Integrand size = 44, antiderivative size = 569 \[ \int \frac {\left (b^2+a x^2\right )^2}{\left (-b^2+a x^2\right )^2 \sqrt {b+\sqrt {b^2+a x^2}}} \, dx=\frac {2 x \left (-2 b^2+a x^2\right )}{\left (-b^2+a x^2\right ) \sqrt {b+\sqrt {b^2+a x^2}}}-\frac {2 \sqrt {2} \sqrt {b} \arctan \left (\frac {\sqrt {a} x}{\sqrt {2} \sqrt {b} \sqrt {b+\sqrt {b^2+a x^2}}}-\frac {\sqrt {b+\sqrt {b^2+a x^2}}}{\sqrt {2} \sqrt {b}}\right )}{\sqrt {a}}-\frac {\sqrt {\frac {1}{2} \left (-1+\sqrt {2}\right )} \sqrt {b} \arctan \left (\frac {\sqrt {a} x}{\sqrt {2 \left (-1+\sqrt {2}\right )} \sqrt {b} \sqrt {b+\sqrt {b^2+a x^2}}}-\frac {\sqrt {b+\sqrt {b^2+a x^2}}}{\sqrt {2 \left (-1+\sqrt {2}\right )} \sqrt {b}}\right )}{\sqrt {a}}-\frac {\sqrt {\frac {1}{2} \left (-1+\sqrt {2}\right )} \sqrt {b} \arctan \left (\frac {\sqrt {a} x}{\sqrt {2 \left (1+\sqrt {2}\right )} \sqrt {b} \sqrt {b+\sqrt {b^2+a x^2}}}-\frac {\sqrt {b+\sqrt {b^2+a x^2}}}{\sqrt {2 \left (1+\sqrt {2}\right )} \sqrt {b}}\right )}{\sqrt {a}}-\frac {\sqrt {-1+\sqrt {2}} \left (2+\sqrt {2}\right ) \sqrt {b} \text {arctanh}\left (\frac {-\frac {a x}{\sqrt {b+\sqrt {b^2+a x^2}}}+\sqrt {a} \sqrt {b+\sqrt {b^2+a x^2}}}{\sqrt {2 \left (-1+\sqrt {2}\right )} \sqrt {a} \sqrt {b}}\right )}{2 \sqrt {a}}+\frac {\sqrt {-1+\sqrt {2}} \left (2+\sqrt {2}\right ) \sqrt {b} \text {arctanh}\left (\frac {-\frac {a x}{\sqrt {b+\sqrt {b^2+a x^2}}}+\sqrt {a} \sqrt {b+\sqrt {b^2+a x^2}}}{\sqrt {2 \left (1+\sqrt {2}\right )} \sqrt {a} \sqrt {b}}\right )}{2 \sqrt {a}} \]
2*x*(a*x^2-2*b^2)/(a*x^2-b^2)/(b+(a*x^2+b^2)^(1/2))^(1/2)-2*2^(1/2)*b^(1/2 )*arctan(1/2*a^(1/2)*x*2^(1/2)/b^(1/2)/(b+(a*x^2+b^2)^(1/2))^(1/2)-1/2*(b+ (a*x^2+b^2)^(1/2))^(1/2)*2^(1/2)/b^(1/2))/a^(1/2)-1/2*(-2+2*2^(1/2))^(1/2) *b^(1/2)*arctan(a^(1/2)*x/(-2+2*2^(1/2))^(1/2)/b^(1/2)/(b+(a*x^2+b^2)^(1/2 ))^(1/2)-(b+(a*x^2+b^2)^(1/2))^(1/2)/(-2+2*2^(1/2))^(1/2)/b^(1/2))/a^(1/2) -1/2*(-2+2*2^(1/2))^(1/2)*b^(1/2)*arctan(a^(1/2)*x/(2+2*2^(1/2))^(1/2)/b^( 1/2)/(b+(a*x^2+b^2)^(1/2))^(1/2)-(b+(a*x^2+b^2)^(1/2))^(1/2)/(2+2*2^(1/2)) ^(1/2)/b^(1/2))/a^(1/2)-1/2*(2^(1/2)-1)^(1/2)*(2+2^(1/2))*b^(1/2)*arctanh( (-a*x/(b+(a*x^2+b^2)^(1/2))^(1/2)+a^(1/2)*(b+(a*x^2+b^2)^(1/2))^(1/2))/(-2 +2*2^(1/2))^(1/2)/a^(1/2)/b^(1/2))/a^(1/2)+1/2*(2^(1/2)-1)^(1/2)*(2+2^(1/2 ))*b^(1/2)*arctanh((-a*x/(b+(a*x^2+b^2)^(1/2))^(1/2)+a^(1/2)*(b+(a*x^2+b^2 )^(1/2))^(1/2))/(2+2*2^(1/2))^(1/2)/a^(1/2)/b^(1/2))/a^(1/2)
Time = 1.04 (sec) , antiderivative size = 238, normalized size of antiderivative = 0.42 \[ \int \frac {\left (b^2+a x^2\right )^2}{\left (-b^2+a x^2\right )^2 \sqrt {b+\sqrt {b^2+a x^2}}} \, dx=-\frac {2 x \left (-2 b^2+a x^2\right )}{\left (b^2-a x^2\right ) \sqrt {b+\sqrt {b^2+a x^2}}}-\frac {\sqrt {2} \sqrt {b} \arctan \left (\frac {\sqrt {a} x}{\sqrt {2} \sqrt {b} \sqrt {b+\sqrt {b^2+a x^2}}}\right )}{\sqrt {a}}-\frac {\sqrt {b} \arctan \left (\frac {\sqrt {-1+\sqrt {2}} \sqrt {a} x}{\sqrt {b} \sqrt {b+\sqrt {b^2+a x^2}}}\right )}{\sqrt {2 \left (1+\sqrt {2}\right )} \sqrt {a}}-\frac {\sqrt {\frac {1}{2} \left (1+\sqrt {2}\right )} \sqrt {b} \text {arctanh}\left (\frac {\sqrt {1+\sqrt {2}} \sqrt {a} x}{\sqrt {b} \sqrt {b+\sqrt {b^2+a x^2}}}\right )}{\sqrt {a}} \]
