3.25.67 \(\int \frac {a-2 b+x}{\sqrt [3]{(-a+x) (-b+x)} (a^2+b d-(2 a+d) x+x^2)} \, dx\) [2467]

3.25.67.1 Optimal result

Integrand size = 42, antiderivative size = 201 \[ \int \frac {a-2 b+x}{\sqrt [3]{(-a+x) (-b+x)} \left (a^2+b d-(2 a+d) x+x^2\right )} \, dx=\frac {\sqrt {3} \arctan \left (\frac {\sqrt {3} \sqrt [3]{d} \sqrt [3]{a b+(-a-b) x+x^2}}{-2 a+2 x+\sqrt [3]{d} \sqrt [3]{a b+(-a-b) x+x^2}}\right )}{d^{2/3}}+\frac {\log \left (a-x+\sqrt [3]{d} \sqrt [3]{a b+(-a-b) x+x^2}\right )}{d^{2/3}}-\frac {\log \left (a^2-2 a x+x^2+\left (-a \sqrt [3]{d}+\sqrt [3]{d} x\right ) \sqrt [3]{a b+(-a-b) x+x^2}+d^{2/3} \left (a b+(-a-b) x+x^2\right )^{2/3}\right )}{2 d^{2/3}} \]

output

3^(1/2)*arctan(3^(1/2)*d^(1/3)*(a*b+(-a-b)*x+x^2)^(1/3)/(-2*a+2*x+d^(1/3)* 
(a*b+(-a-b)*x+x^2)^(1/3)))/d^(2/3)+ln(a-x+d^(1/3)*(a*b+(-a-b)*x+x^2)^(1/3) 
)/d^(2/3)-1/2*ln(a^2-2*a*x+x^2+(-a*d^(1/3)+d^(1/3)*x)*(a*b+(-a-b)*x+x^2)^( 
1/3)+d^(2/3)*(a*b+(-a-b)*x+x^2)^(2/3))/d^(2/3)
 

3.25.67.2 Mathematica [A] (verified)

Time = 4.83 (sec) , antiderivative size = 181, normalized size of antiderivative = 0.90 \[ \int \frac {a-2 b+x}{\sqrt [3]{(-a+x) (-b+x)} \left (a^2+b d-(2 a+d) x+x^2\right )} \, dx=\frac {\sqrt [3]{-a+x} \sqrt [3]{-b+x} \left (2 \sqrt {3} \arctan \left (\frac {\sqrt {3} \sqrt [3]{d} \sqrt [3]{-b+x}}{2 (-a+x)^{2/3}+\sqrt [3]{d} \sqrt [3]{-b+x}}\right )+2 \log \left ((-a+x)^{2/3}-\sqrt [3]{d} \sqrt [3]{-b+x}\right )-\log \left ((-a+x)^{4/3}+\sqrt [3]{d} (-a+x)^{2/3} \sqrt [3]{-b+x}+d^{2/3} (-b+x)^{2/3}\right )\right )}{2 d^{2/3} \sqrt [3]{(-a+x) (-b+x)}} \]

input

Integrate[(a - 2*b + x)/(((-a + x)*(-b + x))^(1/3)*(a^2 + b*d - (2*a + d)* 
x + x^2)),x]
 

output

((-a + x)^(1/3)*(-b + x)^(1/3)*(2*Sqrt[3]*ArcTan[(Sqrt[3]*d^(1/3)*(-b + x) 
^(1/3))/(2*(-a + x)^(2/3) + d^(1/3)*(-b + x)^(1/3))] + 2*Log[(-a + x)^(2/3 
) - d^(1/3)*(-b + x)^(1/3)] - Log[(-a + x)^(4/3) + d^(1/3)*(-a + x)^(2/3)* 
(-b + x)^(1/3) + d^(2/3)*(-b + x)^(2/3)]))/(2*d^(2/3)*((-a + x)*(-b + x))^ 
(1/3))
 

3.25.67.3 Rubi [F]

Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.

\(\displaystyle \int \frac {a-2 b+x}{\sqrt [3]{(x-a) (x-b)} \left (a^2-x (2 a+d)+b d+x^2\right )} \, dx\)

\(\Big \downarrow \) 2048

\(\displaystyle \int \frac {a-2 b+x}{\sqrt [3]{x (-a-b)+a b+x^2} \left (a^2-x (2 a+d)+b d+x^2\right )}dx\)

