3}}-\frac {\arctan \left (\frac {1-\frac {2 \sqrt [3]{b} c^{2/3} x}{\sqrt [3]{a c^2-d^2}}}{\sqrt {3}}\right )}{\sqrt {3} b^{2/3} \sqrt [3]{c} \sqrt [3]{a c^2-d^2}}-\frac {\log \left (\sqrt [3]{a c^2-d^2}+\sqrt [3]{b} c^{2/3} x\right )}{3 b^{2/3} \sqrt [3]{c} \sqrt [3]{a c^2-d^2}}+\frac {\log \left (\left (a c^2-d^2\right )^{2/3}-\sqrt [3]{b} c^{2/3} \sqrt [3]{a c^2-d^2} x+b^{2/3} c^{4/3} x^2\right )}{6 b^{2/3} \sqrt [3]{c} \sqrt [3]{a c^2-d^2}} \]

output
-1/3*ln((a*c^2-d^2)^(1/3)+b^(1/3)*c^(2/3)*x)/b^(2/3)/c^(1/3)/(a*c^2-d^2)^( 
1/3)+1/6*ln((a*c^2-d^2)^(2/3)-b^(1/3)*c^(2/3)*(a*c^2-d^2)^(1/3)*x+b^(2/3)* 
c^(4/3)*x^2)/b^(2/3)/c^(1/3)/(a*c^2-d^2)^(1/3)-1/3*arctan(1/3*(1-2*b^(1/3) 
*c^(2/3)*x/(a*c^2-d^2)^(1/3))*3^(1/2))/b^(2/3)/c^(1/3)/(a*c^2-d^2)^(1/3)*3 
^(1/2)-1/2*d*x^2*AppellF1(2/3,1/2,1,5/3,-b*x^3/a,-b*c^2*x^3/(a*c^2-d^2))*( 
1+b*x^3/a)^(1/2)/(a*c^2-d^2)/(b*x^3+a)^(1/2)
 
3.6.58.2 Mathematica [A] (verified)

Time = 10.21 (sec) , antiderivative size = 252, normalized size of antiderivative = 0.83 \[ \int \frac {x}{a c+b c x^3+d \sqrt {a+b x^3}} \, dx=-\frac {d x^2 \sqrt {1+\frac {b x^3}{a}} \operatorname {AppellF1}\left (\frac {2}{3},\frac {1}{2},1,\frac {5}{3},-\frac {b x^3}{a},-\frac {b c^2 x^3}{a c^2-d^2}\right )}{\left (2 a c^2-2 d^2\right ) \sqrt {a+b x^3}}+\frac {2 \sqrt {3} \arctan \left (\frac {-1+\frac {2 \sqrt [3]{b} c^{2/3} x}{\sqrt [3]{a c^2-d^2}}}{\sqrt {3}}\right )-2 \log \left (\sqrt [3]{a c^2-d^2}+\sqrt [3]{b} c^{2/3} x\right )+\log \left (\left (a c^2-d^2\right )^{2/3}-\sqrt [3]{b} c^{2/3} \sqrt [3]{a c^2-d^2} x+b^{2/3} c^{4/3} x^2\right )}{6 b^{2/3} \sqrt [3]{c} \sqrt [3]{a c^2-d^2}} \]

input
Integrate[x/(a*c + b*c*x^3 + d*Sqrt[a + b*x^3]),x]
 
output
-((d*x^2*Sqrt[1 + (b*x^3)/a]*AppellF1[2/3, 1/2, 1, 5/3, -((b*x^3)/a), -((b 
*c^2*x^3)/(a*c^2 - d^2))])/((2*a*c^2 - 2*d^2)*Sqrt[a + b*x^3])) + (2*Sqrt[ 
3]*ArcTan[(-1 + (2*b^(1/3)*c^(2/3)*x)/(a*c^2 - d^2)^(1/3))/Sqrt[3]] - 2*Lo 
g[(a*c^2 - d^2)^(1/3) + b^(1/3)*c^(2/3)*x] + Log[(a*c^2 - d^2)^(2/3) - b^( 
1/3)*c^(2/3)*(a*c^2 - d^2)^(1/3)*x + b^(2/3)*c^(4/3)*x^2])/(6*b^(2/3)*c^(1 
/3)*(a*c^2 - d^2)^(1/3))
 
3.6.58.3 Rubi [A] (verified)

Time = 0.63 (sec) , antiderivative size = 307, normalized size of antiderivative = 1.01, number of steps used = 13, number of rules used = 12, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.444, Rules used = {2587, 27, 821, 16, 1013, 1012, 1142, 25, 27, 1082, 217, 1103}

Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.

