Integrand size = 135, antiderivative size = 24 \[ \int \frac {-12-403 x-2438 x^2-535 x^3+2360 x^4-672 x^5-128 x^6+48 x^7+e^2 \left (4 x^4+x^5\right )+e \left (-8 x^2-2 x^3-158 x^4+24 x^5+16 x^6\right )+\left (-16 x-204 x^2-48 x^3+32 x^4+8 x^5\right ) \log (4+x)+\left (-4 x^2-x^3\right ) \log ^2(4+x)}{4 x^4+x^5} \, dx=\frac {\left ((5-2 x)^2+\frac {1}{x}+e x+\log (4+x)\right )^2}{x} \]
Leaf count is larger than twice the leaf count of optimal. \(79\) vs. \(2(24)=48\).
Time = 0.07 (sec) , antiderivative size = 79, normalized size of antiderivative = 3.29 \[ \int \frac {-12-403 x-2438 x^2-535 x^3+2360 x^4-672 x^5-128 x^6+48 x^7+e^2 \left (4 x^4+x^5\right )+e \left (-8 x^2-2 x^3-158 x^4+24 x^5+16 x^6\right )+\left (-16 x-204 x^2-48 x^3+32 x^4+8 x^5\right ) \log (4+x)+\left (-4 x^2-x^3\right ) \log ^2(4+x)}{4 x^4+x^5} \, dx=\frac {1}{x^3}+\frac {50}{x^2}+\frac {585+2 e}{x}+\left (600-40 e+e^2\right ) x+8 (-20+e) x^2+16 x^3+2 (-20+e) \log (4+x)+\frac {2 \left (1+25 x+4 x^3\right ) \log (4+x)}{x^2}+\frac {\log ^2(4+x)}{x} \]
Integrate[(-12 - 403*x - 2438*x^2 - 535*x^3 + 2360*x^4 - 672*x^5 - 128*x^6 + 48*x^7 + E^2*(4*x^4 + x^5) + E*(-8*x^2 - 2*x^3 - 158*x^4 + 24*x^5 + 16* x^6) + (-16*x - 204*x^2 - 48*x^3 + 32*x^4 + 8*x^5)*Log[4 + x] + (-4*x^2 - x^3)*Log[4 + x]^2)/(4*x^4 + x^5),x]
x^(-3) + 50/x^2 + (585 + 2*E)/x + (600 - 40*E + E^2)*x + 8*(-20 + E)*x^2 + 16*x^3 + 2*(-20 + E)*Log[4 + x] + (2*(1 + 25*x + 4*x^3)*Log[4 + x])/x^2 + Log[4 + x]^2/x
Leaf count is larger than twice the leaf count of optimal. \(114\) vs. \(2(24)=48\).
Time = 1.12 (sec) , antiderivative size = 114, normalized size of antiderivative = 4.75, number of steps used = 3, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.022, Rules used = {2026, 7293, 2009}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
| \(\displaystyle \int \frac {48 x^7-128 x^6-672 x^5+2360 x^4-535 x^3-2438 x^2+e^2 \left (x^5+4 x^4\right )+\left (-x^3-4 x^2\right ) \log ^2(x+4)+\left (8 x^5+32 x^4-48 x^3-204 x^2-16 x\right ) \log (x+4)+e \left (16 x^6+24 x^5-158 x^4-2 x^3-8 x^2\right )-403 x-12}{x^5+4 x^4} \, dx\) |
| \(\Big \downarrow \) 2026 |
| \(\displaystyle \int \frac {48 x^7-128 x^6-672 x^5+2360 x^4-535 x^3-2438 x^2+e^2 \left (x^5+4 x^4\right )+\left (-x^3-4 x^2\right ) \log ^2(x+4)+\left (8 x^5+32 x^4-48 x^3-204 x^2-16 x\right ) \log (x+4)+e \left (16 x^6+24 x^5-158 x^4-2 x^3-8 x^2\right )-403 x-12}{x^4 (x+4)}dx\) |
