3.12.54 \(\int \frac {(200 x-80 x^2+8 x^3) \log (\frac {25}{x^2})+(400 x-160 x^2+16 x^3+(200 x-120 x^2+16 x^3) \log (\frac {25}{x^2})) \log (\frac {12}{x})}{\log ^3(\frac {25}{x^2}) \log ^3(\frac {12}{x})} \, dx\) [1154]

3.12.54.1 Optimal result
3.12.54.2 Mathematica [A] (verified)
3.12.54.3 Rubi [F]
3.12.54.4 Maple [C] (verified)
3.12.54.5 Fricas [A] (verification not implemented)
3.12.54.6 Sympy [B] (verification not implemented)
3.12.54.7 Maxima [B] (verification not implemented)
3.12.54.8 Giac [B] (verification not implemented)
3.12.54.9 Mupad [B] (verification not implemented)

3.12.54.1 Optimal result

Integrand size = 81, antiderivative size = 28 \[ \int \frac {\left (200 x-80 x^2+8 x^3\right ) \log \left (\frac {25}{x^2}\right )+\left (400 x-160 x^2+16 x^3+\left (200 x-120 x^2+16 x^3\right ) \log \left (\frac {25}{x^2}\right )\right ) \log \left (\frac {12}{x}\right )}{\log ^3\left (\frac {25}{x^2}\right ) \log ^3\left (\frac {12}{x}\right )} \, dx=\frac {4 (5-x)^2 x^2}{\log ^2\left (\frac {25}{x^2}\right ) \log ^2\left (\frac {12}{x}\right )} \]

output
4*x^2/ln(12/x)^2/ln(25/x^2)^2*(5-x)^2
 
3.12.54.2 Mathematica [A] (verified)

Time = 0.44 (sec) , antiderivative size = 26, normalized size of antiderivative = 0.93 \[ \int \frac {\left (200 x-80 x^2+8 x^3\right ) \log \left (\frac {25}{x^2}\right )+\left (400 x-160 x^2+16 x^3+\left (200 x-120 x^2+16 x^3\right ) \log \left (\frac {25}{x^2}\right )\right ) \log \left (\frac {12}{x}\right )}{\log ^3\left (\frac {25}{x^2}\right ) \log ^3\left (\frac {12}{x}\right )} \, dx=\frac {4 (-5+x)^2 x^2}{\log ^2\left (\frac {25}{x^2}\right ) \log ^2\left (\frac {12}{x}\right )} \]

input
Integrate[((200*x - 80*x^2 + 8*x^3)*Log[25/x^2] + (400*x - 160*x^2 + 16*x^ 
3 + (200*x - 120*x^2 + 16*x^3)*Log[25/x^2])*Log[12/x])/(Log[25/x^2]^3*Log[ 
12/x]^3),x]
 
output
(4*(-5 + x)^2*x^2)/(Log[25/x^2]^2*Log[12/x]^2)
 
3.12.54.3 Rubi [F]

Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.

\(\displaystyle \int \frac {\left (8 x^3-80 x^2+200 x\right ) \log \left (\frac {25}{x^2}\right )+\left (16 x^3-160 x^2+\left (16 x^3-120 x^2+200 x\right ) \log \left (\frac {25}{x^2}\right )+400 x\right ) \log \left (\frac {12}{x}\right )}{\log ^3\left (\frac {25}{x^2}\right ) \log ^3\left (\frac {12}{x}\right )} \, dx\)

\(\Big \downarrow \) 7293

\(\displaystyle \int \left (\frac {8 x (x-5)^2}{\log ^2\left (\frac {25}{x^2}\right ) \log ^3\left (\frac {12}{x}\right )}+\frac {8 x (x-5) \left (2 x \log \left (\frac {25}{x^2}\right )-5 \log \left (\frac {25}{x^2}\right )+2 x-10\right )}{\log ^3\left (\frac {25}{x^2}\right ) \log ^2\left (\frac {12}{x}\right )}\right )dx\)