\(\Big \downarrow \) 1375

\(\displaystyle \int \frac {a-2 b+x}{\sqrt [3]{x (-a-b)+a b+x^2} \left (a^2+x (-2 a-d)+b d+x^2\right )}dx\)

input

Int[(a - 2*b + x)/(((-a + x)*(-b + x))^(1/3)*(a^2 + b*d - (2*a + d)*x + x^ 
2)),x]
 

output

$Aborted
 

3.25.67.3.1 Defintions of rubi rules used

rule 1375

Int[((g_.) + (h_.)*(x_))*((a_.) + (b_.)*(x_) + (c_.)*(x_)^2)^(p_)*((d_.) + 
(e_.)*(x_) + (f_.)*(x_)^2)^(q_), x_Symbol] :> Unintegrable[(g + h*x)*(a + b 
*x + c*x^2)^p*(d + e*x + f*x^2)^q, x] /; FreeQ[{a, b, c, d, e, f, g, h, p, 
q}, x]
 

rule 2048

Int[(u_.)*((e_.)*((a_.) + (b_.)*(x_)^(n_.))*((c_) + (d_.)*(x_)^(n_.)))^(p_) 
, x_Symbol] :> Int[u*(a*c*e + (b*c + a*d)*e*x^n + b*d*e*x^(2*n))^p, x] /; F 
reeQ[{a, b, c, d, e, n, p}, x]
 

3.25.67.4 Maple [F]

\[\int \frac {a -2 b +x}{\left (\left (-a +x \right ) \left (-b +x \right )\right )^{\frac {1}{3}} \left (a^{2}+b d -\left (2 a +d \right ) x +x^{2}\right )}d x\]

input

int((a-2*b+x)/((-a+x)*(-b+x))^(1/3)/(a^2+b*d-(2*a+d)*x+x^2),x)
 

output

int((a-2*b+x)/((-a+x)*(-b+x))^(1/3)/(a^2+b*d-(2*a+d)*x+x^2),x)
 

3.25.67.5 Fricas [F(-1)]

Timed out. \[ \int \frac {a-2 b+x}{\sqrt [3]{(-a+x) (-b+x)} \left (a^2+b d-(2 a+d) x+x^2\right )} \, dx=\text {Timed out} \]

input

integrate((a-2*b+x)/((-a+x)*(-b+x))^(1/3)/(a^2+b*d-(2*a+d)*x+x^2),x, algor 
ithm="fricas")
 

output

Timed out
 

3.25.67.6 Sympy [F(-1)]

Timed out. \[ \int \frac {a-2 b+x}{\sqrt [3]{(-a+x) (-b+x)} \left (a^2+b d-(2 a+d) x+x^2\right )} \, dx=\text {Timed out} \]

input

integrate((a-2*b+x)/((-a+x)*(-b+x))**(1/3)/(a**2+b*d-(2*a+d)*x+x**2),x)
 

output

Timed out
 

3.25.67.7 Maxima [F]

\[ \int \frac {a-2 b+x}{\sqrt [3]{(-a+x) (-b+x)} \left (a^2+b d-(2 a+d) x+x^2\right )} \, dx=\int { \frac {a - 2 \, b + x}{{\left (a^{2} + b d - {\left (2 \, a + d\right )} x + x^{2}\right )} \left ({\left (a - x\right )} {\left (b - x\right )}\right )^{\frac {1}{3}}} \,d x } \]

input

integrate((a-2*b+x)/((-a+x)*(-b+x))^(1/3)/(a^2+b*d-(2*a+d)*x+x^2),x, algor 
ithm="maxima")
 

output

integrate((a - 2*b + x)/((a^2 + b*d - (2*a + d)*x + x^2)*((a - x)*(b - x)) 
^(1/3)), x)
 

3.25.67.8 Giac [F]

\[ \int \frac {a-2 b+x}{\sqrt [3]{(-a+x) (-b+x)} \left (a^2+b d-(2 a+d) x+x^2\right )} \, dx=\int { \frac {a - 2 \, b + x}{{\left (a^{2} + b d - {\left (2 \, a + d\right )} x + x^{2}\right )} \left ({\left (a - x\right )} {\left (b - x\right )}\right )^{\frac {1}{3}}} \,d x } \]

input

integrate((a-2*b+x)/((-a+x)*(-b+x))^(1/3)/(a^2+b*d-(2*a+d)*x+x^2),x, algor 
ithm="giac")
 

output

integrate((a - 2*b + x)/((a^2 + b*d - (2*a + d)*x + x^2)*((a - x)*(b - x)) 
^(1/3)), x)
 

3.25.67.9 Mupad [F(-1)]

Timed out. \[ \int \frac {a-2 b+x}{\sqrt [3]{(-a+x) (-b+x)} \left (a^2+b d-(2 a+d) x+x^2\right )} \, dx=\int \frac {a-2\,b+x}{{\left (\left (a-x\right )\,\left (b-x\right )\right )}^{1/3}\,\left (b\,d-x\,\left (2\,a+d\right )+a^2+x^2\right )} \,d x \]

input

int((a - 2*b + x)/(((a - x)*(b - x))^(1/3)*(b*d - x*(2*a + d) + a^2 + x^2) 
),x)
 

output

int((a - 2*b + x)/(((a - x)*(b - x))^(1/3)*(b*d - x*(2*a + d) + a^2 + x^2) 
), x)