Integrand size = 13, antiderivative size = 77 \[ \int \frac {1}{x \sqrt [4]{-1+x^4}} \, dx=-\frac {\arctan \left (\frac {\sqrt {2} \sqrt [4]{-1+x^4}}{-1+\sqrt {-1+x^4}}\right )}{2 \sqrt {2}}-\frac {\text {arctanh}\left (\frac {\sqrt {2} \sqrt [4]{-1+x^4}}{1+\sqrt {-1+x^4}}\right )}{2 \sqrt {2}} \]
-1/4*arctan(2^(1/2)*(x^4-1)^(1/4)/(-1+(x^4-1)^(1/2)))*2^(1/2)-1/4*arctanh( 2^(1/2)*(x^4-1)^(1/4)/(1+(x^4-1)^(1/2)))*2^(1/2)
Time = 0.02 (sec) , antiderivative size = 68, normalized size of antiderivative = 0.88 \[ \int \frac {1}{x \sqrt [4]{-1+x^4}} \, dx=\frac {\arctan \left (\frac {-1+\sqrt {-1+x^4}}{\sqrt {2} \sqrt [4]{-1+x^4}}\right )-\text {arctanh}\left (\frac {\sqrt {2} \sqrt [4]{-1+x^4}}{1+\sqrt {-1+x^4}}\right )}{2 \sqrt {2}} \]
(ArcTan[(-1 + Sqrt[-1 + x^4])/(Sqrt[2]*(-1 + x^4)^(1/4))] - ArcTanh[(Sqrt[ 2]*(-1 + x^4)^(1/4))/(1 + Sqrt[-1 + x^4])])/(2*Sqrt[2])
Time = 0.32 (sec) , antiderivative size = 122, normalized size of antiderivative = 1.58, number of steps used = 11, number of rules used = 10, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.769, Rules used = {798, 73, 826, 1476, 1082, 217, 1479, 25, 27, 1103}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int \frac {1}{x \sqrt [4]{x^4-1}} \, dx\) |
\(\Big \downarrow \) 798 |
\(\displaystyle \frac {1}{4} \int \frac {1}{x^4 \sqrt [4]{x^4-1}}dx^4\) |
\(\Big \downarrow \) 73 |
\(\displaystyle \int \frac {x^8}{x^{16}+1}d\sqrt [4]{x^4-1}\) |
\(\Big \downarrow \) 826 |
\(\displaystyle \frac {1}{2} \int \frac {x^8+1}{x^{16}+1}d\sqrt [4]{x^4-1}-\frac {1}{2} \int \frac {1-x^8}{x^{16}+1}d\sqrt [4]{x^4-1}\) |
\(\Big \downarrow \) 1476 |
\(\displaystyle \frac {1}{2} \left (\frac {1}{2} \int \frac {1}{x^8-\sqrt {2} \sqrt [4]{x^4-1}+1}d\sqrt [4]{x^4-1}+\frac {1}{2} \int \frac {1}{x^8+\sqrt {2} \sqrt [4]{x^4-1}+1}d\sqrt [4]{x^4-1}\right )-\frac {1}{2} \int \frac {1-x^8}{x^{16}+1}d\sqrt [4]{x^4-1}\) |
\(\Big \downarrow \) 1082 |
\(\displaystyle \frac {1}{2} \left (\frac {\int \frac {1}{-x^8-1}d\left (1-\sqrt {2} \sqrt [4]{x^4-1}\right )}{\sqrt {2}}-\frac {\int \frac {1}{-x^8-1}d\left (\sqrt {2} \sqrt [4]{x^4-1}+1\right )}{\sqrt {2}}\right )-\frac {1}{2} \int \frac {1-x^8}{x^{16}+1}d\sqrt [4]{x^4-1}\) |
\(\Big \downarrow \) 217 |