| \(\Big \downarrow \) 7293 |
| \(\displaystyle \int \left (-\frac {12}{(x+4) x^4}+\frac {48 x^3}{x+4}-\frac {403}{(x+4) x^3}-\frac {128 x^2}{x+4}-\frac {2438}{(x+4) x^2}-\frac {\log ^2(x+4)}{x^2}+\frac {2 e \left (8 x^4+12 x^3-79 x^2-x-4\right )}{(x+4) x^2}+\frac {4 \left (2 x^4+8 x^3-12 x^2-51 x-4\right ) \log (x+4)}{(x+4) x^3}-\frac {672 x}{x+4}+\frac {2360}{x+4}-\frac {535}{(x+4) x}+e^2\right )dx\) |
| \(\Big \downarrow \) 2009 |
| \(\displaystyle 16 x^3+\frac {1}{x^3}+8 e x^2-160 x^2+\frac {50}{x^2}+\frac {2 \log (x+4)}{x^2}+e^2 x-40 e x+600 x+\frac {2 e}{x}+\frac {585}{x}-\frac {1}{4} \log ^2(x+4)+\frac {(x+4) \log ^2(x+4)}{4 x}+8 (x+4) \log (x+4)+2 e \log (x+4)-72 \log (x+4)+\frac {50 \log (x+4)}{x}\) |
Int[(-12 - 403*x - 2438*x^2 - 535*x^3 + 2360*x^4 - 672*x^5 - 128*x^6 + 48* x^7 + E^2*(4*x^4 + x^5) + E*(-8*x^2 - 2*x^3 - 158*x^4 + 24*x^5 + 16*x^6) + (-16*x - 204*x^2 - 48*x^3 + 32*x^4 + 8*x^5)*Log[4 + x] + (-4*x^2 - x^3)*L og[4 + x]^2)/(4*x^4 + x^5),x]
x^(-3) + 50/x^2 + 585/x + (2*E)/x + 600*x - 40*E*x + E^2*x - 160*x^2 + 8*E *x^2 + 16*x^3 - 72*Log[4 + x] + 2*E*Log[4 + x] + (2*Log[4 + x])/x^2 + (50* Log[4 + x])/x + 8*(4 + x)*Log[4 + x] - Log[4 + x]^2/4 + ((4 + x)*Log[4 + x ]^2)/(4*x)
3.16.99.3.1 Defintions of rubi rules used
Int[(Fx_.)*(Px_)^(p_.), x_Symbol] :> With[{r = Expon[Px, x, Min]}, Int[x^(p *r)*ExpandToSum[Px/x^r, x]^p*Fx, x] /; IGtQ[r, 0]] /; PolyQ[Px, x] && Integ erQ[p] && !MonomialQ[Px, x] && (ILtQ[p, 0] || !PolyQ[u, x])
Leaf count of result is larger than twice the leaf count of optimal. \(97\) vs. \(2(25)=50\).
Time = 0.34 (sec) , antiderivative size = 98, normalized size of antiderivative = 4.08
| method | result | size |
| norman | \(\frac {1+x^{2} \ln \left (4+x \right )^{2}+\left (-160+8 \,{\mathrm e}\right ) x^{5}+\left (585+2 \,{\mathrm e}\right ) x^{2}+\left (600-40 \,{\mathrm e}+{\mathrm e}^{2}\right ) x^{4}+\left (-40+2 \,{\mathrm e}\right ) x^{3} \ln \left (4+x \right )+50 x +16 x^{6}+50 x^{2} \ln \left (4+x \right )+2 \ln \left (4+x \right ) x +8 \ln \left (4+x \right ) x^{4}}{x^{3}}\) | \(98\) |
