3.25.39 \(\int \frac {x^2 \sqrt [4]{b x^3+a x^4}}{-b+a x} \, dx\) [2439]

3.25.39.1 Optimal result
3.25.39.2 Mathematica [A] (verified)
3.25.39.3 Rubi [A] (verified)
3.25.39.4 Maple [A] (verified)
3.25.39.5 Fricas [C] (verification not implemented)
3.25.39.6 Sympy [F]
3.25.39.7 Maxima [F]
3.25.39.8 Giac [B] (verification not implemented)
3.25.39.9 Mupad [F(-1)]

3.25.39.1 Optimal result

Integrand size = 28, antiderivative size = 198 \[ \int \frac {x^2 \sqrt [4]{b x^3+a x^4}}{-b+a x} \, dx=\frac {\left (101 b^2+52 a b x+32 a^2 x^2\right ) \sqrt [4]{b x^3+a x^4}}{96 a^3}-\frac {155 b^3 \arctan \left (\frac {\sqrt [4]{a} x}{\sqrt [4]{b x^3+a x^4}}\right )}{64 a^{15/4}}+\frac {2 \sqrt [4]{2} b^3 \arctan \left (\frac {\sqrt [4]{2} \sqrt [4]{a} x}{\sqrt [4]{b x^3+a x^4}}\right )}{a^{15/4}}+\frac {155 b^3 \text {arctanh}\left (\frac {\sqrt [4]{a} x}{\sqrt [4]{b x^3+a x^4}}\right )}{64 a^{15/4}}-\frac {2 \sqrt [4]{2} b^3 \text {arctanh}\left (\frac {\sqrt [4]{2} \sqrt [4]{a} x}{\sqrt [4]{b x^3+a x^4}}\right )}{a^{15/4}} \]

output
1/96*(32*a^2*x^2+52*a*b*x+101*b^2)*(a*x^4+b*x^3)^(1/4)/a^3-155/64*b^3*arct 
an(a^(1/4)*x/(a*x^4+b*x^3)^(1/4))/a^(15/4)+2*2^(1/4)*b^3*arctan(2^(1/4)*a^ 
(1/4)*x/(a*x^4+b*x^3)^(1/4))/a^(15/4)+155/64*b^3*arctanh(a^(1/4)*x/(a*x^4+ 
b*x^3)^(1/4))/a^(15/4)-2*2^(1/4)*b^3*arctanh(2^(1/4)*a^(1/4)*x/(a*x^4+b*x^ 
3)^(1/4))/a^(15/4)
 
3.25.39.2 Mathematica [A] (verified)

Time = 0.81 (sec) , antiderivative size = 228, normalized size of antiderivative = 1.15 \[ \int \frac {x^2 \sqrt [4]{b x^3+a x^4}}{-b+a x} \, dx=\frac {x^{9/4} (b+a x)^{3/4} \left (202 a^{3/4} b^2 x^{3/4} \sqrt [4]{b+a x}+104 a^{7/4} b x^{7/4} \sqrt [4]{b+a x}+64 a^{11/4} x^{11/4} \sqrt [4]{b+a x}-465 b^3 \arctan \left (\frac {\sqrt [4]{a} \sqrt [4]{x}}{\sqrt [4]{b+a x}}\right )+384 \sqrt [4]{2} b^3 \arctan \left (\frac {\sqrt [4]{2} \sqrt [4]{a} \sqrt [4]{x}}{\sqrt [4]{b+a x}}\right )+465 b^3 \text {arctanh}\left (\frac {\sqrt [4]{a} \sqrt [4]{x}}{\sqrt [4]{b+a x}}\right )-384 \sqrt [4]{2} b^3 \text {arctanh}\left (\frac {\sqrt [4]{2} \sqrt [4]{a} \sqrt [4]{x}}{\sqrt [4]{b+a x}}\right )\right )}{192 a^{15/4} \left (x^3 (b+a x)\right )^{3/4}} \]

input
Integrate[(x^2*(b*x^3 + a*x^4)^(1/4))/(-b + a*x),x]
 
output
(x^(9/4)*(b + a*x)^(3/4)*(202*a^(3/4)*b^2*x^(3/4)*(b + a*x)^(1/4) + 104*a^ 
(7/4)*b*x^(7/4)*(b + a*x)^(1/4) + 64*a^(11/4)*x^(11/4)*(b + a*x)^(1/4) - 4 
65*b^3*ArcTan[(a^(1/4)*x^(1/4))/(b + a*x)^(1/4)] + 384*2^(1/4)*b^3*ArcTan[ 
(2^(1/4)*a^(1/4)*x^(1/4))/(b + a*x)^(1/4)] + 465*b^3*ArcTanh[(a^(1/4)*x^(1 
/4))/(b + a*x)^(1/4)] - 384*2^(1/4)*b^3*ArcTanh[(2^(1/4)*a^(1/4)*x^(1/4))/ 
(b + a*x)^(1/4)]))/(192*a^(15/4)*(x^3*(b + a*x))^(3/4))
 
3.25.39.3 Rubi [A] (verified)

Time = 0.57 (sec) , antiderivative size = 386, normalized size of antiderivative = 1.95, number of steps used = 23, number of rules used = 22, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.786, Rules used = {1948, 25, 112, 27, 173, 105, 105, 104, 27, 827, 216, 219, 1194, 27, 87, 57, 60, 73, 854, 827, 216, 219}

Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.

\(\displaystyle \int \frac {x^2 \sqrt [4]{a x^4+b x^3}}{a x-b} \, dx\)

\(\Big \downarrow \) 1948

\(\displaystyle \frac {\sqrt [4]{a x^4+b x^3} \int -\frac {x^{11/4} \sqrt [4]{b+a x}}{b-a x}dx}{x^{3/4} \sqrt [4]{a x+b}}\)

\(\Big \downarrow \) 25

\(\displaystyle -\frac {\sqrt [4]{a x^4+b x^3} \int \frac {x^{11/4} \sqrt [4]{b+a x}}{b-a x}dx}{x^{3/4} \sqrt [4]{a x+b}}\)

\(\Big \downarrow \) 112

\(\displaystyle -\frac {\sqrt [4]{a x^4+b x^3} \left (\frac {\int \frac {b x^{7/4} (11 b+13 a x)}{4 (b-a x) (b+a x)^{3/4}}dx}{3 a}-\frac {x^{11/4} \sqrt [4]{a x+b}}{3 a}\right )}{x^{3/4} \sqrt [4]{a x+b}}\)

\(\Big \downarrow \) 27

\(\displaystyle -\frac {\sqrt [4]{a x^4+b x^3} \left (\frac {b \int \frac {x^{7/4} (11 b+13 a x)}{(b-a x) (b+a x)^{3/4}}dx}{12 a}-\frac {x^{11/4} \sqrt [4]{a x+b}}{3 a}\right )}{x^{3/4} \sqrt [4]{a x+b}}\)

\(\Big \downarrow \) 173

\(\displaystyle -\frac {\sqrt [4]{a x^4+b x^3} \left (\frac {b \left (96 b^3 \int \frac {x^{7/4}}{(b-a x) (b+a x)^{11/4}}dx-\frac {\int \frac {x^{7/4} \left (13 x^2 a^5+50 b x a^4+85 b^2 a^3\right )}{(b+a x)^{11/4}}dx}{a^3}\right )}{12 a}-\frac {x^{11/4} \sqrt [4]{a x+b}}{3 a}\right )}{x^{3/4} \sqrt [4]{a x+b}}\)