\(\displaystyle \int \frac {x}{d \sqrt {a+b x^3}+a c+b c x^3} \, dx\)

\(\Big \downarrow \) 2587

\(\displaystyle a c \int \frac {x}{a \left (b c^2 x^3+a c^2-d^2\right )}dx-a d \int \frac {x}{a \sqrt {b x^3+a} \left (b c^2 x^3+a c^2-d^2\right )}dx\)

\(\Big \downarrow \) 27

\(\displaystyle c \int \frac {x}{b c^2 x^3+a c^2-d^2}dx-d \int \frac {x}{\sqrt {b x^3+a} \left (b c^2 x^3+a c^2-d^2\right )}dx\)

\(\Big \downarrow \) 821

\(\displaystyle c \left (\frac {\int \frac {\sqrt [3]{b} c^{2/3} x+\sqrt [3]{a c^2-d^2}}{b^{2/3} c^{4/3} x^2-\sqrt [3]{b} c^{2/3} \sqrt [3]{a c^2-d^2} x+\left (a c^2-d^2\right )^{2/3}}dx}{3 \sqrt [3]{b} c^{2/3} \sqrt [3]{a c^2-d^2}}-\frac {\int \frac {1}{\sqrt [3]{b} c^{2/3} x+\sqrt [3]{a c^2-d^2}}dx}{3 \sqrt [3]{b} c^{2/3} \sqrt [3]{a c^2-d^2}}\right )-d \int \frac {x}{\sqrt {b x^3+a} \left (b c^2 x^3+a c^2-d^2\right )}dx\)

\(\Big \downarrow \) 16

\(\displaystyle c \left (\frac {\int \frac {\sqrt [3]{b} c^{2/3} x+\sqrt [3]{a c^2-d^2}}{b^{2/3} c^{4/3} x^2-\sqrt [3]{b} c^{2/3} \sqrt [3]{a c^2-d^2} x+\left (a c^2-d^2\right )^{2/3}}dx}{3 \sqrt [3]{b} c^{2/3} \sqrt [3]{a c^2-d^2}}-\frac {\log \left (\sqrt [3]{a c^2-d^2}+\sqrt [3]{b} c^{2/3} x\right )}{3 b^{2/3} c^{4/3} \sqrt [3]{a c^2-d^2}}\right )-d \int \frac {x}{\sqrt {b x^3+a} \left (b c^2 x^3+a c^2-d^2\right )}dx\)

\(\Big \downarrow \) 1013

\(\displaystyle c \left (\frac {\int \frac {\sqrt [3]{b} c^{2/3} x+\sqrt [3]{a c^2-d^2}}{b^{2/3} c^{4/3} x^2-\sqrt [3]{b} c^{2/3} \sqrt [3]{a c^2-d^2} x+\left (a c^2-d^2\right )^{2/3}}dx}{3 \sqrt [3]{b} c^{2/3} \sqrt [3]{a c^2-d^2}}-\frac {\log \left (\sqrt [3]{a c^2-d^2}+\sqrt [3]{b} c^{2/3} x\right )}{3 b^{2/3} c^{4/3} \sqrt [3]{a c^2-d^2}}\right )-\frac {d \sqrt {\frac {b x^3}{a}+1} \int \frac {x}{\sqrt {\frac {b x^3}{a}+1} \left (b c^2 x^3+a c^2-d^2\right )}dx}{\sqrt {a+b x^3}}\)