\(\Big \downarrow \) 2009

\(\displaystyle 200 \int \frac {x}{\log ^2\left (\frac {25}{x^2}\right ) \log ^2\left (\frac {12}{x}\right )}dx-120 \int \frac {x^2}{\log ^2\left (\frac {25}{x^2}\right ) \log ^2\left (\frac {12}{x}\right )}dx+200 \int \frac {x}{\log ^2\left (\frac {25}{x^2}\right ) \log ^3\left (\frac {12}{x}\right )}dx-80 \int \frac {x^2}{\log ^2\left (\frac {25}{x^2}\right ) \log ^3\left (\frac {12}{x}\right )}dx+400 \int \frac {x}{\log ^3\left (\frac {25}{x^2}\right ) \log ^2\left (\frac {12}{x}\right )}dx-160 \int \frac {x^2}{\log ^3\left (\frac {25}{x^2}\right ) \log ^2\left (\frac {12}{x}\right )}dx+16 \int \frac {x^3}{\log ^2\left (\frac {25}{x^2}\right ) \log ^2\left (\frac {12}{x}\right )}dx+8 \int \frac {x^3}{\log ^2\left (\frac {25}{x^2}\right ) \log ^3\left (\frac {12}{x}\right )}dx+16 \int \frac {x^3}{\log ^3\left (\frac {25}{x^2}\right ) \log ^2\left (\frac {12}{x}\right )}dx\)

input
Int[((200*x - 80*x^2 + 8*x^3)*Log[25/x^2] + (400*x - 160*x^2 + 16*x^3 + (2 
00*x - 120*x^2 + 16*x^3)*Log[25/x^2])*Log[12/x])/(Log[25/x^2]^3*Log[12/x]^ 
3),x]
 
output
$Aborted
 

3.12.54.3.1 Defintions of rubi rules used

rule 2009
Int[u_, x_Symbol] :> Simp[IntSum[u, x], x] /; SumQ[u]
 

rule 7293
Int[u_, x_Symbol] :> With[{v = ExpandIntegrand[u, x]}, Int[v, x] /; SumQ[v] 
]
 
3.12.54.4 Maple [C] (verified)

Result contains higher order function than in optimal. Order 4 vs. order 3.

Time = 10.16 (sec) , antiderivative size = 44256, normalized size of antiderivative = 1580.57

\[\text {output too large to display}\]

input
int((((16*x^3-120*x^2+200*x)*ln(25/x^2)+16*x^3-160*x^2+400*x)*ln(12/x)+(8* 
x^3-80*x^2+200*x)*ln(25/x^2))/ln(25/x^2)^3/ln(12/x)^3,x)
 
output
result too large to display
 
3.12.54.5 Fricas [A] (verification not implemented)

Time = 0.24 (sec) , antiderivative size = 52, normalized size of antiderivative = 1.86 \[ \int \frac {\left (200 x-80 x^2+8 x^3\right ) \log \left (\frac {25}{x^2}\right )+\left (400 x-160 x^2+16 x^3+\left (200 x-120 x^2+16 x^3\right ) \log \left (\frac {25}{x^2}\right )\right ) \log \left (\frac {12}{x}\right )}{\log ^3\left (\frac {25}{x^2}\right ) \log ^3\left (\frac {12}{x}\right )} \, dx=\frac {16 \, {\left (x^{4} - 10 \, x^{3} + 25 \, x^{2}\right )}}{\log \left (\frac {144}{25}\right )^{2} \log \left (\frac {25}{x^{2}}\right )^{2} + 2 \, \log \left (\frac {144}{25}\right ) \log \left (\frac {25}{x^{2}}\right )^{3} + \log \left (\frac {25}{x^{2}}\right )^{4}} \]

input
integrate((((16*x^3-120*x^2+200*x)*log(25/x^2)+16*x^3-160*x^2+400*x)*log(1 
2/x)+(8*x^3-80*x^2+200*x)*log(25/x^2))/log(25/x^2)^3/log(12/x)^3,x, algori 
thm=\
 
output
16*(x^4 - 10*x^3 + 25*x^2)/(log(144/25)^2*log(25/x^2)^2 + 2*log(144/25)*lo 
g(25/x^2)^3 + log(25/x^2)^4)
 
3.12.54.6 Sympy [B] (verification not implemented)

Leaf count of result is larger than twice the leaf count of optimal. 71 vs. \(2 (24) = 48\).

