3.26.2 \(\int \frac {b+a x^6}{x^3 (-b+a x^3) \sqrt [4]{b x+a x^4}} \, dx\) [2502]

3.26.2.1 Optimal result
3.26.2.2 Mathematica [C] (verified)
3.26.2.3 Rubi [A] (verified)
3.26.2.4 Maple [A] (verified)
3.26.2.5 Fricas [F(-1)]
3.26.2.6 Sympy [F]
3.26.2.7 Maxima [F]
3.26.2.8 Giac [B] (verification not implemented)
3.26.2.9 Mupad [F(-1)]

3.26.2.1 Optimal result

Integrand size = 35, antiderivative size = 208 \[ \int \frac {b+a x^6}{x^3 \left (-b+a x^3\right ) \sqrt [4]{b x+a x^4}} \, dx=\frac {4 \left (b x+a x^4\right )^{3/4}}{9 b x^3}+\frac {2 \arctan \left (\frac {\sqrt [4]{a} \left (b x+a x^4\right )^{3/4}}{b+a x^3}\right )}{3 \sqrt [4]{a}}-\frac {2^{3/4} (a+b) \arctan \left (\frac {\sqrt [4]{2} \sqrt [4]{a} \left (b x+a x^4\right )^{3/4}}{b+a x^3}\right )}{3 \sqrt [4]{a} b}+\frac {2 \text {arctanh}\left (\frac {\sqrt [4]{a} \left (b x+a x^4\right )^{3/4}}{b+a x^3}\right )}{3 \sqrt [4]{a}}-\frac {2^{3/4} (a+b) \text {arctanh}\left (\frac {\sqrt [4]{2} \sqrt [4]{a} \left (b x+a x^4\right )^{3/4}}{b+a x^3}\right )}{3 \sqrt [4]{a} b} \]

output
4/9*(a*x^4+b*x)^(3/4)/b/x^3+2/3*arctan(a^(1/4)*(a*x^4+b*x)^(3/4)/(a*x^3+b) 
)/a^(1/4)-1/3*2^(3/4)*(a+b)*arctan(2^(1/4)*a^(1/4)*(a*x^4+b*x)^(3/4)/(a*x^ 
3+b))/a^(1/4)/b+2/3*arctanh(a^(1/4)*(a*x^4+b*x)^(3/4)/(a*x^3+b))/a^(1/4)-1 
/3*2^(3/4)*(a+b)*arctanh(2^(1/4)*a^(1/4)*(a*x^4+b*x)^(3/4)/(a*x^3+b))/a^(1 
/4)/b
 
3.26.2.2 Mathematica [C] (verified)

Result contains higher order function than in optimal. Order 5 vs. order 3 in optimal.

Time = 13.03 (sec) , antiderivative size = 188, normalized size of antiderivative = 0.90 \[ \int \frac {b+a x^6}{x^3 \left (-b+a x^3\right ) \sqrt [4]{b x+a x^4}} \, dx=\frac {4 \left (-\frac {5 \left (b+a x^3\right )}{a}+15 x^3 \sqrt [4]{1+\frac {a x^3}{b}} \operatorname {Hypergeometric2F1}\left (\frac {1}{4},\frac {1}{4},\frac {5}{4},-\frac {a x^3}{b}\right )+\frac {4 (a+b) \left (b+a x^3\right ) \operatorname {Gamma}\left (\frac {5}{4}\right ) \left (5 \left (b^2+3 a b x^3-4 a^2 x^6\right ) \operatorname {Hypergeometric2F1}\left (1,1,\frac {5}{4},-\frac {2 a x^3}{b-a x^3}\right )-32 a x^3 \left (b+a x^3\right ) \operatorname {Hypergeometric2F1}\left (2,2,\frac {9}{4},-\frac {2 a x^3}{b-a x^3}\right )\right )}{a b \left (b-a x^3\right )^2 \operatorname {Gamma}\left (\frac {1}{4}\right )}\right )}{45 x^2 \sqrt [4]{x \left (b+a x^3\right )}} \]

input
Integrate[(b + a*x^6)/(x^3*(-b + a*x^3)*(b*x + a*x^4)^(1/4)),x]
 
output
(4*((-5*(b + a*x^3))/a + 15*x^3*(1 + (a*x^3)/b)^(1/4)*Hypergeometric2F1[1/ 
4, 1/4, 5/4, -((a*x^3)/b)] + (4*(a + b)*(b + a*x^3)*Gamma[5/4]*(5*(b^2 + 3 
*a*b*x^3 - 4*a^2*x^6)*Hypergeometric2F1[1, 1, 5/4, (-2*a*x^3)/(b - a*x^3)] 
 - 32*a*x^3*(b + a*x^3)*Hypergeometric2F1[2, 2, 9/4, (-2*a*x^3)/(b - a*x^3 
)]))/(a*b*(b - a*x^3)^2*Gamma[1/4])))/(45*x^2*(x*(b + a*x^3))^(1/4))
 