| risch | \(\frac {\ln \left (4+x \right )^{2}}{x}+\frac {2 \left (4 x^{3}+25 x +1\right ) \ln \left (4+x \right )}{x^{2}}+\frac {x^{4} {\mathrm e}^{2}+8 x^{5} {\mathrm e}+16 x^{6}+2 \ln \left (-4-x \right ) x^{3} {\mathrm e}-40 x^{4} {\mathrm e}-160 x^{5}-40 \ln \left (-4-x \right ) x^{3}+600 x^{4}+2 x^{2} {\mathrm e}+585 x^{2}+50 x +1}{x^{3}}\) | \(111\) |
| parallelrisch | \(\frac {x^{4} {\mathrm e}^{2}+8 x^{5} {\mathrm e}+16 x^{6}-8 x^{3} {\mathrm e}^{2}-40 x^{4} {\mathrm e}+2 \ln \left (4+x \right ) x^{3} {\mathrm e}-160 x^{5}+8 \ln \left (4+x \right ) x^{4}+192 x^{3} {\mathrm e}+600 x^{4}-40 x^{3} \ln \left (4+x \right )+1+x^{2} \ln \left (4+x \right )^{2}+2 x^{2} {\mathrm e}-2240 x^{3}+50 x^{2} \ln \left (4+x \right )+585 x^{2}+2 \ln \left (4+x \right ) x +50 x}{x^{3}}\) | \(135\) |
int(((-x^3-4*x^2)*ln(4+x)^2+(8*x^5+32*x^4-48*x^3-204*x^2-16*x)*ln(4+x)+(x^ 5+4*x^4)*exp(1)^2+(16*x^6+24*x^5-158*x^4-2*x^3-8*x^2)*exp(1)+48*x^7-128*x^ 6-672*x^5+2360*x^4-535*x^3-2438*x^2-403*x-12)/(x^5+4*x^4),x,method=_RETURN VERBOSE)
(1+x^2*ln(4+x)^2+(-160+8*exp(1))*x^5+(585+2*exp(1))*x^2+(600-40*exp(1)+exp (1)^2)*x^4+(-40+2*exp(1))*x^3*ln(4+x)+50*x+16*x^6+50*x^2*ln(4+x)+2*ln(4+x) *x+8*ln(4+x)*x^4)/x^3
Leaf count of result is larger than twice the leaf count of optimal. 92 vs. \(2 (25) = 50\).
Time = 0.30 (sec) , antiderivative size = 92, normalized size of antiderivative = 3.83 \[ \int \frac {-12-403 x-2438 x^2-535 x^3+2360 x^4-672 x^5-128 x^6+48 x^7+e^2 \left (4 x^4+x^5\right )+e \left (-8 x^2-2 x^3-158 x^4+24 x^5+16 x^6\right )+\left (-16 x-204 x^2-48 x^3+32 x^4+8 x^5\right ) \log (4+x)+\left (-4 x^2-x^3\right ) \log ^2(4+x)}{4 x^4+x^5} \, dx=\frac {16 \, x^{6} - 160 \, x^{5} + x^{4} e^{2} + 600 \, x^{4} + x^{2} \log \left (x + 4\right )^{2} + 585 \, x^{2} + 2 \, {\left (4 \, x^{5} - 20 \, x^{4} + x^{2}\right )} e + 2 \, {\left (4 \, x^{4} + x^{3} e - 20 \, x^{3} + 25 \, x^{2} + x\right )} \log \left (x + 4\right ) + 50 \, x + 1}{x^{3}} \]
integrate(((-x^3-4*x^2)*log(4+x)^2+(8*x^5+32*x^4-48*x^3-204*x^2-16*x)*log( 4+x)+(x^5+4*x^4)*exp(1)^2+(16*x^6+24*x^5-158*x^4-2*x^3-8*x^2)*exp(1)+48*x^ 7-128*x^6-672*x^5+2360*x^4-535*x^3-2438*x^2-403*x-12)/(x^5+4*x^4),x, algor ithm=\
(16*x^6 - 160*x^5 + x^4*e^2 + 600*x^4 + x^2*log(x + 4)^2 + 585*x^2 + 2*(4* x^5 - 20*x^4 + x^2)*e + 2*(4*x^4 + x^3*e - 20*x^3 + 25*x^2 + x)*log(x + 4) + 50*x + 1)/x^3
Leaf count of result is larger than twice the leaf count of optimal. 83 vs. \(2 (22) = 44\).