\(\Big \downarrow \) 105

\(\displaystyle -\frac {\sqrt [4]{a x^4+b x^3} \left (\frac {b \left (96 b^3 \left (\frac {\int \frac {x^{3/4}}{(b-a x) (b+a x)^{7/4}}dx}{2 a}-\frac {2 x^{7/4}}{7 a b (a x+b)^{7/4}}\right )-\frac {\int \frac {x^{7/4} \left (13 x^2 a^5+50 b x a^4+85 b^2 a^3\right )}{(b+a x)^{11/4}}dx}{a^3}\right )}{12 a}-\frac {x^{11/4} \sqrt [4]{a x+b}}{3 a}\right )}{x^{3/4} \sqrt [4]{a x+b}}\)

\(\Big \downarrow \) 105

\(\displaystyle -\frac {\sqrt [4]{a x^4+b x^3} \left (\frac {b \left (96 b^3 \left (\frac {\frac {\int \frac {1}{\sqrt [4]{x} (b-a x) (b+a x)^{3/4}}dx}{2 a}-\frac {2 x^{3/4}}{3 a b (a x+b)^{3/4}}}{2 a}-\frac {2 x^{7/4}}{7 a b (a x+b)^{7/4}}\right )-\frac {\int \frac {x^{7/4} \left (13 x^2 a^5+50 b x a^4+85 b^2 a^3\right )}{(b+a x)^{11/4}}dx}{a^3}\right )}{12 a}-\frac {x^{11/4} \sqrt [4]{a x+b}}{3 a}\right )}{x^{3/4} \sqrt [4]{a x+b}}\)

\(\Big \downarrow \) 104

\(\displaystyle -\frac {\sqrt [4]{a x^4+b x^3} \left (\frac {b \left (96 b^3 \left (\frac {\frac {2 \int \frac {\sqrt {x}}{b \sqrt {b+a x} \left (1-\frac {2 a x}{b+a x}\right )}d\frac {\sqrt [4]{x}}{\sqrt [4]{b+a x}}}{a}-\frac {2 x^{3/4}}{3 a b (a x+b)^{3/4}}}{2 a}-\frac {2 x^{7/4}}{7 a b (a x+b)^{7/4}}\right )-\frac {\int \frac {x^{7/4} \left (13 x^2 a^5+50 b x a^4+85 b^2 a^3\right )}{(b+a x)^{11/4}}dx}{a^3}\right )}{12 a}-\frac {x^{11/4} \sqrt [4]{a x+b}}{3 a}\right )}{x^{3/4} \sqrt [4]{a x+b}}\)

\(\Big \downarrow \) 27

\(\displaystyle -\frac {\sqrt [4]{a x^4+b x^3} \left (\frac {b \left (96 b^3 \left (\frac {\frac {2 \int \frac {\sqrt {x}}{\sqrt {b+a x} \left (1-\frac {2 a x}{b+a x}\right )}d\frac {\sqrt [4]{x}}{\sqrt [4]{b+a x}}}{a b}-\frac {2 x^{3/4}}{3 a b (a x+b)^{3/4}}}{2 a}-\frac {2 x^{7/4}}{7 a b (a x+b)^{7/4}}\right )-\frac {\int \frac {x^{7/4} \left (13 x^2 a^5+50 b x a^4+85 b^2 a^3\right )}{(b+a x)^{11/4}}dx}{a^3}\right )}{12 a}-\frac {x^{11/4} \sqrt [4]{a x+b}}{3 a}\right )}{x^{3/4} \sqrt [4]{a x+b}}\)

\(\Big \downarrow \) 827

\(\displaystyle -\frac {\sqrt [4]{a x^4+b x^3} \left (\frac {b \left (96 b^3 \left (\frac {\frac {2 \left (\frac {\int \frac {1}{1-\frac {\sqrt {2} \sqrt {a} \sqrt {x}}{\sqrt {b+a x}}}d\frac {\sqrt [4]{x}}{\sqrt [4]{b+a x}}}{2 \sqrt {2} \sqrt {a}}-\frac {\int \frac {1}{\frac {\sqrt {2} \sqrt {a} \sqrt {x}}{\sqrt {b+a x}}+1}d\frac {\sqrt [4]{x}}{\sqrt [4]{b+a x}}}{2 \sqrt {2} \sqrt {a}}\right )}{a b}-\frac {2 x^{3/4}}{3 a b (a x+b)^{3/4}}}{2 a}-\frac {2 x^{7/4}}{7 a b (a x+b)^{7/4}}\right )-\frac {\int \frac {x^{7/4} \left (13 x^2 a^5+50 b x a^4+85 b^2 a^3\right )}{(b+a x)^{11/4}}dx}{a^3}\right )}{12 a}-\frac {x^{11/4} \sqrt [4]{a x+b}}{3 a}\right )}{x^{3/4} \sqrt [4]{a x+b}}\)

\(\Big \downarrow \) 216

\(\displaystyle -\frac {\sqrt [4]{a x^4+b x^3} \left (\frac {b \left (96 b^3 \left (\frac {\frac {2 \left (\frac {\int \frac {1}{1-\frac {\sqrt {2} \sqrt {a} \sqrt {x}}{\sqrt {b+a x}}}d\frac {\sqrt [4]{x}}{\sqrt [4]{b+a x}}}{2 \sqrt {2} \sqrt {a}}-\frac {\arctan \left (\frac {\sqrt [4]{2} \sqrt [4]{a} \sqrt [4]{x}}{\sqrt [4]{a x+b}}\right )}{2\ 2^{3/4} a^{3/4}}\right )}{a b}-\frac {2 x^{3/4}}{3 a b (a x+b)^{3/4}}}{2 a}-\frac {2 x^{7/4}}{7 a b (a x+b)^{7/4}}\right )-\frac {\int \frac {x^{7/4} \left (13 x^2 a^5+50 b x a^4+85 b^2 a^3\right )}{(b+a x)^{11/4}}dx}{a^3}\right )}{12 a}-\frac {x^{11/4} \sqrt [4]{a x+b}}{3 a}\right )}{x^{3/4} \sqrt [4]{a x+b}}\)

\(\Big \downarrow \) 219

\(\displaystyle -\frac {\sqrt [4]{a x^4+b x^3} \left (\frac {b \left (96 b^3 \left (\frac {\frac {2 \left (\frac {\text {arctanh}\left (\frac {\sqrt [4]{2} \sqrt [4]{a} \sqrt [4]{x}}{\sqrt [4]{a x+b}}\right )}{2\ 2^{3/4} a^{3/4}}-\frac {\arctan \left (\frac {\sqrt [4]{2} \sqrt [4]{a} \sqrt [4]{x}}{\sqrt [4]{a x+b}}\right )}{2\ 2^{3/4} a^{3/4}}\right )}{a b}-\frac {2 x^{3/4}}{3 a b (a x+b)^{3/4}}}{2 a}-\frac {2 x^{7/4}}{7 a b (a x+b)^{7/4}}\right )-\frac {\int \frac {x^{7/4} \left (13 x^2 a^5+50 b x a^4+85 b^2 a^3\right )}{(b+a x)^{11/4}}dx}{a^3}\right )}{12 a}-\frac {x^{11/4} \sqrt [4]{a x+b}}{3 a}\right )}{x^{3/4} \sqrt [4]{a x+b}}\)

