Integrand size = 99, antiderivative size = 31 \[ \int \frac {25+150 x-25 x^2+e^{2 e^{-4+x}+2 x} \left (9-4 x+2 x^2+e^{-4+x} \left (8-2 x+2 x^2\right )\right )}{625+e^{4 e^{-4+x}+4 x}+1250 x^2+625 x^4+e^{2 e^{-4+x}+2 x} \left (50+50 x^2\right )} \, dx=\frac {-4+x-x^2}{25+e^{2 e^{-4+x}+2 x}+25 x^2} \]
Time = 0.12 (sec) , antiderivative size = 32, normalized size of antiderivative = 1.03 \[ \int \frac {25+150 x-25 x^2+e^{2 e^{-4+x}+2 x} \left (9-4 x+2 x^2+e^{-4+x} \left (8-2 x+2 x^2\right )\right )}{625+e^{4 e^{-4+x}+4 x}+1250 x^2+625 x^4+e^{2 e^{-4+x}+2 x} \left (50+50 x^2\right )} \, dx=-\frac {4-x+x^2}{25+e^{2 e^{-4+x}+2 x}+25 x^2} \]
Integrate[(25 + 150*x - 25*x^2 + E^(2*E^(-4 + x) + 2*x)*(9 - 4*x + 2*x^2 + E^(-4 + x)*(8 - 2*x + 2*x^2)))/(625 + E^(4*E^(-4 + x) + 4*x) + 1250*x^2 + 625*x^4 + E^(2*E^(-4 + x) + 2*x)*(50 + 50*x^2)),x]
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int \frac {-25 x^2+e^{2 x+2 e^{x-4}} \left (2 x^2+e^{x-4} \left (2 x^2-2 x+8\right )-4 x+9\right )+150 x+25}{625 x^4+1250 x^2+e^{2 x+2 e^{x-4}} \left (50 x^2+50\right )+e^{4 x+4 e^{x-4}}+625} \, dx\) |
\(\Big \downarrow \) 7292 |
\(\displaystyle \int \frac {-25 x^2+e^{2 x+2 e^{x-4}} \left (2 x^2+e^{x-4} \left (2 x^2-2 x+8\right )-4 x+9\right )+150 x+25}{\left (25 x^2+e^{2 x+2 e^{x-4}}+25\right )^2}dx\) |
\(\Big \downarrow \) 7293 |
\(\displaystyle \int \left (\frac {2 e^x x^2+2 e^4 x^2-2 e^x x-4 e^4 x+8 e^x+9 e^4}{e^4 \left (25 x^2+e^{2 x+2 e^{x-4}}+25\right )}-\frac {50 \left (x^2-x+4\right ) \left (e^x x^2+e^4 x^2-e^4 x+e^x+e^4\right )}{e^4 \left (25 x^2+e^{2 x+2 e^{x-4}}+25\right )^2}\right )dx\) |
\(\Big \downarrow \) 2009 |
\(\displaystyle -200 \int \frac {1}{\left (25 x^2+e^{2 x+2 e^{x-4}}+25\right )^2}dx-\frac {200 \int \frac {e^x}{\left (25 x^2+e^{2 x+2 e^{x-4}}+25\right )^2}dx}{e^4}+250 \int \frac {x}{\left (25 x^2+e^{2 x+2 e^{x-4}}+25\right )^2}dx+\frac {50 \int \frac {e^x x}{\left (25 x^2+e^{2 x+2 e^{x-4}}+25\right )^2}dx}{e^4}-300 \int \frac {x^2}{\left (25 x^2+e^{2 x+2 e^{x-4}}+25\right )^2}dx-\frac {250 \int \frac {e^x x^2}{\left (25 x^2+e^{2 x+2 e^{x-4}}+25\right )^2}dx}{e^4}+9 \int \frac {1}{25 x^2+e^{2 x+2 