Integrand size = 29, antiderivative size = 131 \[ \int \frac {1+x^4}{\sqrt {-x-x^2+x^3} \left (-1+x^4\right )} \, dx=-\arctan \left (\frac {\sqrt {-x-x^2+x^3}}{-1-x+x^2}\right )-\frac {1}{2} \sqrt {\frac {1}{5}+\frac {2 i}{5}} \arctan \left (\frac {\sqrt {1-2 i} \sqrt {-x-x^2+x^3}}{-1-x+x^2}\right )-\frac {1}{2} \sqrt {\frac {1}{5}-\frac {2 i}{5}} \arctan \left (\frac {\sqrt {1+2 i} \sqrt {-x-x^2+x^3}}{-1-x+x^2}\right ) \]
-arctan((x^3-x^2-x)^(1/2)/(x^2-x-1))-1/10*(5+10*I)^(1/2)*arctan((1-2*I)^(1 /2)*(x^3-x^2-x)^(1/2)/(x^2-x-1))-1/10*(5-10*I)^(1/2)*arctan((1+2*I)^(1/2)* (x^3-x^2-x)^(1/2)/(x^2-x-1))
Time = 0.60 (sec) , antiderivative size = 135, normalized size of antiderivative = 1.03 \[ \int \frac {1+x^4}{\sqrt {-x-x^2+x^3} \left (-1+x^4\right )} \, dx=-\frac {\sqrt {x} \sqrt {-1-x+x^2} \left (2 \sqrt {5} \arctan \left (\frac {\sqrt {x}}{\sqrt {-1-x+x^2}}\right )+\sqrt {1+2 i} \arctan \left (\frac {\sqrt {1-2 i} \sqrt {x}}{\sqrt {-1-x+x^2}}\right )+\sqrt {1-2 i} \arctan \left (\frac {\sqrt {1+2 i} \sqrt {x}}{\sqrt {-1-x+x^2}}\right )\right )}{2 \sqrt {5} \sqrt {x \left (-1-x+x^2\right )}} \]
-1/2*(Sqrt[x]*Sqrt[-1 - x + x^2]*(2*Sqrt[5]*ArcTan[Sqrt[x]/Sqrt[-1 - x + x ^2]] + Sqrt[1 + 2*I]*ArcTan[(Sqrt[1 - 2*I]*Sqrt[x])/Sqrt[-1 - x + x^2]] + Sqrt[1 - 2*I]*ArcTan[(Sqrt[1 + 2*I]*Sqrt[x])/Sqrt[-1 - x + x^2]]))/(Sqrt[5 ]*Sqrt[x*(-1 - x + x^2)])
Result contains higher order function than in optimal. Order 4 vs. order 3 in optimal.
Time = 1.90 (sec) , antiderivative size = 980, normalized size of antiderivative = 7.48, number of steps used = 6, number of rules used = 5, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.172, Rules used = {2467, 25, 2035, 7276, 2009}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int \frac {x^4+1}{\sqrt {x^3-x^2-x} \left (x^4-1\right )} \, dx\) |
\(\Big \downarrow \) 2467 |
\(\displaystyle \frac {\sqrt {x} \sqrt {x^2-x-1} \int -\frac {x^4+1}{\sqrt {x} \sqrt {x^2-x-1} \left (1-x^4\right )}dx}{\sqrt {x^3-x^2-x}}\) |
\(\Big \downarrow \) 25 |
\(\displaystyle -\frac {\sqrt {x} \sqrt {x^2-x-1} \int \frac {x^4+1}{\sqrt {x} \sqrt {x^2-x-1} \left (1-x^4\right )}dx}{\sqrt {x^3-x^2-x}}\) |
\(\Big \downarrow \) 2035 |
\(\displaystyle -\frac {2 \sqrt {x} \sqrt {x^2-x-1} \int \frac {x^4+1}{\sqrt {x^2-x-1} \left (1-x^4\right )}d\sqrt {x}}{\sqrt {x^3-x^2-x}}\) |