\(\Big \downarrow \) 1194

\(\displaystyle -\frac {\sqrt [4]{a x^4+b x^3} \left (\frac {b \left (96 b^3 \left (\frac {\frac {2 \left (\frac {\text {arctanh}\left (\frac {\sqrt [4]{2} \sqrt [4]{a} \sqrt [4]{x}}{\sqrt [4]{a x+b}}\right )}{2\ 2^{3/4} a^{3/4}}-\frac {\arctan \left (\frac {\sqrt [4]{2} \sqrt [4]{a} \sqrt [4]{x}}{\sqrt [4]{a x+b}}\right )}{2\ 2^{3/4} a^{3/4}}\right )}{a b}-\frac {2 x^{3/4}}{3 a b (a x+b)^{3/4}}}{2 a}-\frac {2 x^{7/4}}{7 a b (a x+b)^{7/4}}\right )-\frac {\frac {\int \frac {5 a^4 b x^{7/4} (136 b+41 a x)}{4 (b+a x)^{11/4}}dx}{2 a}+\frac {13 a^4 x^{15/4}}{2 (a x+b)^{7/4}}}{a^3}\right )}{12 a}-\frac {x^{11/4} \sqrt [4]{a x+b}}{3 a}\right )}{x^{3/4} \sqrt [4]{a x+b}}\)

\(\Big \downarrow \) 27

\(\displaystyle -\frac {\sqrt [4]{a x^4+b x^3} \left (\frac {b \left (96 b^3 \left (\frac {\frac {2 \left (\frac {\text {arctanh}\left (\frac {\sqrt [4]{2} \sqrt [4]{a} \sqrt [4]{x}}{\sqrt [4]{a x+b}}\right )}{2\ 2^{3/4} a^{3/4}}-\frac {\arctan \left (\frac {\sqrt [4]{2} \sqrt [4]{a} \sqrt [4]{x}}{\sqrt [4]{a x+b}}\right )}{2\ 2^{3/4} a^{3/4}}\right )}{a b}-\frac {2 x^{3/4}}{3 a b (a x+b)^{3/4}}}{2 a}-\frac {2 x^{7/4}}{7 a b (a x+b)^{7/4}}\right )-\frac {\frac {5}{8} a^3 b \int \frac {x^{7/4} (136 b+41 a x)}{(b+a x)^{11/4}}dx+\frac {13 a^4 x^{15/4}}{2 (a x+b)^{7/4}}}{a^3}\right )}{12 a}-\frac {x^{11/4} \sqrt [4]{a x+b}}{3 a}\right )}{x^{3/4} \sqrt [4]{a x+b}}\)

\(\Big \downarrow \) 87

\(\displaystyle -\frac {\sqrt [4]{a x^4+b x^3} \left (\frac {b \left (96 b^3 \left (\frac {\frac {2 \left (\frac {\text {arctanh}\left (\frac {\sqrt [4]{2} \sqrt [4]{a} \sqrt [4]{x}}{\sqrt [4]{a x+b}}\right )}{2\ 2^{3/4} a^{3/4}}-\frac {\arctan \left (\frac {\sqrt [4]{2} \sqrt [4]{a} \sqrt [4]{x}}{\sqrt [4]{a x+b}}\right )}{2\ 2^{3/4} a^{3/4}}\right )}{a b}-\frac {2 x^{3/4}}{3 a b (a x+b)^{3/4}}}{2 a}-\frac {2 x^{7/4}}{7 a b (a x+b)^{7/4}}\right )-\frac {\frac {5}{8} a^3 b \left (\frac {380 x^{11/4}}{7 (a x+b)^{7/4}}-\frac {93}{7} \int \frac {x^{7/4}}{(b+a x)^{7/4}}dx\right )+\frac {13 a^4 x^{15/4}}{2 (a x+b)^{7/4}}}{a^3}\right )}{12 a}-\frac {x^{11/4} \sqrt [4]{a x+b}}{3 a}\right )}{x^{3/4} \sqrt [4]{a x+b}}\)

\(\Big \downarrow \) 57

\(\displaystyle -\frac {\sqrt [4]{a x^4+b x^3} \left (\frac {b \left (96 b^3 \left (\frac {\frac {2 \left (\frac {\text {arctanh}\left (\frac {\sqrt [4]{2} \sqrt [4]{a} \sqrt [4]{x}}{\sqrt [4]{a x+b}}\right )}{2\ 2^{3/4} a^{3/4}}-\frac {\arctan \left (\frac {\sqrt [4]{2} \sqrt [4]{a} \sqrt [4]{x}}{\sqrt [4]{a x+b}}\right )}{2\ 2^{3/4} a^{3/4}}\right )}{a b}-\frac {2 x^{3/4}}{3 a b (a x+b)^{3/4}}}{2 a}-\frac {2 x^{7/4}}{7 a b (a x+b)^{7/4}}\right )-\frac {\frac {5}{8} a^3 b \left (\frac {380 x^{11/4}}{7 (a x+b)^{7/4}}-\frac {93}{7} \left (\frac {7 \int \frac {x^{3/4}}{(b+a x)^{3/4}}dx}{3 a}-\frac {4 x^{7/4}}{3 a (a x+b)^{3/4}}\right )\right )+\frac {13 a^4 x^{15/4}}{2 (a x+b)^{7/4}}}{a^3}\right )}{12 a}-\frac {x^{11/4} \sqrt [4]{a x+b}}{3 a}\right )}{x^{3/4} \sqrt [4]{a x+b}}\)

\(\Big \downarrow \) 60

\(\displaystyle -\frac {\sqrt [4]{a x^4+b x^3} \left (\frac {b \left (96 b^3 \left (\frac {\frac {2 \left (\frac {\text {arctanh}\left (\frac {\sqrt [4]{2} \sqrt [4]{a} \sqrt [4]{x}}{\sqrt [4]{a x+b}}\right )}{2\ 2^{3/4} a^{3/4}}-\frac {\arctan \left (\frac {\sqrt [4]{2} \sqrt [4]{a} \sqrt [4]{x}}{\sqrt [4]{a x+b}}\right )}{2\ 2^{3/4} a^{3/4}}\right )}{a b}-\frac {2 x^{3/4}}{3 a b (a x+b)^{3/4}}}{2 a}-\frac {2 x^{7/4}}{7 a b (a x+b)^{7/4}}\right )-\frac {\frac {5}{8} a^3 b \left (\frac {380 x^{11/4}}{7 (a x+b)^{7/4}}-\frac {93}{7} \left (\frac {7 \left (\frac {x^{3/4} \sqrt [4]{a x+b}}{a}-\frac {3 b \int \frac {1}{\sqrt [4]{x} (b+a x)^{3/4}}dx}{4 a}\right )}{3 a}-\frac {4 x^{7/4}}{3 a (a x+b)^{3/4}}\right )\right )+\frac {13 a^4 x^{15/4}}{2 (a x+b)^{7/4}}}{a^3}\right )}{12 a}-\frac {x^{11/4} \sqrt [4]{a x+b}}{3 a}\right )}{x^{3/4} \sqrt [4]{a x+b}}\)