Time = 0.18 (sec) , antiderivative size = 71, normalized size of antiderivative = 2.54 \[ \int \frac {\left (200 x-80 x^2+8 x^3\right ) \log \left (\frac {25}{x^2}\right )+\left (400 x-160 x^2+16 x^3+\left (200 x-120 x^2+16 x^3\right ) \log \left (\frac {25}{x^2}\right )\right ) \log \left (\frac {12}{x}\right )}{\log ^3\left (\frac {25}{x^2}\right ) \log ^3\left (\frac {12}{x}\right )} \, dx=\frac {16 x^{4} - 160 x^{3} + 400 x^{2}}{\log {\left (\frac {25}{x^{2}} \right )}^{4} + \left (- 4 \log {\left (5 \right )} + 4 \log {\left (12 \right )}\right ) \log {\left (\frac {25}{x^{2}} \right )}^{3} + \left (- 8 \log {\left (5 \right )} \log {\left (12 \right )} + 4 \log {\left (5 \right )}^{2} + 4 \log {\left (12 \right )}^{2}\right ) \log {\left (\frac {25}{x^{2}} \right )}^{2}} \]

input
integrate((((16*x**3-120*x**2+200*x)*ln(25/x**2)+16*x**3-160*x**2+400*x)*l 
n(12/x)+(8*x**3-80*x**2+200*x)*ln(25/x**2))/ln(25/x**2)**3/ln(12/x)**3,x)
 
output
(16*x**4 - 160*x**3 + 400*x**2)/(log(25/x**2)**4 + (-4*log(5) + 4*log(12)) 
*log(25/x**2)**3 + (-8*log(5)*log(12) + 4*log(5)**2 + 4*log(12)**2)*log(25 
/x**2)**2)
 
3.12.54.7 Maxima [B] (verification not implemented)

Leaf count of result is larger than twice the leaf count of optimal. 145 vs. \(2 (26) = 52\).

Time = 0.35 (sec) , antiderivative size = 145, normalized size of antiderivative = 5.18 \[ \int \frac {\left (200 x-80 x^2+8 x^3\right ) \log \left (\frac {25}{x^2}\right )+\left (400 x-160 x^2+16 x^3+\left (200 x-120 x^2+16 x^3\right ) \log \left (\frac {25}{x^2}\right )\right ) \log \left (\frac {12}{x}\right )}{\log ^3\left (\frac {25}{x^2}\right ) \log ^3\left (\frac {12}{x}\right )} \, dx=\frac {x^{4} - 10 \, x^{3} + 25 \, x^{2}}{\log \left (5\right )^{2} \log \left (3\right )^{2} + 4 \, \log \left (5\right )^{2} \log \left (3\right ) \log \left (2\right ) + 4 \, \log \left (5\right )^{2} \log \left (2\right )^{2} - 2 \, {\left (\log \left (5\right ) + \log \left (3\right ) + 2 \, \log \left (2\right )\right )} \log \left (x\right )^{3} + \log \left (x\right )^{4} + {\left (\log \left (5\right )^{2} + 4 \, \log \left (5\right ) \log \left (3\right ) + \log \left (3\right )^{2} + 4 \, {\left (2 \, \log \left (5\right ) + \log \left (3\right )\right )} \log \left (2\right ) + 4 \, \log \left (2\right )^{2}\right )} \log \left (x\right )^{2} - 2 \, {\left (\log \left (5\right )^{2} \log \left (3\right ) + \log \left (5\right ) \log \left (3\right )^{2} + 4 \, \log \left (5\right ) \log \left (2\right )^{2} + 2 \, {\left (\log \left (5\right )^{2} + 2 \, \log \left (5\right ) \log \left (3\right )\right )} \log \left (2\right )\right )} \log \left (x\right )} \]