Time = 0.53 (sec) , antiderivative size = 83, normalized size of antiderivative = 3.46 \[ \int \frac {-12-403 x-2438 x^2-535 x^3+2360 x^4-672 x^5-128 x^6+48 x^7+e^2 \left (4 x^4+x^5\right )+e \left (-8 x^2-2 x^3-158 x^4+24 x^5+16 x^6\right )+\left (-16 x-204 x^2-48 x^3+32 x^4+8 x^5\right ) \log (4+x)+\left (-4 x^2-x^3\right ) \log ^2(4+x)}{4 x^4+x^5} \, dx=16 x^{3} + x^{2} \left (-160 + 8 e\right ) + x \left (- 40 e + e^{2} + 600\right ) + 2 \left (-20 + e\right ) \log {\left (x + 4 \right )} + \frac {\log {\left (x + 4 \right )}^{2}}{x} + \frac {\left (8 x^{3} + 50 x + 2\right ) \log {\left (x + 4 \right )}}{x^{2}} + \frac {x^{2} \cdot \left (2 e + 585\right ) + 50 x + 1}{x^{3}} \]
integrate(((-x**3-4*x**2)*ln(4+x)**2+(8*x**5+32*x**4-48*x**3-204*x**2-16*x )*ln(4+x)+(x**5+4*x**4)*exp(1)**2+(16*x**6+24*x**5-158*x**4-2*x**3-8*x**2) *exp(1)+48*x**7-128*x**6-672*x**5+2360*x**4-535*x**3-2438*x**2-403*x-12)/( x**5+4*x**4),x)
16*x**3 + x**2*(-160 + 8*E) + x*(-40*E + exp(2) + 600) + 2*(-20 + E)*log(x + 4) + log(x + 4)**2/x + (8*x**3 + 50*x + 2)*log(x + 4)/x**2 + (x**2*(2*E + 585) + 50*x + 1)/x**3
Leaf count of result is larger than twice the leaf count of optimal. 179 vs. \(2 (25) = 50\).
Time = 0.24 (sec) , antiderivative size = 179, normalized size of antiderivative = 7.46 \[ \int \frac {-12-403 x-2438 x^2-535 x^3+2360 x^4-672 x^5-128 x^6+48 x^7+e^2 \left (4 x^4+x^5\right )+e \left (-8 x^2-2 x^3-158 x^4+24 x^5+16 x^6\right )+\left (-16 x-204 x^2-48 x^3+32 x^4+8 x^5\right ) \log (4+x)+\left (-4 x^2-x^3\right ) \log ^2(4+x)}{4 x^4+x^5} \, dx=16 \, x^{3} - 160 \, x^{2} + {\left (x - 4 \, \log \left (x + 4\right )\right )} e^{2} + 8 \, {\left (x^{2} - 8 \, x + 32 \, \log \left (x + 4\right )\right )} e + 24 \, {\left (x - 4 \, \log \left (x + 4\right )\right )} e + \frac {1}{2} \, {\left (\frac {4}{x} - \log \left (x + 4\right ) + \log \left (x\right )\right )} e + \frac {1}{2} \, {\left (\log \left (x + 4\right ) - \log \left (x\right )\right )} e + 4 \, e^{2} \log \left (x + 4\right ) - 158 \, e \log \left (x + 4\right ) + 608 \, x - \frac {64 \, x^{3} - 8 \, x \log \left (x + 4\right )^{2} - {\left (64 \, x^{3} + 355 \, x^{2} + 400 \, x + 16\right )} \log \left (x + 4\right ) - 4 \, x}{8 \, x^{2}} - \frac {403 \, {\left (x - 2\right )}}{16 \, x^{2}} + \frac {1219}{2 \, x} + \frac {3 \, x^{2} - 6 \, x + 16}{16 \, x^{3}} - \frac {675}{8} \, \log \left (x + 4\right ) \]
integrate(((-x^3-4*x^2)*log(4+x)^2+(8*x^5+32*x^4-48*x^3-204*x^2-16*x)*log( 4+x)+(x^5+4*x^4)*exp(1)^2+(16*x^6+24*x^5-158*x^4-2*x^3-8*x^2)*exp(1)+48*x^ 7-128*x^6-672*x^5+2360*x^4-535*x^3-2438*x^2-403*x-12)/(x^5+4*x^4),x, algor ithm=\
16*x^3 - 160*x^2 + (x - 4*log(x + 4))*e^2 + 8*(x^2 - 8*x + 32*log(x + 4))* e + 24*(x - 4*log(x + 4))*e + 1/2*(4/x - log(x + 4) + log(x))*e + 1/2*(log (x + 4) - log(x))*e + 4*e^2*log(x + 4) - 158*e*log(x + 4) + 608*x - 1/8*(6 4*x^3 - 8*x*log(x + 4)^2 - (64*x^3 + 355*x^2 + 400*x + 16)*log(x + 4) - 4* x)/x^2 - 403/16*(x - 2)/x^2 + 1219/2/x + 1/16*(3*x^2 - 6*x + 16)/x^3 - 675 /8*log(x + 4)
Leaf count of result is larger than twice the leaf count of optimal. 111 vs. \(2 (25) = 50\).