\(\Big \downarrow \) 1012

\(\displaystyle c \left (\frac {\int \frac {\sqrt [3]{b} c^{2/3} x+\sqrt [3]{a c^2-d^2}}{b^{2/3} c^{4/3} x^2-\sqrt [3]{b} c^{2/3} \sqrt [3]{a c^2-d^2} x+\left (a c^2-d^2\right )^{2/3}}dx}{3 \sqrt [3]{b} c^{2/3} \sqrt [3]{a c^2-d^2}}-\frac {\log \left (\sqrt [3]{a c^2-d^2}+\sqrt [3]{b} c^{2/3} x\right )}{3 b^{2/3} c^{4/3} \sqrt [3]{a c^2-d^2}}\right )-\frac {d x^2 \sqrt {\frac {b x^3}{a}+1} \operatorname {AppellF1}\left (\frac {2}{3},\frac {1}{2},1,\frac {5}{3},-\frac {b x^3}{a},-\frac {b c^2 x^3}{a c^2-d^2}\right )}{2 \sqrt {a+b x^3} \left (a c^2-d^2\right )}\)

\(\Big \downarrow \) 1142

\(\displaystyle c \left (\frac {\frac {3}{2} \sqrt [3]{a c^2-d^2} \int \frac {1}{b^{2/3} c^{4/3} x^2-\sqrt [3]{b} c^{2/3} \sqrt [3]{a c^2-d^2} x+\left (a c^2-d^2\right )^{2/3}}dx+\frac {\int -\frac {\sqrt [3]{b} c^{2/3} \left (\sqrt [3]{a c^2-d^2}-2 \sqrt [3]{b} c^{2/3} x\right )}{b^{2/3} c^{4/3} x^2-\sqrt [3]{b} c^{2/3} \sqrt [3]{a c^2-d^2} x+\left (a c^2-d^2\right )^{2/3}}dx}{2 \sqrt [3]{b} c^{2/3}}}{3 \sqrt [3]{b} c^{2/3} \sqrt [3]{a c^2-d^2}}-\frac {\log \left (\sqrt [3]{a c^2-d^2}+\sqrt [3]{b} c^{2/3} x\right )}{3 b^{2/3} c^{4/3} \sqrt [3]{a c^2-d^2}}\right )-\frac {d x^2 \sqrt {\frac {b x^3}{a}+1} \operatorname {AppellF1}\left (\frac {2}{3},\frac {1}{2},1,\frac {5}{3},-\frac {b x^3}{a},-\frac {b c^2 x^3}{a c^2-d^2}\right )}{2 \sqrt {a+b x^3} \left (a c^2-d^2\right )}\)

\(\Big \downarrow \) 25

\(\displaystyle c \left (\frac {\frac {3}{2} \sqrt [3]{a c^2-d^2} \int \frac {1}{b^{2/3} c^{4/3} x^2-\sqrt [3]{b} c^{2/3} \sqrt [3]{a c^2-d^2} x+\left (a c^2-d^2\right )^{2/3}}dx-\frac {\int \frac {\sqrt [3]{b} c^{2/3} \left (\sqrt [3]{a c^2-d^2}-2 \sqrt [3]{b} c^{2/3} x\right )}{b^{2/3} c^{4/3} x^2-\sqrt [3]{b} c^{2/3} \sqrt [3]{a c^2-d^2} x+\left (a c^2-d^2\right )^{2/3}}dx}{2 \sqrt [3]{b} c^{2/3}}}{3 \sqrt [3]{b} c^{2/3} \sqrt [3]{a c^2-d^2}}-\frac {\log \left (\sqrt [3]{a c^2-d^2}+\sqrt [3]{b} c^{2/3} x\right )}{3 b^{2/3} c^{4/3} \sqrt [3]{a c^2-d^2}}\right )-\frac {d x^2 \sqrt {\frac {b x^3}{a}+1} \operatorname {AppellF1}\left (\frac {2}{3},\frac {1}{2},1,\frac {5}{3},-\frac {b x^3}{a},-\frac {b c^2 x^3}{a c^2-d^2}\right )}{2 \sqrt {a+b x^3} \left (a c^2-d^2\right )}\)