\(\Big \downarrow \) 7276 |
\(\displaystyle -\frac {2 \sqrt {x} \sqrt {x^2-x-1} \int \left (\frac {2}{\sqrt {x^2-x-1} \left (1-x^4\right )}-\frac {1}{\sqrt {x^2-x-1}}\right )d\sqrt {x}}{\sqrt {x^3-x^2-x}}\) |
\(\Big \downarrow \) 2009 |
\(\displaystyle -\frac {2 \sqrt {x} \sqrt {x^2-x-1} \left (\frac {\arctan \left (\frac {\sqrt {1-2 i} \sqrt {x}}{\sqrt {x^2-x-1}}\right )}{4 \sqrt {1-2 i}}+\frac {\arctan \left (\frac {\sqrt {1+2 i} \sqrt {x}}{\sqrt {x^2-x-1}}\right )}{4 \sqrt {1+2 i}}-\frac {\left (1+\sqrt {5}\right ) \sqrt {2 x+\sqrt {5}-1} \sqrt {1-\frac {2 x}{1+\sqrt {5}}} \operatorname {EllipticF}\left (\arcsin \left (\sqrt {\frac {2}{1+\sqrt {5}}} \sqrt {x}\right ),\frac {1}{2} \left (-3-\sqrt {5}\right )\right )}{2 \sqrt {2} \left (3+\sqrt {5}\right ) \sqrt {x^2-x-1}}-\frac {\left (1+\sqrt {5}\right ) \sqrt {2 x+\sqrt {5}-1} \sqrt {1-\frac {2 x}{1+\sqrt {5}}} \operatorname {EllipticF}\left (\arcsin \left (\sqrt {\frac {2}{1+\sqrt {5}}} \sqrt {x}\right ),\frac {1}{2} \left (-3-\sqrt {5}\right )\right )}{2 \sqrt {2} \left (1-\sqrt {5}\right ) \sqrt {x^2-x-1}}+\frac {\sqrt {-\left (\left (1-\sqrt {5}\right ) x\right )-2} \sqrt {\frac {\left (1+\sqrt {5}\right ) x+2}{\left (1-\sqrt {5}\right ) x+2}} \operatorname {EllipticF}\left (\arcsin \left (\frac {\sqrt {2} \sqrt [4]{5} \sqrt {x}}{\sqrt {-\left (\left (1-\sqrt {5}\right ) x\right )-2}}\right ),\frac {1}{10} \left (5-\sqrt {5}\right )\right )}{2 \sqrt [4]{5} \left (3+\sqrt {5}\right ) \sqrt {\frac {1}{\left (1-\sqrt {5}\right ) x+2}} \sqrt {x^2-x-1}}+\frac {\sqrt {-\left (\left (1-\sqrt {5}\right ) x\right )-2} \sqrt {\frac {\left (1+\sqrt {5}\right ) x+2}{\left (1-\sqrt {5}\right ) x+2}} \operatorname {EllipticF}\left (\arcsin \left (\frac {\sqrt {2} \sqrt [4]{5} \sqrt {x}}{\sqrt {-\left (\left (1-\sqrt {5}\right ) x\right )-2}}\right ),\frac {1}{10} \left (5-\sqrt {5}\right )\right )}{2 \sqrt [4]{5} \left (1-\sqrt {5}\right ) \sqrt {\frac {1}{\left (1-\sqrt {5}\right ) x+2}} \sqrt {x^2-x-1}}-\frac {\sqrt {-\left (\left (1-\sqrt {5}\right ) x\right )-2} \sqrt {\frac {\left (1+\sqrt {5}\right ) x+2}{\left (1-\sqrt {5}\right ) x+2}} \operatorname {EllipticF}\left (\arcsin \left (\frac {\sqrt {2} \sqrt [4]{5} \sqrt {x}}{\sqrt {-\left (\left (1-\sqrt {5}\right ) x\right )-2}}\right ),\frac {1}{10} \left (5-\sqrt {5}\right )\right )}{4 \sqrt [4]{5} \sqrt {\frac {1}{\left (1-\sqrt {5}\right ) x+2}} \sqrt {x^2-x-1}}+\frac {\left (2+\sqrt {5}\right ) \sqrt {2 x+\sqrt {5}-1} \sqrt {1-\frac {2 x}{1+\sqrt {5}}} \operatorname {EllipticPi}\left (\frac {1}{2} \left (-1-\sqrt {5}\right ),\arcsin \left (\sqrt {\frac {2}{1+\sqrt {5}}} \sqrt {x}\right ),\frac {1}{2} \left (-3-\sqrt {5}\right )\right )}{\sqrt {2} \left (3+\sqrt {5}\right ) \sqrt {x^2-x-1}}-\frac {\sqrt {2 x+\sqrt {5}-1} \sqrt {1-\frac {2 x}{1+\sqrt {5}}} \operatorname {EllipticPi}\left (\frac {1}{2} \left (1+\sqrt {5}\right ),\arcsin \left (\sqrt {\frac {2}{1+\sqrt {5}}} \sqrt {x}\right ),\frac {1}{2} \left (-3-\sqrt {5}\right )\right )}{\sqrt {2} \left (1-\sqrt {5}\right ) \sqrt {x^2-x-1}}\right )}{\sqrt {x^3-x^2-x}}\) |
(-2*Sqrt[x]*Sqrt[-1 - x + x^2]*(ArcTan[(Sqrt[1 - 2*I]*Sqrt[x])/Sqrt[-1 - x + x^2]]/(4*Sqrt[1 - 2*I]) + ArcTan[(Sqrt[1 + 2*I]*Sqrt[x])/Sqrt[-1 - x + x^2]]/(4*Sqrt[1 + 2*I]) - ((1 + Sqrt[5])*Sqrt[-1 + Sqrt[5] + 2*x]*Sqrt[1 - (2*x)/(1 + Sqrt[5])]*EllipticF[ArcSin[Sqrt[2/(1 + Sqrt[5])]*Sqrt[x]], (-3 - Sqrt[5])/2])/(2*Sqrt[2]*(1 - Sqrt[5])*Sqrt[-1 - x + x^2]) - ((1 + Sqrt[ 5])*Sqrt[-1 + Sqrt[5] + 2*x]*Sqrt[1 - (2*x)/(1 + Sqrt[5])]*EllipticF[ArcSi n[Sqrt[2/(1 + Sqrt[5])]*Sqrt[x]], (-3 - Sqrt[5])/2])/(2*Sqrt[2]*(3 + Sqrt[ 5])*Sqrt[-1 - x + x^2]) - (Sqrt[-2 - (1 - Sqrt[5])*x]*Sqrt[(2 + (1 + Sqrt[ 5])*x)/(2 + (1 - Sqrt[5])*x)]*EllipticF[ArcSin[(Sqrt[2]*5^(1/4)*Sqrt[x])/S qrt[-2 - (1 - Sqrt[5])*x]], (5 - Sqrt[5])/10])/(4*5^(1/4)*Sqrt[(2 + (1 - S qrt[5])*x)^(-1)]*Sqrt[-1 - x + x^2]) + (Sqrt[-2 - (1 - Sqrt[5])*x]*Sqrt[(2 + (1 + Sqrt[5])*x)/(2 + (1 - Sqrt[5])*x)]*EllipticF[ArcSin[(Sqrt[2]*5^(1/ 4)*Sqrt[x])/Sqrt[-2 - (1 - Sqrt[5])*x]], (5 - Sqrt[5])/10])/(2*5^(1/4)*(1 - Sqrt[5])*Sqrt[(2 + (1 - Sqrt[5])*x)^(-1)]*Sqrt[-1 - x + x^2]) + (Sqrt[-2 - (1 - Sqrt[5])*x]*Sqrt[(2 + (1 + Sqrt[5])*x)/(2 + (1 - Sqrt[5])*x)]*Elli pticF[ArcSin[(Sqrt[2]*5^(1/4)*Sqrt[x])/Sqrt[-2 - (1 - Sqrt[5])*x]], (5 - S qrt[5])/10])/(2*5^(1/4)*(3 + Sqrt[5])*Sqrt[(2 + (1 - Sqrt[5])*x)^(-1)]*Sqr t[-1 - x + x^2]) + ((2 + Sqrt[5])*Sqrt[-1 + Sqrt[5] + 2*x]*Sqrt[1 - (2*x)/ (1 + Sqrt[5])]*EllipticPi[(-1 - Sqrt[5])/2, ArcSin[Sqrt[2/(1 + Sqrt[5])]*S qrt[x]], (-3 - Sqrt[5])/2])/(Sqrt[2]*(3 + Sqrt[5])*Sqrt[-1 - x + x^2]) ...