e^{x-4}}+25}dx+\frac {8 \int \frac {e^x}{25 x^2+e^{2 x+2 e^{x-4}}+25}dx}{e^4}-4 \int \frac {x}{25 x^2+e^{2 x+2 e^{x-4}}+25}dx-\frac {2 \int \frac {e^x x}{25 x^2+e^{2 x+2 e^{x-4}}+25}dx}{e^4}+2 \int \frac {x^2}{25 x^2+e^{2 x+2 e^{x-4}}+25}dx+\frac {2 \int \frac {e^x x^2}{25 x^2+e^{2 x+2 e^{x-4}}+25}dx}{e^4}-50 \int \frac {x^4}{\left (25 x^2+e^{2 x+2 e^{x-4}}+25\right )^2}dx-\frac {50 \int \frac {e^x x^4}{\left (25 x^2+e^{2 x+2 e^{x-4}}+25\right )^2}dx}{e^4}+100 \int \frac {x^3}{\left (25 x^2+e^{2 x+2 e^{x-4}}+25\right )^2}dx+\frac {50 \int \frac {e^x x^3}{\left (25 x^2+e^{2 x+2 e^{x-4}}+25\right )^2}dx}{e^4}\) |
Int[(25 + 150*x - 25*x^2 + E^(2*E^(-4 + x) + 2*x)*(9 - 4*x + 2*x^2 + E^(-4 + x)*(8 - 2*x + 2*x^2)))/(625 + E^(4*E^(-4 + x) + 4*x) + 1250*x^2 + 625*x ^4 + E^(2*E^(-4 + x) + 2*x)*(50 + 50*x^2)),x]
3.23.70.3.1 Defintions of rubi rules used
Time = 0.16 (sec) , antiderivative size = 28, normalized size of antiderivative = 0.90
method | result | size |
parallelrisch | \(\frac {-x^{2}+x -4}{25 x^{2}+25+{\mathrm e}^{2 x +2 \,{\mathrm e}^{x -4}}}\) | \(28\) |
risch | \(-\frac {x^{2}-x +4}{25 x^{2}+25+{\mathrm e}^{2 x +2 \,{\mathrm e}^{x -4}}}\) | \(31\) |
int((((2*x^2-2*x+8)*exp(x-4)+2*x^2-4*x+9)*exp(x+exp(x-4))^2-25*x^2+150*x+2 5)/(exp(x+exp(x-4))^4+(50*x^2+50)*exp(x+exp(x-4))^2+625*x^4+1250*x^2+625), x,method=_RETURNVERBOSE)
Time = 0.25 (sec) , antiderivative size = 30, normalized size of antiderivative = 0.97 \[ \int \frac {25+150 x-25 x^2+e^{2 e^{-4+x}+2 x} \left (9-4 x+2 x^2+e^{-4+x} \left (8-2 x+2 x^2\right )\right )}{625+e^{4 e^{-4+x}+4 x}+1250 x^2+625 x^4+e^{2 e^{-4+x}+2 x} \left (50+50 x^2\right )} \, dx=-\frac {x^{2} - x + 4}{25 \, x^{2} + e^{\left (2 \, x + 2 \, e^{\left (x - 4\right )}\right )} + 25} \]
integrate((((2*x^2-2*x+8)*exp(x-4)+2*x^2-4*x+9)*exp(x+exp(x-4))^2-25*x^2+1 50*x+25)/(exp(x+exp(x-4))^4+(50*x^2+50)*exp(x+exp(x-4))^2+625*x^4+1250*x^2 +625),x, algorithm=\
Time = 0.10 (sec) , antiderivative size = 24, normalized size of antiderivative = 0.77 \[ \int \frac {25+150 x-25 x^2+e^{2 e^{-4+x}+2 x} \left (9-4 x+2 x^2+e^{-4+x} \left (8-2 x+2 x^2\right )\right )}{625+e^{4 e^{-4+x}+4 x}+1250 x^2+625 x^4+e^{2 e^{-4+x}+2 x} \left (50+50 x^2\right )} \, dx=\frac {- x^{2} + x - 4}{25 x^{2} + e^{2 x + 2 e^{x - 4}} + 25} \]
