Integrand size = 41, antiderivative size = 371 \[ \int \frac {x^3 \left (5 b+9 a x^4\right )}{\sqrt [4]{b x+a x^5} \left (1+b x^5+a x^9\right )} \, dx=-\sqrt {2} \arctan \left (\frac {-2^{2/3} x \sqrt [4]{b x+a x^5}+x^2 \sqrt [4]{b x+a x^5}}{2 \sqrt [6]{2}-\sqrt {2} x+2^{2/3} x \sqrt [4]{b x+a x^5}-x^2 \sqrt [4]{b x+a x^5}}\right )+\sqrt {2} \arctan \left (\frac {-2^{2/3} x \sqrt [4]{b x+a x^5}+x^2 \sqrt [4]{b x+a x^5}}{-2 \sqrt [6]{2}+\sqrt {2} x+2^{2/3} x \sqrt [4]{b x+a x^5}-x^2 \sqrt [4]{b x+a x^5}}\right )-\sqrt {2} \text {arctanh}\left (\frac {-2 2^{5/6} x \sqrt [4]{b x+a x^5}+4 \sqrt [6]{2} x^2 \sqrt [4]{b x+a x^5}-\sqrt {2} x^3 \sqrt [4]{b x+a x^5}}{-2 \sqrt [3]{2}+2\ 2^{2/3} x-x^2-2 \sqrt [3]{2} x^2 \sqrt {b x+a x^5}+2\ 2^{2/3} x^3 \sqrt {b x+a x^5}-x^4 \sqrt {b x+a x^5}}\right ) \]
-2^(1/2)*arctan((-2^(2/3)*x*(a*x^5+b*x)^(1/4)+x^2*(a*x^5+b*x)^(1/4))/(2*2^ (1/6)-x*2^(1/2)+2^(2/3)*x*(a*x^5+b*x)^(1/4)-x^2*(a*x^5+b*x)^(1/4)))+2^(1/2 )*arctan((-2^(2/3)*x*(a*x^5+b*x)^(1/4)+x^2*(a*x^5+b*x)^(1/4))/(-2*2^(1/6)+ x*2^(1/2)+2^(2/3)*x*(a*x^5+b*x)^(1/4)-x^2*(a*x^5+b*x)^(1/4)))-2^(1/2)*arct anh((-2*2^(5/6)*x*(a*x^5+b*x)^(1/4)+4*2^(1/6)*x^2*(a*x^5+b*x)^(1/4)-2^(1/2 )*(a*x^5+b*x)^(1/4)*x^3)/(-2*2^(1/3)+2*2^(2/3)*x-x^2-2*2^(1/3)*x^2*(a*x^5+ b*x)^(1/2)+2*2^(2/3)*x^3*(a*x^5+b*x)^(1/2)-x^4*(a*x^5+b*x)^(1/2)))
\[ \int \frac {x^3 \left (5 b+9 a x^4\right )}{\sqrt [4]{b x+a x^5} \left (1+b x^5+a x^9\right )} \, dx=\int \frac {x^3 \left (5 b+9 a x^4\right )}{\sqrt [4]{b x+a x^5} \left (1+b x^5+a x^9\right )} \, dx \]
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int \frac {x^3 \left (9 a x^4+5 b\right )}{\sqrt [4]{a x^5+b x} \left (a x^9+b x^5+1\right )} \, dx\) |
\(\Big \downarrow \) 2467 |
\(\displaystyle \frac {\sqrt [4]{x} \sqrt [4]{a x^4+b} \int \frac {x^{11/4} \left (9 a x^4+5 b\right )}{\sqrt [4]{a x^4+b} \left (a x^9+b x^5+1\right )}dx}{\sqrt [4]{a x^5+b x}}\) |
\(\Big \downarrow \) 2035 |
\(\displaystyle \frac {4 \sqrt [4]{x} \sqrt [4]{a x^4+b} \int \frac {x^{7/2} \left (9 a x^4+5 b\right )}{\sqrt [4]{a x^4+b} \left (a x^9+b x^5+1\right )}d\sqrt [4]{x}}{\sqrt [4]{a x^5+b x}}\) |
\(\Big \downarrow \) 7293 |
