Integrand size = 13, antiderivative size = 112 \[ \int \frac {x^{13}}{\sqrt [3]{1+x^6}} \, dx=\frac {1}{36} \left (1+x^6\right )^{2/3} \left (-4 x^2+3 x^8\right )+\frac {\arctan \left (\frac {\sqrt {3} x^2}{x^2+2 \sqrt [3]{1+x^6}}\right )}{9 \sqrt {3}}-\frac {1}{27} \log \left (-x^2+\sqrt [3]{1+x^6}\right )+\frac {1}{54} \log \left (x^4+x^2 \sqrt [3]{1+x^6}+\left (1+x^6\right )^{2/3}\right ) \]
1/36*(x^6+1)^(2/3)*(3*x^8-4*x^2)+1/27*arctan(3^(1/2)*x^2/(x^2+2*(x^6+1)^(1 /3)))*3^(1/2)-1/27*ln(-x^2+(x^6+1)^(1/3))+1/54*ln(x^4+x^2*(x^6+1)^(1/3)+(x ^6+1)^(2/3))
Time = 1.77 (sec) , antiderivative size = 107, normalized size of antiderivative = 0.96 \[ \int \frac {x^{13}}{\sqrt [3]{1+x^6}} \, dx=\frac {1}{108} \left (3 x^2 \left (1+x^6\right )^{2/3} \left (-4+3 x^6\right )+4 \sqrt {3} \arctan \left (\frac {\sqrt {3} x^2}{x^2+2 \sqrt [3]{1+x^6}}\right )-4 \log \left (-x^2+\sqrt [3]{1+x^6}\right )+2 \log \left (x^4+x^2 \sqrt [3]{1+x^6}+\left (1+x^6\right )^{2/3}\right )\right ) \]
(3*x^2*(1 + x^6)^(2/3)*(-4 + 3*x^6) + 4*Sqrt[3]*ArcTan[(Sqrt[3]*x^2)/(x^2 + 2*(1 + x^6)^(1/3))] - 4*Log[-x^2 + (1 + x^6)^(1/3)] + 2*Log[x^4 + x^2*(1 + x^6)^(1/3) + (1 + x^6)^(2/3)])/108
Time = 0.20 (sec) , antiderivative size = 97, normalized size of antiderivative = 0.87, number of steps used = 5, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.308, Rules used = {807, 843, 843, 769}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int \frac {x^{13}}{\sqrt [3]{x^6+1}} \, dx\) |
\(\Big \downarrow \) 807 |
\(\displaystyle \frac {1}{2} \int \frac {x^{12}}{\sqrt [3]{x^6+1}}dx^2\) |
\(\Big \downarrow \) 843 |
\(\displaystyle \frac {1}{2} \left (\frac {1}{6} x^8 \left (x^6+1\right )^{2/3}-\frac {2}{3} \int \frac {x^6}{\sqrt [3]{x^6+1}}dx^2\right )\) |
\(\Big \downarrow \) 843 |
\(\displaystyle \frac {1}{2} \left (\frac {1}{6} x^8 \left (x^6+1\right )^{2/3}-\frac {2}{3} \left (\frac {1}{3} x^2 \left (x^6+1\right )^{2/3}-\frac {1}{3} \int \frac {1}{\sqrt [3]{x^6+1}}dx^2\right )\right )\) |
\(\Big \downarrow \) 769 |
\(\displaystyle \frac {1}{2} \left (\frac {1}{6} x^8 \left (x^6+1\right )^{2/3}-\frac {2}{3} \left (\frac {1}{3} \left (\frac {1}{2} \log \left (\sqrt [3]{x^6+1}-x^2\right )-\frac {\arctan \left (\frac {\frac {2 x^2}{\sqrt [3]{x^6+1}}+1}{\sqrt {3}}\right )}{\sqrt {3}}\right )+\frac {1}{3} \left (x^6+1\right )^{2/3} x^2\right )\right )\) |
((x^8*(1 + x^6)^(2/3))/6 - (2*((x^2*(1 + x^6)^(2/3))/3 + (-(ArcTan[(1 + (2 *x^2)/(1 + x^6)^(1/3))/Sqrt[3]]/Sqrt[3]) + Log[-x^2 + (1 + x^6)^(1/3)]/2)/ 3))/3)/2
3.17.64.3.1 Defintions of rubi rules used
Int[((a_) + (b_.)*(x_)^3)^(-1/3), x_Symbol] :> Simp[ArcTan[(1 + 2*Rt[b, 3]* (x/(a + b*x^3)^(1/3)))/Sqrt[3]]/(Sqrt[3]*Rt[b, 3]), x] - Simp[Log[(a + b*x^ 3)^(1/3) - Rt[b, 3]*x]/(2*Rt[b, 3]), x] /; FreeQ[{a, b}, x]
Int[(x_)^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> With[{k = GCD[m + 1, n]}, Simp[1/k Subst[Int[x^((m + 1)/k - 1)*(a + b*x^(n/k))^p, x], x, x^k], x] /; k != 1] /; FreeQ[{a, b, p}, x] && IGtQ[n, 0] && IntegerQ[m]
Int[((c_.)*(x_))^(m_)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> Simp[c^(n - 1)*(c*x)^(m - n + 1)*((a + b*x^n)^(p + 1)/(b*(m + n*p + 1))), x] - Simp[ a*c^n*((m - n + 1)/(b*(m + n*p + 1))) Int[(c*x)^(m - n)*(a + b*x^n)^p, x] , x] /; FreeQ[{a, b, c, p}, x] && IGtQ[n, 0] && GtQ[m, n - 1] && NeQ[m + n* p + 1, 0] && IntBinomialQ[a, b, c, n, m, p, x]
Result contains higher order function than in optimal. Order 5 vs. order 3.