\(\Big \downarrow \) 73

\(\displaystyle -\frac {\sqrt [4]{a x^4+b x^3} \left (\frac {b \left (96 b^3 \left (\frac {\frac {2 \left (\frac {\text {arctanh}\left (\frac {\sqrt [4]{2} \sqrt [4]{a} \sqrt [4]{x}}{\sqrt [4]{a x+b}}\right )}{2\ 2^{3/4} a^{3/4}}-\frac {\arctan \left (\frac {\sqrt [4]{2} \sqrt [4]{a} \sqrt [4]{x}}{\sqrt [4]{a x+b}}\right )}{2\ 2^{3/4} a^{3/4}}\right )}{a b}-\frac {2 x^{3/4}}{3 a b (a x+b)^{3/4}}}{2 a}-\frac {2 x^{7/4}}{7 a b (a x+b)^{7/4}}\right )-\frac {\frac {5}{8} a^3 b \left (\frac {380 x^{11/4}}{7 (a x+b)^{7/4}}-\frac {93}{7} \left (\frac {7 \left (\frac {x^{3/4} \sqrt [4]{a x+b}}{a}-\frac {3 b \int \frac {\sqrt {x}}{(b+a x)^{3/4}}d\sqrt [4]{x}}{a}\right )}{3 a}-\frac {4 x^{7/4}}{3 a (a x+b)^{3/4}}\right )\right )+\frac {13 a^4 x^{15/4}}{2 (a x+b)^{7/4}}}{a^3}\right )}{12 a}-\frac {x^{11/4} \sqrt [4]{a x+b}}{3 a}\right )}{x^{3/4} \sqrt [4]{a x+b}}\)

\(\Big \downarrow \) 854

\(\displaystyle -\frac {\sqrt [4]{a x^4+b x^3} \left (\frac {b \left (96 b^3 \left (\frac {\frac {2 \left (\frac {\text {arctanh}\left (\frac {\sqrt [4]{2} \sqrt [4]{a} \sqrt [4]{x}}{\sqrt [4]{a x+b}}\right )}{2\ 2^{3/4} a^{3/4}}-\frac {\arctan \left (\frac {\sqrt [4]{2} \sqrt [4]{a} \sqrt [4]{x}}{\sqrt [4]{a x+b}}\right )}{2\ 2^{3/4} a^{3/4}}\right )}{a b}-\frac {2 x^{3/4}}{3 a b (a x+b)^{3/4}}}{2 a}-\frac {2 x^{7/4}}{7 a b (a x+b)^{7/4}}\right )-\frac {\frac {5}{8} a^3 b \left (\frac {380 x^{11/4}}{7 (a x+b)^{7/4}}-\frac {93}{7} \left (\frac {7 \left (\frac {x^{3/4} \sqrt [4]{a x+b}}{a}-\frac {3 b \int \frac {\sqrt {x}}{1-a x}d\frac {\sqrt [4]{x}}{\sqrt [4]{b+a x}}}{a}\right )}{3 a}-\frac {4 x^{7/4}}{3 a (a x+b)^{3/4}}\right )\right )+\frac {13 a^4 x^{15/4}}{2 (a x+b)^{7/4}}}{a^3}\right )}{12 a}-\frac {x^{11/4} \sqrt [4]{a x+b}}{3 a}\right )}{x^{3/4} \sqrt [4]{a x+b}}\)

\(\Big \downarrow \) 827

\(\displaystyle -\frac {\sqrt [4]{a x^4+b x^3} \left (\frac {b \left (96 b^3 \left (\frac {\frac {2 \left (\frac {\text {arctanh}\left (\frac {\sqrt [4]{2} \sqrt [4]{a} \sqrt [4]{x}}{\sqrt [4]{a x+b}}\right )}{2\ 2^{3/4} a^{3/4}}-\frac {\arctan \left (\frac {\sqrt [4]{2} \sqrt [4]{a} \sqrt [4]{x}}{\sqrt [4]{a x+b}}\right )}{2\ 2^{3/4} a^{3/4}}\right )}{a b}-\frac {2 x^{3/4}}{3 a b (a x+b)^{3/4}}}{2 a}-\frac {2 x^{7/4}}{7 a b (a x+b)^{7/4}}\right )-\frac {\frac {5}{8} a^3 b \left (\frac {380 x^{11/4}}{7 (a x+b)^{7/4}}-\frac {93}{7} \left (\frac {7 \left (\frac {x^{3/4} \sqrt [4]{a x+b}}{a}-\frac {3 b \left (\frac {\int \frac {1}{1-\sqrt {a} \sqrt {x}}d\frac {\sqrt [4]{x}}{\sqrt [4]{b+a x}}}{2 \sqrt {a}}-\frac {\int \frac {1}{\sqrt {a} \sqrt {x}+1}d\frac {\sqrt [4]{x}}{\sqrt [4]{b+a x}}}{2 \sqrt {a}}\right )}{a}\right )}{3 a}-\frac {4 x^{7/4}}{3 a (a x+b)^{3/4}}\right )\right )+\frac {13 a^4 x^{15/4}}{2 (a x+b)^{7/4}}}{a^3}\right )}{12 a}-\frac {x^{11/4} \sqrt [4]{a x+b}}{3 a}\right )}{x^{3/4} \sqrt [4]{a x+b}}\)

\(\Big \downarrow \) 216

\(\displaystyle -\frac {\sqrt [4]{a x^4+b x^3} \left (\frac {b \left (96 b^3 \left (\frac {\frac {2 \left (\frac {\text {arctanh}\left (\frac {\sqrt [4]{2} \sqrt [4]{a} \sqrt [4]{x}}{\sqrt [4]{a x+b}}\right )}{2\ 2^{3/4} a^{3/4}}-\frac {\arctan \left (\frac {\sqrt [4]{2} \sqrt [4]{a} \sqrt [4]{x}}{\sqrt [4]{a x+b}}\right )}{2\ 2^{3/4} a^{3/4}}\right )}{a b}-\frac {2 x^{3/4}}{3 a b (a x+b)^{3/4}}}{2 a}-\frac {2 x^{7/4}}{7 a b (a x+b)^{7/4}}\right )-\frac {\frac {5}{8} a^3 b \left (\frac {380 x^{11/4}}{7 (a x+b)^{7/4}}-\frac {93}{7} \left (\frac {7 \left (\frac {x^{3/4} \sqrt [4]{a x+b}}{a}-\frac {3 b \left (\frac {\int \frac {1}{1-\sqrt {a} \sqrt {x}}d\frac {\sqrt [4]{x}}{\sqrt [4]{b+a x}}}{2 \sqrt {a}}-\frac {\arctan \left (\frac {\sqrt [4]{a} \sqrt [4]{x}}{\sqrt [4]{a x+b}}\right )}{2 a^{3/4}}\right )}{a}\right )}{3 a}-\frac {4 x^{7/4}}{3 a (a x+b)^{3/4}}\right )\right )+\frac {13 a^4 x^{15/4}}{2 (a x+b)^{7/4}}}{a^3}\right )}{12 a}-\frac {x^{11/4} \sqrt [4]{a x+b}}{3 a}\right )}{x^{3/4} \sqrt [4]{a x+b}}\)