integrate((((2*x**2-2*x+8)*exp(x-4)+2*x**2-4*x+9)*exp(x+exp(x-4))**2-25*x* *2+150*x+25)/(exp(x+exp(x-4))**4+(50*x**2+50)*exp(x+exp(x-4))**2+625*x**4+ 1250*x**2+625),x)
Time = 0.24 (sec) , antiderivative size = 30, normalized size of antiderivative = 0.97 \[ \int \frac {25+150 x-25 x^2+e^{2 e^{-4+x}+2 x} \left (9-4 x+2 x^2+e^{-4+x} \left (8-2 x+2 x^2\right )\right )}{625+e^{4 e^{-4+x}+4 x}+1250 x^2+625 x^4+e^{2 e^{-4+x}+2 x} \left (50+50 x^2\right )} \, dx=-\frac {x^{2} - x + 4}{25 \, x^{2} + e^{\left (2 \, x + 2 \, e^{\left (x - 4\right )}\right )} + 25} \]
integrate((((2*x^2-2*x+8)*exp(x-4)+2*x^2-4*x+9)*exp(x+exp(x-4))^2-25*x^2+1 50*x+25)/(exp(x+exp(x-4))^4+(50*x^2+50)*exp(x+exp(x-4))^2+625*x^4+1250*x^2 +625),x, algorithm=\
Time = 0.30 (sec) , antiderivative size = 30, normalized size of antiderivative = 0.97 \[ \int \frac {25+150 x-25 x^2+e^{2 e^{-4+x}+2 x} \left (9-4 x+2 x^2+e^{-4+x} \left (8-2 x+2 x^2\right )\right )}{625+e^{4 e^{-4+x}+4 x}+1250 x^2+625 x^4+e^{2 e^{-4+x}+2 x} \left (50+50 x^2\right )} \, dx=-\frac {x^{2} - x + 4}{25 \, x^{2} + e^{\left (2 \, x + 2 \, e^{\left (x - 4\right )}\right )} + 25} \]
integrate((((2*x^2-2*x+8)*exp(x-4)+2*x^2-4*x+9)*exp(x+exp(x-4))^2-25*x^2+1 50*x+25)/(exp(x+exp(x-4))^4+(50*x^2+50)*exp(x+exp(x-4))^2+625*x^4+1250*x^2 +625),x, algorithm=\
Timed out. \[ \int \frac {25+150 x-25 x^2+e^{2 e^{-4+x}+2 x} \left (9-4 x+2 x^2+e^{-4+x} \left (8-2 x+2 x^2\right )\right )}{625+e^{4 e^{-4+x}+4 x}+1250 x^2+625 x^4+e^{2 e^{-4+x}+2 x} \left (50+50 x^2\right )} \, dx=\int \frac {150\,x+{\mathrm {e}}^{2\,x+2\,{\mathrm {e}}^{x-4}}\,\left ({\mathrm {e}}^{x-4}\,\left (2\,x^2-2\,x+8\right )-4\,x+2\,x^2+9\right )-25\,x^2+25}{{\mathrm {e}}^{4\,x+4\,{\mathrm {e}}^{x-4}}+{\mathrm {e}}^{2\,x+2\,{\mathrm {e}}^{x-4}}\,\left (50\,x^2+50\right )+1250\,x^2+625\,x^4+625} \,d x \]
int((150*x + exp(2*x + 2*exp(x - 4))*(exp(x - 4)*(2*x^2 - 2*x + 8) - 4*x + 2*x^2 + 9) - 25*x^2 + 25)/(exp(4*x + 4*exp(x - 4)) + exp(2*x + 2*exp(x - 4))*(50*x^2 + 50) + 1250*x^2 + 625*x^4 + 625),x)