Time = 2.10 (sec) , antiderivative size = 17, normalized size of antiderivative = 0.15
method | result | size |
meijerg | \(\frac {x^{14} \operatorname {hypergeom}\left (\left [\frac {1}{3}, \frac {7}{3}\right ], \left [\frac {10}{3}\right ], -x^{6}\right )}{14}\) | \(17\) |
risch | \(\frac {x^{2} \left (3 x^{6}-4\right ) \left (x^{6}+1\right )^{\frac {2}{3}}}{36}+\frac {x^{2} \operatorname {hypergeom}\left (\left [\frac {1}{3}, \frac {1}{3}\right ], \left [\frac {4}{3}\right ], -x^{6}\right )}{9}\) | \(37\) |
pseudoelliptic | \(\frac {9 \left (x^{6}+1\right )^{\frac {2}{3}} x^{8}-12 x^{2} \left (x^{6}+1\right )^{\frac {2}{3}}-4 \sqrt {3}\, \arctan \left (\frac {\sqrt {3}\, \left (x^{2}+2 \left (x^{6}+1\right )^{\frac {1}{3}}\right )}{3 x^{2}}\right )+2 \ln \left (\frac {x^{4}+x^{2} \left (x^{6}+1\right )^{\frac {1}{3}}+\left (x^{6}+1\right )^{\frac {2}{3}}}{x^{4}}\right )-4 \ln \left (\frac {-x^{2}+\left (x^{6}+1\right )^{\frac {1}{3}}}{x^{2}}\right )}{108 \left (x^{4}+x^{2} \left (x^{6}+1\right )^{\frac {1}{3}}+\left (x^{6}+1\right )^{\frac {2}{3}}\right )^{2} \left (-x^{2}+\left (x^{6}+1\right )^{\frac {1}{3}}\right )^{2}}\) | \(143\) |
trager | \(\frac {x^{2} \left (3 x^{6}-4\right ) \left (x^{6}+1\right )^{\frac {2}{3}}}{36}-\frac {\ln \left (-2 \operatorname {RootOf}\left (\textit {\_Z}^{2}-\textit {\_Z} +1\right )^{2} x^{6}+5 \operatorname {RootOf}\left (\textit {\_Z}^{2}-\textit {\_Z} +1\right ) x^{6}-2 x^{6}-3 \operatorname {RootOf}\left (\textit {\_Z}^{2}-\textit {\_Z} +1\right ) \left (x^{6}+1\right )^{\frac {2}{3}} x^{2}-3 x^{4} \left (x^{6}+1\right )^{\frac {1}{3}}+3 x^{2} \left (x^{6}+1\right )^{\frac {2}{3}}+2 \operatorname {RootOf}\left (\textit {\_Z}^{2}-\textit {\_Z} +1\right )-1\right )}{27}+\frac {\operatorname {RootOf}\left (\textit {\_Z}^{2}-\textit {\_Z} +1\right ) \ln \left (\operatorname {RootOf}\left (\textit {\_Z}^{2}-\textit {\_Z} +1\right )^{2} x^{6}-\operatorname {RootOf}\left (\textit {\_Z}^{2}-\textit {\_Z} +1\right ) x^{6}-3 \operatorname {RootOf}\left (\textit {\_Z}^{2}-\textit {\_Z} +1\right ) \left (x^{6}+1\right )^{\frac {1}{3}} x^{4}-2 x^{6}+3 \operatorname {RootOf}\left (\textit {\_Z}^{2}-\textit {\_Z} +1\right ) \left (x^{6}+1\right )^{\frac {2}{3}} x^{2}+3 x^{4} \left (x^{6}+1\right )^{\frac {1}{3}}+\operatorname {RootOf}\left (\textit {\_Z}^{2}-\textit {\_Z} +1\right )-2\right )}{27}\) | \(228\) |