3.26.2.3 Rubi [A] (verified)

Time = 1.20 (sec) , antiderivative size = 215, normalized size of antiderivative = 1.03, number of steps used = 6, number of rules used = 5, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.143, Rules used = {2467, 25, 2035, 7276, 2009}

Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.

\(\displaystyle \int \frac {a x^6+b}{x^3 \left (a x^3-b\right ) \sqrt [4]{a x^4+b x}} \, dx\)

\(\Big \downarrow \) 2467

\(\displaystyle \frac {\sqrt [4]{x} \sqrt [4]{a x^3+b} \int -\frac {a x^6+b}{x^{13/4} \left (b-a x^3\right ) \sqrt [4]{a x^3+b}}dx}{\sqrt [4]{a x^4+b x}}\)

\(\Big \downarrow \) 25

\(\displaystyle -\frac {\sqrt [4]{x} \sqrt [4]{a x^3+b} \int \frac {a x^6+b}{x^{13/4} \left (b-a x^3\right ) \sqrt [4]{a x^3+b}}dx}{\sqrt [4]{a x^4+b x}}\)

\(\Big \downarrow \) 2035

\(\displaystyle -\frac {4 \sqrt [4]{x} \sqrt [4]{a x^3+b} \int \frac {a x^6+b}{x^{5/2} \left (b-a x^3\right ) \sqrt [4]{a x^3+b}}d\sqrt [4]{x}}{\sqrt [4]{a x^4+b x}}\)

\(\Big \downarrow \) 7276

\(\displaystyle -\frac {4 \sqrt [4]{x} \sqrt [4]{a x^3+b} \int \left (-\frac {\sqrt {x} (a+b)}{\left (a x^3-b\right ) \sqrt [4]{a x^3+b}}-\frac {\sqrt {x}}{\sqrt [4]{a x^3+b}}+\frac {1}{x^{5/2} \sqrt [4]{a x^3+b}}\right )d\sqrt [4]{x}}{\sqrt [4]{a x^4+b x}}\)

\(\Big \downarrow \) 2009

\(\displaystyle -\frac {4 \sqrt [4]{x} \sqrt [4]{a x^3+b} \left (-\frac {\arctan \left (\frac {\sqrt [4]{a} x^{3/4}}{\sqrt [4]{a x^3+b}}\right )}{6 \sqrt [4]{a}}+\frac {(a+b) \arctan \left (\frac {\sqrt [4]{2} \sqrt [4]{a} x^{3/4}}{\sqrt [4]{a x^3+b}}\right )}{6 \sqrt [4]{2} \sqrt [4]{a} b}-\frac {\text {arctanh}\left (\frac {\sqrt [4]{a} x^{3/4}}{\sqrt [4]{a x^3+b}}\right )}{6 \sqrt [4]{a}}+\frac {(a+b) \text {arctanh}\left (\frac {\sqrt [4]{2} \sqrt [4]{a} x^{3/4}}{\sqrt [4]{a x^3+b}}\right )}{6 \sqrt [4]{2} \sqrt [4]{a} b}-\frac {\left (a x^3+b\right )^{3/4}}{9 b x^{9/4}}\right )}{\sqrt [4]{a x^4+b x}}\)

input
Int[(b + a*x^6)/(x^3*(-b + a*x^3)*(b*x + a*x^4)^(1/4)),x]
 
output
(-4*x^(1/4)*(b + a*x^3)^(1/4)*(-1/9*(b + a*x^3)^(3/4)/(b*x^(9/4)) - ArcTan 
[(a^(1/4)*x^(3/4))/(b + a*x^3)^(1/4)]/(6*a^(1/4)) + ((a + b)*ArcTan[(2^(1/ 
4)*a^(1/4)*x^(3/4))/(b + a*x^3)^(1/4)])/(6*2^(1/4)*a^(1/4)*b) - ArcTanh[(a 
^(1/4)*x^(3/4))/(b + a*x^3)^(1/4)]/(6*a^(1/4)) + ((a + b)*ArcTanh[(2^(1/4) 
*a^(1/4)*x^(3/4))/(b + a*x^3)^(1/4)])/(6*2^(1/4)*a^(1/4)*b)))/(b*x + a*x^4 
)^(1/4)
 