(-2*x*(-2*b^2 + a*x^2))/((b^2 - a*x^2)*Sqrt[b + Sqrt[b^2 + a*x^2]]) - (Sqr t[2]*Sqrt[b]*ArcTan[(Sqrt[a]*x)/(Sqrt[2]*Sqrt[b]*Sqrt[b + Sqrt[b^2 + a*x^2 ]])])/Sqrt[a] - (Sqrt[b]*ArcTan[(Sqrt[-1 + Sqrt[2]]*Sqrt[a]*x)/(Sqrt[b]*Sq rt[b + Sqrt[b^2 + a*x^2]])])/(Sqrt[2*(1 + Sqrt[2])]*Sqrt[a]) - (Sqrt[(1 + Sqrt[2])/2]*Sqrt[b]*ArcTanh[(Sqrt[1 + Sqrt[2]]*Sqrt[a]*x)/(Sqrt[b]*Sqrt[b + Sqrt[b^2 + a*x^2]])])/Sqrt[a]
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int \frac {\left (a x^2+b^2\right )^2}{\left (a x^2-b^2\right )^2 \sqrt {\sqrt {a x^2+b^2}+b}} \, dx\) |
\(\Big \downarrow \) 7293 |
\(\displaystyle \int \left (-\frac {4 b^2}{\left (b^2-a x^2\right ) \sqrt {\sqrt {a x^2+b^2}+b}}+\frac {1}{\sqrt {\sqrt {a x^2+b^2}+b}}+\frac {4 b^4}{\left (b^2-a x^2\right )^2 \sqrt {\sqrt {a x^2+b^2}+b}}\right )dx\) |
\(\Big \downarrow \) 2009 |
\(\displaystyle a b^2 \int \frac {1}{\left (\sqrt {a} b-a x\right )^2 \sqrt {b+\sqrt {b^2+a x^2}}}dx+a b^2 \int \frac {1}{\left (\sqrt {a} b+a x\right )^2 \sqrt {b+\sqrt {b^2+a x^2}}}dx-b \int \frac {1}{\left (b-\sqrt {a} x\right ) \sqrt {b+\sqrt {b^2+a x^2}}}dx-b \int \frac {1}{\left (b+\sqrt {a} x\right ) \sqrt {b+\sqrt {b^2+a x^2}}}dx+\int \frac {1}{\sqrt {b+\sqrt {b^2+a x^2}}}dx\) |
3.32.2.3.1 Defintions of rubi rules used
\[\int \frac {\left (a \,x^{2}+b^{2}\right )^{2}}{\left (a \,x^{2}-b^{2}\right )^{2} \sqrt {b +\sqrt {a \,x^{2}+b^{2}}}}d x\]
Timed out. \[ \int \frac {\left (b^2+a x^2\right )^2}{\left (-b^2+a x^2\right )^2 \sqrt {b+\sqrt {b^2+a x^2}}} \, dx=\text {Timed out} \]
\[ \int \frac {\left (b^2+a x^2\right )^2}{\left (-b^2+a x^2\right )^2 \sqrt {b+\sqrt {b^2+a x^2}}} \, dx=\int \frac {\left (a x^{2} + b^{2}\right )^{2}}{\sqrt {b + \sqrt {a x^{2} + b^{2}}} \left (a x^{2} - b^{2}\right )^{2}}\, dx \]
\[ \int \frac {\left (b^2+a x^2\right )^2}{\left (-b^2+a x^2\right )^2 \sqrt {b+\sqrt {b^2+a x^2}}} \, dx=\int { \frac {{\left (a x^{2} + b^{2}\right )}^{2}}{{\left (a x^{2} - b^{2}\right )}^{2} \sqrt {b + \sqrt {a x^{2} + b^{2}}}} \,d x } \]
\[ \int \frac {\left (b^2+a x^2\right )^2}{\left (-b^2+a x^2\right )^2 \sqrt {b+\sqrt {b^2+a x^2}}} \, dx=\int { \frac {{\left (a x^{2} + b^{2}\right )}^{2}}{{\left (a x^{2} - b^{2}\right )}^{2} \sqrt {b + \sqrt {a x^{2} + b^{2}}}} \,d x } \]
Timed out. \[ \int \frac {\left (b^2+a x^2\right )^2}{\left (-b^2+a x^2\right )^2 \sqrt {b+\sqrt {b^2+a x^2}}} \, dx=\int \frac {{\left (b^2+a\,x^2\right )}^2}{{\left (a\,x^2-b^2\right )}^2\,\sqrt {b+\sqrt {b^2+a\,x^2}}} \,d x \]