\(\displaystyle \frac {1}{2} \left (\frac {\arctan \left (\sqrt {2} \sqrt [4]{x^4-1}+1\right )}{\sqrt {2}}-\frac {\arctan \left (1-\sqrt {2} \sqrt [4]{x^4-1}\right )}{\sqrt {2}}\right )-\frac {1}{2} \int \frac {1-x^8}{x^{16}+1}d\sqrt [4]{x^4-1}\) |
\(\Big \downarrow \) 1479 |
\(\displaystyle \frac {1}{2} \left (\frac {\int -\frac {\sqrt {2}-2 \sqrt [4]{x^4-1}}{x^8-\sqrt {2} \sqrt [4]{x^4-1}+1}d\sqrt [4]{x^4-1}}{2 \sqrt {2}}+\frac {\int -\frac {\sqrt {2} \left (\sqrt {2} \sqrt [4]{x^4-1}+1\right )}{x^8+\sqrt {2} \sqrt [4]{x^4-1}+1}d\sqrt [4]{x^4-1}}{2 \sqrt {2}}\right )+\frac {1}{2} \left (\frac {\arctan \left (\sqrt {2} \sqrt [4]{x^4-1}+1\right )}{\sqrt {2}}-\frac {\arctan \left (1-\sqrt {2} \sqrt [4]{x^4-1}\right )}{\sqrt {2}}\right )\) |
\(\Big \downarrow \) 25 |
\(\displaystyle \frac {1}{2} \left (-\frac {\int \frac {\sqrt {2}-2 \sqrt [4]{x^4-1}}{x^8-\sqrt {2} \sqrt [4]{x^4-1}+1}d\sqrt [4]{x^4-1}}{2 \sqrt {2}}-\frac {\int \frac {\sqrt {2} \left (\sqrt {2} \sqrt [4]{x^4-1}+1\right )}{x^8+\sqrt {2} \sqrt [4]{x^4-1}+1}d\sqrt [4]{x^4-1}}{2 \sqrt {2}}\right )+\frac {1}{2} \left (\frac {\arctan \left (\sqrt {2} \sqrt [4]{x^4-1}+1\right )}{\sqrt {2}}-\frac {\arctan \left (1-\sqrt {2} \sqrt [4]{x^4-1}\right )}{\sqrt {2}}\right )\) |
\(\Big \downarrow \) 27 |
\(\displaystyle \frac {1}{2} \left (-\frac {\int \frac {\sqrt {2}-2 \sqrt [4]{x^4-1}}{x^8-\sqrt {2} \sqrt [4]{x^4-1}+1}d\sqrt [4]{x^4-1}}{2 \sqrt {2}}-\frac {1}{2} \int \frac {\sqrt {2} \sqrt [4]{x^4-1}+1}{x^8+\sqrt {2} \sqrt [4]{x^4-1}+1}d\sqrt [4]{x^4-1}\right )+\frac {1}{2} \left (\frac {\arctan \left (\sqrt {2} \sqrt [4]{x^4-1}+1\right )}{\sqrt {2}}-\frac {\arctan \left (1-\sqrt {2} \sqrt [4]{x^4-1}\right )}{\sqrt {2}}\right )\) |
\(\Big \downarrow \) 1103 |
\(\displaystyle \frac {1}{2} \left (\frac {\arctan \left (\sqrt {2} \sqrt [4]{x^4-1}+1\right )}{\sqrt {2}}-\frac {\arctan \left (1-\sqrt {2} \sqrt [4]{x^4-1}\right )}{\sqrt {2}}\right )+\frac {1}{2} \left (\frac {\log \left (x^8-\sqrt {2} \sqrt [4]{x^4-1}+1\right )}{2 \sqrt {2}}-\frac {\log \left (x^8+\sqrt {2} \sqrt [4]{x^4-1}+1\right )}{2 \sqrt {2}}\right )\) |
(-(ArcTan[1 - Sqrt[2]*(-1 + x^4)^(1/4)]/Sqrt[2]) + ArcTan[1 + Sqrt[2]*(-1 + x^4)^(1/4)]/Sqrt[2])/2 + (Log[1 + x^8 - Sqrt[2]*(-1 + x^4)^(1/4)]/(2*Sqr t[2]) - Log[1 + x^8 + Sqrt[2]*(-1 + x^4)^(1/4)]/(2*Sqrt[2]))/2