3.26.2.3.1 Defintions of rubi rules used

rule 25
Int[-(Fx_), x_Symbol] :> Simp[Identity[-1]   Int[Fx, x], x]
 

rule 2009
Int[u_, x_Symbol] :> Simp[IntSum[u, x], x] /; SumQ[u]
 

rule 2035
Int[(Fx_)*(x_)^(m_), x_Symbol] :> With[{k = Denominator[m]}, Simp[k   Subst 
[Int[x^(k*(m + 1) - 1)*SubstPower[Fx, x, k], x], x, x^(1/k)], x]] /; Fracti 
onQ[m] && AlgebraicFunctionQ[Fx, x]
 

rule 2467
Int[(Fx_.)*(Px_)^(p_), x_Symbol] :> With[{r = Expon[Px, x, Min]}, Simp[Px^F 
racPart[p]/(x^(r*FracPart[p])*ExpandToSum[Px/x^r, x]^FracPart[p])   Int[x^( 
p*r)*ExpandToSum[Px/x^r, x]^p*Fx, x], x] /; IGtQ[r, 0]] /; FreeQ[p, x] && P 
olyQ[Px, x] &&  !IntegerQ[p] &&  !MonomialQ[Px, x] &&  !PolyQ[Fx, x]
 

rule 7276
Int[(u_)/((a_) + (b_.)*(x_)^(n_)), x_Symbol] :> With[{v = RationalFunctionE 
xpand[u/(a + b*x^n), x]}, Int[v, x] /; SumQ[v]] /; FreeQ[{a, b}, x] && IGtQ 
[n, 0]
 
3.26.2.4 Maple [A] (verified)

Time = 0.78 (sec) , antiderivative size = 187, normalized size of antiderivative = 0.90

method result size
pseudoelliptic \(\frac {-\frac {\ln \left (\frac {x 2^{\frac {1}{4}} a^{\frac {1}{4}}+{\left (x \left (a \,x^{3}+b \right )\right )}^{\frac {1}{4}}}{-x 2^{\frac {1}{4}} a^{\frac {1}{4}}+{\left (x \left (a \,x^{3}+b \right )\right )}^{\frac {1}{4}}}\right ) \left (a +b \right ) 2^{\frac {3}{4}} x^{3}}{2}+\ln \left (\frac {x \,a^{\frac {1}{4}}+{\left (x \left (a \,x^{3}+b \right )\right )}^{\frac {1}{4}}}{-x \,a^{\frac {1}{4}}+{\left (x \left (a \,x^{3}+b \right )\right )}^{\frac {1}{4}}}\right ) b \,x^{3}+\arctan \left (\frac {{\left (x \left (a \,x^{3}+b \right )\right )}^{\frac {1}{4}} 2^{\frac {3}{4}}}{2 x \,a^{\frac {1}{4}}}\right ) \left (a +b \right ) 2^{\frac {3}{4}} x^{3}-2 \arctan \left (\frac {{\left (x \left (a \,x^{3}+b \right )\right )}^{\frac {1}{4}}}{x \,a^{\frac {1}{4}}}\right ) b \,x^{3}+\frac {4 {\left (x \left (a \,x^{3}+b \right )\right )}^{\frac {3}{4}} a^{\frac {1}{4}}}{3}}{3 a^{\frac {1}{4}} x^{3} b}\) \(187\)

input
int((a*x^6+b)/x^3/(a*x^3-b)/(a*x^4+b*x)^(1/4),x,method=_RETURNVERBOSE)
 
output
1/3*(-1/2*ln((x*2^(1/4)*a^(1/4)+(x*(a*x^3+b))^(1/4))/(-x*2^(1/4)*a^(1/4)+( 
x*(a*x^3+b))^(1/4)))*(a+b)*2^(3/4)*x^3+ln((x*a^(1/4)+(x*(a*x^3+b))^(1/4))/ 
(-x*a^(1/4)+(x*(a*x^3+b))^(1/4)))*b*x^3+arctan(1/2*(x*(a*x^3+b))^(1/4)/x*2 
^(3/4)/a^(1/4))*(a+b)*2^(3/4)*x^3-2*arctan((x*(a*x^3+b))^(1/4)/x/a^(1/4))* 
b*x^3+4/3*(x*(a*x^3+b))^(3/4)*a^(1/4))/a^(1/4)/x^3/b
 
