Integrand size = 13, antiderivative size = 87 \[ \int \frac {\left (1+x^5\right )^{2/3}}{x} \, dx=\frac {3}{10} \left (1+x^5\right )^{2/3}+\frac {1}{5} \sqrt {3} \arctan \left (\frac {1}{\sqrt {3}}+\frac {2 \sqrt [3]{1+x^5}}{\sqrt {3}}\right )+\frac {1}{5} \log \left (-1+\sqrt [3]{1+x^5}\right )-\frac {1}{10} \log \left (1+\sqrt [3]{1+x^5}+\left (1+x^5\right )^{2/3}\right ) \]
3/10*(x^5+1)^(2/3)+1/5*3^(1/2)*arctan(1/3*3^(1/2)+2/3*(x^5+1)^(1/3)*3^(1/2 ))+1/5*ln(-1+(x^5+1)^(1/3))-1/10*ln(1+(x^5+1)^(1/3)+(x^5+1)^(2/3))
Time = 0.05 (sec) , antiderivative size = 80, normalized size of antiderivative = 0.92 \[ \int \frac {\left (1+x^5\right )^{2/3}}{x} \, dx=\frac {1}{10} \left (3 \left (1+x^5\right )^{2/3}+2 \sqrt {3} \arctan \left (\frac {1+2 \sqrt [3]{1+x^5}}{\sqrt {3}}\right )+2 \log \left (-1+\sqrt [3]{1+x^5}\right )-\log \left (1+\sqrt [3]{1+x^5}+\left (1+x^5\right )^{2/3}\right )\right ) \]
(3*(1 + x^5)^(2/3) + 2*Sqrt[3]*ArcTan[(1 + 2*(1 + x^5)^(1/3))/Sqrt[3]] + 2 *Log[-1 + (1 + x^5)^(1/3)] - Log[1 + (1 + x^5)^(1/3) + (1 + x^5)^(2/3)])/1 0
Time = 0.19 (sec) , antiderivative size = 70, normalized size of antiderivative = 0.80, number of steps used = 7, number of rules used = 6, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.462, Rules used = {798, 60, 67, 16, 1083, 217}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int \frac {\left (x^5+1\right )^{2/3}}{x} \, dx\) |
\(\Big \downarrow \) 798 |
\(\displaystyle \frac {1}{5} \int \frac {\left (x^5+1\right )^{2/3}}{x^5}dx^5\) |
\(\Big \downarrow \) 60 |
\(\displaystyle \frac {1}{5} \left (\int \frac {1}{x^5 \sqrt [3]{x^5+1}}dx^5+\frac {3}{2} \left (x^5+1\right )^{2/3}\right )\) |
\(\Big \downarrow \) 67 |
\(\displaystyle \frac {1}{5} \left (-\frac {3}{2} \int \frac {1}{1-\sqrt [3]{x^5+1}}d\sqrt [3]{x^5+1}+\frac {3}{2} \int \frac {1}{x^{10}+\sqrt [3]{x^5+1}+1}d\sqrt [3]{x^5+1}+\frac {3}{2} \left (x^5+1\right )^{2/3}-\frac {1}{2} \log \left (x^5\right )\right )\) |
\(\Big \downarrow \) 16 |
\(\displaystyle \frac {1}{5} \left (\frac {3}{2} \int \frac {1}{x^{10}+\sqrt [3]{x^5+1}+1}d\sqrt [3]{x^5+1}+\frac {3}{2} \left (x^5+1\right )^{2/3}-\frac {1}{2} \log \left (x^5\right )+\frac {3}{2} \log \left (1-\sqrt [3]{x^5+1}\right )\right )\) |
\(\Big \downarrow \) 1083 |
\(\displaystyle \frac {1}{5} \left (-3 \int \frac {1}{-x^{10}-3}d\left (2 \sqrt [3]{x^5+1}+1\right )+\frac {3}{2} \left (x^5+1\right )^{2/3}-\frac {1}{2} \log \left (x^5\right )+\frac {3}{2} \log \left (1-\sqrt [3]{x^5+1}\right )\right )\) |
\(\Big \downarrow \) 217 |
\(\displaystyle \frac {1}{5} \left (\sqrt {3} \arctan \left (\frac {2 \sqrt [3]{x^5+1}+1}{\sqrt {3}}\right )+\frac {3}{2} \left (x^5+1\right )^{2/3}-\frac {\log \left (x^5\right )}{2}+\frac {3}{2} \log \left (1-\sqrt [3]{x^5+1}\right )\right )\) |
((3*(1 + x^5)^(2/3))/2 + Sqrt[3]*ArcTan[(1 + 2*(1 + x^5)^(1/3))/Sqrt[3]] - Log[x^5]/2 + (3*Log[1 - (1 + x^5)^(1/3)])/2)/5
3.12.89.3.1 Defintions of rubi rules used