3.11.14.3.1 Defintions of rubi rules used
Int[(a_)*(Fx_), x_Symbol] :> Simp[a Int[Fx, x], x] /; FreeQ[a, x] && !Ma tchQ[Fx, (b_)*(Gx_) /; FreeQ[b, x]]
Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> With[ {p = Denominator[m]}, Simp[p/b Subst[Int[x^(p*(m + 1) - 1)*(c - a*(d/b) + d*(x^p/b))^n, x], x, (a + b*x)^(1/p)], x]] /; FreeQ[{a, b, c, d}, x] && Lt Q[-1, m, 0] && LeQ[-1, n, 0] && LeQ[Denominator[n], Denominator[m]] && IntL inearQ[a, b, c, d, m, n, x]
Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(-(Rt[-a, 2]*Rt[-b, 2])^( -1))*ArcTan[Rt[-b, 2]*(x/Rt[-a, 2])], x] /; FreeQ[{a, b}, x] && PosQ[a/b] & & (LtQ[a, 0] || LtQ[b, 0])
Int[(x_)^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> Simp[1/n Subst [Int[x^(Simplify[(m + 1)/n] - 1)*(a + b*x)^p, x], x, x^n], x] /; FreeQ[{a, b, m, n, p}, x] && IntegerQ[Simplify[(m + 1)/n]]
Int[(x_)^2/((a_) + (b_.)*(x_)^4), x_Symbol] :> With[{r = Numerator[Rt[a/b, 2]], s = Denominator[Rt[a/b, 2]]}, Simp[1/(2*s) Int[(r + s*x^2)/(a + b*x^ 4), x], x] - Simp[1/(2*s) Int[(r - s*x^2)/(a + b*x^4), x], x]] /; FreeQ[{ a, b}, x] && (GtQ[a/b, 0] || (PosQ[a/b] && AtomQ[SplitProduct[SumBaseQ, a]] && AtomQ[SplitProduct[SumBaseQ, b]]))
Int[((a_) + (b_.)*(x_) + (c_.)*(x_)^2)^(-1), x_Symbol] :> With[{q = 1 - 4*S implify[a*(c/b^2)]}, Simp[-2/b Subst[Int[1/(q - x^2), x], x, 1 + 2*c*(x/b )], x] /; RationalQ[q] && (EqQ[q^2, 1] || !RationalQ[b^2 - 4*a*c])] /; Fre eQ[{a, b, c}, x]
Int[((d_) + (e_.)*(x_))/((a_.) + (b_.)*(x_) + (c_.)*(x_)^2), x_Symbol] :> S imp[d*(Log[RemoveContent[a + b*x + c*x^2, x]]/b), x] /; FreeQ[{a, b, c, d, e}, x] && EqQ[2*c*d - b*e, 0]
Int[((d_) + (e_.)*(x_)^2)/((a_) + (c_.)*(x_)^4), x_Symbol] :> With[{q = Rt[ 2*(d/e), 2]}, Simp[e/(2*c) Int[1/Simp[d/e + q*x + x^2, x], x], x] + Simp[ e/(2*c) Int[1/Simp[d/e - q*x + x^2, x], x], x]] /; FreeQ[{a, c, d, e}, x] && EqQ[c*d^2 - a*e^2, 0] && PosQ[d*e]
Int[((d_) + (e_.)*(x_)^2)/((a_) + (c_.)*(x_)^4), x_Symbol] :> With[{q = Rt[ -2*(d/e), 2]}, Simp[e/(2*c*q) Int[(q - 2*x)/Simp[d/e + q*x - x^2, x], x], x] + Simp[e/(2*c*q) Int[(q + 2*x)/Simp[d/e - q*x - x^2, x], x], x]] /; F reeQ[{a, c, d, e}, x] && EqQ[c*d^2 - a*e^2, 0] && NegQ[d*e]
Result contains higher order function than in optimal. Order 9 vs. order 3.