\(\Big \downarrow \) 27

\(\displaystyle c \left (\frac {\frac {3}{2} \sqrt [3]{a c^2-d^2} \int \frac {1}{b^{2/3} c^{4/3} x^2-\sqrt [3]{b} c^{2/3} \sqrt [3]{a c^2-d^2} x+\left (a c^2-d^2\right )^{2/3}}dx-\frac {1}{2} \int \frac {\sqrt [3]{a c^2-d^2}-2 \sqrt [3]{b} c^{2/3} x}{b^{2/3} c^{4/3} x^2-\sqrt [3]{b} c^{2/3} \sqrt [3]{a c^2-d^2} x+\left (a c^2-d^2\right )^{2/3}}dx}{3 \sqrt [3]{b} c^{2/3} \sqrt [3]{a c^2-d^2}}-\frac {\log \left (\sqrt [3]{a c^2-d^2}+\sqrt [3]{b} c^{2/3} x\right )}{3 b^{2/3} c^{4/3} \sqrt [3]{a c^2-d^2}}\right )-\frac {d x^2 \sqrt {\frac {b x^3}{a}+1} \operatorname {AppellF1}\left (\frac {2}{3},\frac {1}{2},1,\frac {5}{3},-\frac {b x^3}{a},-\frac {b c^2 x^3}{a c^2-d^2}\right )}{2 \sqrt {a+b x^3} \left (a c^2-d^2\right )}\)

\(\Big \downarrow \) 1082

\(\displaystyle c \left (\frac {\frac {3 \int \frac {1}{-\left (1-\frac {2 \sqrt [3]{b} c^{2/3} x}{\sqrt [3]{a c^2-d^2}}\right )^2-3}d\left (1-\frac {2 \sqrt [3]{b} c^{2/3} x}{\sqrt [3]{a c^2-d^2}}\right )}{\sqrt [3]{b} c^{2/3}}-\frac {1}{2} \int \frac {\sqrt [3]{a c^2-d^2}-2 \sqrt [3]{b} c^{2/3} x}{b^{2/3} c^{4/3} x^2-\sqrt [3]{b} c^{2/3} \sqrt [3]{a c^2-d^2} x+\left (a c^2-d^2\right )^{2/3}}dx}{3 \sqrt [3]{b} c^{2/3} \sqrt [3]{a c^2-d^2}}-\frac {\log \left (\sqrt [3]{a c^2-d^2}+\sqrt [3]{b} c^{2/3} x\right )}{3 b^{2/3} c^{4/3} \sqrt [3]{a c^2-d^2}}\right )-\frac {d x^2 \sqrt {\frac {b x^3}{a}+1} \operatorname {AppellF1}\left (\frac {2}{3},\frac {1}{2},1,\frac {5}{3},-\frac {b x^3}{a},-\frac {b c^2 x^3}{a c^2-d^2}\right )}{2 \sqrt {a+b x^3} \left (a c^2-d^2\right )}\)

\(\Big \downarrow \) 217

\(\displaystyle c \left (\frac {-\frac {1}{2} \int \frac {\sqrt [3]{a c^2-d^2}-2 \sqrt [3]{b} c^{2/3} x}{b^{2/3} c^{4/3} x^2-\sqrt [3]{b} c^{2/3} \sqrt [3]{a c^2-d^2} x+\left (a c^2-d^2\right )^{2/3}}dx-\frac {\sqrt {3} \arctan \left (\frac {1-\frac {2 \sqrt [3]{b} c^{2/3} x}{\sqrt [3]{a c^2-d^2}}}{\sqrt {3}}\right )}{\sqrt [3]{b} c^{2/3}}}{3 \sqrt [3]{b} c^{2/3} \sqrt [3]{a c^2-d^2}}-\frac {\log \left (\sqrt [3]{a c^2-d^2}+\sqrt [3]{b} c^{2/3} x\right )}{3 b^{2/3} c^{4/3} \sqrt [3]{a c^2-d^2}}\right )-\frac {d x^2 \sqrt {\frac {b x^3}{a}+1} \operatorname {AppellF1}\left (\frac {2}{3},\frac {1}{2},1,\frac {5}{3},-\frac {b x^3}{a},-\frac {b c^2 x^3}{a c^2-d^2}\right )}{2 \sqrt {a+b x^3} \left (a c^2-d^2\right )}\)