3.26.2.5 Fricas [F(-1)]

Timed out. \[ \int \frac {b+a x^6}{x^3 \left (-b+a x^3\right ) \sqrt [4]{b x+a x^4}} \, dx=\text {Timed out} \]

input
integrate((a*x^6+b)/x^3/(a*x^3-b)/(a*x^4+b*x)^(1/4),x, algorithm="fricas")
 
output
Timed out
 
3.26.2.6 Sympy [F]

\[ \int \frac {b+a x^6}{x^3 \left (-b+a x^3\right ) \sqrt [4]{b x+a x^4}} \, dx=\int \frac {a x^{6} + b}{x^{3} \sqrt [4]{x \left (a x^{3} + b\right )} \left (a x^{3} - b\right )}\, dx \]

input
integrate((a*x**6+b)/x**3/(a*x**3-b)/(a*x**4+b*x)**(1/4),x)
 
output
Integral((a*x**6 + b)/(x**3*(x*(a*x**3 + b))**(1/4)*(a*x**3 - b)), x)
 
3.26.2.7 Maxima [F]

\[ \int \frac {b+a x^6}{x^3 \left (-b+a x^3\right ) \sqrt [4]{b x+a x^4}} \, dx=\int { \frac {a x^{6} + b}{{\left (a x^{4} + b x\right )}^{\frac {1}{4}} {\left (a x^{3} - b\right )} x^{3}} \,d x } \]

input
integrate((a*x^6+b)/x^3/(a*x^3-b)/(a*x^4+b*x)^(1/4),x, algorithm="maxima")
 
output
integrate((a*x^6 + b)/((a*x^4 + b*x)^(1/4)*(a*x^3 - b)*x^3), x)
 
3.26.2.8 Giac [B] (verification not implemented)

Leaf count of result is larger than twice the leaf count of optimal. 437 vs. \(2 (164) = 328\).

Time = 0.30 (sec) , antiderivative size = 437, normalized size of antiderivative = 2.10 \[ \int \frac {b+a x^6}{x^3 \left (-b+a x^3\right ) \sqrt [4]{b x+a x^4}} \, dx=\frac {\sqrt {2} \left (-a\right )^{\frac {3}{4}} \arctan \left (\frac {\sqrt {2} {\left (\sqrt {2} \left (-a\right )^{\frac {1}{4}} + 2 \, {\left (a + \frac {b}{x^{3}}\right )}^{\frac {1}{4}}\right )}}{2 \, \left (-a\right )^{\frac {1}{4}}}\right )}{3 \, a} + \frac {\sqrt {2} \left (-a\right )^{\frac {3}{4}} \arctan \left (-\frac {\sqrt {2} {\left (\sqrt {2} \left (-a\right )^{\frac {1}{4}} - 2 \, {\left (a + \frac {b}{x^{3}}\right )}^{\frac {1}{4}}\right )}}{2 \, \left (-a\right )^{\frac {1}{4}}}\right )}{3 \, a} - \frac {\sqrt {2} \left (-a\right )^{\frac {3}{4}} \log \left (\sqrt {2} \left (-a\right )^{\frac {1}{4}} {\left (a + \frac {b}{x^{3}}\right )}^{\frac {1}{4}} + \sqrt {-a} + \sqrt {a + \frac {b}{x^{3}}}\right )}{6 \, a} + \frac {\sqrt {2} \left (-a\right )^{\frac {3}{4}} \log \left (-\sqrt {2} \left (-a\right )^{\frac {1}{4}} {\left (a + \frac {b}{x^{3}}\right )}^{\frac {1}{4}} + \sqrt {-a} + \sqrt {a + \frac {b}{x^{3}}}\right )}{6 \, a} - \frac {2^{\frac {1}{4}} {\left (a + b\right )} \log \left (2^{\frac {3}{4}} \left (-a\right )^{\frac {1}{4}} {\left (a + \frac {b}{x^{3}}\right )}^{\frac {1}{4}} + \sqrt {2} \sqrt {-a} + \sqrt {a + \frac {b}{x^{3}}}\right )}{6 \, \left (-a\right )^{\frac {1}{4}} b} + \frac {2^{\frac {1}{4}} {\left (a + b\right )} \log \left (-2^{\frac {3}{4}} \left (-a\right )^{\frac {1}{4}} {\left (a + \frac {b}{x^{3}}\right )}^{\frac {1}{4}} + \sqrt {2} \sqrt {-a} + \sqrt {a + \frac {b}{x^{3}}}\right )}{6 \, \left (-a\right )^{\frac {1}{4}} b} - \frac {\sqrt {2} {\left (2^{\frac {3}{4}} \left (-a\right )^{\frac {3}{4}} a + 2^{\frac {3}{4}} \left (-a\right )^{\frac {3}{4}} b\right )} \arctan \left (\frac {2^{\frac {1}{4}} {\left (2^{\frac {3}{4}} \left (-a\right )^{\frac {1}{4}} + 2 \, {\left (a + \frac {b}{x^{3}}\right )}^{\frac {1}{4}}\right )}}{2 \, \left (-a\right )^{\frac {1}{4}}}\right )}{6 \, a b} - \frac {\sqrt {2} {\left (2^{\frac {3}{4}} \left (-a\right )^{\frac {3}{4}} a + 2^{\frac {3}{4}} \left (-a\right )^{\frac {3}{4}} b\right )} \arctan \left (-\frac {2^{\frac {1}{4}} {\left (2^{\frac {3}{4}} \left (-a\right )^{\frac {1}{4}} - 2 \, {\left (a + \frac {b}{x^{3}}\right )}^{\frac {1}{4}}\right )}}{2 \, \left (-a\right )^{\frac {1}{4}}}\right )}{6 \, a b} + \frac {4 \, {\left (a + \frac {b}{x^{3}}\right )}^{\frac {3}{4}}}{9 \, b} \]