\(\Big \downarrow \) 219

\(\displaystyle -\frac {\sqrt [4]{a x^4+b x^3} \left (\frac {b \left (96 b^3 \left (\frac {\frac {2 \left (\frac {\text {arctanh}\left (\frac {\sqrt [4]{2} \sqrt [4]{a} \sqrt [4]{x}}{\sqrt [4]{a x+b}}\right )}{2\ 2^{3/4} a^{3/4}}-\frac {\arctan \left (\frac {\sqrt [4]{2} \sqrt [4]{a} \sqrt [4]{x}}{\sqrt [4]{a x+b}}\right )}{2\ 2^{3/4} a^{3/4}}\right )}{a b}-\frac {2 x^{3/4}}{3 a b (a x+b)^{3/4}}}{2 a}-\frac {2 x^{7/4}}{7 a b (a x+b)^{7/4}}\right )-\frac {\frac {13 a^4 x^{15/4}}{2 (a x+b)^{7/4}}+\frac {5}{8} a^3 b \left (\frac {380 x^{11/4}}{7 (a x+b)^{7/4}}-\frac {93}{7} \left (\frac {7 \left (\frac {x^{3/4} \sqrt [4]{a x+b}}{a}-\frac {3 b \left (\frac {\text {arctanh}\left (\frac {\sqrt [4]{a} \sqrt [4]{x}}{\sqrt [4]{a x+b}}\right )}{2 a^{3/4}}-\frac {\arctan \left (\frac {\sqrt [4]{a} \sqrt [4]{x}}{\sqrt [4]{a x+b}}\right )}{2 a^{3/4}}\right )}{a}\right )}{3 a}-\frac {4 x^{7/4}}{3 a (a x+b)^{3/4}}\right )\right )}{a^3}\right )}{12 a}-\frac {x^{11/4} \sqrt [4]{a x+b}}{3 a}\right )}{x^{3/4} \sqrt [4]{a x+b}}\)

input
Int[(x^2*(b*x^3 + a*x^4)^(1/4))/(-b + a*x),x]
 
output
-(((b*x^3 + a*x^4)^(1/4)*(-1/3*(x^(11/4)*(b + a*x)^(1/4))/a + (b*(-(((13*a 
^4*x^(15/4))/(2*(b + a*x)^(7/4)) + (5*a^3*b*((380*x^(11/4))/(7*(b + a*x)^( 
7/4)) - (93*((-4*x^(7/4))/(3*a*(b + a*x)^(3/4)) + (7*((x^(3/4)*(b + a*x)^( 
1/4))/a - (3*b*(-1/2*ArcTan[(a^(1/4)*x^(1/4))/(b + a*x)^(1/4)]/a^(3/4) + A 
rcTanh[(a^(1/4)*x^(1/4))/(b + a*x)^(1/4)]/(2*a^(3/4))))/a))/(3*a)))/7))/8) 
/a^3) + 96*b^3*((-2*x^(7/4))/(7*a*b*(b + a*x)^(7/4)) + ((-2*x^(3/4))/(3*a* 
b*(b + a*x)^(3/4)) + (2*(-1/2*ArcTan[(2^(1/4)*a^(1/4)*x^(1/4))/(b + a*x)^( 
1/4)]/(2^(3/4)*a^(3/4)) + ArcTanh[(2^(1/4)*a^(1/4)*x^(1/4))/(b + a*x)^(1/4 
)]/(2*2^(3/4)*a^(3/4))))/(a*b))/(2*a))))/(12*a)))/(x^(3/4)*(b + a*x)^(1/4) 
))
 

3.25.39.3.1 Defintions of rubi rules used

rule 25
Int[-(Fx_), x_Symbol] :> Simp[Identity[-1]   Int[Fx, x], x]
 

rule 27
Int[(a_)*(Fx_), x_Symbol] :> Simp[a   Int[Fx, x], x] /; FreeQ[a, x] &&  !Ma 
tchQ[Fx, (b_)*(Gx_) /; FreeQ[b, x]]
 

rule 57
Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> Simp[ 
(a + b*x)^(m + 1)*((c + d*x)^n/(b*(m + 1))), x] - Simp[d*(n/(b*(m + 1))) 
Int[(a + b*x)^(m + 1)*(c + d*x)^(n - 1), x], x] /; FreeQ[{a, b, c, d}, x] & 
& GtQ[n, 0] && LtQ[m, -1] &&  !(IntegerQ[n] &&  !IntegerQ[m]) &&  !(ILeQ[m 
+ n + 2, 0] && (FractionQ[m] || GeQ[2*n + m + 1, 0])) && IntLinearQ[a, b, c 
, d, m, n, x]
 

rule 60
Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> Simp[ 
(a + b*x)^(m + 1)*((c + d*x)^n/(b*(m + n + 1))), x] + Simp[n*((b*c - a*d)/( 
b*(m + n + 1)))   Int[(a + b*x)^m*(c + d*x)^(n - 1), x], x] /; FreeQ[{a, b, 
 c, d}, x] && GtQ[n, 0] && NeQ[m + n + 1, 0] &&  !(IGtQ[m, 0] && ( !Integer 
Q[n] || (GtQ[m, 0] && LtQ[m - n, 0]))) &&  !ILtQ[m + n + 2, 0] && IntLinear 
Q[a, b, c, d, m, n, x]
 

rule 73
Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> With[ 
{p = Denominator[m]}, Simp[p/b   Subst[Int[x^(p*(m + 1) - 1)*(c - a*(d/b) + 
 d*(x^p/b))^n, x], x, (a + b*x)^(1/p)], x]] /; FreeQ[{a, b, c, d}, x] && Lt 
Q[-1, m, 0] && LeQ[-1, n, 0] && LeQ[Denominator[n], Denominator[m]] && IntL 
inearQ[a, b, c, d, m, n, x]
 

rule 87
Int[((a_.) + (b_.)*(x_))*((c_.) + (d_.)*(x_))^(n_.)*((e_.) + (f_.)*(x_))^(p 
_.), x_] :> Simp[(-(b*e - a*f))*(c + d*x)^(n + 1)*((e + f*x)^(p + 1)/(f*(p 
+ 1)*(c*f - d*e))), x] - Simp[(a*d*f*(n + p + 2) - b*(d*e*(n + 1) + c*f*(p 
+ 1)))/(f*(p + 1)*(c*f - d*e))   Int[(c + d*x)^n*(e + f*x)^(p + 1), x], x] 
/; FreeQ[{a, b, c, d, e, f, n}, x] && LtQ[p, -1] && ( !LtQ[n, -1] || Intege 
rQ[p] ||  !(IntegerQ[n] ||  !(EqQ[e, 0] ||  !(EqQ[c, 0] || LtQ[p, n]))))
 

rule 104
Int[(((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_))/((e_.) + (f_.)*(x 
_)), x_] :> With[{q = Denominator[m]}, Simp[q   Subst[Int[x^(q*(m + 1) - 1) 
/(b*e - a*f - (d*e - c*f)*x^q), x], x, (a + b*x)^(1/q)/(c + d*x)^(1/q)], x] 
] /; FreeQ[{a, b, c, d, e, f}, x] && EqQ[m + n + 1, 0] && RationalQ[n] && L 
tQ[-1, m, 0] && SimplerQ[a + b*x, c + d*x]
 

rule 105
Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_)*((e_.) + (f_.)*(x_) 
)^(p_), x_] :> Simp[(a + b*x)^(m + 1)*(c + d*x)^n*((e + f*x)^(p + 1)/((m + 
1)*(b*e - a*f))), x] - Simp[n*((d*e - c*f)/((m + 1)*(b*e - a*f)))   Int[(a 
+ b*x)^(m + 1)*(c + d*x)^(n - 1)*(e + f*x)^p, x], x] /; FreeQ[{a, b, c, d, 
e, f, m, p}, x] && EqQ[m + n + p + 2, 0] && GtQ[n, 0] && (SumSimplerQ[m, 1] 
 ||  !SumSimplerQ[p, 1]) && NeQ[m, -1]
 