\(\Big \downarrow \) 1103

\(\displaystyle c \left (\frac {\frac {\log \left (-\sqrt [3]{b} c^{2/3} x \sqrt [3]{a c^2-d^2}+\left (a c^2-d^2\right )^{2/3}+b^{2/3} c^{4/3} x^2\right )}{2 \sqrt [3]{b} c^{2/3}}-\frac {\sqrt {3} \arctan \left (\frac {1-\frac {2 \sqrt [3]{b} c^{2/3} x}{\sqrt [3]{a c^2-d^2}}}{\sqrt {3}}\right )}{\sqrt [3]{b} c^{2/3}}}{3 \sqrt [3]{b} c^{2/3} \sqrt [3]{a c^2-d^2}}-\frac {\log \left (\sqrt [3]{a c^2-d^2}+\sqrt [3]{b} c^{2/3} x\right )}{3 b^{2/3} c^{4/3} \sqrt [3]{a c^2-d^2}}\right )-\frac {d x^2 \sqrt {\frac {b x^3}{a}+1} \operatorname {AppellF1}\left (\frac {2}{3},\frac {1}{2},1,\frac {5}{3},-\frac {b x^3}{a},-\frac {b c^2 x^3}{a c^2-d^2}\right )}{2 \sqrt {a+b x^3} \left (a c^2-d^2\right )}\)

input
Int[x/(a*c + b*c*x^3 + d*Sqrt[a + b*x^3]),x]
 
output
-1/2*(d*x^2*Sqrt[1 + (b*x^3)/a]*AppellF1[2/3, 1/2, 1, 5/3, -((b*x^3)/a), - 
((b*c^2*x^3)/(a*c^2 - d^2))])/((a*c^2 - d^2)*Sqrt[a + b*x^3]) + c*(-1/3*Lo 
g[(a*c^2 - d^2)^(1/3) + b^(1/3)*c^(2/3)*x]/(b^(2/3)*c^(4/3)*(a*c^2 - d^2)^ 
(1/3)) + (-((Sqrt[3]*ArcTan[(1 - (2*b^(1/3)*c^(2/3)*x)/(a*c^2 - d^2)^(1/3) 
)/Sqrt[3]])/(b^(1/3)*c^(2/3))) + Log[(a*c^2 - d^2)^(2/3) - b^(1/3)*c^(2/3) 
*(a*c^2 - d^2)^(1/3)*x + b^(2/3)*c^(4/3)*x^2]/(2*b^(1/3)*c^(2/3)))/(3*b^(1 
/3)*c^(2/3)*(a*c^2 - d^2)^(1/3)))
 

3.6.58.3.1 Defintions of rubi rules used

rule 16
Int[(c_.)/((a_.) + (b_.)*(x_)), x_Symbol] :> Simp[c*(Log[RemoveContent[a + 
b*x, x]]/b), x] /; FreeQ[{a, b, c}, x]
 

rule 25
Int[-(Fx_), x_Symbol] :> Simp[Identity[-1]   Int[Fx, x], x]
 

rule 27
Int[(a_)*(Fx_), x_Symbol] :> Simp[a   Int[Fx, x], x] /; FreeQ[a, x] &&  !Ma 
tchQ[Fx, (b_)*(Gx_) /; FreeQ[b, x]]
 

rule 217
Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(-(Rt[-a, 2]*Rt[-b, 2])^( 
-1))*ArcTan[Rt[-b, 2]*(x/Rt[-a, 2])], x] /; FreeQ[{a, b}, x] && PosQ[a/b] & 
& (LtQ[a, 0] || LtQ[b, 0])
 

rule 821
Int[(x_)/((a_) + (b_.)*(x_)^3), x_Symbol] :> Simp[-(3*Rt[a, 3]*Rt[b, 3])^(- 
1)   Int[1/(Rt[a, 3] + Rt[b, 3]*x), x], x] + Simp[1/(3*Rt[a, 3]*Rt[b, 3]) 
 Int[(Rt[a, 3] + Rt[b, 3]*x)/(Rt[a, 3]^2 - Rt[a, 3]*Rt[b, 3]*x + Rt[b, 3]^2 
*x^2), x], x] /; FreeQ[{a, b}, x]
 

rule 1012
Int[((e_.)*(x_))^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_)*((c_) + (d_.)*(x_)^(n_ 
))^(q_), x_Symbol] :> Simp[a^p*c^q*((e*x)^(m + 1)/(e*(m + 1)))*AppellF1[(m 
+ 1)/n, -p, -q, 1 + (m + 1)/n, (-b)*(x^n/a), (-d)*(x^n/c)], x] /; FreeQ[{a, 
 b, c, d, e, m, n, p, q}, x] && NeQ[b*c - a*d, 0] && NeQ[m, -1] && NeQ[m, n 
 - 1] && (IntegerQ[p] || GtQ[a, 0]) && (IntegerQ[q] || GtQ[c, 0])
 