input
integrate((a*x^6+b)/x^3/(a*x^3-b)/(a*x^4+b*x)^(1/4),x, algorithm="giac")
 
output
1/3*sqrt(2)*(-a)^(3/4)*arctan(1/2*sqrt(2)*(sqrt(2)*(-a)^(1/4) + 2*(a + b/x 
^3)^(1/4))/(-a)^(1/4))/a + 1/3*sqrt(2)*(-a)^(3/4)*arctan(-1/2*sqrt(2)*(sqr 
t(2)*(-a)^(1/4) - 2*(a + b/x^3)^(1/4))/(-a)^(1/4))/a - 1/6*sqrt(2)*(-a)^(3 
/4)*log(sqrt(2)*(-a)^(1/4)*(a + b/x^3)^(1/4) + sqrt(-a) + sqrt(a + b/x^3)) 
/a + 1/6*sqrt(2)*(-a)^(3/4)*log(-sqrt(2)*(-a)^(1/4)*(a + b/x^3)^(1/4) + sq 
rt(-a) + sqrt(a + b/x^3))/a - 1/6*2^(1/4)*(a + b)*log(2^(3/4)*(-a)^(1/4)*( 
a + b/x^3)^(1/4) + sqrt(2)*sqrt(-a) + sqrt(a + b/x^3))/((-a)^(1/4)*b) + 1/ 
6*2^(1/4)*(a + b)*log(-2^(3/4)*(-a)^(1/4)*(a + b/x^3)^(1/4) + sqrt(2)*sqrt 
(-a) + sqrt(a + b/x^3))/((-a)^(1/4)*b) - 1/6*sqrt(2)*(2^(3/4)*(-a)^(3/4)*a 
 + 2^(3/4)*(-a)^(3/4)*b)*arctan(1/2*2^(1/4)*(2^(3/4)*(-a)^(1/4) + 2*(a + b 
/x^3)^(1/4))/(-a)^(1/4))/(a*b) - 1/6*sqrt(2)*(2^(3/4)*(-a)^(3/4)*a + 2^(3/ 
4)*(-a)^(3/4)*b)*arctan(-1/2*2^(1/4)*(2^(3/4)*(-a)^(1/4) - 2*(a + b/x^3)^( 
1/4))/(-a)^(1/4))/(a*b) + 4/9*(a + b/x^3)^(3/4)/b
 
3.26.2.9 Mupad [F(-1)]

Timed out. \[ \int \frac {b+a x^6}{x^3 \left (-b+a x^3\right ) \sqrt [4]{b x+a x^4}} \, dx=-\int \frac {a\,x^6+b}{x^3\,{\left (a\,x^4+b\,x\right )}^{1/4}\,\left (b-a\,x^3\right )} \,d x \]

input
int(-(b + a*x^6)/(x^3*(b*x + a*x^4)^(1/4)*(b - a*x^3)),x)
 
output
-int((b + a*x^6)/(x^3*(b*x + a*x^4)^(1/4)*(b - a*x^3)), x)