\(\displaystyle \frac {4 \sqrt [4]{x} \sqrt [4]{a x^4+b} \int \left (\frac {9 a x^{15/2}}{\sqrt [4]{a x^4+b} \left (a x^9+b x^5+1\right )}+\frac {5 b x^{7/2}}{\sqrt [4]{a x^4+b} \left (a x^9+b x^5+1\right )}\right )d\sqrt [4]{x}}{\sqrt [4]{a x^5+b x}}\) |
\(\Big \downarrow \) 2009 |
\(\displaystyle \frac {4 \sqrt [4]{x} \sqrt [4]{a x^4+b} \left (5 b \int \frac {x^{7/2}}{\sqrt [4]{a x^4+b} \left (a x^9+b x^5+1\right )}d\sqrt [4]{x}+9 a \int \frac {x^{15/2}}{\sqrt [4]{a x^4+b} \left (a x^9+b x^5+1\right )}d\sqrt [4]{x}\right )}{\sqrt [4]{a x^5+b x}}\) |
3.30.70.3.1 Defintions of rubi rules used
Int[(Fx_)*(x_)^(m_), x_Symbol] :> With[{k = Denominator[m]}, Simp[k Subst [Int[x^(k*(m + 1) - 1)*SubstPower[Fx, x, k], x], x, x^(1/k)], x]] /; Fracti onQ[m] && AlgebraicFunctionQ[Fx, x]
Int[(Fx_.)*(Px_)^(p_), x_Symbol] :> With[{r = Expon[Px, x, Min]}, Simp[Px^F racPart[p]/(x^(r*FracPart[p])*ExpandToSum[Px/x^r, x]^FracPart[p]) Int[x^( p*r)*ExpandToSum[Px/x^r, x]^p*Fx, x], x] /; IGtQ[r, 0]] /; FreeQ[p, x] && P olyQ[Px, x] && !IntegerQ[p] && !MonomialQ[Px, x] && !PolyQ[Fx, x]
\[\int \frac {x^{3} \left (9 a \,x^{4}+5 b \right )}{\left (a \,x^{5}+b x \right )^{\frac {1}{4}} \left (a \,x^{9}+b \,x^{5}+1\right )}d x\]
Timed out. \[ \int \frac {x^3 \left (5 b+9 a x^4\right )}{\sqrt [4]{b x+a x^5} \left (1+b x^5+a x^9\right )} \, dx=\text {Timed out} \]
\[ \int \frac {x^3 \left (5 b+9 a x^4\right )}{\sqrt [4]{b x+a x^5} \left (1+b x^5+a x^9\right )} \, dx=\int \frac {x^{3} \cdot \left (9 a x^{4} + 5 b\right )}{\sqrt [4]{x \left (a x^{4} + b\right )} \left (a x^{9} + b x^{5} + 1\right )}\, dx \]
\[ \int \frac {x^3 \left (5 b+9 a x^4\right )}{\sqrt [4]{b x+a x^5} \left (1+b x^5+a x^9\right )} \, dx=\int { \frac {{\left (9 \, a x^{4} + 5 \, b\right )} x^{3}}{{\left (a x^{9} + b x^{5} + 1\right )} {\left (a x^{5} + b x\right )}^{\frac {1}{4}}} \,d x } \]
\[ \int \frac {x^3 \left (5 b+9 a x^4\right )}{\sqrt [4]{b x+a x^5} \left (1+b x^5+a x^9\right )} \, dx=\int { \frac {{\left (9 \, a x^{4} + 5 \, b\right )} x^{3}}{{\left (a x^{9} + b x^{5} + 1\right )} {\left (a x^{5} + b x\right )}^{\frac {1}{4}}} \,d x } \]
Timed out. \[ \int \frac {x^3 \left (5 b+9 a x^4\right )}{\sqrt [4]{b x+a x^5} \left (1+b x^5+a x^9\right )} \, dx=\int \frac {x^3\,\left (9\,a\,x^4+5\,b\right )}{{\left (a\,x^5+b\,x\right )}^{1/4}\,\left (a\,x^9+b\,x^5+1\right )} \,d x \]