rule 1013
Int[((e_.)*(x_))^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_)*((c_) + (d_.)*(x_)^(n_ 
))^(q_), x_Symbol] :> Simp[a^IntPart[p]*((a + b*x^n)^FracPart[p]/(1 + b*(x^ 
n/a))^FracPart[p])   Int[(e*x)^m*(1 + b*(x^n/a))^p*(c + d*x^n)^q, x], x] /; 
 FreeQ[{a, b, c, d, e, m, n, p, q}, x] && NeQ[b*c - a*d, 0] && NeQ[m, -1] & 
& NeQ[m, n - 1] &&  !(IntegerQ[p] || GtQ[a, 0])
 

rule 1082
Int[((a_) + (b_.)*(x_) + (c_.)*(x_)^2)^(-1), x_Symbol] :> With[{q = 1 - 4*S 
implify[a*(c/b^2)]}, Simp[-2/b   Subst[Int[1/(q - x^2), x], x, 1 + 2*c*(x/b 
)], x] /; RationalQ[q] && (EqQ[q^2, 1] ||  !RationalQ[b^2 - 4*a*c])] /; Fre 
eQ[{a, b, c}, x]
 

rule 1103
Int[((d_) + (e_.)*(x_))/((a_.) + (b_.)*(x_) + (c_.)*(x_)^2), x_Symbol] :> S 
imp[d*(Log[RemoveContent[a + b*x + c*x^2, x]]/b), x] /; FreeQ[{a, b, c, d, 
e}, x] && EqQ[2*c*d - b*e, 0]
 

rule 1142
Int[((d_.) + (e_.)*(x_))/((a_) + (b_.)*(x_) + (c_.)*(x_)^2), x_Symbol] :> S 
imp[(2*c*d - b*e)/(2*c)   Int[1/(a + b*x + c*x^2), x], x] + Simp[e/(2*c) 
Int[(b + 2*c*x)/(a + b*x + c*x^2), x], x] /; FreeQ[{a, b, c, d, e}, x]
 

rule 2587
Int[(u_.)/((c_) + (d_.)*(x_)^(n_) + (e_.)*Sqrt[(a_) + (b_.)*(x_)^(n_)]), x_ 
Symbol] :> Simp[c   Int[u/(c^2 - a*e^2 + c*d*x^n), x], x] - Simp[a*e   Int[ 
u/((c^2 - a*e^2 + c*d*x^n)*Sqrt[a + b*x^n]), x], x] /; FreeQ[{a, b, c, d, e 
, n}, x] && EqQ[b*c - a*d, 0]
 
3.6.58.4 Maple [C] (warning: unable to verify)

Result contains higher order function than in optimal. Order 9 vs. order 6.

Time = 0.88 (sec) , antiderivative size = 665, normalized size of antiderivative = 2.19

