3.30.35 \(\int \frac {1}{(b+a x) \sqrt [4]{b^2 x+a^2 x^3}} \, dx\) [2935]

3.30.35.1 Optimal result

Integrand size = 25, antiderivative size = 345 \[ \int \frac {1}{(b+a x) \sqrt [4]{b^2 x+a^2 x^3}} \, dx=\frac {\arctan \left (\frac {2 \sqrt [4]{a} \sqrt [4]{b} \sqrt [4]{b^2 x+a^2 x^3}}{2^{3/4} b-2^{3/4} a x+2 \sqrt [4]{a} \sqrt [4]{b} \sqrt [4]{b^2 x+a^2 x^3}}\right )}{2\ 2^{3/4} a^{3/4} b^{3/4}}-\frac {\arctan \left (\frac {2 \sqrt [4]{a} \sqrt [4]{b} \sqrt [4]{b^2 x+a^2 x^3}}{-2^{3/4} b+2^{3/4} a x+2 \sqrt [4]{a} \sqrt [4]{b} \sqrt [4]{b^2 x+a^2 x^3}}\right )}{2\ 2^{3/4} a^{3/4} b^{3/4}}-\frac {\text {arctanh}\left (\frac {-\frac {b^2}{\sqrt [4]{2}}+2^{3/4} a b x-\frac {a^2 x^2}{\sqrt [4]{2}}-2 \sqrt [4]{2} \sqrt {a} \sqrt {b} \sqrt {b^2 x+a^2 x^3}}{-2 \sqrt [4]{a} b^{5/4} \sqrt [4]{b^2 x+a^2 x^3}+2 a^{5/4} \sqrt [4]{b} x \sqrt [4]{b^2 x+a^2 x^3}}\right )}{2\ 2^{3/4} a^{3/4} b^{3/4}} \]

output

1/4*arctan(2*a^(1/4)*b^(1/4)*(a^2*x^3+b^2*x)^(1/4)/(2^(3/4)*b-2^(3/4)*a*x+ 
2*a^(1/4)*b^(1/4)*(a^2*x^3+b^2*x)^(1/4)))*2^(1/4)/a^(3/4)/b^(3/4)-1/4*arct 
an(2*a^(1/4)*b^(1/4)*(a^2*x^3+b^2*x)^(1/4)/(-2^(3/4)*b+2^(3/4)*a*x+2*a^(1/ 
4)*b^(1/4)*(a^2*x^3+b^2*x)^(1/4)))*2^(1/4)/a^(3/4)/b^(3/4)-1/4*arctanh((-1 
/2*2^(3/4)*b^2+2^(3/4)*a*b*x-1/2*a^2*x^2*2^(3/4)-2*2^(1/4)*a^(1/2)*b^(1/2) 
*(a^2*x^3+b^2*x)^(1/2))/(-2*a^(1/4)*b^(5/4)*(a^2*x^3+b^2*x)^(1/4)+2*a^(5/4 
)*b^(1/4)*x*(a^2*x^3+b^2*x)^(1/4)))*2^(1/4)/a^(3/4)/b^(3/4)
 

3.30.35.2 Mathematica [F]

\[ \int \frac {1}{(b+a x) \sqrt [4]{b^2 x+a^2 x^3}} \, dx=\int \frac {1}{(b+a x) \sqrt [4]{b^2 x+a^2 x^3}} \, dx \]

input

Integrate[1/((b + a*x)*(b^2*x + a^2*x^3)^(1/4)),x]
 

output

Integrate[1/((b + a*x)*(b^2*x + a^2*x^3)^(1/4)), x]
 

3.30.35.3 Rubi [F]

Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.

\(\displaystyle \int \frac {1}{(a x+b) \sqrt [4]{a^2 x^3+b^2 x}} \, dx\)

\(\Big \downarrow \) 2467

\(\displaystyle \frac {\sqrt [4]{x} \sqrt [4]{a^2 x^2+b^2} \int \frac {1}{\sqrt [4]{x} (b+a x) \sqrt [4]{b^2+a^2 x^2}}dx}{\sqrt [4]{a^2 x^3+b^2 x}}\)

\(\Big \downarrow \) 616

\(\displaystyle \frac {4 \sqrt [4]{x} \sqrt [4]{a^2 x^2+b^2} \int \frac {\sqrt {x}}{(b+a x) \sqrt [4]{b^2+a^2 x^2}}d\sqrt [4]{x}}{\sqrt [4]{a^2 x^3+b^2 x}}\)