Int[(c_.)/((a_.) + (b_.)*(x_)), x_Symbol] :> Simp[c*(Log[RemoveContent[a + b*x, x]]/b), x] /; FreeQ[{a, b, c}, x]
Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> Simp[ (a + b*x)^(m + 1)*((c + d*x)^n/(b*(m + n + 1))), x] + Simp[n*((b*c - a*d)/( b*(m + n + 1))) Int[(a + b*x)^m*(c + d*x)^(n - 1), x], x] /; FreeQ[{a, b, c, d}, x] && GtQ[n, 0] && NeQ[m + n + 1, 0] && !(IGtQ[m, 0] && ( !Integer Q[n] || (GtQ[m, 0] && LtQ[m - n, 0]))) && !ILtQ[m + n + 2, 0] && IntLinear Q[a, b, c, d, m, n, x]
Int[1/(((a_.) + (b_.)*(x_))*((c_.) + (d_.)*(x_))^(1/3)), x_Symbol] :> With[ {q = Rt[(b*c - a*d)/b, 3]}, Simp[-Log[RemoveContent[a + b*x, x]]/(2*b*q), x ] + (Simp[3/(2*b) Subst[Int[1/(q^2 + q*x + x^2), x], x, (c + d*x)^(1/3)], x] - Simp[3/(2*b*q) Subst[Int[1/(q - x), x], x, (c + d*x)^(1/3)], x])] / ; FreeQ[{a, b, c, d}, x] && PosQ[(b*c - a*d)/b]
Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(-(Rt[-a, 2]*Rt[-b, 2])^( -1))*ArcTan[Rt[-b, 2]*(x/Rt[-a, 2])], x] /; FreeQ[{a, b}, x] && PosQ[a/b] & & (LtQ[a, 0] || LtQ[b, 0])
Int[(x_)^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> Simp[1/n Subst [Int[x^(Simplify[(m + 1)/n] - 1)*(a + b*x)^p, x], x, x^n], x] /; FreeQ[{a, b, m, n, p}, x] && IntegerQ[Simplify[(m + 1)/n]]
Int[((a_) + (b_.)*(x_) + (c_.)*(x_)^2)^(-1), x_Symbol] :> Simp[-2 Subst[I nt[1/Simp[b^2 - 4*a*c - x^2, x], x], x, b + 2*c*x], x] /; FreeQ[{a, b, c}, x]
Result contains higher order function than in optimal. Order 5 vs. order 3.
Time = 6.58 (sec) , antiderivative size = 64, normalized size of antiderivative = 0.74
method | result | size |
meijerg | \(-\frac {\sqrt {3}\, \Gamma \left (\frac {2}{3}\right ) \left (-\frac {2 \pi \sqrt {3}\, x^{5} \operatorname {hypergeom}\left (\left [\frac {1}{3}, 1, 1\right ], \left [2, 2\right ], -x^{5}\right )}{3 \Gamma \left (\frac {2}{3}\right )}-\frac {\left (\frac {3}{2}-\frac {\pi \sqrt {3}}{6}-\frac {3 \ln \left (3\right )}{2}+5 \ln \left (x \right )\right ) \pi \sqrt {3}}{\Gamma \left (\frac {2}{3}\right )}\right )}{15 \pi }\) | \(64\) |
pseudoelliptic | \(\frac {3 \left (x^{5}+1\right )^{\frac {2}{3}}}{10}+\frac {\ln \left (-1+\left (x^{5}+1\right )^{\frac {1}{3}}\right )}{5}-\frac {\ln \left (1+\left (x^{5}+1\right )^{\frac {1}{3}}+\left (x^{5}+1\right )^{\frac {2}{3}}\right )}{10}+\frac {\sqrt {3}\, \arctan \left (\frac {\left (2 \left (x^{5}+1\right )^{\frac {1}{3}}+1\right ) \sqrt {3}}{3}\right )}{5}\) | \(64\) |
trager | \(\frac {3 \left (x^{5}+1\right )^{\frac {2}{3}}}{10}-\frac {\ln \left (\frac {-5765684175 \operatorname {RootOf}\left (9 \textit {\_Z}^{2}+3 \textit {\_Z} +1\right )^{2} x^{5}-28880825748 \operatorname {RootOf}\left (9 \textit {\_Z}^{2}+3 \textit {\_Z} +1\right ) x^{5}-23115141573 x^{5}+13505667948 \operatorname {RootOf}\left (9 \textit {\_Z}^{2}+3 \textit {\_Z} +1\right ) \left (x^{5}+1\right )^{\frac {2}{3}}-31460820339 \left (x^{5}+1\right )^{\frac {2}{3}}+13505667948 \operatorname {RootOf}\left (9 \textit {\_Z}^{2}+3 \textit {\_Z} +1\right ) \left (x^{5}+1\right )^{\frac {1}{3}}+5765684175 \operatorname {RootOf}\left (9 \textit {\_Z}^{2}+3 \textit {\_Z} +1\right )^{2}-31460820339 \left (x^{5}+1\right )^{\frac {1}{3}}+15427562673 \operatorname {RootOf}\left (9 \textit {\_Z}^{2}+3 \textit {\_Z} +1\right )-30820188764}{x^{5}}\right )}{5}-\frac {3 \ln \left (\frac {-5765684175 \operatorname {RootOf}\left (9 \textit {\_Z}^{2}+3 \textit {\_Z} +1\right )^{2} x^{5}-28880825748 \operatorname {RootOf}\left (9 \textit {\_Z}^{2}+3 \textit {\_Z} +1\right ) x^{5}-23115141573 x^{5}+13505667948 \operatorname {RootOf}\left (9 \textit {\_Z}^{2}+3 \textit {\_Z} +1\right ) \left (x^{5}+1\right )^{\frac {2}{3}}-31460820339 \left (x^{5}+1\right )^{\frac {2}{3}}+13505667948 \operatorname {RootOf}\left (9 \textit {\_Z}^{2}+3 \textit {\_Z} +1\right ) \left (x^{5}+1\right )^{\frac {1}{3}}+5765684175 \operatorname {RootOf}\left (9 \textit {\_Z}^{2}+3 \textit {\_Z} +1\right )^{2}-31460820339 \left (x^{5}+1\right )^{\frac {1}{3}}+15427562673 \operatorname {RootOf}\left (9 \textit {\_Z}^{2}+3 \textit {\_Z} +1\right )-30820188764}{x^{5}}\right ) \operatorname {RootOf}\left (9 \textit {\_Z}^{2}+3 \textit {\_Z} +1\right )}{5}+\frac {3 \operatorname {RootOf}\left (9 \textit {\_Z}^{2}+3 \textit {\_Z} +1\right ) \ln \left (\frac {-132201 \operatorname {RootOf}\left (9 \textit {\_Z}^{2}+3 \textit {\_Z} +1\right )^{2} x^{5}+126582 \operatorname {RootOf}\left (9 \textit {\_Z}^{2}+3 \textit {\_Z} +1\right ) x^{5}-25632 x^{5}+137820 \operatorname {RootOf}\left (9 \textit {\_Z}^{2}+3 \textit {\_Z} +1\right ) \left (x^{5}+1\right )^{\frac {2}{3}}-78769 \left (x^{5}+1\right )^{\frac {2}{3}}+137820 \operatorname {RootOf}\left (9 \textit {\_Z}^{2}+3 \textit {\_Z} +1\right ) \left (x^{5}+1\right )^{\frac {1}{3}}+132201 \operatorname {RootOf}\left (9 \textit {\_Z}^{2}+3 \textit {\_Z} +1\right )^{2}-78769 \left (x^{5}+1\right )^{\frac {1}{3}}+181887 \operatorname {RootOf}\left (9 \textit {\_Z}^{2}+3 \textit {\_Z} +1\right )-64080}{x^{5}}\right )}{5}\) | \(435\) |
-1/15/Pi*3^(1/2)*GAMMA(2/3)*(-2/3*Pi*3^(1/2)/GAMMA(2/3)*x^5*hypergeom([1/3 ,1,1],[2,2],-x^5)-(3/2-1/6*Pi*3^(1/2)-3/2*ln(3)+5*ln(x))*Pi*3^(1/2)/GAMMA( 2/3))
Time = 0.25 (sec) , antiderivative size = 65, normalized size of antiderivative = 0.75 \[ \int \frac {\left (1+x^5\right )^{2/3}}{x} \, dx=\frac {1}{5} \, \sqrt {3} \arctan \left (\frac {2}{3} \, \sqrt {3} {\left (x^{5} + 1\right )}^{\frac {1}{3}} + \frac {1}{3} \, \sqrt {3}\right ) + \frac {3}{10} \, {\left (x^{5} + 1\right )}^{\frac {2}{3}} - \frac {1}{10} \, \log \left ({\left (x^{5} + 1\right )}^{\frac {2}{3}} + {\left (x^{5} + 1\right )}^{\frac {1}{3}} + 1\right ) + \frac {1}{5} \, \log \left ({\left (x^{5} + 1\right )}^{\frac {1}{3}} - 1\right ) \]
1/5*sqrt(3)*arctan(2/3*sqrt(3)*(x^5 + 1)^(1/3) + 1/3*sqrt(3)) + 3/10*(x^5 + 1)^(2/3) - 1/10*log((x^5 + 1)^(2/3) + (x^5 + 1)^(1/3) + 1) + 1/5*log((x^ 5 + 1)^(1/3) - 1)
Result contains complex when optimal does not.