rule 112
Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_)*((e_.) + (f_.)*(x_) 
)^(p_), x_] :> Simp[(a + b*x)^m*(c + d*x)^n*((e + f*x)^(p + 1)/(f*(m + n + 
p + 1))), x] - Simp[1/(f*(m + n + p + 1))   Int[(a + b*x)^(m - 1)*(c + d*x) 
^(n - 1)*(e + f*x)^p*Simp[c*m*(b*e - a*f) + a*n*(d*e - c*f) + (d*m*(b*e - a 
*f) + b*n*(d*e - c*f))*x, x], x], x] /; FreeQ[{a, b, c, d, e, f, p}, x] && 
GtQ[m, 0] && GtQ[n, 0] && NeQ[m + n + p + 1, 0] && (IntegersQ[2*m, 2*n, 2*p 
] || (IntegersQ[m, n + p] || IntegersQ[p, m + n]))
 

rule 173
Int[(((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_)*((g_.) + (h_.)*(x_ 
)))/((e_.) + (f_.)*(x_)), x_] :> Simp[(f*g - e*h)*((c*f - d*e)^(m + n + 1)/ 
f^(m + n + 2))   Int[(a + b*x)^m/((c + d*x)^(m + 1)*(e + f*x)), x], x] + Si 
mp[1/f^(m + n + 2)   Int[((a + b*x)^m/(c + d*x)^(m + 1))*ExpandToSum[(f^(m 
+ n + 2)*(c + d*x)^(m + n + 1)*(g + h*x) - (f*g - e*h)*(c*f - d*e)^(m + n + 
 1))/(e + f*x), x], x], x] /; FreeQ[{a, b, c, d, e, f, g, h}, x] && IGtQ[m 
+ n + 1, 0] && (LtQ[m, 0] || SumSimplerQ[m, 1] ||  !SumSimplerQ[n, 1])
 

rule 216
Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(1/(Rt[a, 2]*Rt[b, 2]))*A 
rcTan[Rt[b, 2]*(x/Rt[a, 2])], x] /; FreeQ[{a, b}, x] && PosQ[a/b] && (GtQ[a 
, 0] || GtQ[b, 0])
 

rule 219
Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(1/(Rt[a, 2]*Rt[-b, 2]))* 
ArcTanh[Rt[-b, 2]*(x/Rt[a, 2])], x] /; FreeQ[{a, b}, x] && NegQ[a/b] && (Gt 
Q[a, 0] || LtQ[b, 0])
 

rule 827
Int[(x_)^2/((a_) + (b_.)*(x_)^4), x_Symbol] :> With[{r = Numerator[Rt[-a/b, 
 2]], s = Denominator[Rt[-a/b, 2]]}, Simp[s/(2*b)   Int[1/(r + s*x^2), x], 
x] - Simp[s/(2*b)   Int[1/(r - s*x^2), x], x]] /; FreeQ[{a, b}, x] &&  !GtQ 
[a/b, 0]
 

rule 854
Int[(x_)^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> Simp[a^(p + (m + 
 1)/n)   Subst[Int[x^m/(1 - b*x^n)^(p + (m + 1)/n + 1), x], x, x/(a + b*x^n 
)^(1/n)], x] /; FreeQ[{a, b}, x] && IGtQ[n, 0] && LtQ[-1, p, 0] && NeQ[p, - 
2^(-1)] && IntegersQ[m, p + (m + 1)/n]
 

rule 1194
Int[((d_.) + (e_.)*(x_))^(m_)*((f_.) + (g_.)*(x_))^(n_)*((a_.) + (b_.)*(x_) 
 + (c_.)*(x_)^2)^(p_.), x_Symbol] :> Simp[c^p*(d + e*x)^(m + 2*p)*((f + g*x 
)^(n + 1)/(g*e^(2*p)*(m + n + 2*p + 1))), x] + Simp[1/(g*e^(2*p)*(m + n + 2 
*p + 1))   Int[(d + e*x)^m*(f + g*x)^n*ExpandToSum[g*(m + n + 2*p + 1)*(e^( 
2*p)*(a + b*x + c*x^2)^p - c^p*(d + e*x)^(2*p)) - c^p*(e*f - d*g)*(m + 2*p) 
*(d + e*x)^(2*p - 1), x], x], x] /; FreeQ[{a, b, c, d, e, f, g}, x] && IGtQ 
[p, 0] &&  !IntegerQ[m] &&  !IntegerQ[n] && NeQ[m + n + 2*p + 1, 0]
 

rule 1948
Int[((e_.)*(x_))^(m_.)*((a_.)*(x_)^(j_.) + (b_.)*(x_)^(jn_.))^(p_)*((c_) + 
(d_.)*(x_)^(n_.))^(q_.), x_Symbol] :> Simp[e^IntPart[m]*(e*x)^FracPart[m]*( 
(a*x^j + b*x^(j + n))^FracPart[p]/(x^(FracPart[m] + j*FracPart[p])*(a + b*x 
^n)^FracPart[p]))   Int[x^(m + j*p)*(a + b*x^n)^p*(c + d*x^n)^q, x], x] /; 
FreeQ[{a, b, c, d, e, j, m, n, p, q}, x] && EqQ[jn, j + n] &&  !IntegerQ[p] 
 && NeQ[b*c - a*d, 0] &&  !(EqQ[n, 1] && EqQ[j, 1])
 
3.25.39.4 Maple [A] (verified)

Time = 0.78 (sec) , antiderivative size = 219, normalized size of antiderivative = 1.11

method result size
pseudoelliptic \(\frac {128 \left (x^{3} \left (a x +b \right )\right )^{\frac {1}{4}} a^{\frac {11}{4}} x^{2}+208 a^{\frac {7}{4}} b x \left (x^{3} \left (a x +b \right )\right )^{\frac {1}{4}}+404 b^{2} \left (x^{3} \left (a x +b \right )\right )^{\frac {1}{4}} a^{\frac {3}{4}}-384 \,2^{\frac {1}{4}} \ln \left (\frac {-x 2^{\frac {1}{4}} a^{\frac {1}{4}}-\left (x^{3} \left (a x +b \right )\right )^{\frac {1}{4}}}{x 2^{\frac {1}{4}} a^{\frac {1}{4}}-\left (x^{3} \left (a x +b \right )\right )^{\frac {1}{4}}}\right ) b^{3}-768 \,2^{\frac {1}{4}} \arctan \left (\frac {\left (x^{3} \left (a x +b \right )\right )^{\frac {1}{4}} 2^{\frac {3}{4}}}{2 x \,a^{\frac {1}{4}}}\right ) b^{3}+465 \ln \left (\frac {a^{\frac {1}{4}} x +\left (x^{3} \left (a x +b \right )\right )^{\frac {1}{4}}}{-a^{\frac {1}{4}} x +\left (x^{3} \left (a x +b \right )\right )^{\frac {1}{4}}}\right ) b^{3}+930 \arctan \left (\frac {\left (x^{3} \left (a x +b \right )\right )^{\frac {1}{4}}}{a^{\frac {1}{4}} x}\right ) b^{3}}{384 a^{\frac {15}{4}}}\) \(219\)

input
int(x^2*(a*x^4+b*x^3)^(1/4)/(a*x-b),x,method=_RETURNVERBOSE)
 
output
1/384*(128*(x^3*(a*x+b))^(1/4)*a^(11/4)*x^2+208*a^(7/4)*b*x*(x^3*(a*x+b))^ 
(1/4)+404*b^2*(x^3*(a*x+b))^(1/4)*a^(3/4)-384*2^(1/4)*ln((-x*2^(1/4)*a^(1/ 
4)-(x^3*(a*x+b))^(1/4))/(x*2^(1/4)*a^(1/4)-(x^3*(a*x+b))^(1/4)))*b^3-768*2 
^(1/4)*arctan(1/2*(x^3*(a*x+b))^(1/4)/x*2^(3/4)/a^(1/4))*b^3+465*ln((a^(1/ 
4)*x+(x^3*(a*x+b))^(1/4))/(-a^(1/4)*x+(x^3*(a*x+b))^(1/4)))*b^3+930*arctan 
(1/a^(1/4)/x*(x^3*(a*x+b))^(1/4))*b^3)/a^(15/4)
 
3.25.39.5 Fricas [C] (verification not implemented)

Result contains complex when optimal does not.