\(\Big \downarrow \) 1888

\(\displaystyle \frac {4 \sqrt [4]{x} \sqrt [4]{a^2 x^2+b^2} \int \frac {\sqrt {x}}{(b+a x) \sqrt [4]{b^2+a^2 x^2}}d\sqrt [4]{x}}{\sqrt [4]{a^2 x^3+b^2 x}}\)

input

Int[1/((b + a*x)*(b^2*x + a^2*x^3)^(1/4)),x]
 

output

$Aborted
 

3.30.35.3.1 Defintions of rubi rules used

rule 616

Int[((e_.)*(x_))^(m_)*((c_) + (d_.)*(x_))^(n_)*((a_) + (b_.)*(x_)^2)^(p_), 
x_Symbol] :> With[{k = Denominator[m]}, Simp[k/e   Subst[Int[x^(k*(m + 1) - 
 1)*(c + d*(x^k/e))^n*(a + b*(x^(2*k)/e^2))^p, x], x, (e*x)^(1/k)], x]] /; 
FreeQ[{a, b, c, d, e, p}, x] && ILtQ[n, 0] && FractionQ[m]
 

rule 1888

Int[((f_.)*(x_))^(m_.)*((a_) + (c_.)*(x_)^(n2_.))^(p_.)*((d_) + (e_.)*(x_)^ 
(n_))^(q_.), x_Symbol] :> Unintegrable[(f*x)^m*(d + e*x^n)^q*(a + c*x^(2*n) 
)^p, x] /; FreeQ[{a, c, d, e, f, m, n, p, q}, x] && EqQ[n2, 2*n]
 

rule 2467

Int[(Fx_.)*(Px_)^(p_), x_Symbol] :> With[{r = Expon[Px, x, Min]}, Simp[Px^F 
racPart[p]/(x^(r*FracPart[p])*ExpandToSum[Px/x^r, x]^FracPart[p])   Int[x^( 
p*r)*ExpandToSum[Px/x^r, x]^p*Fx, x], x] /; IGtQ[r, 0]] /; FreeQ[p, x] && P 
olyQ[Px, x] &&  !IntegerQ[p] &&  !MonomialQ[Px, x] &&  !PolyQ[Fx, x]
 

3.30.35.4 Maple [F]

\[\int \frac {1}{\left (a x +b \right ) \left (a^{2} x^{3}+b^{2} x \right )^{\frac {1}{4}}}d x\]

input

int(1/(a*x+b)/(a^2*x^3+b^2*x)^(1/4),x)
 

output

int(1/(a*x+b)/(a^2*x^3+b^2*x)^(1/4),x)
 

3.30.35.5 Fricas [F(-1)]

Timed out. \[ \int \frac {1}{(b+a x) \sqrt [4]{b^2 x+a^2 x^3}} \, dx=\text {Timed out} \]

input

integrate(1/(a*x+b)/(a^2*x^3+b^2*x)^(1/4),x, algorithm="fricas")
 

output

Timed out
 

3.30.35.6 Sympy [F]

\[ \int \frac {1}{(b+a x) \sqrt [4]{b^2 x+a^2 x^3}} \, dx=\int \frac {1}{\sqrt [4]{x \left (a^{2} x^{2} + b^{2}\right )} \left (a x + b\right )}\, dx \]

input

integrate(1/(a*x+b)/(a**2*x**3+b**2*x)**(1/4),x)
 

output

Integral(1/((x*(a**2*x**2 + b**2))**(1/4)*(a*x + b)), x)
 

3.30.35.7 Maxima [F]

\[ \int \frac {1}{(b+a x) \sqrt [4]{b^2 x+a^2 x^3}} \, dx=\int { \frac {1}{{\left (a^{2} x^{3} + b^{2} x\right )}^{\frac {1}{4}} {\left (a x + b\right )}} \,d x } \]

input

integrate(1/(a*x+b)/(a^2*x^3+b^2*x)^(1/4),x, algorithm="maxima")
 

output

integrate(1/((a^2*x^3 + b^2*x)^(1/4)*(a*x + b)), x)
 

3.30.35.8 Giac [F]

\[ \int \frac {1}{(b+a x) \sqrt [4]{b^2 x+a^2 x^3}} \, dx=\int { \frac {1}{{\left (a^{2} x^{3} + b^{2} x\right )}^{\frac {1}{4}} {\left (a x + b\right )}} \,d x } \]

input

integrate(1/(a*x+b)/(a^2*x^3+b^2*x)^(1/4),x, algorithm="giac")
 

output

integrate(1/((a^2*x^3 + b^2*x)^(1/4)*(a*x + b)), x)
 

3.30.35.9 Mupad [F(-1)]

Timed out. \[ \int \frac {1}{(b+a x) \sqrt [4]{b^2 x+a^2 x^3}} \, dx=\int \frac {1}{{\left (a^2\,x^3+b^2\,x\right )}^{1/4}\,\left (b+a\,x\right )} \,d x \]

input

int(1/((b^2*x + a^2*x^3)^(1/4)*(b + a*x)),x)
 

output

int(1/((b^2*x + a^2*x^3)^(1/4)*(b + a*x)), x)