Time = 0.55 (sec) , antiderivative size = 37, normalized size of antiderivative = 0.43 \[ \int \frac {\left (1+x^5\right )^{2/3}}{x} \, dx=- \frac {x^{\frac {10}{3}} \Gamma \left (- \frac {2}{3}\right ) {{}_{2}F_{1}\left (\begin {matrix} - \frac {2}{3}, - \frac {2}{3} \\ \frac {1}{3} \end {matrix}\middle | {\frac {e^{i \pi }}{x^{5}}} \right )}}{5 \Gamma \left (\frac {1}{3}\right )} \]
Time = 0.28 (sec) , antiderivative size = 63, normalized size of antiderivative = 0.72 \[ \int \frac {\left (1+x^5\right )^{2/3}}{x} \, dx=\frac {1}{5} \, \sqrt {3} \arctan \left (\frac {1}{3} \, \sqrt {3} {\left (2 \, {\left (x^{5} + 1\right )}^{\frac {1}{3}} + 1\right )}\right ) + \frac {3}{10} \, {\left (x^{5} + 1\right )}^{\frac {2}{3}} - \frac {1}{10} \, \log \left ({\left (x^{5} + 1\right )}^{\frac {2}{3}} + {\left (x^{5} + 1\right )}^{\frac {1}{3}} + 1\right ) + \frac {1}{5} \, \log \left ({\left (x^{5} + 1\right )}^{\frac {1}{3}} - 1\right ) \]
1/5*sqrt(3)*arctan(1/3*sqrt(3)*(2*(x^5 + 1)^(1/3) + 1)) + 3/10*(x^5 + 1)^( 2/3) - 1/10*log((x^5 + 1)^(2/3) + (x^5 + 1)^(1/3) + 1) + 1/5*log((x^5 + 1) ^(1/3) - 1)
Time = 0.28 (sec) , antiderivative size = 64, normalized size of antiderivative = 0.74 \[ \int \frac {\left (1+x^5\right )^{2/3}}{x} \, dx=\frac {1}{5} \, \sqrt {3} \arctan \left (\frac {1}{3} \, \sqrt {3} {\left (2 \, {\left (x^{5} + 1\right )}^{\frac {1}{3}} + 1\right )}\right ) + \frac {3}{10} \, {\left (x^{5} + 1\right )}^{\frac {2}{3}} - \frac {1}{10} \, \log \left ({\left (x^{5} + 1\right )}^{\frac {2}{3}} + {\left (x^{5} + 1\right )}^{\frac {1}{3}} + 1\right ) + \frac {1}{5} \, \log \left ({\left | {\left (x^{5} + 1\right )}^{\frac {1}{3}} - 1 \right |}\right ) \]
1/5*sqrt(3)*arctan(1/3*sqrt(3)*(2*(x^5 + 1)^(1/3) + 1)) + 3/10*(x^5 + 1)^( 2/3) - 1/10*log((x^5 + 1)^(2/3) + (x^5 + 1)^(1/3) + 1) + 1/5*log(abs((x^5 + 1)^(1/3) - 1))
Time = 5.78 (sec) , antiderivative size = 89, normalized size of antiderivative = 1.02 \[ \int \frac {\left (1+x^5\right )^{2/3}}{x} \, dx=\frac {\ln \left (\frac {9\,{\left (x^5+1\right )}^{1/3}}{25}-\frac {9}{25}\right )}{5}+\ln \left (\frac {9\,{\left (x^5+1\right )}^{1/3}}{25}-9\,{\left (-\frac {1}{10}+\frac {\sqrt {3}\,1{}\mathrm {i}}{10}\right )}^2\right )\,\left (-\frac {1}{10}+\frac {\sqrt {3}\,1{}\mathrm {i}}{10}\right )-\ln \left (\frac {9\,{\left (x^5+1\right )}^{1/3}}{25}-9\,{\left (\frac {1}{10}+\frac {\sqrt {3}\,1{}\mathrm {i}}{10}\right )}^2\right )\,\left (\frac {1}{10}+\frac {\sqrt {3}\,1{}\mathrm {i}}{10}\right )+\frac {3\,{\left (x^5+1\right )}^{2/3}}{10} \]