Time = 0.26 (sec) , antiderivative size = 485, normalized size of antiderivative = 2.45 \[ \int \frac {x^2 \sqrt [4]{b x^3+a x^4}}{-b+a x} \, dx=-\frac {384 \cdot 2^{\frac {1}{4}} a^{3} \left (\frac {b^{12}}{a^{15}}\right )^{\frac {1}{4}} \log \left (\frac {2^{\frac {1}{4}} a^{4} x \left (\frac {b^{12}}{a^{15}}\right )^{\frac {1}{4}} + {\left (a x^{4} + b x^{3}\right )}^{\frac {1}{4}} b^{3}}{x}\right ) - 384 \cdot 2^{\frac {1}{4}} a^{3} \left (\frac {b^{12}}{a^{15}}\right )^{\frac {1}{4}} \log \left (-\frac {2^{\frac {1}{4}} a^{4} x \left (\frac {b^{12}}{a^{15}}\right )^{\frac {1}{4}} - {\left (a x^{4} + b x^{3}\right )}^{\frac {1}{4}} b^{3}}{x}\right ) + 384 i \cdot 2^{\frac {1}{4}} a^{3} \left (\frac {b^{12}}{a^{15}}\right )^{\frac {1}{4}} \log \left (\frac {i \cdot 2^{\frac {1}{4}} a^{4} x \left (\frac {b^{12}}{a^{15}}\right )^{\frac {1}{4}} + {\left (a x^{4} + b x^{3}\right )}^{\frac {1}{4}} b^{3}}{x}\right ) - 384 i \cdot 2^{\frac {1}{4}} a^{3} \left (\frac {b^{12}}{a^{15}}\right )^{\frac {1}{4}} \log \left (\frac {-i \cdot 2^{\frac {1}{4}} a^{4} x \left (\frac {b^{12}}{a^{15}}\right )^{\frac {1}{4}} + {\left (a x^{4} + b x^{3}\right )}^{\frac {1}{4}} b^{3}}{x}\right ) - 465 \, a^{3} \left (\frac {b^{12}}{a^{15}}\right )^{\frac {1}{4}} \log \left (\frac {155 \, {\left (a^{4} x \left (\frac {b^{12}}{a^{15}}\right )^{\frac {1}{4}} + {\left (a x^{4} + b x^{3}\right )}^{\frac {1}{4}} b^{3}\right )}}{x}\right ) + 465 \, a^{3} \left (\frac {b^{12}}{a^{15}}\right )^{\frac {1}{4}} \log \left (-\frac {155 \, {\left (a^{4} x \left (\frac {b^{12}}{a^{15}}\right )^{\frac {1}{4}} - {\left (a x^{4} + b x^{3}\right )}^{\frac {1}{4}} b^{3}\right )}}{x}\right ) + 465 i \, a^{3} \left (\frac {b^{12}}{a^{15}}\right )^{\frac {1}{4}} \log \left (-\frac {155 \, {\left (i \, a^{4} x \left (\frac {b^{12}}{a^{15}}\right )^{\frac {1}{4}} - {\left (a x^{4} + b x^{3}\right )}^{\frac {1}{4}} b^{3}\right )}}{x}\right ) - 465 i \, a^{3} \left (\frac {b^{12}}{a^{15}}\right )^{\frac {1}{4}} \log \left (-\frac {155 \, {\left (-i \, a^{4} x \left (\frac {b^{12}}{a^{15}}\right )^{\frac {1}{4}} - {\left (a x^{4} + b x^{3}\right )}^{\frac {1}{4}} b^{3}\right )}}{x}\right ) - 4 \, {\left (a x^{4} + b x^{3}\right )}^{\frac {1}{4}} {\left (32 \, a^{2} x^{2} + 52 \, a b x + 101 \, b^{2}\right )}}{384 \, a^{3}} \]

input
integrate(x^2*(a*x^4+b*x^3)^(1/4)/(a*x-b),x, algorithm="fricas")
 
output
-1/384*(384*2^(1/4)*a^3*(b^12/a^15)^(1/4)*log((2^(1/4)*a^4*x*(b^12/a^15)^( 
1/4) + (a*x^4 + b*x^3)^(1/4)*b^3)/x) - 384*2^(1/4)*a^3*(b^12/a^15)^(1/4)*l 
og(-(2^(1/4)*a^4*x*(b^12/a^15)^(1/4) - (a*x^4 + b*x^3)^(1/4)*b^3)/x) + 384 
*I*2^(1/4)*a^3*(b^12/a^15)^(1/4)*log((I*2^(1/4)*a^4*x*(b^12/a^15)^(1/4) + 
(a*x^4 + b*x^3)^(1/4)*b^3)/x) - 384*I*2^(1/4)*a^3*(b^12/a^15)^(1/4)*log((- 
I*2^(1/4)*a^4*x*(b^12/a^15)^(1/4) + (a*x^4 + b*x^3)^(1/4)*b^3)/x) - 465*a^ 
3*(b^12/a^15)^(1/4)*log(155*(a^4*x*(b^12/a^15)^(1/4) + (a*x^4 + b*x^3)^(1/ 
4)*b^3)/x) + 465*a^3*(b^12/a^15)^(1/4)*log(-155*(a^4*x*(b^12/a^15)^(1/4) - 
 (a*x^4 + b*x^3)^(1/4)*b^3)/x) + 465*I*a^3*(b^12/a^15)^(1/4)*log(-155*(I*a 
^4*x*(b^12/a^15)^(1/4) - (a*x^4 + b*x^3)^(1/4)*b^3)/x) - 465*I*a^3*(b^12/a 
^15)^(1/4)*log(-155*(-I*a^4*x*(b^12/a^15)^(1/4) - (a*x^4 + b*x^3)^(1/4)*b^ 
3)/x) - 4*(a*x^4 + b*x^3)^(1/4)*(32*a^2*x^2 + 52*a*b*x + 101*b^2))/a^3
 
3.25.39.6 Sympy [F]

\[ \int \frac {x^2 \sqrt [4]{b x^3+a x^4}}{-b+a x} \, dx=\int \frac {x^{2} \sqrt [4]{x^{3} \left (a x + b\right )}}{a x - b}\, dx \]

input
integrate(x**2*(a*x**4+b*x**3)**(1/4)/(a*x-b),x)
 
output
Integral(x**2*(x**3*(a*x + b))**(1/4)/(a*x - b), x)
 
3.25.39.7 Maxima [F]

\[ \int \frac {x^2 \sqrt [4]{b x^3+a x^4}}{-b+a x} \, dx=\int { \frac {{\left (a x^{4} + b x^{3}\right )}^{\frac {1}{4}} x^{2}}{a x - b} \,d x } \]

input
integrate(x^2*(a*x^4+b*x^3)^(1/4)/(a*x-b),x, algorithm="maxima")
 
output
integrate((a*x^4 + b*x^3)^(1/4)*x^2/(a*x - b), x)
 
3.25.39.8 Giac [B] (verification not implemented)

Leaf count of result is larger than twice the leaf count of optimal. 461 vs. \(2 (158) = 316\).