3.19.91.3.1 Defintions of rubi rules used
Int[(Fx_)*(x_)^(m_), x_Symbol] :> With[{k = Denominator[m]}, Simp[k Subst [Int[x^(k*(m + 1) - 1)*SubstPower[Fx, x, k], x], x, x^(1/k)], x]] /; Fracti onQ[m] && AlgebraicFunctionQ[Fx, x]
Int[(Fx_.)*(Px_)^(p_), x_Symbol] :> With[{r = Expon[Px, x, Min]}, Simp[Px^F racPart[p]/(x^(r*FracPart[p])*ExpandToSum[Px/x^r, x]^FracPart[p]) Int[x^( p*r)*ExpandToSum[Px/x^r, x]^p*Fx, x], x] /; IGtQ[r, 0]] /; FreeQ[p, x] && P olyQ[Px, x] && !IntegerQ[p] && !MonomialQ[Px, x] && !PolyQ[Fx, x]
Int[(u_)/((a_) + (b_.)*(x_)^(n_)), x_Symbol] :> With[{v = RationalFunctionE xpand[u/(a + b*x^n), x]}, Int[v, x] /; SumQ[v]] /; FreeQ[{a, b}, x] && IGtQ [n, 0]
Leaf count of result is larger than twice the leaf count of optimal. \(224\) vs. \(2(105)=210\).
Time = 6.07 (sec) , antiderivative size = 225, normalized size of antiderivative = 1.72
method | result | size |
default | \(-\frac {-\sqrt {5}\, \ln \left (\frac {-\sqrt {x \left (x^{2}-x -1\right )}\, \sqrt {-2+2 \sqrt {5}}+x \sqrt {5}+x^{2}-x -1}{x}\right )+\sqrt {5}\, \ln \left (\frac {\sqrt {x \left (x^{2}-x -1\right )}\, \sqrt {-2+2 \sqrt {5}}+x \sqrt {5}+x^{2}-x -1}{x}\right )+\left (-5-\sqrt {5}\right ) \arctan \left (\frac {\sqrt {-2+2 \sqrt {5}}\, x +2 \sqrt {x \left (x^{2}-x -1\right )}}{x \sqrt {2+2 \sqrt {5}}}\right )-10 \arctan \left (\frac {\sqrt {x \left (x^{2}-x -1\right )}}{x}\right ) \sqrt {2+2 \sqrt {5}}+\left (5+\sqrt {5}\right ) \arctan \left (\frac {\sqrt {-2+2 \sqrt {5}}\, x -2 \sqrt {x \left (x^{2}-x -1\right )}}{x \sqrt {2+2 \sqrt {5}}}\right )}{10 \sqrt {2+2 \sqrt {5}}}\) | \(225\) |
pseudoelliptic | \(-\frac {-\sqrt {5}\, \ln \left (\frac {-\sqrt {x \left (x^{2}-x -1\right )}\, \sqrt {-2+2 \sqrt {5}}+x \sqrt {5}+x^{2}-x -1}{x}\right )+\sqrt {5}\, \ln \left (\frac {\sqrt {x \left (x^{2}-x -1\right )}\, \sqrt {-2+2 \sqrt {5}}+x \sqrt {5}+x^{2}-x -1}{x}\right )+\left (-5-\sqrt {5}\right ) \arctan \left (\frac {\sqrt {-2+2 \sqrt {5}}\, x +2 \sqrt {x \left (x^{2}-x -1\right )}}{x \sqrt {2+2 \sqrt {5}}}\right )-10 \arctan \left (\frac {\sqrt {x \left (x^{2}-x -1\right )}}{x}\right ) \sqrt {2+2 \sqrt {5}}+\left (5+\sqrt {5}\right ) \arctan \left (\frac {\sqrt {-2+2 \sqrt {5}}\, x -2 \sqrt {x \left (x^{2}-x -1\right )}}{x \sqrt {2+2 \sqrt {5}}}\right )}{10 \sqrt {2+2 \sqrt {5}}}\) | \(225\) |