input
integrate((((16*x^3-120*x^2+200*x)*log(25/x^2)+16*x^3-160*x^2+400*x)*log(1 
2/x)+(8*x^3-80*x^2+200*x)*log(25/x^2))/log(25/x^2)^3/log(12/x)^3,x, algori 
thm=\
 
output
(x^4 - 10*x^3 + 25*x^2)/(log(5)^2*log(3)^2 + 4*log(5)^2*log(3)*log(2) + 4* 
log(5)^2*log(2)^2 - 2*(log(5) + log(3) + 2*log(2))*log(x)^3 + log(x)^4 + ( 
log(5)^2 + 4*log(5)*log(3) + log(3)^2 + 4*(2*log(5) + log(3))*log(2) + 4*l 
og(2)^2)*log(x)^2 - 2*(log(5)^2*log(3) + log(5)*log(3)^2 + 4*log(5)*log(2) 
^2 + 2*(log(5)^2 + 2*log(5)*log(3))*log(2))*log(x))
 
3.12.54.8 Giac [B] (verification not implemented)

Leaf count of result is larger than twice the leaf count of optimal. 284 vs. \(2 (26) = 52\).

Time = 0.32 (sec) , antiderivative size = 284, normalized size of antiderivative = 10.14 \[ \int \frac {\left (200 x-80 x^2+8 x^3\right ) \log \left (\frac {25}{x^2}\right )+\left (400 x-160 x^2+16 x^3+\left (200 x-120 x^2+16 x^3\right ) \log \left (\frac {25}{x^2}\right )\right ) \log \left (\frac {12}{x}\right )}{\log ^3\left (\frac {25}{x^2}\right ) \log ^3\left (\frac {12}{x}\right )} \, dx=\frac {x^{4} \log \left (12\right )^{2} - 2 \, x^{4} \log \left (12\right ) \log \left (5\right ) + x^{4} \log \left (5\right )^{2} - 10 \, x^{3} \log \left (12\right )^{2} + 20 \, x^{3} \log \left (12\right ) \log \left (5\right ) - 10 \, x^{3} \log \left (5\right )^{2} + 25 \, x^{2} \log \left (12\right )^{2} - 50 \, x^{2} \log \left (12\right ) \log \left (5\right ) + 25 \, x^{2} \log \left (5\right )^{2}}{\log \left (12\right )^{4} \log \left (5\right )^{2} - 2 \, \log \left (12\right )^{3} \log \left (5\right )^{3} + \log \left (12\right )^{2} \log \left (5\right )^{4} - 2 \, \log \left (12\right )^{4} \log \left (5\right ) \log \left (x\right ) + 2 \, \log \left (12\right )^{3} \log \left (5\right )^{2} \log \left (x\right ) + 2 \, \log \left (12\right )^{2} \log \left (5\right )^{3} \log \left (x\right ) - 2 \, \log \left (12\right ) \log \left (5\right )^{4} \log \left (x\right ) + \log \left (12\right )^{4} \log \left (x\right )^{2} + 2 \, \log \left (12\right )^{3} \log \left (5\right ) \log \left (x\right )^{2} - 6 \, \log \left (12\right )^{2} \log \left (5\right )^{2} \log \left (x\right )^{2} + 2 \, \log \left (12\right ) \log \left (5\right )^{3} \log \left (x\right )^{2} + \log \left (5\right )^{4} \log \left (x\right )^{2} - 2 \, \log \left (12\right )^{3} \log \left (x\right )^{3} + 2 \, \log \left (12\right )^{2} \log \left (5\right ) \log \left (x\right )^{3} + 2 \, \log \left (12\right ) \log \left (5\right )^{2} \log \left (x\right )^{3} - 2 \, \log \left (5\right )^{3} \log \left (x\right )^{3} + \log \left (12\right )^{2} \log \left (x\right )^{4} - 2 \, \log \left (12\right ) \log \left (5\right ) \log \left (x\right )^{4} + \log \left (5\right )^{2} \log \left (x\right )^{4}} \]