method result size
elliptic \(\frac {\sqrt {b \,x^{3}+a}\, \left (d +c \sqrt {b \,x^{3}+a}\right ) \left (-\frac {\ln \left (x +\left (\frac {a \,c^{2}-d^{2}}{b \,c^{2}}\right )^{\frac {1}{3}}\right )}{3 b c \left (\frac {a \,c^{2}-d^{2}}{b \,c^{2}}\right )^{\frac {1}{3}}}+\frac {\ln \left (x^{2}-\left (\frac {a \,c^{2}-d^{2}}{b \,c^{2}}\right )^{\frac {1}{3}} x +\left (\frac {a \,c^{2}-d^{2}}{b \,c^{2}}\right )^{\frac {2}{3}}\right )}{6 b c \left (\frac {a \,c^{2}-d^{2}}{b \,c^{2}}\right )^{\frac {1}{3}}}+\frac {\sqrt {3}\, \arctan \left (\frac {\sqrt {3}\, \left (\frac {2 x}{\left (\frac {a \,c^{2}-d^{2}}{b \,c^{2}}\right )^{\frac {1}{3}}}-1\right )}{3}\right )}{3 b c \left (\frac {a \,c^{2}-d^{2}}{b \,c^{2}}\right )^{\frac {1}{3}}}-\frac {i \sqrt {2}\, \left (\munderset {\underline {\hspace {1.25 ex}}\alpha =\operatorname {RootOf}\left (b \,c^{2} \textit {\_Z}^{3}+a \,c^{2}-d^{2}\right )}{\sum }\frac {\left (-b^{2} a \right )^{\frac {1}{3}} \sqrt {2}\, \sqrt {\frac {i b \left (2 x +\frac {\left (-b^{2} a \right )^{\frac {1}{3}}-i \sqrt {3}\, \left (-b^{2} a \right )^{\frac {1}{3}}}{b}\right )}{\left (-b^{2} a \right )^{\frac {1}{3}}}}\, \sqrt {\frac {b \left (x -\frac {\left (-b^{2} a \right )^{\frac {1}{3}}}{b}\right )}{-3 \left (-b^{2} a \right )^{\frac {1}{3}}+i \sqrt {3}\, \left (-b^{2} a \right )^{\frac {1}{3}}}}\, \sqrt {-\frac {i b \left (2 x +\frac {\left (-b^{2} a \right )^{\frac {1}{3}}+i \sqrt {3}\, \left (-b^{2} a \right )^{\frac {1}{3}}}{b}\right )}{2 \left (-b^{2} a \right )^{\frac {1}{3}}}}\, \left (i \left (-b^{2} a \right )^{\frac {1}{3}} \sqrt {3}\, \underline {\hspace {1.25 ex}}\alpha b -i \left (-b^{2} a \right )^{\frac {2}{3}} \sqrt {3}+2 \underline {\hspace {1.25 ex}}\alpha ^{2} b^{2}-\left (-b^{2} a \right )^{\frac {1}{3}} \underline {\hspace {1.25 ex}}\alpha b -\left (-b^{2} a \right )^{\frac {2}{3}}\right ) \Pi \left (\frac {\sqrt {3}\, \sqrt {\frac {i \left (x +\frac {\left (-b^{2} a \right )^{\frac {1}{3}}}{2 b}-\frac {i \sqrt {3}\, \left (-b^{2} a \right )^{\frac {1}{3}}}{2 b}\right ) \sqrt {3}\, b}{\left (-b^{2} a \right )^{\frac {1}{3}}}}}{3}, -\frac {c^{2} \left (2 i \left (-b^{2} a \right )^{\frac {1}{3}} \sqrt {3}\, \underline {\hspace {1.25 ex}}\alpha ^{2} b -i \left (-b^{2} a \right )^{\frac {2}{3}} \sqrt {3}\, \underline {\hspace {1.25 ex}}\alpha +i \sqrt {3}\, a b -3 \left (-b^{2} a \right )^{\frac {2}{3}} \underline {\hspace {1.25 ex}}\alpha -3 a b \right )}{2 b \,d^{2}}, \sqrt {\frac {i \sqrt {3}\, \left (-b^{2} a \right )^{\frac {1}{3}}}{b \left (-\frac {3 \left (-b^{2} a \right )^{\frac {1}{3}}}{2 b}+\frac {i \sqrt {3}\, \left (-b^{2} a \right )^{\frac {1}{3}}}{2 b}\right )}}\right )}{2 \underline {\hspace {1.25 ex}}\alpha \sqrt {b \,x^{3}+a}}\right )}{3 d \,b^{3}}\right )}{a c +b c \,x^{3}+d \sqrt {b \,x^{3}+a}}\) \(665\)
default \(\text {Expression too large to display}\) \(1925\)

input
int(x/(a*c+b*c*x^3+d*(b*x^3+a)^(1/2)),x,method=_RETURNVERBOSE)
 