Time = 6.66 (sec) , antiderivative size = 79, normalized size of antiderivative = 1.03
method | result | size |
meijerg | \(\frac {\sqrt {2}\, \Gamma \left (\frac {3}{4}\right ) {\left (-\operatorname {signum}\left (x^{4}-1\right )\right )}^{\frac {1}{4}} \left (\frac {\pi \sqrt {2}\, x^{4} \operatorname {hypergeom}\left (\left [1, 1, \frac {5}{4}\right ], \left [2, 2\right ], x^{4}\right )}{4 \Gamma \left (\frac {3}{4}\right )}+\frac {\left (-3 \ln \left (2\right )-\frac {\pi }{2}+4 \ln \left (x \right )+i \pi \right ) \pi \sqrt {2}}{\Gamma \left (\frac {3}{4}\right )}\right )}{8 \pi \operatorname {signum}\left (x^{4}-1\right )^{\frac {1}{4}}}\) | \(79\) |
pseudoelliptic | \(\frac {\sqrt {2}\, \left (\ln \left (\frac {\sqrt {x^{4}-1}-\left (x^{4}-1\right )^{\frac {1}{4}} \sqrt {2}+1}{\sqrt {x^{4}-1}+\left (x^{4}-1\right )^{\frac {1}{4}} \sqrt {2}+1}\right )+2 \arctan \left (\left (x^{4}-1\right )^{\frac {1}{4}} \sqrt {2}+1\right )+2 \arctan \left (\left (x^{4}-1\right )^{\frac {1}{4}} \sqrt {2}-1\right )\right )}{8}\) | \(84\) |
trager | \(\frac {\operatorname {RootOf}\left (\textit {\_Z}^{4}+1\right )^{3} \ln \left (-\frac {\operatorname {RootOf}\left (\textit {\_Z}^{4}+1\right )^{3} x^{4}-2 \operatorname {RootOf}\left (\textit {\_Z}^{4}+1\right )^{3}-2 \left (x^{4}-1\right )^{\frac {1}{4}} \operatorname {RootOf}\left (\textit {\_Z}^{4}+1\right )^{2}-2 \sqrt {x^{4}-1}\, \operatorname {RootOf}\left (\textit {\_Z}^{4}+1\right )-2 \left (x^{4}-1\right )^{\frac {3}{4}}}{x^{4}}\right )}{4}+\frac {\operatorname {RootOf}\left (\textit {\_Z}^{4}+1\right ) \ln \left (\frac {2 \sqrt {x^{4}-1}\, \operatorname {RootOf}\left (\textit {\_Z}^{4}+1\right )^{3}-\operatorname {RootOf}\left (\textit {\_Z}^{4}+1\right ) x^{4}-2 \left (x^{4}-1\right )^{\frac {1}{4}} \operatorname {RootOf}\left (\textit {\_Z}^{4}+1\right )^{2}+2 \left (x^{4}-1\right )^{\frac {3}{4}}+2 \operatorname {RootOf}\left (\textit {\_Z}^{4}+1\right )}{x^{4}}\right )}{4}\) | \(158\) |
1/8/Pi*2^(1/2)*GAMMA(3/4)/signum(x^4-1)^(1/4)*(-signum(x^4-1))^(1/4)*(1/4* Pi*2^(1/2)/GAMMA(3/4)*x^4*hypergeom([1,1,5/4],[2,2],x^4)+(-3*ln(2)-1/2*Pi+ 4*ln(x)+I*Pi)*Pi*2^(1/2)/GAMMA(3/4))
Result contains complex when optimal does not.
Time = 0.26 (sec) , antiderivative size = 85, normalized size of antiderivative = 1.10 \[ \int \frac {1}{x \sqrt [4]{-1+x^4}} \, dx=\left (\frac {1}{8} i - \frac {1}{8}\right ) \, \sqrt {2} \log \left (\left (i + 1\right ) \, \sqrt {2} + 2 \, {\left (x^{4} - 1\right )}^{\frac {1}{4}}\right ) - \left (\frac {1}{8} i + \frac {1}{8}\right ) \, \sqrt {2} \log \left (-\left (i - 1\right ) \, \sqrt {2} + 2 \, {\left (x^{4} - 1\right )}^{\frac {1}{4}}\right ) + \left (\frac {1}{8} i + \frac {1}{8}\right ) \, \sqrt {2} \log \left (\left (i - 1\right ) \, \sqrt {2} + 2 \, {\left (x^{4} - 1\right )}^{\frac {1}{4}}\right ) - \left (\frac {1}{8} i - \frac {1}{8}\right ) \, \sqrt {2} \log \left (-\left (i + 1\right ) \, \sqrt {2} + 2 \, {\left (x^{4} - 1\right )}^{\frac {1}{4}}\right ) \]
(1/8*I - 1/8)*sqrt(2)*log((I + 1)*sqrt(2) + 2*(x^4 - 1)^(1/4)) - (1/8*I + 1/8)*sqrt(2)*log(-(I - 1)*sqrt(2) + 2*(x^4 - 1)^(1/4)) + (1/8*I + 1/8)*sqr t(2)*log((I - 1)*sqrt(2) + 2*(x^4 - 1)^(1/4)) - (1/8*I - 1/8)*sqrt(2)*log( -(I + 1)*sqrt(2) + 2*(x^4 - 1)^(1/4))
Result contains complex when optimal does not.