input
integrate((((16*x^3-120*x^2+200*x)*log(25/x^2)+16*x^3-160*x^2+400*x)*log(1 
2/x)+(8*x^3-80*x^2+200*x)*log(25/x^2))/log(25/x^2)^3/log(12/x)^3,x, algori 
thm=\
 
output
(x^4*log(12)^2 - 2*x^4*log(12)*log(5) + x^4*log(5)^2 - 10*x^3*log(12)^2 + 
20*x^3*log(12)*log(5) - 10*x^3*log(5)^2 + 25*x^2*log(12)^2 - 50*x^2*log(12 
)*log(5) + 25*x^2*log(5)^2)/(log(12)^4*log(5)^2 - 2*log(12)^3*log(5)^3 + l 
og(12)^2*log(5)^4 - 2*log(12)^4*log(5)*log(x) + 2*log(12)^3*log(5)^2*log(x 
) + 2*log(12)^2*log(5)^3*log(x) - 2*log(12)*log(5)^4*log(x) + log(12)^4*lo 
g(x)^2 + 2*log(12)^3*log(5)*log(x)^2 - 6*log(12)^2*log(5)^2*log(x)^2 + 2*l 
og(12)*log(5)^3*log(x)^2 + log(5)^4*log(x)^2 - 2*log(12)^3*log(x)^3 + 2*lo 
g(12)^2*log(5)*log(x)^3 + 2*log(12)*log(5)^2*log(x)^3 - 2*log(5)^3*log(x)^ 
3 + log(12)^2*log(x)^4 - 2*log(12)*log(5)*log(x)^4 + log(5)^2*log(x)^4)
 
3.12.54.9 Mupad [B] (verification not implemented)

Time = 10.50 (sec) , antiderivative size = 70, normalized size of antiderivative = 2.50 \[ \int \frac {\left (200 x-80 x^2+8 x^3\right ) \log \left (\frac {25}{x^2}\right )+\left (400 x-160 x^2+16 x^3+\left (200 x-120 x^2+16 x^3\right ) \log \left (\frac {25}{x^2}\right )\right ) \log \left (\frac {12}{x}\right )}{\log ^3\left (\frac {25}{x^2}\right ) \log ^3\left (\frac {12}{x}\right )} \, dx=\frac {4\,x^2\,{\left (x-5\right )}^2}{4\,{\ln \left (\frac {12}{x}\right )}^4-4\,{\ln \left (\frac {12}{x}\right )}^3\,\left (2\,\ln \left (\frac {1}{x}\right )+\ln \left (\frac {144\,x^2}{25}\right )\right )+{\ln \left (\frac {12}{x}\right )}^2\,{\left (2\,\ln \left (\frac {1}{x}\right )+\ln \left (\frac {144\,x^2}{25}\right )\right )}^2} \]

input
int((log(12/x)*(400*x + log(25/x^2)*(200*x - 120*x^2 + 16*x^3) - 160*x^2 + 
 16*x^3) + log(25/x^2)*(200*x - 80*x^2 + 8*x^3))/(log(12/x)^3*log(25/x^2)^ 
3),x)
 
output
(4*x^2*(x - 5)^2)/(4*log(12/x)^4 - 4*log(12/x)^3*(2*log(1/x) + log((144*x^ 
2)/25)) + log(12/x)^2*(2*log(1/x) + log((144*x^2)/25))^2)