output
(b*x^3+a)^(1/2)*(d+c*(b*x^3+a)^(1/2))/(a*c+b*c*x^3+d*(b*x^3+a)^(1/2))*(-1/ 
3/b/c/((a*c^2-d^2)/b/c^2)^(1/3)*ln(x+((a*c^2-d^2)/b/c^2)^(1/3))+1/6/b/c/(( 
a*c^2-d^2)/b/c^2)^(1/3)*ln(x^2-((a*c^2-d^2)/b/c^2)^(1/3)*x+((a*c^2-d^2)/b/ 
c^2)^(2/3))+1/3/b/c*3^(1/2)/((a*c^2-d^2)/b/c^2)^(1/3)*arctan(1/3*3^(1/2)*( 
2/((a*c^2-d^2)/b/c^2)^(1/3)*x-1))-1/3*I/d/b^3*2^(1/2)*sum(1/_alpha*(-b^2*a 
)^(1/3)*(1/2*I*b*(2*x+1/b*((-b^2*a)^(1/3)-I*3^(1/2)*(-b^2*a)^(1/3)))/(-b^2 
*a)^(1/3))^(1/2)*(b*(x-1/b*(-b^2*a)^(1/3))/(-3*(-b^2*a)^(1/3)+I*3^(1/2)*(- 
b^2*a)^(1/3)))^(1/2)*(-1/2*I*b*(2*x+1/b*((-b^2*a)^(1/3)+I*3^(1/2)*(-b^2*a) 
^(1/3)))/(-b^2*a)^(1/3))^(1/2)/(b*x^3+a)^(1/2)*(I*(-b^2*a)^(1/3)*3^(1/2)*_ 
alpha*b-I*(-b^2*a)^(2/3)*3^(1/2)+2*_alpha^2*b^2-(-b^2*a)^(1/3)*_alpha*b-(- 
b^2*a)^(2/3))*EllipticPi(1/3*3^(1/2)*(I*(x+1/2/b*(-b^2*a)^(1/3)-1/2*I*3^(1 
/2)/b*(-b^2*a)^(1/3))*3^(1/2)*b/(-b^2*a)^(1/3))^(1/2),-1/2/b*c^2*(2*I*(-b^ 
2*a)^(1/3)*3^(1/2)*_alpha^2*b-I*(-b^2*a)^(2/3)*3^(1/2)*_alpha+I*3^(1/2)*a* 
b-3*(-b^2*a)^(2/3)*_alpha-3*a*b)/d^2,(I*3^(1/2)/b*(-b^2*a)^(1/3)/(-3/2/b*( 
-b^2*a)^(1/3)+1/2*I*3^(1/2)/b*(-b^2*a)^(1/3)))^(1/2)),_alpha=RootOf(_Z^3*b 
*c^2+a*c^2-d^2)))
 
3.6.58.5 Fricas [F(-1)]

Timed out. \[ \int \frac {x}{a c+b c x^3+d \sqrt {a+b x^3}} \, dx=\text {Timed out} \]

input
integrate(x/(a*c+b*c*x^3+d*(b*x^3+a)^(1/2)),x, algorithm="fricas")
 
output
Timed out
 
3.6.58.6 Sympy [F]

\[ \int \frac {x}{a c+b c x^3+d \sqrt {a+b x^3}} \, dx=\int \frac {x}{a c + b c x^{3} + d \sqrt {a + b x^{3}}}\, dx \]

input
integrate(x/(a*c+b*c*x**3+d*(b*x**3+a)**(1/2)),x)
 
output
Integral(x/(a*c + b*c*x**3 + d*sqrt(a + b*x**3)), x)
 
3.6.58.7 Maxima [F]

\[ \int \frac {x}{a c+b c x^3+d \sqrt {a+b x^3}} \, dx=\int { \frac {x}{b c x^{3} + a c + \sqrt {b x^{3} + a} d} \,d x } \]

input
integrate(x/(a*c+b*c*x^3+d*(b*x^3+a)^(1/2)),x, algorithm="maxima")
 
output
integrate(x/(b*c*x^3 + a*c + sqrt(b*x^3 + a)*d), x)
 
3.6.58.8 Giac [F]

\[ \int \frac {x}{a c+b c x^3+d \sqrt {a+b x^3}} \, dx=\int { \frac {x}{b c x^{3} + a c + \sqrt {b x^{3} + a} d} \,d x } \]

input
integrate(x/(a*c+b*c*x^3+d*(b*x^3+a)^(1/2)),x, algorithm="giac")
 
output
integrate(x/(b*c*x^3 + a*c + sqrt(b*x^3 + a)*d), x)
 
3.6.58.9 Mupad [F(-1)]

Timed out. \[ \int \frac {x}{a c+b c x^3+d \sqrt {a+b x^3}} \, dx=\int \frac {x}{a\,c+d\,\sqrt {b\,x^3+a}+b\,c\,x^3} \,d x \]

input
int(x/(a*c + d*(a + b*x^3)^(1/2) + b*c*x^3),x)
 
output
int(x/(a*c + d*(a + b*x^3)^(1/2) + b*c*x^3), x)