Time = 0.27 (sec) , antiderivative size = 102, normalized size of antiderivative = 0.91 \[ \int \frac {x^{13}}{\sqrt [3]{1+x^6}} \, dx=\frac {1}{36} \, {\left (3 \, x^{8} - 4 \, x^{2}\right )} {\left (x^{6} + 1\right )}^{\frac {2}{3}} - \frac {1}{27} \, \sqrt {3} \arctan \left (\frac {\sqrt {3} x^{2} + 2 \, \sqrt {3} {\left (x^{6} + 1\right )}^{\frac {1}{3}}}{3 \, x^{2}}\right ) - \frac {1}{27} \, \log \left (-\frac {x^{2} - {\left (x^{6} + 1\right )}^{\frac {1}{3}}}{x^{2}}\right ) + \frac {1}{54} \, \log \left (\frac {x^{4} + {\left (x^{6} + 1\right )}^{\frac {1}{3}} x^{2} + {\left (x^{6} + 1\right )}^{\frac {2}{3}}}{x^{4}}\right ) \]
1/36*(3*x^8 - 4*x^2)*(x^6 + 1)^(2/3) - 1/27*sqrt(3)*arctan(1/3*(sqrt(3)*x^ 2 + 2*sqrt(3)*(x^6 + 1)^(1/3))/x^2) - 1/27*log(-(x^2 - (x^6 + 1)^(1/3))/x^ 2) + 1/54*log((x^4 + (x^6 + 1)^(1/3)*x^2 + (x^6 + 1)^(2/3))/x^4)
Result contains complex when optimal does not.
Time = 1.72 (sec) , antiderivative size = 29, normalized size of antiderivative = 0.26 \[ \int \frac {x^{13}}{\sqrt [3]{1+x^6}} \, dx=\frac {x^{14} \Gamma \left (\frac {7}{3}\right ) {{}_{2}F_{1}\left (\begin {matrix} \frac {1}{3}, \frac {7}{3} \\ \frac {10}{3} \end {matrix}\middle | {x^{6} e^{i \pi }} \right )}}{6 \Gamma \left (\frac {10}{3}\right )} \]
Time = 0.26 (sec) , antiderivative size = 122, normalized size of antiderivative = 1.09 \[ \int \frac {x^{13}}{\sqrt [3]{1+x^6}} \, dx=-\frac {1}{27} \, \sqrt {3} \arctan \left (\frac {1}{3} \, \sqrt {3} {\left (\frac {2 \, {\left (x^{6} + 1\right )}^{\frac {1}{3}}}{x^{2}} + 1\right )}\right ) - \frac {\frac {7 \, {\left (x^{6} + 1\right )}^{\frac {2}{3}}}{x^{4}} - \frac {4 \, {\left (x^{6} + 1\right )}^{\frac {5}{3}}}{x^{10}}}{36 \, {\left (\frac {2 \, {\left (x^{6} + 1\right )}}{x^{6}} - \frac {{\left (x^{6} + 1\right )}^{2}}{x^{12}} - 1\right )}} + \frac {1}{54} \, \log \left (\frac {{\left (x^{6} + 1\right )}^{\frac {1}{3}}}{x^{2}} + \frac {{\left (x^{6} + 1\right )}^{\frac {2}{3}}}{x^{4}} + 1\right ) - \frac {1}{27} \, \log \left (\frac {{\left (x^{6} + 1\right )}^{\frac {1}{3}}}{x^{2}} - 1\right ) \]
-1/27*sqrt(3)*arctan(1/3*sqrt(3)*(2*(x^6 + 1)^(1/3)/x^2 + 1)) - 1/36*(7*(x ^6 + 1)^(2/3)/x^4 - 4*(x^6 + 1)^(5/3)/x^10)/(2*(x^6 + 1)/x^6 - (x^6 + 1)^2 /x^12 - 1) + 1/54*log((x^6 + 1)^(1/3)/x^2 + (x^6 + 1)^(2/3)/x^4 + 1) - 1/2 7*log((x^6 + 1)^(1/3)/x^2 - 1)
\[ \int \frac {x^{13}}{\sqrt [3]{1+x^6}} \, dx=\int { \frac {x^{13}}{{\left (x^{6} + 1\right )}^{\frac {1}{3}}} \,d x } \]
Timed out. \[ \int \frac {x^{13}}{\sqrt [3]{1+x^6}} \, dx=\int \frac {x^{13}}{{\left (x^6+1\right )}^{1/3}} \,d x \]