Time = 0.28 (sec) , antiderivative size = 111, normalized size of antiderivative = 4.62 \[ \int \frac {-12-403 x-2438 x^2-535 x^3+2360 x^4-672 x^5-128 x^6+48 x^7+e^2 \left (4 x^4+x^5\right )+e \left (-8 x^2-2 x^3-158 x^4+24 x^5+16 x^6\right )+\left (-16 x-204 x^2-48 x^3+32 x^4+8 x^5\right ) \log (4+x)+\left (-4 x^2-x^3\right ) \log ^2(4+x)}{4 x^4+x^5} \, dx=\frac {16 \, x^{6} + 8 \, x^{5} e - 160 \, x^{5} + x^{4} e^{2} - 40 \, x^{4} e + 8 \, x^{4} \log \left (x + 4\right ) + 2 \, x^{3} e \log \left (x + 4\right ) + 600 \, x^{4} - 40 \, x^{3} \log \left (x + 4\right ) + x^{2} \log \left (x + 4\right )^{2} + 2 \, x^{2} e + 50 \, x^{2} \log \left (x + 4\right ) + 585 \, x^{2} + 2 \, x \log \left (x + 4\right ) + 50 \, x + 1}{x^{3}} \]
integrate(((-x^3-4*x^2)*log(4+x)^2+(8*x^5+32*x^4-48*x^3-204*x^2-16*x)*log( 4+x)+(x^5+4*x^4)*exp(1)^2+(16*x^6+24*x^5-158*x^4-2*x^3-8*x^2)*exp(1)+48*x^ 7-128*x^6-672*x^5+2360*x^4-535*x^3-2438*x^2-403*x-12)/(x^5+4*x^4),x, algor ithm=\
(16*x^6 + 8*x^5*e - 160*x^5 + x^4*e^2 - 40*x^4*e + 8*x^4*log(x + 4) + 2*x^ 3*e*log(x + 4) + 600*x^4 - 40*x^3*log(x + 4) + x^2*log(x + 4)^2 + 2*x^2*e + 50*x^2*log(x + 4) + 585*x^2 + 2*x*log(x + 4) + 50*x + 1)/x^3
Time = 14.27 (sec) , antiderivative size = 88, normalized size of antiderivative = 3.67 \[ \int \frac {-12-403 x-2438 x^2-535 x^3+2360 x^4-672 x^5-128 x^6+48 x^7+e^2 \left (4 x^4+x^5\right )+e \left (-8 x^2-2 x^3-158 x^4+24 x^5+16 x^6\right )+\left (-16 x-204 x^2-48 x^3+32 x^4+8 x^5\right ) \log (4+x)+\left (-4 x^2-x^3\right ) \log ^2(4+x)}{4 x^4+x^5} \, dx=600\,x-40\,\ln \left (x+4\right )+2\,\ln \left (x+4\right )\,\mathrm {e}+8\,x\,\ln \left (x+4\right )+\frac {2\,\ln \left (x+4\right )+50}{x^2}-40\,x\,\mathrm {e}+x\,{\mathrm {e}}^2+8\,x^2\,\mathrm {e}+\frac {{\ln \left (x+4\right )}^2+50\,\ln \left (x+4\right )+2\,\mathrm {e}+585}{x}-160\,x^2+\frac {1}{x^3}+16\,x^3 \]
int(-(403*x - exp(2)*(4*x^4 + x^5) + exp(1)*(8*x^2 + 2*x^3 + 158*x^4 - 24* x^5 - 16*x^6) + log(x + 4)^2*(4*x^2 + x^3) + log(x + 4)*(16*x + 204*x^2 + 48*x^3 - 32*x^4 - 8*x^5) + 2438*x^2 + 535*x^3 - 2360*x^4 + 672*x^5 + 128*x ^6 - 48*x^7 + 12)/(4*x^4 + x^5),x)