trager | \(\text {Expression too large to display}\) | \(915\) |
elliptic | \(\text {Expression too large to display}\) | \(1685\) |
-1/10/(2+2*5^(1/2))^(1/2)*(-5^(1/2)*ln((-(x*(x^2-x-1))^(1/2)*(-2+2*5^(1/2) )^(1/2)+x*5^(1/2)+x^2-x-1)/x)+5^(1/2)*ln(((x*(x^2-x-1))^(1/2)*(-2+2*5^(1/2 ))^(1/2)+x*5^(1/2)+x^2-x-1)/x)+(-5-5^(1/2))*arctan(((-2+2*5^(1/2))^(1/2)*x +2*(x*(x^2-x-1))^(1/2))/x/(2+2*5^(1/2))^(1/2))-10*arctan((x*(x^2-x-1))^(1/ 2)/x)*(2+2*5^(1/2))^(1/2)+(5+5^(1/2))*arctan(((-2+2*5^(1/2))^(1/2)*x-2*(x* (x^2-x-1))^(1/2))/x/(2+2*5^(1/2))^(1/2)))
Both result and optimal contain complex but leaf count of result is larger than twice the leaf count of optimal. 324 vs. \(2 (97) = 194\).
Time = 0.34 (sec) , antiderivative size = 324, normalized size of antiderivative = 2.47 \[ \int \frac {1+x^4}{\sqrt {-x-x^2+x^3} \left (-1+x^4\right )} \, dx=-\frac {1}{40} \, \sqrt {5} \sqrt {-2 i - 1} \log \left (\frac {5 \, x^{4} + \left (20 i - 10\right ) \, x^{3} - 2 \, \sqrt {5} \sqrt {-2 i - 1} \sqrt {x^{3} - x^{2} - x} {\left (-\left (2 i - 1\right ) \, x^{2} + \left (2 i + 4\right ) \, x + 2 i - 1\right )} - \left (20 i + 30\right ) \, x^{2} - \left (20 i - 10\right ) \, x + 5}{x^{4} + 2 \, x^{2} + 1}\right ) + \frac {1}{40} \, \sqrt {5} \sqrt {-2 i - 1} \log \left (\frac {5 \, x^{4} + \left (20 i - 10\right ) \, x^{3} - 2 \, \sqrt {5} \sqrt {-2 i - 1} \sqrt {x^{3} - x^{2} - x} {\left (\left (2 i - 1\right ) \, x^{2} - \left (2 i + 4\right ) \, x - 2 i + 1\right )} - \left (20 i + 30\right ) \, x^{2} - \left (20 i - 10\right ) \, x + 5}{x^{4} + 2 \, x^{2} + 1}\right ) - \frac {1}{40} \, \sqrt {5} \sqrt {2 i - 1} \log \left (\frac {5 \, x^{4} - \left (20 i + 10\right ) \, x^{3} - 2 \, \sqrt {5} \sqrt {2 i - 1} \sqrt {x^{3} - x^{2} - x} {\left (\left (2 i + 1\right ) \, x^{2} - \left (2 i - 4\right ) \, x - 2 i - 1\right )} + \left (20 i - 30\right ) \, x^{2} + \left (20 i + 10\right ) \, x + 5}{x^{4} + 2 \, x^{2} + 1}\right ) + \frac {1}{40} \, \sqrt {5} \sqrt {2 i - 1} \log \left (\frac {5 \, x^{4} - \left (20 i + 10\right ) \, x^{3} - 2 \, \sqrt {5} \sqrt {2 i - 1} \sqrt {x^{3} - x^{2} - x} {\left (-\left (2 i + 1\right ) \, x^{2} + \left (2 i - 4\right ) \, x + 2 i + 1\right )} + \left (20 i - 30\right ) \, x^{2} + \left (20 i + 10\right ) \, x + 5}{x^{4} + 2 \, x^{2} + 1}\right ) + \frac {1}{2} \, \arctan \left (\frac {x^{2} - 2 \, x - 1}{2 \, \sqrt {x^{3} - x^{2} - x}}\right ) \]
-1/40*sqrt(5)*sqrt(-2*I - 1)*log((5*x^4 + (20*I - 10)*x^3 - 2*sqrt(5)*sqrt (-2*I - 1)*sqrt(x^3 - x^2 - x)*(-(2*I - 1)*x^2 + (2*I + 4)*x + 2*I - 1) - (20*I + 30)*x^2 - (20*I - 10)*x + 5)/(x^4 + 2*x^2 + 1)) + 1/40*sqrt(5)*sqr t(-2*I - 1)*log((5*x^4 + (20*I - 10)*x^3 - 2*sqrt(5)*sqrt(-2*I - 1)*sqrt(x ^3 - x^2 - x)*((2*I - 1)*x^2 - (2*I + 4)*x - 2*I + 1) - (20*I + 30)*x^2 - (20*I - 10)*x + 5)/(x^4 + 2*x^2 + 1)) - 1/40*sqrt(5)*sqrt(2*I - 1)*log((5* x^4 - (20*I + 10)*x^3 - 2*sqrt(5)*sqrt(2*I - 1)*sqrt(x^3 - x^2 - x)*((2*I + 1)*x^2 - (2*I - 4)*x - 2*I - 1) + (20*I - 30)*x^2 + (20*I + 10)*x + 5)/( x^4 + 2*x^2 + 1)) + 1/40*sqrt(5)*sqrt(2*I - 1)*log((5*x^4 - (20*I + 10)*x^ 3 - 2*sqrt(5)*sqrt(2*I - 1)*sqrt(x^3 - x^2 - x)*(-(2*I + 1)*x^2 + (2*I - 4 )*x + 2*I + 1) + (20*I - 30)*x^2 + (20*I + 10)*x + 5)/(x^4 + 2*x^2 + 1)) + 1/2*arctan(1/2*(x^2 - 2*x - 1)/sqrt(x^3 - x^2 - x))
\[ \int \frac {1+x^4}{\sqrt {-x-x^2+x^3} \left (-1+x^4\right )} \, dx=\int \frac {x^{4} + 1}{\sqrt {x \left (x^{2} - x - 1\right )} \left (x - 1\right ) \left (x + 1\right ) \left (x^{2} + 1\right )}\, dx \]
\[ \int \frac {1+x^4}{\sqrt {-x-x^2+x^3} \left (-1+x^4\right )} \, dx=\int { \frac {x^{4} + 1}{{\left (x^{4} - 1\right )} \sqrt {x^{3} - x^{2} - x}} \,d x } \]
\[ \int \frac {1+x^4}{\sqrt {-x-x^2+x^3} \left (-1+x^4\right )} \, dx=\int { \frac {x^{4} + 1}{{\left (x^{4} - 1\right )} \sqrt {x^{3} - x^{2} - x}} \,d x } \]
Time = 5.37 (sec) , antiderivative size = 658, normalized size of antiderivative = 5.02 \[ \int \frac {1+x^4}{\sqrt {-x-x^2+x^3} \left (-1+x^4\right )} \, dx=\frac {2\,\left (\frac {\sqrt {5}}{2}+\frac {1}{2}\right )\,\sqrt {\frac {x}{\frac {\sqrt {5}}{2}+\frac {1}{2}}}\,\sqrt {\frac {x+\frac {\sqrt {5}}{2}-\frac {1}{2}}{\frac {\sqrt {5}}{2}-\frac {1}{2}}}\,\mathrm {F}\left (\mathrm {asin}\left (\sqrt {\frac {x}{\frac {\sqrt {5}}{2}+\frac {1}{2}}}\right )\middle |-\frac {\frac {\sqrt {5}}{2}+\frac {1}{2}}{\frac {\sqrt {5}}{2}-\frac {1}{2}}\right )\,\sqrt {\frac {\frac {\sqrt {5}}{2}-x+\frac {1}{2}}{\frac {\sqrt {5}}{2}+\frac {1}{2}}}}{\sqrt {x^3-x^2-\left (\frac {\sqrt {5}}{2}-\frac {1}{2}\right )\,\left (\frac {\sqrt {5}}{2}+\frac {1}{2}\right )\,x}}-\frac {\left (\frac {\sqrt {5}}{2}+\frac {1}{2}\right )\,\sqrt {\frac {x}{\frac {\sqrt {5}}{2}+\frac {1}{2}}}\,\sqrt {\frac {x+\frac {\sqrt {5}}{2}-\frac {1}{2}}{\frac {\sqrt {5}}{2}-\frac {1}{2}}}\,\sqrt {\frac {\frac {\sqrt {5}}{2}-x+\frac {1}{2}}{\frac {\sqrt {5}}{2}+\frac {1}{2}}}\,\Pi \left (-\frac {\sqrt {5}}{2}-\frac {1}{2};\mathrm {asin}\left (\sqrt {\frac {x}{\frac {\sqrt {5}}{2}+\frac {1}{2}}}\right )\middle |-\frac {\frac {\sqrt {5}}{2}+\frac {1}{2}}{\frac {\sqrt {5}}{2}-\frac {1}{2}}\right )}{\sqrt {x^3-x^2-\left (\frac {\sqrt {5}}{2}-\frac {1}{2}\right )\,\left (\frac {\sqrt {5}}{2}+\frac {1}{2}\right )\,x}}-\frac {\left (\frac {\sqrt {5}}{2}+\frac {1}{2}\right )\,\sqrt {\frac {x}{\frac {\sqrt {5}}{2}+\frac {1}{2}}}\,\sqrt {\frac {x+\frac {\sqrt {5}}{2}-\frac {1}{2}}{\frac {\sqrt {5}}{2}-\frac {1}{2}}}\,\sqrt {\frac {\frac {\sqrt {5}}{2}-x+\frac {1}{2}}{\frac {\sqrt {5}}{2}+\frac {1}{2}}}\,\Pi \left (\frac {\sqrt {5}}{2}+\frac {1}{2};\mathrm {asin}\left (\sqrt {\frac {x}{\frac {\sqrt {5}}{2}+\frac {1}{2}}}\right )\middle |-\frac {\frac {\sqrt {5}}{2}+\frac {1}{2}}{\frac {\sqrt {5}}{2}-\frac {1}{2}}\right )}{\sqrt {x^3-x^2-\left (\frac {\sqrt {5}}{2}-\frac {1}{2}\right )\,\left (\frac {\sqrt {5}}{2}+\frac {1}{2}\right )\,x}}-\frac {\left (\frac {\sqrt {5}}{2}+\frac {1}{2}\right )\,\sqrt {\frac {x}{\frac {\sqrt {5}}{2}+\frac {1}{2}}}\,\sqrt {\frac {x+\frac {\sqrt {5}}{2}-\frac {1}{2}}{\frac {\sqrt {5}}{2}-\frac {1}{2}}}\,\sqrt {\frac {\frac {\sqrt {5}}{2}-x+\frac {1}{2}}{\frac {\sqrt {5}}{2}+\frac {1}{2}}}\,\Pi \left (-\frac {\sqrt {5}\,1{}\mathrm {i}}{2}-\frac {1}{2}{}\mathrm {i};\mathrm {asin}\left (\sqrt {\frac {x}{\frac {\sqrt {5}}{2}+\frac {1}{2}}}\right )\middle |-\frac {\frac {\sqrt {5}}{2}+\frac {1}{2}}{\frac {\sqrt {5}}{2}-\frac {1}{2}}\right )}{\sqrt {x^3-x^2-\left (\frac {\sqrt {5}}{2}-\frac {1}{2}\right )\,\left (\frac {\sqrt {5}}{2}+\frac {1}{2}\right )\,x}}-\frac {\left (\frac {\sqrt {5}}{2}+\frac {1}{2}\right )\,\sqrt {\frac {x}{\frac {\sqrt {5}}{2}+\frac {1}{2}}}\,\sqrt {\frac {x+\frac {\sqrt {5}}{2}-\frac {1}{2}}{\frac {\sqrt {5}}{2}-\frac {1}{2}}}\,\sqrt {\frac {\frac {\sqrt {5}}{2}-x+\frac {1}{2}}{\frac {\sqrt {5}}{2}+\frac {1}{2}}}\,\Pi \left (\frac {\sqrt {5}\,1{}\mathrm {i}}{2}+\frac {1}{2}{}\mathrm {i};\mathrm {asin}\left (\sqrt {\frac {x}{\frac {\sqrt {5}}{2}+\frac {1}{2}}}\right )\middle |-\frac {\frac {\sqrt {5}}{2}+\frac {1}{2}}{\frac {\sqrt {5}}{2}-\frac {1}{2}}\right )}{\sqrt {x^3-x^2-\left (\frac {\sqrt {5}}{2}-\frac {1}{2}\right )\,\left (\frac {\sqrt {5}}{2}+\frac {1}{2}\right )\,x}} \]
(2*(5^(1/2)/2 + 1/2)*(x/(5^(1/2)/2 + 1/2))^(1/2)*((x + 5^(1/2)/2 - 1/2)/(5 ^(1/2)/2 - 1/2))^(1/2)*ellipticF(asin((x/(5^(1/2)/2 + 1/2))^(1/2)), -(5^(1 /2)/2 + 1/2)/(5^(1/2)/2 - 1/2))*((5^(1/2)/2 - x + 1/2)/(5^(1/2)/2 + 1/2))^ (1/2))/(x^3 - x^2 - x*(5^(1/2)/2 - 1/2)*(5^(1/2)/2 + 1/2))^(1/2) - ((5^(1/ 2)/2 + 1/2)*(x/(5^(1/2)/2 + 1/2))^(1/2)*((x + 5^(1/2)/2 - 1/2)/(5^(1/2)/2 - 1/2))^(1/2)*((5^(1/2)/2 - x + 1/2)/(5^(1/2)/2 + 1/2))^(1/2)*ellipticPi(- 5^(1/2)/2 - 1/2, asin((x/(5^(1/2)/2 + 1/2))^(1/2)), -(5^(1/2)/2 + 1/2)/(5 ^(1/2)/2 - 1/2)))/(x^3 - x^2 - x*(5^(1/2)/2 - 1/2)*(5^(1/2)/2 + 1/2))^(1/2 ) - ((5^(1/2)/2 + 1/2)*(x/(5^(1/2)/2 + 1/2))^(1/2)*((x + 5^(1/2)/2 - 1/2)/ (5^(1/2)/2 - 1/2))^(1/2)*((5^(1/2)/2 - x + 1/2)/(5^(1/2)/2 + 1/2))^(1/2)*e llipticPi(5^(1/2)/2 + 1/2, asin((x/(5^(1/2)/2 + 1/2))^(1/2)), -(5^(1/2)/2 + 1/2)/(5^(1/2)/2 - 1/2)))/(x^3 - x^2 - x*(5^(1/2)/2 - 1/2)*(5^(1/2)/2 + 1 /2))^(1/2) - ((5^(1/2)/2 + 1/2)*(x/(5^(1/2)/2 + 1/2))^(1/2)*((x + 5^(1/2)/ 2 - 1/2)/(5^(1/2)/2 - 1/2))^(1/2)*((5^(1/2)/2 - x + 1/2)/(5^(1/2)/2 + 1/2) )^(1/2)*ellipticPi(- (5^(1/2)*1i)/2 - 1i/2, asin((x/(5^(1/2)/2 + 1/2))^(1/ 2)), -(5^(1/2)/2 + 1/2)/(5^(1/2)/2 - 1/2)))/(x^3 - x^2 - x*(5^(1/2)/2 - 1/ 2)*(5^(1/2)/2 + 1/2))^(1/2) - ((5^(1/2)/2 + 1/2)*(x/(5^(1/2)/2 + 1/2))^(1/ 2)*((x + 5^(1/2)/2 - 1/2)/(5^(1/2)/2 - 1/2))^(1/2)*((5^(1/2)/2 - x + 1/2)/ (5^(1/2)/2 + 1/2))^(1/2)*ellipticPi((5^(1/2)*1i)/2 + 1i/2, asin((x/(5^(1/2 )/2 + 1/2))^(1/2)), -(5^(1/2)/2 + 1/2)/(5^(1/2)/2 - 1/2)))/(x^3 - x^2 -...