Time = 0.37 (sec) , antiderivative size = 461, normalized size of antiderivative = 2.33 \[ \int \frac {x^2 \sqrt [4]{b x^3+a x^4}}{-b+a x} \, dx=-\frac {2^{\frac {3}{4}} \left (-a\right )^{\frac {1}{4}} b^{3} \arctan \left (\frac {2^{\frac {1}{4}} {\left (2^{\frac {3}{4}} \left (-a\right )^{\frac {1}{4}} + 2 \, {\left (a + \frac {b}{x}\right )}^{\frac {1}{4}}\right )}}{2 \, \left (-a\right )^{\frac {1}{4}}}\right )}{a^{4}} - \frac {2^{\frac {3}{4}} \left (-a\right )^{\frac {1}{4}} b^{3} \arctan \left (-\frac {2^{\frac {1}{4}} {\left (2^{\frac {3}{4}} \left (-a\right )^{\frac {1}{4}} - 2 \, {\left (a + \frac {b}{x}\right )}^{\frac {1}{4}}\right )}}{2 \, \left (-a\right )^{\frac {1}{4}}}\right )}{a^{4}} - \frac {2^{\frac {3}{4}} \left (-a\right )^{\frac {1}{4}} b^{3} \log \left (2^{\frac {3}{4}} \left (-a\right )^{\frac {1}{4}} {\left (a + \frac {b}{x}\right )}^{\frac {1}{4}} + \sqrt {2} \sqrt {-a} + \sqrt {a + \frac {b}{x}}\right )}{2 \, a^{4}} + \frac {2^{\frac {3}{4}} \left (-a\right )^{\frac {1}{4}} b^{3} \log \left (-2^{\frac {3}{4}} \left (-a\right )^{\frac {1}{4}} {\left (a + \frac {b}{x}\right )}^{\frac {1}{4}} + \sqrt {2} \sqrt {-a} + \sqrt {a + \frac {b}{x}}\right )}{2 \, a^{4}} + \frac {155 \, \sqrt {2} \left (-a\right )^{\frac {1}{4}} b^{3} \arctan \left (\frac {\sqrt {2} {\left (\sqrt {2} \left (-a\right )^{\frac {1}{4}} + 2 \, {\left (a + \frac {b}{x}\right )}^{\frac {1}{4}}\right )}}{2 \, \left (-a\right )^{\frac {1}{4}}}\right )}{128 \, a^{4}} + \frac {155 \, \sqrt {2} \left (-a\right )^{\frac {1}{4}} b^{3} \arctan \left (-\frac {\sqrt {2} {\left (\sqrt {2} \left (-a\right )^{\frac {1}{4}} - 2 \, {\left (a + \frac {b}{x}\right )}^{\frac {1}{4}}\right )}}{2 \, \left (-a\right )^{\frac {1}{4}}}\right )}{128 \, a^{4}} + \frac {155 \, \sqrt {2} \left (-a\right )^{\frac {1}{4}} b^{3} \log \left (\sqrt {2} \left (-a\right )^{\frac {1}{4}} {\left (a + \frac {b}{x}\right )}^{\frac {1}{4}} + \sqrt {-a} + \sqrt {a + \frac {b}{x}}\right )}{256 \, a^{4}} + \frac {155 \, \sqrt {2} b^{3} \log \left (-\sqrt {2} \left (-a\right )^{\frac {1}{4}} {\left (a + \frac {b}{x}\right )}^{\frac {1}{4}} + \sqrt {-a} + \sqrt {a + \frac {b}{x}}\right )}{256 \, \left (-a\right )^{\frac {3}{4}} a^{3}} + \frac {{\left (101 \, {\left (a + \frac {b}{x}\right )}^{\frac {9}{4}} b^{3} - 150 \, {\left (a + \frac {b}{x}\right )}^{\frac {5}{4}} a b^{3} + 81 \, {\left (a + \frac {b}{x}\right )}^{\frac {1}{4}} a^{2} b^{3}\right )} x^{3}}{96 \, a^{3} b^{3}} \]

input
integrate(x^2*(a*x^4+b*x^3)^(1/4)/(a*x-b),x, algorithm="giac")
 
output
-2^(3/4)*(-a)^(1/4)*b^3*arctan(1/2*2^(1/4)*(2^(3/4)*(-a)^(1/4) + 2*(a + b/ 
x)^(1/4))/(-a)^(1/4))/a^4 - 2^(3/4)*(-a)^(1/4)*b^3*arctan(-1/2*2^(1/4)*(2^ 
(3/4)*(-a)^(1/4) - 2*(a + b/x)^(1/4))/(-a)^(1/4))/a^4 - 1/2*2^(3/4)*(-a)^( 
1/4)*b^3*log(2^(3/4)*(-a)^(1/4)*(a + b/x)^(1/4) + sqrt(2)*sqrt(-a) + sqrt( 
a + b/x))/a^4 + 1/2*2^(3/4)*(-a)^(1/4)*b^3*log(-2^(3/4)*(-a)^(1/4)*(a + b/ 
x)^(1/4) + sqrt(2)*sqrt(-a) + sqrt(a + b/x))/a^4 + 155/128*sqrt(2)*(-a)^(1 
/4)*b^3*arctan(1/2*sqrt(2)*(sqrt(2)*(-a)^(1/4) + 2*(a + b/x)^(1/4))/(-a)^( 
1/4))/a^4 + 155/128*sqrt(2)*(-a)^(1/4)*b^3*arctan(-1/2*sqrt(2)*(sqrt(2)*(- 
a)^(1/4) - 2*(a + b/x)^(1/4))/(-a)^(1/4))/a^4 + 155/256*sqrt(2)*(-a)^(1/4) 
*b^3*log(sqrt(2)*(-a)^(1/4)*(a + b/x)^(1/4) + sqrt(-a) + sqrt(a + b/x))/a^ 
4 + 155/256*sqrt(2)*b^3*log(-sqrt(2)*(-a)^(1/4)*(a + b/x)^(1/4) + sqrt(-a) 
 + sqrt(a + b/x))/((-a)^(3/4)*a^3) + 1/96*(101*(a + b/x)^(9/4)*b^3 - 150*( 
a + b/x)^(5/4)*a*b^3 + 81*(a + b/x)^(1/4)*a^2*b^3)*x^3/(a^3*b^3)
 
3.25.39.9 Mupad [F(-1)]

Timed out. \[ \int \frac {x^2 \sqrt [4]{b x^3+a x^4}}{-b+a x} \, dx=-\int \frac {x^2\,{\left (a\,x^4+b\,x^3\right )}^{1/4}}{b-a\,x} \,d x \]

input
int(-(x^2*(a*x^4 + b*x^3)^(1/4))/(b - a*x),x)
 
output
-int((x^2*(a*x^4 + b*x^3)^(1/4))/(b - a*x), x)