Time = 0.48 (sec) , antiderivative size = 31, normalized size of antiderivative = 0.40 \[ \int \frac {1}{x \sqrt [4]{-1+x^4}} \, dx=- \frac {\Gamma \left (\frac {1}{4}\right ) {{}_{2}F_{1}\left (\begin {matrix} \frac {1}{4}, \frac {1}{4} \\ \frac {5}{4} \end {matrix}\middle | {\frac {e^{2 i \pi }}{x^{4}}} \right )}}{4 x \Gamma \left (\frac {5}{4}\right )} \]
Time = 0.27 (sec) , antiderivative size = 102, normalized size of antiderivative = 1.32 \[ \int \frac {1}{x \sqrt [4]{-1+x^4}} \, dx=\frac {1}{4} \, \sqrt {2} \arctan \left (\frac {1}{2} \, \sqrt {2} {\left (\sqrt {2} + 2 \, {\left (x^{4} - 1\right )}^{\frac {1}{4}}\right )}\right ) + \frac {1}{4} \, \sqrt {2} \arctan \left (-\frac {1}{2} \, \sqrt {2} {\left (\sqrt {2} - 2 \, {\left (x^{4} - 1\right )}^{\frac {1}{4}}\right )}\right ) - \frac {1}{8} \, \sqrt {2} \log \left (\sqrt {2} {\left (x^{4} - 1\right )}^{\frac {1}{4}} + \sqrt {x^{4} - 1} + 1\right ) + \frac {1}{8} \, \sqrt {2} \log \left (-\sqrt {2} {\left (x^{4} - 1\right )}^{\frac {1}{4}} + \sqrt {x^{4} - 1} + 1\right ) \]
1/4*sqrt(2)*arctan(1/2*sqrt(2)*(sqrt(2) + 2*(x^4 - 1)^(1/4))) + 1/4*sqrt(2 )*arctan(-1/2*sqrt(2)*(sqrt(2) - 2*(x^4 - 1)^(1/4))) - 1/8*sqrt(2)*log(sqr t(2)*(x^4 - 1)^(1/4) + sqrt(x^4 - 1) + 1) + 1/8*sqrt(2)*log(-sqrt(2)*(x^4 - 1)^(1/4) + sqrt(x^4 - 1) + 1)
Time = 0.25 (sec) , antiderivative size = 102, normalized size of antiderivative = 1.32 \[ \int \frac {1}{x \sqrt [4]{-1+x^4}} \, dx=\frac {1}{4} \, \sqrt {2} \arctan \left (\frac {1}{2} \, \sqrt {2} {\left (\sqrt {2} + 2 \, {\left (x^{4} - 1\right )}^{\frac {1}{4}}\right )}\right ) + \frac {1}{4} \, \sqrt {2} \arctan \left (-\frac {1}{2} \, \sqrt {2} {\left (\sqrt {2} - 2 \, {\left (x^{4} - 1\right )}^{\frac {1}{4}}\right )}\right ) - \frac {1}{8} \, \sqrt {2} \log \left (\sqrt {2} {\left (x^{4} - 1\right )}^{\frac {1}{4}} + \sqrt {x^{4} - 1} + 1\right ) + \frac {1}{8} \, \sqrt {2} \log \left (-\sqrt {2} {\left (x^{4} - 1\right )}^{\frac {1}{4}} + \sqrt {x^{4} - 1} + 1\right ) \]
1/4*sqrt(2)*arctan(1/2*sqrt(2)*(sqrt(2) + 2*(x^4 - 1)^(1/4))) + 1/4*sqrt(2 )*arctan(-1/2*sqrt(2)*(sqrt(2) - 2*(x^4 - 1)^(1/4))) - 1/8*sqrt(2)*log(sqr t(2)*(x^4 - 1)^(1/4) + sqrt(x^4 - 1) + 1) + 1/8*sqrt(2)*log(-sqrt(2)*(x^4 - 1)^(1/4) + sqrt(x^4 - 1) + 1)
Time = 5.95 (sec) , antiderivative size = 45, normalized size of antiderivative = 0.58 \[ \int \frac {1}{x \sqrt [4]{-1+x^4}} \, dx=\sqrt {2}\,\mathrm {atan}\left (\sqrt {2}\,{\left (x^4-1\right )}^{1/4}\,\left (\frac {1}{2}-\frac {1}{2}{}\mathrm {i}\right )\right )\,\left (\frac {1}{4}-\frac {1}{4}{}\mathrm {i}\right )+\sqrt {2}\,\mathrm {atan}\left (\sqrt {2}\,{\left (x^4-1\right )}^{1/4}\,\left (\frac {1}{2}+\frac {1}{2}{}\mathrm {i}\right )\right )\,\left (\frac {1}{4}+\frac {1}{4}{}\mathrm {i}\right ) \]